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value | sentences stringlengths 1 3.93k | ts stringlengths 26 26 | user stringlengths 2 11 | sentence_id stringlengths 44 53 | timestamp float64 1.5B 1.56B | __index_level_0__ int64 0 106k |
|---|---|---|---|---|---|---|---|
pythondev | help | <@Von> optionally, i wrote a library for this called “delegator.py”, which makes it a bit easier :) | 2018-01-15T10:35:00.000393 | Meghan | pythondev_help_Meghan_2018-01-15T10:35:00.000393 | 1,516,012,500.000393 | 29,124 |
pythondev | help | I'll give it a look, thanks | 2018-01-15T10:52:45.000211 | Von | pythondev_help_Von_2018-01-15T10:52:45.000211 | 1,516,013,565.000211 | 29,125 |
pythondev | help | it is so weird... | 2018-01-15T18:22:29.000144 | Stefan | pythondev_help_Stefan_2018-01-15T18:22:29.000144 | 1,516,040,549.000144 | 29,126 |
pythondev | help | also with a normal function it is not possible this way | 2018-01-15T18:24:24.000331 | Stefan | pythondev_help_Stefan_2018-01-15T18:24:24.000331 | 1,516,040,664.000331 | 29,127 |
pythondev | help | not so anonymous, eh? | 2018-01-15T18:24:56.000272 | Brande | pythondev_help_Brande_2018-01-15T18:24:56.000272 | 1,516,040,696.000272 | 29,128 |
pythondev | help | <https://stackoverflow.com/questions/10875442/possible-to-change-a-functions-repr-in-python> | 2018-01-15T18:25:11.000108 | Stefan | pythondev_help_Stefan_2018-01-15T18:25:11.000108 | 1,516,040,711.000108 | 29,129 |
pythondev | help | but seriously... this is so counterintuitive | 2018-01-15T18:25:26.000029 | Stefan | pythondev_help_Stefan_2018-01-15T18:25:26.000029 | 1,516,040,726.000029 | 29,130 |
pythondev | help | it should just work | 2018-01-15T18:25:30.000054 | Stefan | pythondev_help_Stefan_2018-01-15T18:25:30.000054 | 1,516,040,730.000054 | 29,131 |
pythondev | help | Hey Everyone | 2018-01-15T18:26:20.000288 | Frances | pythondev_help_Frances_2018-01-15T18:26:20.000288 | 1,516,040,780.000288 | 29,132 |
pythondev | help | hoping to get some quick advice on an issue that I know I'm close to solving. I am running code to save a csv but getting an error because the filename saves with a carriage return and newline character at the beginning. eg. \r\nmyfile.csv | 2018-01-15T18:26:32.000089 | Frances | pythondev_help_Frances_2018-01-15T18:26:32.000089 | 1,516,040,792.000089 | 29,133 |
pythondev | help | ```
outputFile = open('/output/'+filename, 'wb')
outputWriter = csv.writer(outputFile)
``` | 2018-01-15T18:27:52.000335 | Frances | pythondev_help_Frances_2018-01-15T18:27:52.000335 | 1,516,040,872.000335 | 29,134 |
pythondev | help | "No, because repr(f) is done as type(f).__repr__(f) instead." | 2018-01-15T18:27:53.000074 | Stefan | pythondev_help_Stefan_2018-01-15T18:27:53.000074 | 1,516,040,873.000074 | 29,135 |
pythondev | help | anyone have experience with google cloud vision api? | 2018-01-15T23:58:02.000040 | Shila | pythondev_help_Shila_2018-01-15T23:58:02.000040 | 1,516,060,682.00004 | 29,136 |
pythondev | help | on windows, python 3.6, trying two different methods for accessing the api, both are failing | 2018-01-15T23:58:17.000129 | Shila | pythondev_help_Shila_2018-01-15T23:58:17.000129 | 1,516,060,697.000129 | 29,137 |
pythondev | help | one says “cannot import name types” | 2018-01-15T23:58:38.000003 | Shila | pythondev_help_Shila_2018-01-15T23:58:38.000003 | 1,516,060,718.000003 | 29,138 |
pythondev | help | the other says it’s expecting something in the google authentication json file, but doesn’t say what it’s expecting | 2018-01-15T23:58:54.000150 | Shila | pythondev_help_Shila_2018-01-15T23:58:54.000150 | 1,516,060,734.00015 | 29,139 |
