blob_id string | repo_name string | path string | length_bytes int64 | score float64 | int_score int64 | text string | is_english bool |
|---|---|---|---|---|---|---|---|
47dbe1afe497cd782da601861888775c94cb3e7c | brandonmorren/python | /C3 iteratie/oefIteratie/oefening 5.py | 619 | 4.25 | 4 | number = int(input("enter a number: "))
if number != 0:
smallest_number = number
highest_number = number
difference = 0
while number != 0:
if number < smallest_number:
smallest_number = number
else:
if number > highest_number:
highest_number = numb... | true |
8ae7e1a9e691f66b965f09644bf849f4938d5506 | brandonmorren/python | /C10 set/OefeningenSet/oef 5.py | 479 | 4.4375 | 4 | months_days = {"January": 31, "February": 28, "March": 31,
"April": 30, "May": 31, "June": 30, "July": 31,
"August": 31, "September": 30, "October": 31,
"November": 30, "December": 31}
input_month = input("Month (press enter for an overview of all months): ")
if input_month... | true |
12a0e490f5025bca17f7957ae7cf6a7677bfd7fe | naldridge/algorithm_exercises | /algorithm_exercise.py | 1,468 | 4.25 | 4 | # Algos
## 1. Bubble Sort
Write a program to sort a list of numbers in ascending order, comparing and swapping two numbers at a time.
```python
[3,1,4,2]
[1,3,4,2]
[1,3,2,4]
[1,2,3,4]
```
## 2. Candies
Given the list `candies` and the integer `extra_candies`, where `candies[i]` represents the number of candie... | true |
6d4c8d2e2843896ebe132366a5a5e3b35064a0c7 | ydj515/python-cleancode | /Chapter6/not_use_descriptor.py | 1,013 | 4.1875 | 4 | #-*- coding: utf-8 -*-
"""
속성을 가진 이란적인 클래스인데 속성의 값이 달라질 때마다 추적
속성의 setter 메소드에서 값이 변경될 때 검사하여 리스트와 같은 내부 변수에 값을 저장
"""
class Travller:
def __init__(self, name, current_city):
self.name = name
self._current_city = current_city
self._cities_visited = [current_city]
@property
def... | false |
a1c49869e7026c54009ebac29d8b485fcc570072 | WesleyPereiraValoes/Python | /Curso em Python Mundo 3/ex113.py | 672 | 4.21875 | 4 | while True:
try:
num = int(input('Digite um número inteiro: '))
except KeyboardInterrupt:
num = 0
print('Usuario desistiu de inserir um valor!')
break
except:
print(f'ERROR: Digite um número inteiro válido!')
else:
print(f'O número digitado foi {num}.')
... | false |
440aad874dfa186c0419813799507b6f4a31debb | midathanapallivamshi/Saloodo | /Question one challange( return reverse of string)/reversestring.py | 988 | 4.28125 | 4 | #!/usr/bin/env python3
import random
# Json module import only if we are reading json input reading and currently we are not reading json input and hence commenting out
# import json
def reverse_string(str_input):
"""
This method is used to reverse a string
"""
reverse_string = str_input[1:]
... | true |
4187ba4726a9bd9feda1d72edf9a0a7215f9bdbf | saipavandarsi/Python-Learnings | /FileSamples/ReverseFileContent.py | 344 | 4.3125 | 4 | #File content Reversing
#Using read()
file = open('myfile.txt', 'r')
content = file.read()
print content
print content[::-1]
# Using ReadLines
file = open('myfile.txt', 'r')
content_lines = file.readlines()
#content_lines[::-1] is to reverse lines
for line in content_lines[::-1]:
#print characters in reverse
... | true |
f387d5872cd714e4f672fa9cd08e788072c4cd99 | jldroid25/DevOps | /Python_scripting/Review_Python/Foundation/1-BasicPython/integers_floats.py | 683 | 4.125 | 4 | ''' ------ Working with Integers and Floats in Python -----
There are two Python data types that could be used for numeric values:
- int - for integer values
- float - for decimal or floating point values
You can create a value that follows
the data type by using the following syntax:
'''
x = int(4.7) # x is no... | true |
d32d3cfd34306257a27952348fa9c647a504ecb1 | jldroid25/DevOps | /Python_scripting/Review_Python/Foundation/2-DataStructures/dictionaries.py | 1,178 | 4.125 | 4 | # Dictionary :
'''
A Data Type for mutable object that store pairs or mappings of unique keys to values.
'''
elements = {'hydrogen': 1, 'helium': 2, 'carbon': 6 }
elements['lithium']= 3
print("\n\n")
print(elements)
print("\n\n")
# We can also use " in" in dictionaries to check if an element is present.
print("... | true |
dbdc1a6706be097b1727dcfa8d72c3511011dbbd | jldroid25/DevOps | /Python_scripting/Review_Python/Foundation/6-iterator-generator/iterator-generator.py | 2,954 | 4.78125 | 5 | import numpy as np
'''
--Iterators And Generators
- Iterables: are objects that can return one of their elements at a time,
such as a list. Many of the built-in functions we’ve used so far,
like 'enumerate,' return an iterator.
- An iterator: is an object that represents a "stream of data".
This is different from ... | true |
8b03d7b5c1edd3313ff972108fa7fc3173cc2a01 | jldroid25/DevOps | /Python_scripting/Review_Python/Foundation/5-Scripting/ScriptingRawInput.py | 571 | 4.3125 | 4 | # -------------Scripting Raw Input ------------------#
#using the input() function
name = input("Enter a name: ")
#print("Welcome come in ", name.title())
# When using the the input() with numbers
# you must include the data type "int()" or "float()" funtion
# else python will throw an error
print('\n')
num = int(... | true |
8e77e139517c1ed083f00c390ed2bcc29d29654d | jldroid25/DevOps | /Python_scripting/Review_Python/Foundation/2-DataStructures/CompoundDataStruct.py | 1,279 | 4.1875 | 4 | # Compound DataStructure is a combination of dictionary inside another
# to have elements names to another dictionary that stores that collection data.
# Essentially it's a nested dictionary
print("\n\n")
elements = {
'hydrogen': {'number': 1, 'weight': 1.000794, 'Symbol' : 'H'} ,
'helium': {'number': 2, 'w... | false |
fe263deeeb9e60830db38532633f728b325271c6 | Zachary3352/reading-journal-Zachary3352 | /shapes.py | 2,162 | 4.375 | 4 | import turtle
#------------------------------------------------------------------------------
# Make some shapes
# Work through exercises 1-4 in Chapter 4.3.
#------------------------------------------------------------------------------
# Square
# NOTE: for part 2 of 4.3, you will add another parameter to this fun... | false |
95657382a090f8341cfe2aebfad9cb5dadb3e75f | antonio00/blue-vscode | /MODULO 01/AULA 10/EX01.PY | 328 | 4.15625 | 4 | # Escreva um programa que pede a senha ao usuário,
# e só sai do looping quando digitarem corretamente a senha
senha = '5467'
tentativa=input("Digite a senha:")
while senha != tentativa:
print("Senha Incorreta! Tente novamente!")
