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pythondev
help
are there any alternative in stead of `*`
2018-02-14T17:47:32.000474
Jenna
pythondev_help_Jenna_2018-02-14T17:47:32.000474
1,518,630,452.000474
34,324
pythondev
help
spark doesn’t support `*` i think
2018-02-14T17:47:54.000569
Jenna
pythondev_help_Jenna_2018-02-14T17:47:54.000569
1,518,630,474.000569
34,325
pythondev
help
but that’s fine i could just use the index
2018-02-14T17:48:40.000222
Jenna
pythondev_help_Jenna_2018-02-14T17:48:40.000222
1,518,630,520.000222
34,326
pythondev
help
hmm... it says SyntaxError: invalid syntax does it have any more information ?
2018-02-14T17:57:34.000149
Monroe
pythondev_help_Monroe_2018-02-14T17:57:34.000149
1,518,631,054.000149
34,327
pythondev
help
Does it say anything like "Item not subscriptable"?
2018-02-14T17:58:38.000466
Monroe
pythondev_help_Monroe_2018-02-14T17:58:38.000466
1,518,631,118.000466
34,328
pythondev
help
Probably a stupid question, but I’m doing ``` gb_faker = Faker('en_GB') print(gb_faker.longitude)``` and getting printed out `<bound method Provider.longitude of <faker.providers.address.en_GB.Provider object at 0x7f750f572b38>>`, whereas docs say ```fake.longitude() # Decimal('-137.746732')``` any ...
2018-02-14T18:05:10.000334
Breana
pythondev_help_Breana_2018-02-14T18:05:10.000334
1,518,631,510.000334
34,329
pythondev
help
Oh.. missing `()` :facepalm:
2018-02-14T18:05:30.000158
Breana
pythondev_help_Breana_2018-02-14T18:05:30.000158
1,518,631,530.000158
34,330
pythondev
help
It’s late. :smile:
2018-02-14T18:05:33.000293
Breana
pythondev_help_Breana_2018-02-14T18:05:33.000293
1,518,631,533.000293
34,331
pythondev
help
getting faked out?
2018-02-14T18:08:47.000115
Monroe
pythondev_help_Monroe_2018-02-14T18:08:47.000115
1,518,631,727.000115
34,332
pythondev
help
Lol
2018-02-14T18:19:04.000154
Shaun
pythondev_help_Shaun_2018-02-14T18:19:04.000154
1,518,632,344.000154
34,333
pythondev
help
i should have really read the source code first, why did I just assume that `Faker('en_GB')` would provide only UK long/lats :smile:
2018-02-14T18:25:05.000040
Breana
pythondev_help_Breana_2018-02-14T18:25:05.000040
1,518,632,705.00004
34,334
pythondev
help
fun fact, it doesn’t.
2018-02-14T18:25:14.000098
Breana
pythondev_help_Breana_2018-02-14T18:25:14.000098
1,518,632,714.000098
34,335
pythondev
help
<@Monroe> what do you think ^?
2018-02-14T18:28:03.000307
Jenna
pythondev_help_Jenna_2018-02-14T18:28:03.000307
1,518,632,883.000307
34,336
pythondev
help
What is the type of item at that point?
2018-02-14T18:37:16.000025
Monroe
pythondev_help_Monroe_2018-02-14T18:37:16.000025
1,518,633,436.000025
34,337
pythondev
help
My brain hurts, can you star-arg a mapped object in a tuple result of an interation??!?
2018-02-14T18:44:04.000363
Monroe
pythondev_help_Monroe_2018-02-14T18:44:04.000363
1,518,633,844.000363
34,338
pythondev
help
<@Jenna> lambda doesn’t take parentheses
2018-02-14T19:13:50.000118
Reynalda
pythondev_help_Reynalda_2018-02-14T19:13:50.000118
1,518,635,630.000118
34,339
pythondev
help
lambda (user, domain): should be lambda user, domain:
2018-02-14T19:14:00.000264
Reynalda
pythondev_help_Reynalda_2018-02-14T19:14:00.000264
1,518,635,640.000264
34,340
pythondev
help
Hi guys, I would like to verify something. Is `newid()` in `mssql` same as any immutable UUID objects within the `uuid` module?