pythondev | help | Hey guys i'm on a Codewars challenge , and im getting this error `TypeError: expected a character buffer object` | 2018-01-16T04:39:10.000525 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:39:10.000525 | 1,516,077,550.000525 | 29,140 |
pythondev | help | Can anyone explain to me what this means? | 2018-01-16T04:39:22.000203 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:39:22.000203 | 1,516,077,562.000203 | 29,141 |
pythondev | help | ```
def get_middle(s):
num = len(s)
if num % 2 == 0:
print('even')
one = num/2-1
two = num/2
return(s[one] + s[two])
else:
print("odd")
index = int(num/2)
print(s.find(index))
``` | 2018-01-16T04:39:29.000267 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:39:29.000267 | 1,516,077,569.000267 | 29,142 |
pythondev | help | I think the error is coming from the last two lines of the function | 2018-01-16T04:39:44.000438 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:39:44.000438 | 1,516,077,584.000438 | 29,143 |
pythondev | help | s.find() takes a string | 2018-01-16T04:42:27.000371 | Barney | pythondev_help_Barney_2018-01-16T04:42:27.000371 | 1,516,077,747.000371 | 29,144 |
pythondev | help | not a number | 2018-01-16T04:42:28.000147 | Barney | pythondev_help_Barney_2018-01-16T04:42:28.000147 | 1,516,077,748.000147 | 29,145 |
pythondev | help | ```
>>> 'abcdef'.find('cd')
2
``` | 2018-01-16T04:42:43.000346 | Barney | pythondev_help_Barney_2018-01-16T04:42:43.000346 | 1,516,077,763.000346 | 29,146 |
pythondev | help | maybe you wanted `s[index]`? | 2018-01-16T04:43:11.000079 | Barney | pythondev_help_Barney_2018-01-16T04:43:11.000079 | 1,516,077,791.000079 | 29,147 |
pythondev | help | `return(s.index(str(num/2)))` | 2018-01-16T04:50:16.000325 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:50:16.000325 | 1,516,078,216.000325 | 29,148 |
pythondev | help | Now im getting substring not found | 2018-01-16T04:50:22.000282 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:50:22.000282 | 1,516,078,222.000282 | 29,149 |
pythondev | help | because there's no such substring in `s` | 2018-01-16T04:51:05.000165 | Barney | pythondev_help_Barney_2018-01-16T04:51:05.000165 | 1,516,078,265.000165 | 29,150 |
pythondev | help | probably:) | 2018-01-16T04:51:10.000162 | Barney | pythondev_help_Barney_2018-01-16T04:51:10.000162 | 1,516,078,270.000162 | 29,151 |
pythondev | help | 'return(s.index(num/2))' - So why is this expecting a character buffer? | 2018-01-16T04:51:59.000573 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:51:59.000573 | 1,516,078,319.000573 | 29,152 |
pythondev | help | what | 2018-01-16T04:52:09.000118 | Barney | pythondev_help_Barney_2018-01-16T04:52:09.000118 | 1,516,078,329.000118 | 29,153 |
pythondev | help | str.index is a function that takes a string `a`, and looks for `a` in `str` | 2018-01-16T04:52:39.000101 | Barney | pythondev_help_Barney_2018-01-16T04:52:39.000101 | 1,516,078,359.000101 | 29,154 |
pythondev | help | and then tells you in which position it was found | 2018-01-16T04:52:49.000630 | Barney | pythondev_help_Barney_2018-01-16T04:52:49.000630 | 1,516,078,369.00063 | 29,155 |
pythondev | help | i.e., `"abcdef".index("cd")` is 2 | 2018-01-16T04:53:03.000395 | Barney | pythondev_help_Barney_2018-01-16T04:53:03.000395 | 1,516,078,383.000395 | 29,156 |
pythondev | help | Okay so how do i search by index? | 2018-01-16T04:53:17.000080 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:53:17.000080 | 1,516,078,397.00008 | 29,157 |
