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| using namespace std; | |
| const ll inf = 1e18; | |
| ll n, k, ara[5009]; | |
| ll xorcs[5009][5009], xorsum[5009][5009], dp[5009][5009]; | |
| void solve(ll lo, ll hi, ll left, ll right, ll part) | |
| { | |
| if(lo > hi) return; | |
| ll mid = (lo + hi) / 2; | |
| dp[mid][part] = inf; | |
| ll indx; | |
| for(ll i = left; i <= right && i <= mid; i++) { | |
| ll c = dp[i - 1][part - 1] + xorsum[i][mid]; | |
| if(c < dp[mid][part]) { | |
| dp[mid][part] = c; | |
| indx = i; | |
| } | |
| } | |
| solve(lo, mid - 1, left, indx, part); | |
| solve(mid + 1, hi, indx, right, part); | |
| } | |
| int main() | |
| { | |
| scanf("%lld %lld", &n, &k); | |
| k++; | |
| for(ll i = 1; i <= n; i++) scanf("%lld", &ara[i]); | |
| for(ll i = 1; i <= n; i++) { | |
| for(ll j = i + 1; j <= n; j++) | |
| xorcs[i][j] = (ara[i] ^ ara[j]) + xorcs[i][j - 1]; | |
| } | |
| for(ll i = 1; i <= n; i++) { | |
| ll sum = 0; | |
| for(ll j = i - 1; j >= 1; j--) { | |
| sum += xorcs[j][i]; | |
| xorsum[j][i] = sum; | |
| } | |
| } | |
| for(ll i = 0; i <= 5002; i++) { | |
| dp[i][0] = inf; | |
| } | |
| dp[0][0] = 0; | |
| for(ll i = 1; i <= k; i++) | |
| solve(1, n, 1, n, i); | |
| cout << dp[n][k] << endl; | |
| return 0; | |