2018-02-14T20:55:58.000266
Margert
pythondev_help_Margert_2018-02-14T20:55:58.000266
1,518,641,758.000266
34,341
pythondev
help
<@Margert> nope, Microsoft doesn’t use any `uuid` implementation, they have their own GUID implementation
2018-02-14T21:06:08.000078
Brande
pythondev_help_Brande_2018-02-14T21:06:08.000078
1,518,642,368.000078
34,342
pythondev
help
They both, however, will return GUIDs of the same structure
2018-02-14T21:06:42.000130
Brande
pythondev_help_Brande_2018-02-14T21:06:42.000130
1,518,642,402.00013
34,343
pythondev
help
Oh, I see. Thanks for the feedback <@Brande>. So is it safe to use `uuid.uuid4()` as a representation of a `newid()` in `mssql` when using `sqlalchemy`? I came upon a column that has a default value of `newid()` so I’m not sure how I should proceed.
2018-02-14T21:08:38.000121
Margert
pythondev_help_Margert_2018-02-14T21:08:38.000121
1,518,642,518.000121
34,344
pythondev
help
If the column has a default value, then don’t give it any value at all, let the database insert it
2018-02-14T21:09:11.000120
Brande
pythondev_help_Brande_2018-02-14T21:09:11.000120
1,518,642,551.00012
34,345
pythondev
help
It’ll generate/insert the GUID faster than doing it on the code-side, and it’s better for the database to enforce the data for the column with a default
2018-02-14T21:09:48.000162
Brande
pythondev_help_Brande_2018-02-14T21:09:48.000162
1,518,642,588.000162
34,346
pythondev
help
Also if you give it `uuid4`s then it may increase the likelihood of a collision because of using 2 different algorithms, but I’m just speculating. tl;dr, just use one type
2018-02-14T21:11:14.000010
Brande
pythondev_help_Brande_2018-02-14T21:11:14.000010
1,518,642,674.00001
34,347
pythondev
help
Sorry, my mistake, the column has no default value, is not nullable, but expects a `newid()` as a value. I’ve verified this by checking the table structure and the stored procedure that inserts values into it.
2018-02-14T21:11:39.000171
Margert
pythondev_help_Margert_2018-02-14T21:11:39.000171
1,518,642,699.000171
34,348
pythondev
help
Ah, okay, then yes go ahead and use a `uuid4`
2018-02-14T21:12:28.000139
Brande
pythondev_help_Brande_2018-02-14T21:12:28.000139
1,518,642,748.000139
34,349
pythondev
help
Great! One last thing
2018-02-14T21:12:56.000211
Margert
pythondev_help_Margert_2018-02-14T21:12:56.000211
1,518,642,776.000211
34,350
pythondev
help
Since you mention a possible collision, should I declare this block of code within a `try ... except`? I would declare the column as `unique=True`, but I’m not sure if `sqlalchemy` would generate a new `uuid4()` if ever the generated GUID already exists in the database.
2018-02-14T21:14:39.000158
Margert
pythondev_help_Margert_2018-02-14T21:14:39.000158
1,518,642,879.000158
34,351
pythondev
help
The possibility is so small of a uuidv4 collision I wouldn’t worry unless you’re doing a lot of inserts
2018-02-14T21:16:38.000060
Brande
pythondev_help_Brande_2018-02-14T21:16:38.000060
1,518,642,998.00006
34,352
pythondev
help
Noted <@Brande>! Thank you so much! :simple_smile:
2018-02-14T21:18:40.000166
Margert
pythondev_help_Margert_2018-02-14T21:18:40.000166
1,518,643,120.000166
34,353
pythondev
help
Hey everyone! Am I right in saying that the big O efficiency of this function is O(n^3)? ``` def question1(s, t): if s and t: first_occurence = 0 for index, source in enumerate(s): for target in t: if target is source: first_occurence = index ...