pythondev | help | with integer? | 2018-01-16T04:53:32.000111 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:53:32.000111 | 1,516,078,412.000111 | 29,158 |
pythondev | help | `string[n]`? | 2018-01-16T04:53:56.000132 | Barney | pythondev_help_Barney_2018-01-16T04:53:56.000132 | 1,516,078,436.000132 | 29,159 |
pythondev | help | i.e., `"abcdef"[1]` is `"b"` | 2018-01-16T04:54:09.000006 | Barney | pythondev_help_Barney_2018-01-16T04:54:09.000006 | 1,516,078,449.000006 | 29,160 |
pythondev | help | oh jesus. | 2018-01-16T04:54:33.000323 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:54:33.000323 | 1,516,078,473.000323 | 29,161 |
pythondev | help | `return(s[num/2])` - i was over thinking it, thansks :slightly_smiling_face: sorted now. | 2018-01-16T04:54:56.000288 | Tanesha | pythondev_help_Tanesha_2018-01-16T04:54:56.000288 | 1,516,078,496.000288 | 29,162 |
pythondev | help | Would anyone happen to know how to login to a django-powered site by giving credentials through the url? Or is it too variable to say? | 2018-01-16T08:13:35.000025 | Von | pythondev_help_Von_2018-01-16T08:13:35.000025 | 1,516,090,415.000025 | 29,163 |
pythondev | help | That isn’t a normally supported pattern as it is quite insecure | 2018-01-16T08:21:46.000187 | Cecila | pythondev_help_Cecila_2018-01-16T08:21:46.000187 | 1,516,090,906.000187 | 29,164 |
pythondev | help | don’t | 2018-01-16T08:21:48.000494 | Floy | pythondev_help_Floy_2018-01-16T08:21:48.000494 | 1,516,090,908.000494 | 29,165 |
pythondev | help | So it would depend on the site supporting it and making the security compromise | 2018-01-16T08:21:59.000426 | Cecila | pythondev_help_Cecila_2018-01-16T08:21:59.000426 | 1,516,090,919.000426 | 29,166 |
pythondev | help | you can provide a token via url, which is often used with api services | 2018-01-16T08:22:08.000239 | Floy | pythondev_help_Floy_2018-01-16T08:22:08.000239 | 1,516,090,928.000239 | 29,167 |
pythondev | help | but all that is doing is saying you’re ok to access that particular resource | 2018-01-16T08:22:30.000092 | Floy | pythondev_help_Floy_2018-01-16T08:22:30.000092 | 1,516,090,950.000092 | 29,168 |
pythondev | help | and honestly, if I came across any site doing that, I would not use it and think the developer/agency/company is incompentent | 2018-01-16T08:23:07.000322 | Floy | pythondev_help_Floy_2018-01-16T08:23:07.000322 | 1,516,090,987.000322 | 29,169 |
pythondev | help | Point taken, thank you | 2018-01-16T08:23:39.000613 | Von | pythondev_help_Von_2018-01-16T08:23:39.000613 | 1,516,091,019.000613 | 29,170 |
pythondev | help | :thumbsup: | 2018-01-16T08:26:02.000556 | Floy | pythondev_help_Floy_2018-01-16T08:26:02.000556 | 1,516,091,162.000556 | 29,171 |
pythondev | help | Hi peeps! I hope I am posting in the right channel. Is there a channel for jupyter related issues/questions discussions? | 2018-01-16T09:41:15.000512 | Milly | pythondev_help_Milly_2018-01-16T09:41:15.000512 | 1,516,095,675.000512 | 29,172 |
pythondev | help | If you click on "Channels" you can search for it | 2018-01-16T09:44:28.000825 | Von | pythondev_help_Von_2018-01-16T09:44:28.000825 | 1,516,095,868.000825 | 29,173 |
pythondev | help | Cant fin it <@Von>. Did I miss it? Also cant create channels. | 2018-01-16T09:46:24.000034 | Milly | pythondev_help_Milly_2018-01-16T09:46:24.000034 | 1,516,095,984.000034 | 29,174 |
pythondev | help | Any idea whom/where can i request for it?
