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1.31 kB
| using namespace std; | |
| ll dp[100009]; | |
| struct node { | |
| ll l, r; | |
| } ara[100009]; | |
| bool operator <(node a, node b) | |
| { | |
| if(a.l != b.l) | |
| return a.l < b.l; | |
| return a.r < b.r; | |
| } | |
| ll n; | |
| ll solve(ll i) | |
| { | |
| if(i > n) | |
| return 0; | |
| if(dp[i] != -1) | |
| return dp[i]; | |
| ll ret = solve(i + 1) % mod; | |
| node tmp = ara[i]; | |
| ll pos = n + 1, lo = i + 1, hi = n; | |
| while(lo <= hi) { | |
| ll mid = (lo + hi) / 2; | |
| if(ara[mid].l < ara[i].r) | |
| lo = mid + 1; | |
| else { | |
| pos = mid; | |
| hi = mid - 1; | |
| } | |
| } | |
| //cout << ara[i].r << " " << ara[pos].r << endl; | |
| ret = (ret + 1 + solve(pos)) % mod; | |
| return dp[i] = ret; | |
| } | |
| int main() | |
| { | |
| while(scanf("%lld", &n) && n != -1) { | |
| memset(dp, -1, sizeof(dp)); | |
| for(ll i = 1; i <= n; i++) | |
| scanf("%lld %lld", &ara[i].l, &ara[i].r); | |
| sort(ara + 1, ara + n + 1); | |
| ll ans = solve(1); | |
| ll num = ans, cnt = 0; | |
| if(num == 0) | |
| cnt++; | |
| while(num != 0) { | |
| num /= 10; | |
| cnt++; | |
| } | |
| ll rem = 8 - cnt; | |
| for(ll i = 1; i <= rem; i++) | |
| printf("0"); | |
| printf("%lld\n", ans); | |
| } | |
| return 0; | |
| } | |