tentativa=input("Digite a senha:")
print("Senha correta. Acesso liberado...")
| false |
4445febfb60cfa94adc57d490b02afe4d66c2397 | GaborBakos/codes | /CCI/Arrays_and_Strings_CHP1/1_string_compression.py | 1,037 | 4.375 | 4 | '''
Implement a method to perform basic string compression using the counts of repeated characters.
EXAMPLE:
Input: aabcccccaaa
Output: a2b1c5a3
If the "compressed" string would not become smaller than the original return the original.
You can assume the string has only uppercase and lowercase... | true |
08871a22ab49d1750f9d5ccdda7d90686b751e42 | Nao801/opp | /kadai.py | 1,626 | 4.46875 | 4 | '''
課題1:円オブジェクト
次のコードが正しく動作するようなCircleクラスを実装すること
areaは面積、perimeterは周囲長という意味
#半径1の円
Circle1 = Circle(radius=1)
print(circle1.area()) #3.14
print(circle1.perimeter()) #6.28
#半径3の円
Circle3 = Circle(radius=3)
print(circle3.area()) #28.27
print(circle3.perimeter()) #18.85
'''
import math
class Circle:
def __init__(s... | false |
5b6c99aa27f6d2c4c7466dff79492c41882f8fda | BeahMarques/Workspace-Python | /Seção 3/exercicio26/app.py | 310 | 4.21875 | 4 | Categoria = int(input("Qual sua categoria: "))
if Categoria == 1:
print("Voce escolheu a categoria BOLSA!")
elif Categoria == 2:
print("Voce escolheu a categoria TENIS!")
elif Categoria == 3:
print("Voce escolheu a categoria MOCHILA!")
else:
print("Essa categoria não foi encontrada") | false |
aff2467f53cb555016ebfd476cec773bbb316f7f | Spandan-Dutta/Snake_Water_Gun_Game | /SNAKE_WATER_GUN_GAME.PY | 2,988 | 4.21875 | 4 | """
So the game is all about that:
1) If you choose Snake and computer choose Gun, you loose as computer shots the snake with a gun.
2) If you choose Gun and computer choose water, you loose as gun is thrown in the water.
3) If you choose Snake and computer choose Water, you wins as Snake drinks the water.
"""
i... | true |
04fd2d654936f8cc705f5a362a4326f175995ddc | standrewscollege2018/2020-year-11-classwork-Bmc9529 | /For loop example.py | 366 | 4.1875 | 4 | """ for loop example, for loops run up to but not the final number"""
i = 1
#in for loops we set a start, enging and increment valu
for i in range(1,1001):
if i % 3 == 0 and i % 5 == 0:
print("fizzbuzz")
elif i % 3 == 0 and not i % 5 == 0:
print("fizz")
elif i % 5 == 0 and not i % 3 == 0:
... | false |
464c3b7fcfd0409dc72f9a238227af789aed4aa0 | Asmithasharon/Python-Programming | /square_root.py | 409 | 4.375 | 4 | '''
To find the square root of a number using newton's method.
'''
def sq_root(number, precision):
sqroot = number
while abs(number - (sqroot * sqroot)) > precision :
#'''abs() is to get the absolute value'''
sqroot = (sqroot + number / sqroot) / 2
return sqroot
number = int(inp... | true |
0425427f405ff360a9b61b66dd26ecfd25f1ba28 | pawnwithn0name/Python-30.03-RaKe | /py_07_04_second/decision_making/if-demo.py | 386 | 4.1875 | 4 | num = float(input("Enter a floating-point: "))
var = int(input("Enter an integer: "))
if num > 100:
print("Numbers entered: {}, {} is greater than 100.".format(num, var))
print("Numbers entered: {1}, {0} is greater than 100.".format(num, var))
print(f"Numbers entered: {num}, {var} is greater than 100.")
... | true |
faa9cc5542f7bb23f5c8e60b779a089381ae319d | BitanuCS/Python | /College-SemV/07. occurrence of each letter.py | 270 | 4.125 | 4 |
#Count the occurrence of each letter in "Maharaja Manindra Chandra College".
str = 'Maharaja Manindra Chandra College'
freq = {}
for i in str:
if i in freq:
freq[i] += 1
else:
freq[i] = 1
print("Frequencies of {} is:\n {}".format(str,freq))
| false |
6829fda3257b5e28f7d54f699bfedabb1ef6da06 | BitanuCS/Python | /College-SemV/10. vehicle class with max_speed and mileage attributes.py | 437 | 4.25 | 4 |