PS: Thanks for the response buddy!! | 2018-01-16T09:47:42.000638 | Milly | pythondev_help_Milly_2018-01-16T09:47:42.000638 | 1,516,096,062.000638 | 29,175 |
pythondev | help | No idea if it exists or not, just pointing to where you can look for it | 2018-01-16T09:48:10.000470 | Von | pythondev_help_Von_2018-01-16T09:48:10.000470 | 1,516,096,090.00047 | 29,176 |
pythondev | help | You should be able to make it yourself | 2018-01-16T09:49:16.000106 | Von | pythondev_help_Von_2018-01-16T09:49:16.000106 | 1,516,096,156.000106 | 29,177 |
pythondev | help | Unfortunately, I dont see the :heavy_plus_sign: next to *Channels* to make it. | 2018-01-16T09:50:29.000358 | Milly | pythondev_help_Milly_2018-01-16T09:50:29.000358 | 1,516,096,229.000358 | 29,178 |
pythondev | help | Ah, then I guess we can't. Get a hold of a mod | 2018-01-16T09:51:42.000059 | Von | pythondev_help_Von_2018-01-16T09:51:42.000059 | 1,516,096,302.000059 | 29,179 |
pythondev | help | Guys, how could I remove all characters after *'.'* in an url? | 2018-01-16T10:04:33.000396 | Nilda | pythondev_help_Nilda_2018-01-16T10:04:33.000396 | 1,516,097,073.000396 | 29,180 |
pythondev | help | I'm trying this but doens't work : .rstrip('.')[-1] | 2018-01-16T10:05:02.000501 | Nilda | pythondev_help_Nilda_2018-01-16T10:05:02.000501 | 1,516,097,102.000501 | 29,181 |
pythondev | help | split the string on the `.` | 2018-01-16T10:05:10.000381 | Porsha | pythondev_help_Porsha_2018-01-16T10:05:10.000381 | 1,516,097,110.000381 | 29,182 |
pythondev | help | I want just the content before the last *.* | 2018-01-16T10:05:42.000446 | Nilda | pythondev_help_Nilda_2018-01-16T10:05:42.000446 | 1,516,097,142.000446 | 29,183 |
pythondev | help | ```my_str = "<http://www.example.com|www.example.com>"
a, b, c = my_str.split(".")
print(a, b, c)``` | 2018-01-16T10:06:29.000021 | Porsha | pythondev_help_Porsha_2018-01-16T10:06:29.000021 | 1,516,097,189.000021 | 29,184 |
pythondev | help | I would even say
```
my_str = "<http://www.example.com|www.example.com>"
*a, b = my_str.split(".")
print(b)
``` | 2018-01-16T10:07:30.000183 | Sadye | pythondev_help_Sadye_2018-01-16T10:07:30.000183 | 1,516,097,250.000183 | 29,185 |
pythondev | help | If you need only the 'com' part | 2018-01-16T10:07:37.000615 | Sadye | pythondev_help_Sadye_2018-01-16T10:07:37.000615 | 1,516,097,257.000615 | 29,186 |
pythondev | help | I know that you need the stuff before, but I just wanted to showcase this neat language feature :slightly_smiling_face: | 2018-01-16T10:08:12.001015 | Sadye | pythondev_help_Sadye_2018-01-16T10:08:12.001015 | 1,516,097,292.001015 | 29,187 |
pythondev | help | This is providing you're working with a TLD with 1 dot | 2018-01-16T10:08:17.000001 | Porsha | pythondev_help_Porsha_2018-01-16T10:08:17.000001 | 1,516,097,297.000001 | 29,188 |
pythondev | help | if you are parsing url there is probably a module in the stdlib | 2018-01-16T10:09:09.000443 | Micki | pythondev_help_Micki_2018-01-16T10:09:09.000443 | 1,516,097,349.000443 | 29,189 |
pythondev | help | Btw, if you'll do this on a regular bases and with a different types of TLDs, I had good experience with <https://github.com/john-kurkowski/tldextract> | 2018-01-16T10:09:30.000342 | Sadye | pythondev_help_Sadye_2018-01-16T10:09:30.000342 | 1,516,097,370.000342 | 29,190 |
pythondev | help | ```my_str = "<https://www.example.com>"
split_str = my_str.split(".")