2018-02-15T02:13:44.000231
Lucina
pythondev_help_Lucina_2018-02-15T02:13:44.000231
1,518,660,824.000231
34,354
pythondev
help
Let's say I have the following code: ``` class A: def run(self): print("A") class B: def run(self): print("A") class C(A, B): def run(self): super().run() print("A") c = C() c.run() ``` In this example. would there be a difference if I call B.run() instead of super.run()...
2018-02-15T02:15:55.000139
Hank
pythondev_help_Hank_2018-02-15T02:15:55.000139
1,518,660,955.000139
34,355
pythondev
help
<@Hank> this stack overflow post give a nice explanation of `super` with multiple inheritance
2018-02-15T02:23:09.000082
Micki
pythondev_help_Micki_2018-02-15T02:23:09.000082
1,518,661,389.000082
34,356
pythondev
help
<@Lucina> let's say the length of `s` is N and the length of `t` is M ``` for index, source in enumerate(s): for target in t: ``` gives you O(N*M) If the length of `substring` is K, ``` for char in t: if substring.find(char) &lt; 0: ``` gives you O(M*K) In total it's O(N*M + M*K) which roughly equals to O(N^2) ...
2018-02-15T02:31:51.000068
Aleida
pythondev_help_Aleida_2018-02-15T02:31:51.000068
1,518,661,911.000068
34,357
pythondev
help
I think you forgot to add the link, Ovv
2018-02-15T02:39:08.000143
Hank
pythondev_help_Hank_2018-02-15T02:39:08.000143
1,518,662,348.000143
34,358
pythondev
help
sorry :smile: <https://stackoverflow.com/questions/3277367/how-does-pythons-super-work-with-multiple-inheritance>
2018-02-15T02:39:29.000100
Micki
pythondev_help_Micki_2018-02-15T02:39:29.000100
1,518,662,369.0001
34,359
pythondev
help
crash course into CS by <@Aleida> :smile:
2018-02-15T02:48:28.000171
Sadye
pythondev_help_Sadye_2018-02-15T02:48:28.000171
1,518,662,908.000171
34,360
pythondev
help
As a self learner O notation is something I never understood :smile: but I don't really try to understand it...
2018-02-15T02:50:28.000200
Micki
pythondev_help_Micki_2018-02-15T02:50:28.000200
1,518,663,028.0002
34,361
pythondev
help
<@Micki> there's a very simple mnemonic you can easily remember - find loops in your program, each inner loop gives you `* iterable_length`, each sibling loop gives you `+ iterable_length` to the total complexity you calculated so far
2018-02-15T02:51:52.000155
Aleida
pythondev_help_Aleida_2018-02-15T02:51:52.000155
1,518,663,112.000155
34,362
pythondev
help
If there's recursion involved you're likely to end up with a factorial of the input
2018-02-15T02:52:47.000261
Aleida
pythondev_help_Aleida_2018-02-15T02:52:47.000261
1,518,663,167.000261
34,363
pythondev
help
Sometimes clever algorithms multiply by a logarithm which is likely not the case in your program
2018-02-15T02:53:21.000121
Aleida
pythondev_help_Aleida_2018-02-15T02:53:21.000121
1,518,663,201.000121
34,364
pythondev
help
Pretty much everything else is a constant
2018-02-15T02:53:29.000126
Aleida
pythondev_help_Aleida_2018-02-15T02:53:29.000126
1,518,663,209.000126
34,365
pythondev
help
Seems simple enough
2018-02-15T02:56:10.000302
Micki
pythondev_help_Micki_2018-02-15T02:56:10.000302
1,518,663,370.000302
34,366
pythondev
help
<@Aleida> ahh, okay. i originally had O(n^2) but thought since I had that second for loop that iterated through `t` and `substring` that it would give me `n^3`... wasn't entirely sure that was correct, which is why i came here to ask heh
2018-02-15T02:58:12.000187
Lucina
pythondev_help_Lucina_2018-02-15T02:58:12.000187
1,518,663,492.000187
34,367
pythondev
help
also, thank you sir for the great explanation.