# creat a vehicle class with max_speed and mileage attributes.
class Vehicle:
def __init__(self,max_speed, mileage):
self.max_speed = max_speed
self.mileage = mileage
print("Max. Speed of your car is: {}\nMileage is: {}".format(max_speed,mileage))
max_speed = float(input("What is the max... | true |
56354c5fcf9292ceaae13f4455af5ec3437d7c5e | pksingh786/BETTER-CALCULATOR | /BETTER CALCULATOR.py | 601 | 4.25 | 4 | #this is a better calculatorin comparison of previous one
first_num=float(input("enter first number:"))
second_num=float(input("enter second number:"))
print("press + for addition")
print("press - for subtraction")
print("press * for Multiplication")
print("press / for division")
input=input("enter the symbol fo... | true |
2b53d5961c27ba0e1144b4eb74065e29bf6e7471 | mochapup/LPTHW | /ex20_SD5.py | 1,078 | 4.28125 | 4 | # Functions and files
# import argv
from sys import argv
# Scripr and argument input
script, input_file = argv
# defining function that prints all of file
def print_all(f):
print(f.read())
# defining a function to rewind to character 0 of file
def rewind(f):
f.seek(0)
# defining a function to print each line s... | true |
e40e0d6fb683e2da5b75fbe9ad8f3385b7ad7617 | alfrash/git_1 | /Pandas/Pandas_1.py | 763 | 4.28125 | 4 | import pandas as pd
groceries = pd.Series(data=[30,6,'yes','no'],index=['eggs', 'apples', 'milk', 'bread'])
print(groceries)
print(groceries.shape)
print(groceries.ndim)
print(groceries.size)
print(groceries.values)
print(groceries.index)
print('banana' in groceries)
# lesson 5 - Accessing and Deleting Elements in P... | true |
413300290ba3ef27daa57ef52f45af5189bef2a6 | IvanyukStas/different_lessons | /reverse_every_acdeting.py | 1,099 | 4.125 | 4 | def reverse_ascending(items):
# your code here
temp_items = []
new_items = []
for i in range(len(items)):
if i == len(items)-1:
temp_items.append(items[i])
temp_items.reverse()
for j in temp_items:
new_items.append(j)
continue
... | false |
9fa1c6ab1f961cce3d2464b1e8079a2bd407c631 | chetangargnitd/Python-Guide-for-Beginners | /Factorial/iterativeFactorial.py | 442 | 4.40625 | 4 | # Python program to find the factorial of a given number
# input the number to find its factorial
num = int(input("Enter a number: "))
factorial = 1
if num < 0: #factorial doesn't exist for a negative number
print("Please enter a valid number!")
elif num == 0: #factorial of 0 is 1
print("The factorial of 0... | true |
63a8f0dfb92e74e4fa574f3048f810823893b820 | gabrielavirna/python_data_structures_and_algorithms | /my_work/ch3_stacks_and_queues/bracket_matching_app.py | 1,856 | 4.15625 | 4 | """
Bracket-matching application
----------------------------
- using our stack implementation, verify whether a statement containing brackets --(, [, or {-- is balanced:
whether the number of closing brackets matches the number of opening brackets
- It will also ensure that one pair of brackets really is contained... | true |
b14bab37f60ba19116cf36475643ac4e7e4a1cd6 | gabrielavirna/python_data_structures_and_algorithms | /my_work/ch2_lists_and_pointer_structures/lists_and_pointers.py | 2,302 | 4.34375 | 4 | """
Pointers
--------
Ex:
a house that you want to sell;
a few Python functions that work with images, so you pass high-resolution image data between your functions.
Those large image files remain in one single place in memory. What you do is create variables that hold the locations
of those images in memory. The... | true |
28920f935d378841ec8750148075236777dfe2b1 | gabrielavirna/python_data_structures_and_algorithms | /my_work/ch2_lists_and_pointer_structures/circular_lists.py | 2,502 | 4.15625 | 4 | """
Circular lists
---------------
- a special case of a linked list
- It is a list where the endpoints are connected: the last node in the list points back to the first node
- Circular lists can be based on both singly and doubly linked lists
- In the case of a doubly linked circular list, the first node also needs to... | true |
0ffa31e363ce141ddc7d5a7f5526aadd74046f7d | gabrielavirna/python_data_structures_and_algorithms | /my_work/ch10_design_techniques_&_strategies/coin_counting_greedy.py | 2,416 | 4.46875 | 4 | """
Greedy algorithms
- make decisions that yield the largest benefit in the interim.
- Aim: that by making these high yielding benefit choices, the total path will lead to an overall good solution or end.
Coin-counting problem
---------------------
In some arbitrary country, we have the denominations 1 GHC, 5 GHC, an... | true |
da4dd699a4259d0df6e34bb1f2edc256b504b1da | aadyajha12/Covid19-SmartAlarm | /CA3/time_conversion.py | 965 | 4.21875 | 4 | from datetime import datetime
def minutes_to_seconds(minutes) -> int:
"""Converts minutes to seconds"""
return int(minutes) * 60
def hours_to_minutes(hours) -> int:
"""Converts hours to minutes"""
return int(hours) * 60
def hhmm_to_seconds(hhmm: str):
if len(hhmm.split(':')) != 2:
prin... | false |
912d8a64e49846144609746390f49caba462873c | zhangler1/leetcodepractice | /树与图/Trie Tree/Implement Trie (Prefix Tree)208.py | 1,552 | 4.125 | 4 | class TrieNode:
def __init__(self):
"""
Initialize your Node data structure here.
"""
self.children=[None]*26
self.endcount=0
class Trie:
def __init__(self):
"""
Initialize your data structure here.
"""
self.head=TrieNode()
def inser... | true |
55d07ac39edf980053d80525264424d8eaf416fc | mokrunka/Classes-and-Objects | /countcapitalconsonants.py | 992 | 4.375 | 4 | #Write a function called count_capital_consonants. This
#function should take as input a string, and return as output
#a single integer. The number the function returns should be
#the count of characters from the string that were capital
#consonants. For this problem, consider Y a consonant.
#
#For example:
#
# count_c... | true |
de8d4a940fb3c2098f2e4b6ff689f5a1a69e749f | mushamajay/PythonAssignments | /question8.py | 345 | 4.21875 | 4 | def maximum(numOne, numTwo):
if numOne>numTwo:
return numOne;
else:
return numTwo;
numOne = float(input("Enter your first number: "))
numTwo = float(input("Enter your second number: "))
print("You entered: {} {} " .format(numOne,numTwo))
print("The larger of the two numbers is: {} " .format(... | true |
50384a3fafcc828dcd563081d8c458c4965d523b | IgorToro/mi_primer_proyecto | /comer_helado.py | 1,587 | 4.21875 | 4 | apetece_helado_input = input("¿Te apetece un helado? (Si / No):").upper()
if apetece_helado_input == "SI":
apetece_helado = True
elif apetece_helado_input == "NO":
apetece_helado = False
else:
print("Te he dicho que digas Si o No, no se que me has dicho, cuento como que no quieres un helado")
apetece_h... | false |
aa27be886488997a3f89d12ca493d0b1162360fa | mary-tano/python-programming | /python_for_kids/book/Projects/fenster8.py | 945 | 4.21875 | 4 | # Разметка окна
from tkinter import *
class Window() :
# Инициализация
def __init__(self, Titel) :
self.Window = Tk()
self.Window.title(Titel)
self.Window.config(width=260, height=120)
self.Display = Label(self.Window, text="Как это сделать?")
