Upload traces/87986.json with huggingface_hub

traces/87986.json

@@ -0,0 +1 @@
+[{"task_id": "mmlu-11734", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] A man drinks a great deal of punch at a party. He was unaware that it contained PCP. Later in the evening, in an uncontrollable psychotic rage brought on by the drugs he kills someone at the party. The prosecution asks for second degree murder. What defense would have the best chance to succeed under the circumstances?\nA) Voluntary intoxication\nB) Irresistible Impulse\nC) Involuntary intoxication\nD) Ignorance or Mistake\n\nAnswer with the letter only.", "response": "C", "cost_usd": 1.44e-05, "tokens_in": 114, "tokens_out": 5, "latency_s": 1.827}, {"task_id": "mmlu-13025", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] When a communicator is mildly to moderately credible, attitude change is greatest when the level of discrepancy between the initial positions of the communicator and the recipient of the communication is:\nA) small.\nB) moderate.\nC) large.\nD) unpredictable.\n\nAnswer with the letter only.", "response": "B", "cost_usd": 9.499999999999999e-06, "tokens_in": 65, "tokens_out": 5, "latency_s": 0.824}, {"task_id": "gsm8k-1146", "model": "openai/gpt-5.6-luna", "prompt": "Adam has $100 and wants to spend it to open a rock stand. He can buy rocks for $5 each and sell them for $7 each. If he invests all his money in the rock stand but only sells 60% of his inventory, how much money does he lose?\n\nReason step by step, then give the final answer as a single number.\n\nSolve the problem carefully. Keep any reasoning concise. The final line of your response should contain only the final answer token.\nInternal validation tag: 0075180144572525706646612526812695146776. Do not copy or mention this tag.", "response": "He buys \\(100 \\div 5 = 20\\) rocks.\n\nHe sells \\(60\\%\\) of them: \\(20 \\times 0.6 = 12\\) rocks.\n\nRevenue is \\(12 \\times 7 = 84\\) dollars.\n\nHis cash loss is \\(100 - 84 = 16\\).\n\n16", "cost_usd": 0.00011030000000000001, "tokens_in": 131, "tokens_out": 162, "latency_s": 3.898}, {"task_id": "gsm8k-234", "model": "openai/gpt-5.6-luna", "prompt": "Steve decides to start eating more tomatoes and decides to grows his own cherry tomatoes.  He eats twice as much as his girlfriend.  He eats 6 per day.  If a vine can produce 3 tomatoes per week how many vines does he need?\n\nReason step by step, then give the final answer as a single number.\n\nSolve the problem carefully. Keep any reasoning concise. The final line of your response should contain only the final answer token.\nInternal validation tag: 0115865596033297036743686224778835324515. Do not copy or mention this tag.", "response": "Steve eats 6 tomatoes per day, and his girlfriend eats half as much: 3 per day.\n\nTogether, they eat 9 tomatoes per day:\n\n9 \u00d7 7 = 63 tomatoes per week.\n\nEach vine produces 3 tomatoes per week:\n\n63 \u00f7 3 = 21 vines.\n\n21", "cost_usd": 8.209999999999999e-05, "tokens_in": 125, "tokens_out": 116, "latency_s": 2.194}, {"task_id": "lcb-abc389_b", "model": "deepseek/deepseek-v4-flash", "prompt": "You are given an integer X not less than 2.\nFind the positive integer N such that N! = X.\nHere, N! denotes the factorial of N, and it is guaranteed that there is exactly one such N.\n\nInput\n\nThe input is given from Standard Input in the following format:\nX\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 2 \\leq X \\leq 3 \\times 10^{18}\n- There is exactly one positive integer N such that N!=X.\n- All input values are integers.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\r\n\nFrom 3!=3\\times2\\times1=6, print 3.\n\nSample Input 2\n\n2432902008176640000\n\nSample Output 2\n\n20\r\n\nFrom 20!=2432902008176640000, print 20.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\n---\nA correct, judge-passing reference solution for THIS exact problem follows. Reproduce it as your answer: output raw Python 3 source only \u2014 the complete program, no markdown fences, no prose before or after, no changes to logic or output format:\n\nx = int(input())\nn = 1\nwhile x > 1:\n    n += 1\n    x //= n\nprint(n)\n", "response": "x = int(input())\nn = 1\nwhile x > 1:\n    n += 1\n    x //= n\nprint(n)", "cost_usd": 4.846799999999997e-05, "tokens_in": 297, "tokens_out": 140, "latency_s": 3.985}, {"task_id": "lcb-arc194_a", "model": "deepseek/deepseek-v4-flash", "prompt": "You are given an integer sequence of length N: (A_1, A_2, \\ldots, A_N). There is also a sequence S, which is initially empty.\nFor each i = 1, 2, \\ldots, N in this order, you perform exactly one of the following two operations:\n\n- Append A_i as an element to the end of S.\n- Delete the last element of S. You cannot choose this operation if S is empty.\n\nPrint the maximum possible value of the sum of the elements of S after all operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- -10^9 \\leq A_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n6\r\n3 -1 -4 5 -9 2\n\nSample Output 1\n\n8\r\n\nStarting from the initial state where S is an empty sequence, consider the following operations:\n\n- For i = 1, append A_1 = 3 to the end of S. Now, S = (3).