2018-02-15T02:58:21.000311
Lucina
pythondev_help_Lucina_2018-02-15T02:58:21.000311
1,518,663,501.000311
34,368
pythondev
help
N^3 would be if you had a third inner loop
2018-02-15T02:58:40.000172
Aleida
pythondev_help_Aleida_2018-02-15T02:58:40.000172
1,518,663,520.000172
34,369
pythondev
help
ahh gotcha
2018-02-15T02:58:47.000040
Lucina
pythondev_help_Lucina_2018-02-15T02:58:47.000040
1,518,663,527.00004
34,370
pythondev
help
i don't really understand why it would greatly increase the complexity if N and M were smaller. that just means `substring` would be smaller and thus less complex, no?
2018-02-15T03:00:39.000273
Lucina
pythondev_help_Lucina_2018-02-15T03:00:39.000273
1,518,663,639.000273
34,371
pythondev
help
not increase, but influence
2018-02-15T03:05:03.000269
Sadye
pythondev_help_Sadye_2018-02-15T03:05:03.000269
1,518,663,903.000269
34,372
pythondev
help
<@Lucina> in big-O notation constants are thrown away so O(2N) == O(N). Even O(100N) == O(N). But you can't really throw away these constants if N is small
2018-02-15T03:08:16.000334
Aleida
pythondev_help_Aleida_2018-02-15T03:08:16.000334
1,518,664,096.000334
34,373
pythondev
help
hmm, ok. well i appreciate the input guys. trying to get my head wrapped around how to decipher what my code's efficency is a struggle, but i'm slowly figuring it out.
2018-02-15T03:08:22.000306
Lucina
pythondev_help_Lucina_2018-02-15T03:08:22.000306
1,518,664,102.000306
34,374
pythondev
help
hmm... ok, i think i see what you're saying.
2018-02-15T03:09:14.000265
Lucina
pythondev_help_Lucina_2018-02-15T03:09:14.000265
1,518,664,154.000265
34,375
pythondev
help
For example if you have a 128*N algorithm and N is 2, in a big-O notation you have a O(N) algorithm. But in reality you have roughly O(N^8)
2018-02-15T03:09:49.000349
Aleida
pythondev_help_Aleida_2018-02-15T03:09:49.000349
1,518,664,189.000349
34,376
pythondev
help
Hey :smile: Have any of you used `argparse` before ?
2018-02-15T10:46:29.000899
Gwyn
pythondev_help_Gwyn_2018-02-15T10:46:29.000899
1,518,691,589.000899
34,377
pythondev
help
I'd like to have something to disable the use of option `-x -y -z` if option `-a` is not enabled
2018-02-15T10:46:59.000331
Gwyn
pythondev_help_Gwyn_2018-02-15T10:46:59.000331
1,518,691,619.000331
34,378
pythondev
help
I haven’t done that in argparse, but I’ve done it in Click. The approach in Click revolved around writing a custom validator that inspected the provided arguments and raised a usage error if the desired combination was not found.