self.Display.place(x=50, y=20, width=160, height... | false |
18a6899c57c124e3763853d806b282f1dacfab8c | Elena-Yasch/GB_Python_Homework | /task1.py | 465 | 4.125 | 4 | #1. Поработайте с переменными, создайте несколько, выведите на экран, запросите у пользователя несколько чисел
# и строк и сохраните в переменные, выведите на экран.
name = input('Enter your first name:\n')
print(name)
last_name = input('Enter your last name:\n')
print(last_name)
age = int(input('Enter your age:\n'))... | false |
7924ab943291d81d40280a3e46e35b0fbcaffda3 | anayatzirojas/lesson6python | /lesson6/problem3/problem3.py | 483 | 4.15625 | 4 | name = input ('What is your name?')
print ('Hi' + name + ','' ' 'my name is Girlfriend Bot!''<3')
mood = input ('How was your day, Lover?')
print ('Hmm I am looking up the meaning of' + mood +' ' 'just one minute.')
press= input ('I have a surprise for you. Click the screen and type okay.')
print ('HACKED! VIRUSES IS I... | true |
e98f404d2cdb6b1a7cbc0f6172da400fdb305ca2 | renankemiya/exercicios | /2.Estrutura_De_Decisão_wiki.Python/estrutura_de_decisão_5.py | 913 | 4.21875 | 4 | # Faça um programa para a leitura de duas notas parciais de um aluno.
# O programa deve calcular a média alcançada por aluno e apresentar:
# A mensagem "Aprovado", se a média alcançada for maior ou igual a sete;
# A mensagem "Reprovado", se a média for menor do que sete;
# A mensagem "Aprovado com Distinção", se a mé... | false |
67f0a9da8deef35de2945f9810b7faf7dbd50018 | renankemiya/exercicios | /2.Estrutura_De_Decisão_wiki.Python/estrutura_de_decisão_15.py | 1,774 | 4.28125 | 4 | # Faça um Programa que peça os 3 lados de um triângulo. O programa deverá informar se os valores
# podem ser um triângulo. Indique, caso os lados formem um triângulo, se o mesmo é: equilátero, isósceles ou escaleno.
# Dicas:
# Três lados formam um triângulo quando a soma de quaisquer dois lados for maior que o tercei... | false |
f364eb5a8a75807803b802aecfb0b17ee9e94724 | renankemiya/exercicios | /3.Estrutura_De_Repetição_wiki.Python/estrutura_de_repetição_1.py | 405 | 4.21875 | 4 | # Faça um programa que peça uma nota, entre zero e dez. Mostre uma mensagem caso o valor seja inválido e continue
# pedindo até que o usuário informe um valor válido.
nota = float(input('Insira um nota entre 0 a 10: '))
while nota < 0 or nota > 10:
print('Nota Inválida')
nota = float(input('Insira um nota e... | false |
ef1ab96d6b4dd0eb988a31bf3e15b13528e9678b | lohib/Programming--language | /hack3.py | 243 | 4.15625 | 4 | def is_leap(year):
leap=False
if year%4==0:
if year%100==0 and not year%400==0:
leap=False
else:
leap=True
return leap
year=2004
print(is_leap(year))
year=1990
print(is_leap(year))
year=1996
print(is_leap(year))
| false |
32ff4110bcd5bc8c2d1bb1455216581a0e68bc1b | oshrishaul/lesson1 | /Lesson2/Assignment_Class2/Extra2.py | 700 | 4.21875 | 4 | # # Create a nested for loop to create X shape (width is 7, length is 7):
# i=0
# j=4
# for row in range(5):
# for col in range(5):
# if row==i and col==j:
# print("*",end="")
# i=i+1
# j=j-1
# elif row==col:
# print("*",end="")
# else:
# ... | true |
69e4baa9758d9808ac6f72cfe90059b76b874da8 | standrewscollege2018/2020-year-12-python-code-JustineLeeNZ | /credit_manager.py | 2,896 | 4.40625 | 4 | """ Manage student info about L1 NCEA credits - Ms Lee. """
def display_all_students():
""" Display all students in a list. """
print("\nLIST OF STUDENTS")
for index in range(0, len(students)):
print("{}. {} Credits: {}".format(index+1, students[index][0], students[index][1] ))
# stores init... | true |
88627a52218cf3c4fff7d39f34f565f9f39990ee | AssafR/sandbox | /generators.py | 2,172 | 4.375 | 4 | def with_index(itr):
"""This is the same as builtin function enumerate. Don't use this except as an exercise.
I changed the name, because I don't like overriding builtin names.
Produces an iterable which returns pairs (i,x) where x is the value of the original,
and i is its index i... | true |
18f595f69bafa2de6f12e3e22e85efc24ab91d82 | knowledgeforall/Big_Data | /Big Data/arrays.py | 935 | 4.125 | 4 |
#create empty array
A = []
print("Array A: ", A)
#create a "populated" array
B = [12, 23, 56, 17, 23]
print("Array B: ", B)
#Add an element to an array
print("Before adding to A: ", A)
A.append(90)
print("After adding to A: ", A)
#access the 2nd element in array B
print("The second element in Array B is: ", B[1]... | true |
ae879397835b9f1a95459a6bdc70d12252a3754a | baraluga/programming_sandbox | /python/miscellaneous/binary_tree_optimizer.py | 2,117 | 4.34375 | 4 | '''
Recall that a full binary tree is one in which each node is either a leaf
node, or has two children. Given a binary tree, convert it to a full one by
removing nodes with only one child.