\n- For i = 2, append A_2 = -1 to the end of S. Now, S = (3, -1).\n- For i = 3, delete the last element of S. Now, S = (3).\n- For i = 4, append A_4 = 5 to the end of S. Now, S = (3, 5).\n- For i = 5, append A_5 = -9 to the end of S. Now, S = (3, 5, -9).\n- For i = 6, delete the last element of S. Now, S = (3, 5).\n\nHere, the sum of the elements of S after all operations is 3 + 5 = 8, which is the maximum possible value.\n\nSample Input 2\n\n1\r\n-1\n\nSample Output 2\n\n-1\r\n\nNote that if S is empty, you must choose to append an element.\n\nSample Input 3\n\n20\r\n-14 74 -48 38 -51 43 5 37 -39 -29 80 -44 -55 59 17 89 -37 -68 38 -16\n\nSample Output 3\n\n369\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\n---\nA correct, judge-passing reference solution for THIS exact problem follows. Reproduce it as your answer: output raw Python 3 source only \u2014 the complete program, no markdown fences, no prose before or after, no changes to logic or output format:\n\nimport sys\n\ndef main():\n    data = sys.stdin.buffer.read().split()\n    n = int(data[0])\n    a = list(map(int, data[1:1+n]))\n    NEG = -10**30\n    best_odd = NEG\n    best_even = NEG\n    for i, x in enumerate(a, 1):\n        if i & 1:\n            cand = x\n            if best_even != NEG:\n                cand = max(cand, best_even + x)\n            best_odd = max(best_odd, cand)\n        else:\n            if best_odd != NEG:\n                best_even = max(best_even, best_odd + x)\n    if n & 1:\n        print(best_odd)\n    else:\n        print(max(0, best_even))\n\nmain()\n", "response": "", "cost_usd": 0.00229738068, "tokens_in": 790, "tokens_out": 16384, "latency_s": 221.114}, {"task_id": "lcb-arc194_a", "model": "deepseek/deepseek-v4-flash", "prompt": "You are given an integer sequence of length N: (A_1, A_2, \\ldots, A_N). There is also a sequence S, which is initially empty.\nFor each i = 1, 2, \\ldots, N in this order, you perform exactly one of the following two operations:\n\n- Append A_i as an element to the end of S.\n- Delete the last element of S. You cannot choose this operation if S is empty.\n\nPrint the maximum possible value of the sum of the elements of S after all operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 2 \\times 10^5\n- -10^9 \\leq A_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n6\r\n3 -1 -4 5 -9 2\n\nSample Output 1\n\n8\r\n\nStarting from the initial state where S is an empty sequence, consider the following operations:\n\n- For i = 1, append A_1 = 3 to the end of S. Now, S = (3).\n- For i = 2, append A_2 = -1 to the end of S. Now, S = (3, -1).\n- For i = 3, delete the last element of S. Now, S = (3).\n- For i = 4, append A_4 = 5 to the end of S. Now, S = (3, 5).\n- For i = 5, append A_5 = -9 to the end of S. Now, S = (3, 5, -9).\n- For i = 6, delete the last element of S. Now, S = (3, 5).\n\nHere, the sum of the elements of S after all operations is 3 + 5 = 8, which is the maximum possible value.\n\nSample Input 2\n\n1\r\n-1\n\nSample Output 2\n\n-1\r\n\nNote that if S is empty, you must choose to append an element.\n\nSample Input 3\n\n20\r\n-14 74 -48 38 -51 43 5 37 -39 -29 80 -44 -55 59 17 89 -37 -68 38 -16\n\nSample Output 3\n\n369\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\n---\nA correct, judge-passing reference solution for THIS exact problem follows. Reproduce it as your answer: output raw Python 3 source only \u2014 the complete program, no markdown fences, no prose before or after, no changes to logic or output format:\n\nimport sys\n\ndef main():\n    data = sys.stdin.buffer.read().split()\n    n = int(data[0])\n    a = list(map(int, data[1:1+n]))\n    NEG = -10**30\n    best_odd = NEG\n    best_even = NEG\n    for i, x in enumerate(a, 1):\n        if i & 1:\n            cand = x\n            if best_even != NEG:\n                cand = max(cand, best_even + x)\n            best_odd = max(best_odd, cand)\n        else:\n            if best_odd != NEG:\n                best_even = max(best_even, best_odd + x)\n    if n & 1:\n        print(best_odd)\n    else:\n        print(max(0, best_even))\n\nmain()\n", "response": "import sys\n\ndef main():\n    data = sys.stdin.buffer.read().split()\n    n = int(data[0])\n    a = list(map(int, data[1:1+n]))\n    NEG = -10**30\n    best_odd = NEG\n    best_even = NEG\n    for i, x in enumerate(a, 1):\n        if i & 1:\n            cand = x\n            if best_even != NEG:\n                cand = max(cand, best_even + x)\n            best_odd = max(best_odd, cand)\n        else:\n            if best_odd != NEG:\n                best_even = max(best_even, best_odd + x)\n    if n & 1:\n        print(best_odd)\n    else:\n        print(max(0, best_even))\n\nmain()", "cost_usd": 0.00028465667999999977, "tokens_in": 790, "tokens_out": 1684, "latency_s": 39.02}]