2018-02-15T10:48:47.000141
Zack
pythondev_help_Zack_2018-02-15T10:48:47.000141
1,518,691,727.000141
34,379
pythondev
help
Not sure if there’s something similar in argparse
2018-02-15T10:48:56.000014
Zack
pythondev_help_Zack_2018-02-15T10:48:56.000014
1,518,691,736.000014
34,380
pythondev
help
Let's say I have these options set with argparse: ``` --foo --bar --me --to --roses ``` And i only want to be able to have the options `--foo` and `--bar` available if `--me` is set but `--to` can be used on `--me` and `--roses`
2018-02-15T10:49:05.000891
Gwyn
pythondev_help_Gwyn_2018-02-15T10:49:05.000891
1,518,691,745.000891
34,381
pythondev
help
Click looks nice but I went with argparse because I'm trying to only use standart lib (Because reasons :stuck_out_tongue: but basically I "can't" use other libs using pip because users would have to install the modules everytime and that sucks (unless it can be automated))
2018-02-15T10:50:23.000280
Gwyn
pythondev_help_Gwyn_2018-02-15T10:50:23.000280
1,518,691,823.00028
34,382
pythondev
help
You could just parse them and throw an error accordingly: ``` if <http://args.me|args.me>: if args.foo is None or args.bar is None: parser.error('error message')```
2018-02-15T10:51:47.000672
Brande
pythondev_help_Brande_2018-02-15T10:51:47.000672
1,518,691,907.000672
34,383
pythondev
help
I know that’s not the exact logic you want but it can be handled that way
2018-02-15T10:52:22.000756
Brande
pythondev_help_Brande_2018-02-15T10:52:22.000756
1,518,691,942.000756
34,384
pythondev
help
could also do it in a custom action it seems: <https://docs.python.org/3/library/argparse.html#action>
2018-02-15T10:52:23.000169
Zack
pythondev_help_Zack_2018-02-15T10:52:23.000169
1,518,691,943.000169
34,385
pythondev
help
<@Brande>’s suggestion sounds easier though. :stuck_out_tongue:
2018-02-15T10:53:05.000544
Zack
pythondev_help_Zack_2018-02-15T10:53:05.000544
1,518,691,985.000544
34,386
pythondev
help
``` if args.no_libftest and args.project != "libft": parser.error("`--no-libftest' can only be applied if libft is selected " "with `--project'") ``` That's what i've been doing but I have a lot of them (See below) and I was wondering if there was an easier way
2018-02-15T10:54:34.000045
Gwyn
pythondev_help_Gwyn_2018-02-15T10:54:34.000045
1,518,692,074.000045
34,387
pythondev
help
``` 42PyChecker Copyright (C) 2018-present Jules Lasne &lt;jules.lasne@gmail.com&gt; This program comes with ABSOLUTELY NO WARRANTY; for details run with `--show-w'. This is free software, and you are welcome to redistribute it under certain conditions; run with `--show-c' for details. usage: 42PyChecker.py [-h] [-...
2018-02-15T10:54:47.000767
Gwyn
pythondev_help_Gwyn_2018-02-15T10:54:47.000767
1,518,692,087.000767
34,388
pythondev
help
(And a lot more to come)
2018-02-15T10:54:57.000600
Gwyn
pythondev_help_Gwyn_2018-02-15T10:54:57.000600
1,518,692,097.0006
34,389
pythondev
help
The custom action might be a good choice then, just because it would allow you to define per-argument what the restrictions are, and if you remove it, at least part of the logic is sure to get cleaned up (obviously other arguments might still to refer to it though)
2018-02-15T10:56:01.000899
Zack
pythondev_help_Zack_2018-02-15T10:56:01.000899
1,518,692,161.000899
34,390
pythondev
help
They will be "obsolete" when I add a GUI (well still usefull if ran with `--go-gui`)
2018-02-15T10:56:03.000916
Gwyn
pythondev_help_Gwyn_2018-02-15T10:56:03.000916
1,518,692,163.000916
34,391
pythondev
help
Either that or you could just abstract it out into a validation function and put it somewhere else so as to not overwhelm the entrypoint of your program with all that validation
2018-02-15T10:56:32.000030
Zack
pythondev_help_Zack_2018-02-15T10:56:32.000030
1,518,692,192.00003
34,392
pythondev
help
Yep that's what I'm thinking about :slightly_smiling_face:
2018-02-15T10:57:14.000489
Gwyn
pythondev_help_Gwyn_2018-02-15T10:57:14.000489
1,518,692,234.000489
34,393
pythondev
help
Is there a way to easily ``` - Start a python script. - Catch an error from one or more libs not being installed - Run the pip install on the user's computer - Run the script again and not have the error ```