For example, given the following tree:
0
/ \
1 2
/ \
3 4
\ / ... | true |
bce7773067afd0c81466166e792751c5be04d7ec | chenlifeng283/learning_python | /7-handling conditions/code_challenge_and_solution.py | 529 | 4.40625 | 4 | # Fix the mistakes in this code and test based on the description below
# if I enter 2.00 I should see the message "The tax rate is: 0.07"
# if I enter 1.00 I should see the message "The tax rate is :0.07"
# if I enter 0.5 I should see the message "The tax rate is: 0"
price = input('How much did you pay?')
price = flo... | true |
0e123b02dca275d099869084f1ed52a9a18d571c | chenlifeng283/learning_python | /1-print/ask_for_input.py | 244 | 4.28125 | 4 | #The input function allows you to prompy the user for a value
#You need to declare a variable to hold the value entered by the user
name=input("What's your name?") #if string has single quotes,it must be enclosed in double quotes.
print(name)
| true |
84594d387e3c44e7e3cd50cf6e33b210e27a865a | BenDataAnalyst/Practice-Coding-Questions | /leetcode/67-Easy-Add-Binary/answer.py | 618 | 4.21875 | 4 | #!/usr/bin/env python
#-------------------------------------------------------------------------------
# Cheaty Python way :)
# Other way would be to add each digit bit by bit, and having a carry bit when > 1
class Solution:
def addBinary(self, a, b):
"""
:type a: str
:type b: str
:... | true |
615668717c061bcdcfcc4c3f7dbe4130aeb6401b | JHHXYZ/DSCS2020 | /Assignments/Assignment 2/part3.py | 2,574 | 4.5625 | 5 | # building a ml model with sklearn
import numpy as np
import pandas as pd
"""
1. Load your data from part 2
Create two lists. One should contain the name of the features (i.e. the input
variables) you want to use to train your model, the other should contain the
column name of the labels
"""
# your code
"""
2. Div... | true |
0bb19fcdb98d6c46c174347921246fe25cf69777 | BillyRockz/Magic-8-Ball | /main.py | 1,215 | 4.125 | 4 | '''This is a game of 8-Ball where you can ask Yes/No Questions and get answers'''
alpha = True
while alpha == True:
name = input("What is your name?: ")
if name.isalpha() and name.strip():
alpha = False
beta = True
while beta == True:
question = input("Ask a (Yes/No) question: ")
beta = False
else:
pr... | true |
6a8130d24de307de61d263b0bdc358a602cfd985 | khelryst/Learning-Python | /gradechecker.py | 444 | 4.21875 | 4 | grade = input('Enter your grade: ')
try:
grade = float(grade)
except:
grade = input('Enter a number from 0.0 - 1.0: ')
if float(grade) >= 0.9:
grade = 'A'
elif float(grade) >=0.8:
grade = 'B'
elif float(grade) >= 0.7:
grade = 'C'
elif float(grade) >= 0.6:
grade = 'D'
elif float(grade) < 0.6:
... | false |
0e89f43161009efc79d682584518c8cce89196d6 | ngovanuc/UDA_NMLT_Python_chapter06 | /page_203_project_03.py | 925 | 4.3125 | 4 | """
author : Ngô Văn Úc
date: 30/08/2021
program: 3. Elena complains that the recursive newton function in Project 2 includes an extra
argument for the estimate. The function’s users should not have to provide this
value, which is always the same, when they call this function. Modify the definition
of the functio... | true |
0c99a8c25c99644fbaddb94b22a7146aad09b854 | ngovanuc/UDA_NMLT_Python_chapter06 | /page_199_exercise_03.py | 477 | 4.3125 | 4 | """
author : Ngô Văn Úc
date: 30/08/2021
program: 2. Write the code for a filtering that generates a list of the positive numbers in a list
named numbers. You should use a lambda to create the auxiliary function.
solution:
- sử dụng bộ loc filter
"""
word = ["a", "hello", "Uc", "handsome", "b", "c", "d"]
... | true |
cb9ad2b4f192f67206af6f565a7cb50a36b13f40 | jjena560/Data-Structures | /strings/strings.py | 656 | 4.15625 | 4 | def createStack():
stack = []
return stack
def push(stack, item):
stack.append(item)
def pop(stack):
return stack.pop()
def reverse(string):
n = len(string)
try:
stack = createStack()
for i in range(n):
push(stack, string[i])
string = ""
... | true |
61813e43dbfb6c4be84104f9e042207ef3beeb2e | sohitmiglani/Applications-in-Python | /Max Heaps.py | 931 | 4.125 | 4 | # This is the algorithm for building and working with heaps, which is a tree-based data structure.
# It allows us to build a heap from a given list, extract certain element, add and remove them.
def max_heapify(A, i):
left = 2 * i + 1
right = 2 * i + 2
largest = i
if left < len(A) and A[left] > A[la... | true |
a1e1308263ba36420c3b7095ae682addf3898b33 | sohitmiglani/Applications-in-Python | /Hash Tables.py | 1,391 | 4.40625 | 4 | # This is an algorithm to produce hash tables and implement hashing functions for efficient data storage and retrieval.
# It also has 4 examples of hashing functions that can be used to store strings.
import random
import string
def randomword(length):
return ''.join(random.choice(string.lowercase) for i in ra... | true |
fab8ea8638fbb524c1b423a6aac64cca4e692cbd | nzrfrz/praxis-academy | /novice/01-02/list_comprehension.py | 1,529 | 4.28125 | 4 | from math import pi
print("using math lib to calculate pi: ")
print(
[str(round(pi, i)) for i in range(1, 6)]
)
print("")
# Create a list of squares
squares = []
for x in range(10):
squares.append(x ** 2)
# Creates or overwrite 'x' after loop
squares = list(map(lambda x: x ** 2, range(10)))
# Simple version ... | true |
c41456a23f31788093696b4433813bc63d57b5d4 | Devanshiq/Python-Programs | /rectangle.py | 1,460 | 4.1875 | 4 | # class rectangle():
# pass
#
#
# r1=rectangle()
# r2=rectangle()
#
#
# r1.height=40
# r1.width=60
#
# r2.height=60
# r2.width=30
#
# print(r1.height*r1.width)
# print(r2.height*r2.width)
# class rectangle():
# def __init__(self,height,width):
# print(height*width)
# self.... | false |
23083506114f10882ec02b046f74a4fe502d042f | Devanshiq/Python-Programs | /car.py | 2,450 | 4.125 | 4 | # class car:
# pass
#
# ford=car()
# honda=car()
# audi=car()
# ford.speed=200
# honda.speed=400
# audi.speed=100
# ford.color='black'
# honda.color='blue'
# audi.colour='maroon'
# print(ford.speed)
# print(audi.colour)
# print(honda.color)
# class car():
# def __init__(self,speed,color):
#... | true |
f093c70bedeaf48c1a139c49a2252224b515d27c | ziGFriedman/My_programs | /Single_double_positive_negative_digit.py | 658 | 4.28125 | 4 | '''Какое число: однозначное или двухзначное, положительное или отрицательное?'''