domain = split_str[1]
print(domain)``` | 2018-01-16T10:09:45.000536 | Porsha | pythondev_help_Porsha_2018-01-16T10:09:45.000536 | 1,516,097,385.000536 | 29,191 |
pythondev | help | and stdlib has `urllib.parse.urlparse` in Python3 | 2018-01-16T10:10:12.000993 | Sadye | pythondev_help_Sadye_2018-01-16T10:10:12.000993 | 1,516,097,412.000993 | 29,192 |
pythondev | help | Slice the split string to pull out the domain name | 2018-01-16T10:10:15.000229 | Porsha | pythondev_help_Porsha_2018-01-16T10:10:15.000229 | 1,516,097,415.000229 | 29,193 |
pythondev | help | Or use a library lol | 2018-01-16T10:10:27.000517 | Porsha | pythondev_help_Porsha_2018-01-16T10:10:27.000517 | 1,516,097,427.000517 | 29,194 |
pythondev | help | <@Milly>, <#C0JB9ATQV|data_science> would probably be able to answer any questions about jupyter. | 2018-01-16T10:11:43.000547 | Davina | pythondev_help_Davina_2018-01-16T10:11:43.000547 | 1,516,097,503.000547 | 29,195 |
pythondev | help | The problem is that I need all before the last dot | 2018-01-16T10:14:54.000686 | Nilda | pythondev_help_Nilda_2018-01-16T10:14:54.000686 | 1,516,097,694.000686 | 29,196 |
pythondev | help | I will check the library | 2018-01-16T10:15:04.000608 | Nilda | pythondev_help_Nilda_2018-01-16T10:15:04.000608 | 1,516,097,704.000608 | 29,197 |
pythondev | help | I could use regex too, forgot this detail | 2018-01-16T10:19:05.000366 | Nilda | pythondev_help_Nilda_2018-01-16T10:19:05.000366 | 1,516,097,945.000366 | 29,198 |
pythondev | help | <@Nilda> a.partition() (without 'r') would look for the first occurrence | 2018-01-16T10:20:46.000589 | Denisha | pythondev_help_Denisha_2018-01-16T10:20:46.000589 | 1,516,098,046.000589 | 29,199 |
pythondev | help | <@Tifany>ex Worked Perfectly! I didn't know rpartition, Thank you all <@Porsha> <@Sadye> <@Micki> | 2018-01-16T10:25:58.000280 | Nilda | pythondev_help_Nilda_2018-01-16T10:25:58.000280 | 1,516,098,358.00028 | 29,200 |
pythondev | help | <@Nilda> that will break on 2 period TLDs | 2018-01-16T10:27:50.000425 | Brande | pythondev_help_Brande_2018-01-16T10:27:50.000425 | 1,516,098,470.000425 | 29,201 |
pythondev | help | @joe yes. but I think he was not looking for tld's anyway. But if that was the goal, then better use a good library for it, because there are too many edge cases. | 2018-01-16T10:29:10.000282 | Denisha | pythondev_help_Denisha_2018-01-16T10:29:10.000282 | 1,516,098,550.000282 | 29,202 |
pythondev | help | what’s a 2 period TLD? | 2018-01-16T10:29:18.000537 | Zack | pythondev_help_Zack_2018-01-16T10:29:18.000537 | 1,516,098,558.000537 | 29,203 |
pythondev | help | <@Nilda> You can always slice the string on the `.` and concatenate the slices together | 2018-01-16T10:29:19.000702 | Porsha | pythondev_help_Porsha_2018-01-16T10:29:19.000702 | 1,516,098,559.000702 | 29,204 |
pythondev | help | <@Zack>.<http://co.uk|co.uk>, .<http://com.au|com.au> etc.. | 2018-01-16T10:29:43.000415 | Porsha | pythondev_help_Porsha_2018-01-16T10:29:43.000415 | 1,516,098,583.000415 | 29,205 |
pythondev | help | .uk is the TLD there though? | 2018-01-16T10:30:05.000623 | Zack | pythondev_help_Zack_2018-01-16T10:30:05.000623 | 1,516,098,605.000623 | 29,206 |
pythondev | help | well on the literal sense yeah | 2018-01-16T10:30:32.000101 | Micki | pythondev_help_Micki_2018-01-16T10:30:32.000101 | 1,516,098,632.000101 | 29,207 |
pythondev | help | but I think people refer to them as TLD anyways | 2018-01-16T10:30:49.000504 | Micki | pythondev_help_Micki_2018-01-16T10:30:49.000504 | 1,516,098,649.000504 | 29,208 |
