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Add lean source and binary files (part 84)
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import OAI.LinearAlgebra.Hadamard.CubeFibers
namespace OAI
/-! The dichotomy implied by the two Fourier product identities. -/
open scoped BigOperators Matrix
namespace HadamardSix
def crossCharge : Charge := differenceCharge 2 0 3
def sameCharge : Charge := differenceCharge 2 0 1
lemma crossCharge_eq : crossCharge = ![2, 0, 0, -2, 0, 0] := by decide
lemma sameCharge_eq : sameCharge = ![2, -2, 0, 0, 0, 0] := by decide
private def pairOrdering : Index → Index → Index → Index :=
![ ![![0, 1, 2, 3, 4, 5],
![0, 1, 2, 3, 4, 5],
![0, 2, 1, 3, 4, 5],
![0, 1, 2, 3, 4, 5],
![0, 1, 2, 4, 3, 5],
![0, 1, 2, 4, 5, 3]],
![![1, 0, 2, 3, 4, 5],
![0, 1, 2, 3, 4, 5],
![2, 0, 1, 3, 4, 5],
![1, 0, 2, 3, 4, 5],
![1, 0, 2, 4, 3, 5],
![1, 0, 2, 4, 5, 3]],
![![1, 2, 0, 3, 4, 5],
![2, 1, 0, 3, 4, 5],
![0, 1, 2, 3, 4, 5],
![1, 2, 0, 3, 4, 5],
![1, 2, 0, 4, 3, 5],
![1, 2, 0, 4, 5, 3]],
![![3, 4, 5, 0, 1, 2],
![4, 3, 5, 0, 1, 2],
![4, 5, 3, 0, 1, 2],
![0, 1, 2, 3, 4, 5],
![3, 4, 5, 0, 1, 2],
![3, 4, 5, 0, 2, 1]],
![![3, 4, 5, 1, 0, 2],
![4, 3, 5, 1, 0, 2],
![4, 5, 3, 1, 0, 2],
![3, 4, 5, 1, 0, 2],
![0, 1, 2, 3, 4, 5],
![3, 4, 5, 2, 0, 1]],
![![3, 4, 5, 1, 2, 0],
![4, 3, 5, 1, 2, 0],
![4, 5, 3, 1, 2, 0],
![3, 4, 5, 1, 2, 0],
![3, 4, 5, 2, 1, 0],
![0, 1, 2, 3, 4, 5]]]
private lemma pairOrdering_bijective (i j : Index) :
Function.Bijective (pairOrdering i j) := by
fin_cases i <;> fin_cases j <;> decide
lemma double_difference_transport (i j : Index) (hij : i ≠ j) :
∃ (p : Equiv.Perm Index) (q : Charge),
(q = crossCharge ∨ q = sameCharge) ∧
(permuteCharge p alpha = alpha ∨ permuteCharge p alpha = -alpha) ∧
permuteCharge p q = differenceCharge 2 i j := by
let p := Equiv.ofBijective (pairOrdering i j) (pairOrdering_bijective i j)
refine ⟨p, if i.val / 3 = j.val / 3 then sameCharge else crossCharge, ?_, ?_, ?_⟩
· split_ifs <;> simp
· fin_cases i <;> fin_cases j <;> decide
· fin_cases i <;> fin_cases j <;> first | exact (hij rfl).elim | decide
lemma dichotomy_of_product_identities {H : Matrix6} (hH : IsComplexHadamard H)
(hcross : ∀ p : Equiv.Perm Index,
g H (permuteCharge p alpha) * g H (permuteCharge p crossCharge) = 0)
(hsame : ∀ p : Equiv.Perm Index,
g H (permuteCharge p alpha) * g H (permuteCharge p sameCharge) = 0) :
(∀ p : Equiv.Perm Index, g H (permuteCharge p alpha) = 0) ∨
IsComplexHadamard (entrywiseSquare H) := by
classical
by_cases hvanish : ∀ p : Equiv.Perm Index, g H (permuteCharge p alpha) = 0
· exact Or.inl hvanish
right
push Not at hvanish
obtain ⟨p, hp⟩ := hvanish
let K : Matrix6 := fun i k => H (p.symm i) k
have hK : IsComplexHadamard K := hH.permute_rows p.symm
have hnonzero : g K alpha ≠ 0 := by
simpa [K, ← g_permuteCharge] using hp
have hnegative : g K (-alpha) ≠ 0 := by
rw [g_neg hK.1]
exact star_ne_zero.mpr hnonzero
have hc (q : Equiv.Perm Index) :
g K (permuteCharge q alpha) * g K (permuteCharge q crossCharge) = 0 := by
simpa only [K, ← g_permuteCharge, permuteCharge_trans] using hcross (p.trans q)
have hs (q : Equiv.Perm Index) :
g K (permuteCharge q alpha) * g K (permuteCharge q sameCharge) = 0 := by
simpa only [K, ← g_permuteCharge, permuteCharge_trans] using hsame (p.trans q)
have hKs : IsComplexHadamard (entrywiseSquare K) := by
apply (square_hadamard_iff hK.1).mpr
intro i j hij
obtain ⟨q, a, ha, hqa, hqx⟩ := double_difference_transport i j hij
have hprod : g K (permuteCharge q alpha) * g K (permuteCharge q a) = 0 := by
rcases ha with rfl | rfl
· exact hc q
· exact hs q
rw [hqx] at hprod
have hfirst : g K (permuteCharge q alpha) ≠ 0 := by
rcases hqa with hqa | hqa
· simpa only [hqa] using hnonzero
· simpa only [hqa] using hnegative
exact (mul_eq_zero.mp hprod).resolve_left hfirst
have hback := hKs.permute_rows p
change IsComplexHadamard (fun i k => H i k ^ 2)
simpa only [K, entrywiseSquare, Equiv.symm_apply_apply] using hback
end HadamardSix
end OAI