def digit(n):
if n == 0:
print('Ноль - однозначное число')
else:
if n > 0:
print('Положительное', end=' ')
else:
print('Отрицательное', end=' ')
if abs(n) < 10:
pr... | false |
52258bb913b812c121a1eb90466fd018ac6fb643 | ziGFriedman/My_programs | /Area_and_perimeter_of_a_right_triangle.py | 1,267 | 4.71875 | 5 | '''Найти площадь и периметр прямоугольного треугольника'''
# Найти площадь и периметр прямоугольного треугольника по двум заданным катетам.
# Площадь прямоугольного треугольника равна половине площади прямоугольника, стороны которого равны
# длинам катетов.
# Периметр находится путем сложения длин всех сторон треугольн... | false |
35a77aa042a95f8f956fc013e68efc9d3f1da89c | 656021898/python_project | /homework/homework_1018/User.py | 1,009 | 4.375 | 4 | # 1：创建一个名为 User 的类：
# 1）其中包含属性 first_name 和 last_name，还有用户简介通常会存储的其他几个属性，均是自定义， 请放在初始化函数里面。
# 2）在类 User 中定义一个名为 describe_user()的方法，它打印用户信息摘要；
# 3）再定义一个名为 greet_user()的方法，它向用户发出个性化的问候。:
# 请创建多个表示不同用户的实例，并对每个实例都调用上述两个方法。
class User:
def __init__(self,first_name,last_name,sex="男",age=25):
self.first_name = f... | false |
06413d33de4cb40afd3c7109cf3baf084693b74a | korn13r/RTR105 | /dgr_20181015.py | 1,222 | 4.28125 | 4 | # Conditional steps
x = 5
if x < 10:
print('Smaller')
if x > 20:
print('Bigger')
print ('Finish')
# Comparison operators
x = 5
if x == 5:
print('Equals 5')
if x > 4:
print('Greater than or Equals 5')
if x < 6:
print('Less than or Equals 5')
if x != 6:
print('Not Equals 6')
# one way decision... | false |
75df350c68c6ff04cf879d80be5d97f2a75f48f0 | byn3/holbertonschool-higher_level_programming | /0x07-python-test_driven_development/0-add_integer.py | 575 | 4.21875 | 4 | #!/usr/bin/python3
""" this is my add_integer module """
def add_integer(a, b=98):
"""Function that returns the addition of a + b
Args:
a: should be an int. if not throw error
b: second int. if not throw error. default val is 98.
Returns:
The addition of a + b or a raised TypeErr... | true |
0e6ca5815e21b5a3d5225dc2934d1ba0f390708e | ag-ds-bubble/projEuler | /solutions/solution6.py | 821 | 4.125 | 4 | """
Author : Achintya Gupta
Date Created : 22-09-2020
"""
"""
Problem Statement
------------------------------------------------
Q) The sum of the squares of the first ten natural numbers is, 385
The square of the sum of the first ten natural numbers is, 3025
Hence the difference between the sum of the square... | true |
e81ed59d35f3094800cf2c92ad860dfa50fd3dbd | ag-ds-bubble/projEuler | /solutions/solution4.py | 924 | 4.1875 | 4 | """
Author : Achintya Gupta
Date Created : 22-09-2020
"""
"""
Problem Statement
------------------------------------------------
Q) A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99.
Find the largest palindrome made from the produc... | true |
99a4a4fd4f46f677d72f1a41c11fa89d404f9497 | arkaris/gb_python_basic | /lesson1/task1.py | 368 | 4.1875 | 4 | user_input = input('Введите 3-значное число: ')
numbers = map(int, user_input)
numbers_sum = 0;
for number in numbers:
numbers_sum += number
print("Сумма цифр:", numbers_sum)
numbers_mul = 1;
for number in numbers:
numbers_mul *= number
print("Произведение цифр:", numbers_mul)
input('Работа завершена.') | true |
29ede9877a7ecd003c6320b86aa65c0a5a19dfd9 | BillyCussen/CodingPractice | /Python/Data Structures & Algorithms Module - Python/Revision/SearchAndSortAlgorithms/BubbleSort1.py | 296 | 4.125 | 4 | """
BubbleSort1.py
Billy Cussen
09/02/2021
"""
def bubbleSort(list):
for i in range(len(list)):
for j in range(len(list)-1):
if list[j] > list[j+1]:
list[j], list[j+1] = list[j+1], list[j]
myList = [10,8,4,2,6]
bubbleSort(myList)
for i in myList:
print(i) | false |
5d8b1ceb96d3447722a3bafccb880d1809b8be49 | BillyCussen/CodingPractice | /Python/Data Structures & Algorithms Module - Python/Revision/SearchAndSortAlgorithms/BubbleSort.py | 310 | 4.125 | 4 | """
BubbleSort.py
Billy Cussen
09/02/2021
"""
def bubbleSortArray(arr):
for i in range (len(arr)):
for j in range (len(arr)-1):
if(arr[j]>arr[j+1]):
arr[j], arr[j+1] = arr[j+1], arr[j]
arr1 = [5,4,2,3,1]
bubbleSortArray(arr1)
for i in range(len(arr1)):
print(arr1[i]) | false |
6f2b7477d373945c06ebb7adccb9ff8b5489e841 | BillyCussen/CodingPractice | /Python/Data Structures & Algorithms Module - Python/Week7/Factorial.py | 358 | 4.125 | 4 | """
Factorial.py
Billy Cussen
17/11/2020
"""
def factorial(num):
res = num
while num != 1:
num-=1
res*=num
return res
def factorialRecursion(num):
if num == 1 or num == 0:
return num
return num * factorialRecursion(num-1)
print("Factorial: "+str(factorial(5)))
print("Factor... | false |
acc7a33673cb8edc553e7ab7337c425259c187a5 | mmayes3/Projects | /Tree-Node/Tree-node.py | 1,289 | 4.25 | 4 | class TreeNode(object):
def __init__(self, value):
self.value = value
self.left = None
self.middle = None
self.right = None
def insert_node(self, new_value):
if new_value < self.value:
if self.left == None:
self.left = TreeNode(new_value)
... | false |
d607dcb8b0da5dcbf7e7cded267b4c58ff70cb7e | coder562/python | /83-exercise 18.py | 271 | 4.1875 | 4 | # define a function that takes a number(n)
# return a dictionary containing cube of numbers from 1 to n
# example
# cube_finder(3)
# {1:1,2:8,3:27}
def cube_finder(n):
cubes={}
for i in range(1,n+1):
cubes[i]=i**3
return cubes
print(cube_finder(10)) | true |