2018-02-15T10:58:13.000437
Gwyn
pythondev_help_Gwyn_2018-02-15T10:58:13.000437
1,518,692,293.000437
34,394
pythondev
help
I've just ran into this SO, might want to look into that, unless there's a better way to do it <https://stackoverflow.com/questions/12332975/installing-python-module-within-code>
2018-02-15T10:59:21.000126
Gwyn
pythondev_help_Gwyn_2018-02-15T10:59:21.000126
1,518,692,361.000126
34,395
pythondev
help
Yes you could catch an error and subprocess a `pip` call, but I’d recommend against it. Let users install packages, don’t do that for them
2018-02-15T10:59:22.000408
Brande
pythondev_help_Brande_2018-02-15T10:59:22.000408
1,518,692,362.000408
34,396
pythondev
help
&gt; Let users install packages, don’t do that for them That's why I'm trying to go FULL STDLIB :slightly_smiling_face:
2018-02-15T10:59:55.000281
Gwyn
pythondev_help_Gwyn_2018-02-15T10:59:55.000281
1,518,692,395.000281
34,397
pythondev
help
Include a `requirements.txt` or `setup.py` and the command for the user to run to install them in an error message if a package is missing
2018-02-15T10:59:57.000694
Brande
pythondev_help_Brande_2018-02-15T10:59:57.000694
1,518,692,397.000694
34,398
pythondev
help
Sure :slightly_smiling_face: I'll do that when and if I ever need to install external packages for this project
2018-02-15T11:00:52.000741
Gwyn
pythondev_help_Gwyn_2018-02-15T11:00:52.000741
1,518,692,452.000741
34,399
pythondev
help
```list1=[(u'<http://michaelkors.com|michaelkors.com>', 1), (u'<http://bestbuy.com|bestbuy.com>', 2), (u'<http://hrblock.com|hrblock.com>', 3)] array1=array([6, 4, 8]) desired_output=[(u'<http://michaelkors.com|michaelkors.com>', 1,6), (u'<http://bestbuy.com|bestbuy.com>', 2,4), (u'<http://hrblock.com|hrblock.com>'...
2018-02-15T12:49:21.000403
Jenna
pythondev_help_Jenna_2018-02-15T12:49:21.000403
1,518,698,961.000403
34,400
pythondev
help
what’s the best way to make this happen?
2018-02-15T12:49:32.000793
Jenna
pythondev_help_Jenna_2018-02-15T12:49:32.000793
1,518,698,972.000793
34,401
pythondev
help
<@Jenna> you can tuple "append" with a trailing comma. `des_out= list[1] + (array1[1],)` Note the trailing comma after the `array[1]`. Be attentive of the input and output types. Obviously the above solution would need to be extended
2018-02-15T13:50:13.000406
Monroe
pythondev_help_Monroe_2018-02-15T13:50:13.000406
1,518,702,613.000406
34,402
pythondev
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<@Monroe> does that mean i need a for loop in order to go through all elements
2018-02-15T13:53:12.000401
Jenna
pythondev_help_Jenna_2018-02-15T13:53:12.000401
1,518,702,792.000401
34,403
pythondev
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yes, there's probably a more elegant form of zip or map here, but I don't know it
2018-02-15T13:58:47.000459
Monroe
pythondev_help_Monroe_2018-02-15T13:58:47.000459
1,518,703,127.000459
34,404
pythondev
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:thumbsup_all:
2018-02-15T13:59:17.000134
Jenna
pythondev_help_Jenna_2018-02-15T13:59:17.000134
1,518,703,157.000134
34,405
pythondev
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If anyone knows django_otp at all, @ me please - I can not for the life of me figure out how it is expiring before my session expiration since the device key is in the session and I don't see a method to `del` it based on some sort of expiration
2018-02-15T20:56:07.000211
Huong
pythondev_help_Huong_2018-02-15T20:56:07.000211
1,518,728,167.000211
34,406
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Hello to All
2018-02-16T04:53:25.000159
Jed
pythondev_help_Jed_2018-02-16T04:53:25.000159
1,518,756,805.000159
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I just want to spread a bit of information in this section
2018-02-16T04:53:44.000199
Jed
pythondev_help_Jed_2018-02-16T04:53:44.000199
1,518,756,824.000199
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pythondev