pythondev | help | I guess `.<http://co.uk|co.uk>` is the relevant registrar though? | 2018-01-16T10:30:50.000824 | Zack | pythondev_help_Zack_2018-01-16T10:30:50.000824 | 1,516,098,650.000824 | 29,209 |
pythondev | help | use a library. you can't do this with some simple split() or regex. Or you'll run into issues later on | 2018-01-16T10:31:46.000856 | Denisha | pythondev_help_Denisha_2018-01-16T10:31:46.000856 | 1,516,098,706.000856 | 29,210 |
pythondev | help | is there anything else peered with `.co` in `.<http://co.uk|co.uk>` or `.<http://co.au|co.au>`? | 2018-01-16T10:32:26.000161 | Zack | pythondev_help_Zack_2018-01-16T10:32:26.000161 | 1,516,098,746.000161 | 29,211 |
pythondev | help | It really depends what domains you're working with | 2018-01-16T10:32:41.000004 | Porsha | pythondev_help_Porsha_2018-01-16T10:32:41.000004 | 1,516,098,761.000004 | 29,212 |
pythondev | help | Subdomains might cause issues | 2018-01-16T10:32:48.000854 | Porsha | pythondev_help_Porsha_2018-01-16T10:32:48.000854 | 1,516,098,768.000854 | 29,213 |
pythondev | help | But I'm sure you could write some simple logic to get around it | 2018-01-16T10:33:09.000556 | Porsha | pythondev_help_Porsha_2018-01-16T10:33:09.000556 | 1,516,098,789.000556 | 29,214 |
pythondev | help | ah, interesting, internet says yes. | 2018-01-16T10:33:18.000539 | Zack | pythondev_help_Zack_2018-01-16T10:33:18.000539 | 1,516,098,798.000539 | 29,215 |
pythondev | help | why re-invent the wheel. | 2018-01-16T10:33:27.000096 | Denisha | pythondev_help_Denisha_2018-01-16T10:33:27.000096 | 1,516,098,807.000096 | 29,216 |
pythondev | help | Well, generally in public available domains such as `.<http://co.uk|co.uk>` `.uk` is a ccTLD (<https://en.wikipedia.org/wiki/List_of_Internet_top-level_domains#Country_code_top-level_domains>) and `.co` is a second-level domain (<https://en.wikipedia.org/wiki/Second-level_domain>) | 2018-01-16T10:34:42.000338 | Sadye | pythondev_help_Sadye_2018-01-16T10:34:42.000338 | 1,516,098,882.000338 | 29,217 |
pythondev | help | <https://docs.python.org/2/library/urlparse.html> | 2018-01-16T10:35:14.000311 | Denisha | pythondev_help_Denisha_2018-01-16T10:35:14.000311 | 1,516,098,914.000311 | 29,218 |
pythondev | help | Thing is, you can't write reliable logic in code to determine whether domain is available or not for registering sub domains (if you need it). You can only rely on hardcoded list. | 2018-01-16T10:36:22.000413 | Sadye | pythondev_help_Sadye_2018-01-16T10:36:22.000413 | 1,516,098,982.000413 | 29,219 |
pythondev | help | Because by definition `example` in `<http://example.com|example.com>` and `co` in `<http://co.uk|co.uk>` are the same, but they are not the same in practice, obviously | 2018-01-16T10:37:08.000381 | Sadye | pythondev_help_Sadye_2018-01-16T10:37:08.000381 | 1,516,099,028.000381 | 29,220 |
pythondev | help | But usually people refer to domains such as `.<http://co.uk|co.uk>` and `.<http://com.au|com.au>` as TLD as well, just as <@Micki> said. | 2018-01-16T10:39:35.000047 | Sadye | pythondev_help_Sadye_2018-01-16T10:39:35.000047 | 1,516,099,175.000047 | 29,221 |
pythondev | help | is there a way to easily display the cotents of a `itertools._grouper` object? | 2018-01-16T10:43:11.000221 | Theressa | pythondev_help_Theressa_2018-01-16T10:43:11.000221 | 1,516,099,391.000221 | 29,222 |
pythondev | help | in this script there's a `itertools.groupby` object created with it's key and group passed into a function... this function then does some fancyness with the `_grouper` argument | 2018-01-16T10:44:58.000272 | Theressa | pythondev_help_Theressa_2018-01-16T10:44:58.000272 | 1,516,099,498.000272 | 29,223 |
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