fef7dce0af13470cf2e11f12163e5d14624a5f1a | coder562/python | /74-more about tuples.py | 827 | 4.5 | 4 | #looping in tuple
# tuple with one element
# tuple without parenthesis
# tuple unpacking
# list inside tuple
# some functions that you can use with tuples
mixed=(1,2,3,4.5)
# for loop and tuple
# for i in mixed:
# print(i)
#we can use while loop too
# tuple with one element
nums=(1,) #, is important as python de... | true |
b61f899f7e22db47f9793d4f8e4d2f4750f6e729 | coder562/python | /65-more about lists.py | 547 | 4.21875 | 4 | #generate lists with range function
# something more about pop method
# index method
# pass list to a function
# numbers = list(range(1,10))
numbers=[1,2,3,4,5,6,7,8,9,10,1]
# print(numbers)
# print(numbers.pop()) #pop returns the value popped
# print(numbers)
# print(numbers.index(1)) #by defalut search from 0th p... | true |
d75bc9a6e32a78551ff8eae7e4bb75adb2226659 | coder562/python | /88-list comprehenstion.py | 734 | 4.21875 | 4 | #list compreshension
# with the help of list comprehension we can create of list in one line
#create a list of squares from 1 to 10
# squares=[]
# for i in range(1,11):
# squares.append(i**2)
# print(squares)
#by using list comprehension
# square2=[i**2 for i in range(1,11)]
# print(square2)
# cretate list of n... | true |
42e3bb8b71a449580d8b7699b45b76965e89dc41 | coder562/python | /52-variable scope.py | 390 | 4.125 | 4 | x=5 #global variable which is defined outside the function
def func():
global x #to change the value of global variable we use term global
x=7 #the variable defined inside the function are called local variables
return x #x has only scope upto func() not in func2() x cant be used outside func() function
pri... | true |
ed20bbc58702b64ae4b1724646dd431d41f2fcaa | coder562/python | /68-exercise 14.py | 343 | 4.5625 | 5 | # define a function that take list of words as argument and
# return list with reverse of every element in that list
# example
# ['abc','tuv','xyz']--->['cba','vut','zyx']
def reverse_elements(l):
elements = []
for i in l:
elements.append(i[::-1])
return elements
words=['abc','tuv','xyz']
print(re... | true |
b6dbcf61531c5ec98deaac7f4c4a5b405316acc3 | coder562/python | /46-function practice.py | 951 | 4.125 | 4 | # def last_char(name):
# return name[-1]
# print(last_char("vaishali"))
# last_char(9) #error
# define function and check number is even or odd
# def odd_even(num):
# if num%2==0: #% is used to check reminder
# return "even"
# else:
# return "odd"
# print(odd_even(10))
#another method
# d... | true |
774e4fb24567730de3c894550630a51245ed94d0 | Ernestoc14/Python | /pila.py | 795 | 4.3125 | 4 | # Implementacion de Pilas en Python Basico y Sencillo para ERDD con LIFO
pila = [1,2,3] #Creacion de PILA con tres elementos
print('La pila es:') #Impresion de PILA
print(pila)
#Agregamos elementos por el final
print ('Agregamos los numeros 4 y 5 a la Pila')
pila.append(4) #Agregamos el elemento 4 a la PILA
pila.appe... | false |
45c4c66ff2ccb6042a070256a5056ba573708575 | nkhanhng/namkhanh-fundamental-c4e15 | /session4/homework/turtle_excersise/ex2.py | 344 | 4.15625 | 4 | from turtle import *
def draw_rectangle(m,n):
for i in range(2):
forward(m)
left(90)
forward(n)
left(90)
shape("turtle")
speed(1)
colors = ['red', 'blue', 'brown', 'yellow', 'grey']
for j in colors:
color(str(j))
begin_fill()
draw_rectangle(50,100)
forward(50)
... | true |
bd8b9b509d2fe919f97a8685cc8145d1c75b883f | nkhanhng/namkhanh-fundamental-c4e15 | /session6/calc.py | 640 | 4.21875 | 4 | def eval(x,y,op):
result = 0
if op == "+":
result = x + y
elif op == "-":
result = x - y
elif op == "*":
result = x * y
elif op == "/":
result = x // y
return result
# x = int(input("x = "))
# oper = input("Operation(+,-,*,/): ")
# y = int(input("y = "))
# eval... | false |
7c207be73a0defe569ec799b188b5b3544bec62b | RavinderSinghPB/data-structure-and-algorithm | /array/Find the number of sub-arrays having even sum.py | 1,132 | 4.15625 | 4 | def countEvenSum(arr, n):
# A temporary array of size 2. temp[0] is
# going to store count of even subarrays
# and temp[1] count of odd.
# temp[0] is initialized as 1 because there
# a single even element is also counted as
# a subarray
temp = [1, 0]
# Initialize count. sum is sum of el... | true |
a822bde45c53e20f84c19e17ef0abb4b8923cc27 | RavinderSinghPB/data-structure-and-algorithm | /puzzle/range of comp no.py | 442 | 4.125 | 4 | def factorial(n):
a = 1
for i in range(2, n + 1):
a *= i
return a
# to print range of length n
# having all composite integers
def Range(n):
a = factorial(n + 2) + 2
b = a + n - 1
if n==(b-a+1):
return 1
else:
return 0
#print("[" + str(a) + ", " + str(b) + "]"... | false |
7c54a34f8b6476b7ebef606d1416b911b525a135 | devodev/cracking_the_coding_interview_practice | /8.recursion/8.4.py | 957 | 4.3125 | 4 |
def get_subsets(s):
if not s:
return None
return _get_subsets(s, 0)
def _get_subsets(s, n):
all_subsets = None
if len(s) == n:
all_subsets = []
all_subsets.append(set())
else:
all_subsets = _get_subsets(s, n+1)
item = s[n]
more_subsets = []
... | true |
2b1a3141594ad6c66dfa4ce3491b62f7551dccb6 | Adem54/Python-Tutorials | /Günün Soruları/3.soru.py | 787 | 4.28125 | 4 | """
Kullanicidan bir kelime alan, ve bu kelimedeki sesli harflerin toplam sayisini ve sesli harflerin kelimenin
kacinci harfleri oldugunu ekrana yazdiran python programini yaziniz.