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Hello <@Jed> if we are talking about paid support please post that in <#C080T8XT2|job_board> this channel is not really the place. Otherwise we usually prefer for help request to be public to share knowledge
2018-02-16T04:55:49.000358
Micki
pythondev_help_Micki_2018-02-16T04:55:49.000358
1,518,756,949.000358
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pythondev
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Thanks Ovv, I would request you to please share some job boards or forums in your place that are good for the same so that I can post
2018-02-16T04:57:00.000388
Jed
pythondev_help_Jed_2018-02-16T04:57:00.000388
1,518,757,020.000388
34,410
pythondev
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If you click on the link in my message :point_up: it will lead you to the channel
2018-02-16T04:58:10.000134
Micki
pythondev_help_Micki_2018-02-16T04:58:10.000134
1,518,757,090.000134
34,411
pythondev
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Thanks
2018-02-16T04:58:51.000403
Jed
pythondev_help_Jed_2018-02-16T04:58:51.000403
1,518,757,131.000403
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pythondev
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Hey :slightly_smiling_face: Is there any way to remove all escape sequences from a file ? like those: `\033[0;32mok\033[0m`
2018-02-16T06:19:24.000325
Gwyn
pythondev_help_Gwyn_2018-02-16T06:19:24.000325
1,518,761,964.000325
34,413
pythondev
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<@Gwyn> <https://superuser.com/a/380778>
2018-02-16T06:47:52.000321
Barney
pythondev_help_Barney_2018-02-16T06:47:52.000321
1,518,763,672.000321
34,414
pythondev
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there's a Regex which you can plug anywhere
2018-02-16T06:48:03.000353
Barney
pythondev_help_Barney_2018-02-16T06:48:03.000353
1,518,763,683.000353
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pythondev
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if I have made two directories, where should my `run.py` live?
2018-02-16T06:49:54.000140
Milo
pythondev_help_Milo_2018-02-16T06:49:54.000140
1,518,763,794.00014
34,416
pythondev
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ignore, managed to solve it, I created another directory and housed it outside this
2018-02-16T06:52:28.000377
Milo
pythondev_help_Milo_2018-02-16T06:52:28.000377
1,518,763,948.000377
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pythondev
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<https://stackoverflow.com/questions/48826986/how-do-i-use-sqlalchemy-session-to-persist-data-to-relationships>
2018-02-16T08:07:53.000194
Heath
pythondev_help_Heath_2018-02-16T08:07:53.000194
1,518,768,473.000194
34,418
pythondev
help
Help needed
2018-02-16T08:07:58.000258
Heath
pythondev_help_Heath_2018-02-16T08:07:58.000258
1,518,768,478.000258
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pythondev
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It's a many-to-many relationship actually
2018-02-16T08:28:34.000376
Barney
pythondev_help_Barney_2018-02-16T08:28:34.000376
1,518,769,714.000376
34,420
pythondev
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since user can bookmark multiple feeds, and one feed can be bookmarked by multiple users
2018-02-16T08:28:48.000298
Barney
pythondev_help_Barney_2018-02-16T08:28:48.000298
1,518,769,728.000298
34,421
pythondev
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User.bookmarks should be: ``` bookmarks = relationship('Feed', secondary='user_feeds', ...) ``` Note the `secondary` keyword
2018-02-16T08:30:15.000263
Barney
pythondev_help_Barney_2018-02-16T08:30:15.000263
1,518,769,815.000263
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pythondev
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And then you have an association table (needed for many-to-many): ``` user_feeds = Table('user_feeds', Base.metadata, Column('user_id', Integer, ForeignKey('users.id')), Column('feed_id', Integer, ForeignKey('feeds.id')) ) ```
2018-02-16T08:31:48.000309
Barney
pythondev_help_Barney_2018-02-16T08:31:48.000309
1,518,769,908.000309
34,423