Kullanicinin sadece kucuk harfleri kullanidigini varsayabilirsiniz.
Ornek Program Outputu:
====================================
lutfen bir ... | false |
c8143a9de01ab254cd4cd68b21dbc4962be490ef | Adem54/Python-Tutorials | /Günün Soruları/slice_methdou.py | 1,553 | 4.25 | 4 | a = [10, 12, 13, 17, 19, 21, 24, 27, 31, 34]
print(a[:2])
# add 1 number
# a[:0] = [30]
# add two numbers
# a[:0] = [40, 50]
# print(a)
b = a[:] # Bir listenin kopyasını almak içi kullanırız
print(b)
# Normalde parmetre olarak 3 eleman alır a[star,stop,step] şekllindedir ve star başlangıç indisi stop duracağı
# indis... | false |
efeb5601c4525d64eab0adf492fafe131ed921a1 | Adem54/Python-Tutorials | /3.Week/python9.py | 1,219 | 4.3125 | 4 | # Kullanıcıya while döngüsü 3 kere doğru pin girme şansı verin.Hatalı girişler için ekrana "Hatalı Giriş.
# Tekrar PIN girin" yazdırın
# 3 girişten birinde doğru pin girilirse "PIN Kabul Edildi. Hesabınıza Erişebilirsiniz." yazdırın.
# 3 girişte de yanlış girilirse "3'den Fazla Giriş Hakkınız Yok. Hesabınız Kilitlendi!... | false |
e765fb185b8d55cb1c1a37595e229a1e047ea78c | Adem54/Python-Tutorials | /sinav/9.py | 521 | 4.21875 | 4 | """
Verilen iki liste arasındaki farklı elemanları bulan ve bunlardan yeni bir liste oluşturan program yazınız.
Örnek:
list1 = [1, 2, 3, 4]
list2 = [3, 4, 5, 6]
Çıktı:
[1, 2, 5, 6]
"""
def farkli_elemanlari_bul(liste1, liste2):
liste = []
for eleman1 in liste1:
if eleman1 not in liste2:
... | false |
7228c8f644f982b022646dff0c24af3ba0b031c1 | Suka91/RS | /CodeArena/CodeArena/Resources/Leap_Year/version3/Leap_Year.py | 440 | 4.34375 | 4 | def leap_year(year):
if(...)==0:
if(...)== 0:
if(...) == 0:
print("{0} is a leap year".format(year))
return 1
else:
print("{0} is not a leap year".format(year))
return -1
else:
print("{0} is a leap y... | true |
1c3ed6a743b865524ff8f21fd85105f92996407f | AntonioRafaelGarcia/LPtheHW | /ex20/ex20.py | 1,581 | 4.375 | 4 | # makes argv available in this script
from sys import argv
# uses argv to assign user input when calling script
script, input_file = argv
# defines function to read and print input variable file
def print_all(f):
print(f.read())
# defines function to go to very first line of inputted variable file
def rewind(f):... | true |
63dbc6ca29923a63a42477c45d138a7c29d7c26e | AntonioRafaelGarcia/LPtheHW | /ex12.py | 312 | 4.28125 | 4 | # string prompts and directly assigns to three separate variables
age = input("How old are you? ")
height = input("How tall are you? ")
weight = input("How much do you weigh? ")
# f prints a string statement seeded with those prompted variables
print(f"So, you're {age} old, {height} tall and {weight} heavy.")
| true |
b56b81731cb6a6cacbbdaf7d45d645ea040a10ef | mkwak73/probability | /chapter 1/exercises/exercise1.py | 1,183 | 4.4375 | 4 | # Chapter 1 - Exercise 1
# Author: Michael Kwak
# Date: December 26 2016
#######################################################
#
# random () - return the next random floating point number in the range [0.0, 1.0)
#
import random
#
# get input for number of tosses for this simulation
#
n = int(input("Enter the val... | true |
a7a9e67983effa2597e33420b34085c55e0ed2b7 | mkwak73/probability | /chapter 1/exercises/exercise9.py | 2,743 | 4.125 | 4 | # Chapter 1 - Exercise 9 - Labouchere system
# Author: Michael Kwak
# Date: January 4 2016
#######################################################################################
#
# random () - return the next random floating point
# number in the range [0.0, 1.0)
#
import random
from math import floor
#
# defin... | true |
6b39f64cd03f762d6f7a8bfb79842a845fac5107 | Kowenjko/Python_Homework_13_Kowenjko | /test_2.py | 2,973 | 4.15625 | 4 | """
Examples:
triangle = Triangle([3, 3, 3])
Use classes TriangleNotValidArgumentException and TriangleNotExistException
Create class TriangleTest with parametrized unittest for class Triangle
test data:
"""
import unittest
import math
class Triangle:
def __init__(self, t):
self.t = t
def input_valu... | false |
ea6b1b325303699febde9050a58e031f18651475 | NaregAmirianMegan/Hailstone-Problem | /hailstone_interactive.py | 558 | 4.125 | 4 | def isEven(num):
if(num%2 == 0):
return True
else:
return False
def applyOdd(num):
return 3*num + 1
def applyEven(num):
return num/2
def analyze(num, count):
if(isEven(num)):
num = applyEven(num)
else:
num = applyOdd(num)
if(num == 1):
print("Value:... | true |
391c94dc9513855243ea8658926ff404ac1510b2 | yangwenbinGit/python_programe | /python_04/do_slice.py | 2,282 | 4.1875 | 4 | # 切片
# 取一个list或tuple的部分元素是非常常见的操作。比如，一个list如下：
L = ['Michael', 'Sarah', 'Tracy', 'Bob', 'Jack']
# 取前3个元素，应该怎么做？笨办法就是:
print(L[0],L[1],L[2])
# 也可以用循环的方式 方式一
i=0
for x in L:
if(i<3):
print(L[i])
i=i+1
# 方式二 range(5)生成的序列是从0开始小于5的整数 list(range(5)) 会将生成的数转换为list
r=[]
n=3
for i in list(range(n)):
r.app... | false |
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