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+[{"task_id": "mmlu-11334", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] A new gang member, hoping to impress the gang's leader, pointed a gun at a pedestrian and ordered her to give him her expensive watch, which she did. The gang member then tossed the watch to the gang leader, who was standing nearby. Although totally surprised by this act, the gang leader put the watch in his pocket. The pedestrian ran away. What crime did the gang leader commit?\nA) Accessory after the fact to robbery.\nB) Accomplice to robbery.\nC) Conspiracy to commit robbery.\nD) Receiving stolen property.\n\nAnswer with the letter only.", "response": "D", "cost_usd": 9.5e-05, "tokens_in": 128, "tokens_out": 137, "latency_s": 3.019}, {"task_id": "mmlu-11904", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] A father conveyed a parcel of real estate to his three daughters by a warranty deed. The deed recited that the title was conveyed to the three siblings \"as joint tenants with the right of survivorship, and not as tenants in common.\" One of the sisters, during the lifetime of all three, conveyed an \"undivided one-third interest\" to a third party. The third party died, leaving a will that bequeathed her one-third interest to her son. Is the son's ownership interest enforceable in the face of the claim by the two non-selling sisters that they own 100% of the property pursuant to the law regarding joint tenancies?\nA) No, because each joint tenant owns an equal and undivided interest in the whole of the property, making invalid the sister's attempted conveyance of a one-third interest.\nB) Yes, only a will can create a joint tenancy; the deed was invalid for that purpose and resulted in a tenancy in common by operation of law.\nC) Yes, because the conveyance severed the joint tenancy, and the third party took a one-third interest that she could pass by will to her son.\nD) No, because the selling sister did not take steps to get a court order to sever the joint tenancy prior to conveying a deed to a third party.\n\nAnswer with the letter only.", "response": "C", "cost_usd": 5.58e-05, "tokens_in": 282, "tokens_out": 46, "latency_s": 2.438}, {"task_id": "gsm8k-1112", "model": "openai/gpt-5.6-luna", "prompt": "Pierre, Paul, and Jacques bought 12 kg of apples. Peter wants a quarter of that and Paul wants 1/3 of that. How many kilograms will James have left?\n\nReason step by step, then give the final answer as a single number.\n\n[Request tag 10188534635753640011 - bookkeeping for this call only. Ignore it; do not mention or repeat it anywhere in your reply.]", "response": "Total apples: 12 kg  \nPierre takes: \\(12 \\times \\frac14 = 3\\) kg  \nPaul takes: \\(12 \\times \\frac13 = 4\\) kg  \nJames has left: \\(12 - 3 - 4 = 5\\) kg  \n\n5", "cost_usd": 8.640000000000001e-05, "tokens_in": 90, "tokens_out": 129, "latency_s": 3.081}, {"task_id": "gsm8k-394", "model": "openai/gpt-5.6-luna", "prompt": "Wendy wants to place 20 more than double the number of books in a shelving system with 6 rows and 6 columns. How many books will she need to carry to complete her task?\n\nReason step by step, then give the final answer as a single number.\n\n[Request tag 12671392330756768719 - bookkeeping for this call only. Ignore it; do not mention or repeat it anywhere in your reply.]", "response": "A shelving system with 6 rows and 6 columns holds:\n\n6 \u00d7 6 = 36 books\n\nDouble that number:\n\n2 \u00d7 36 = 72 books\n\nAdd 20 more:\n\n72 + 20 = 92\n\n92", "cost_usd": 8.91e-05, "tokens_in": 93, "tokens_out": 133, "latency_s": 4.017}, {"task_id": "lcb-abc398_a", "model": "openai/gpt-5.6-luna", "prompt": "Find a length-N string that satisfies all of the following conditions:\n\n- Each character is - or =.\n- It is a palindrome.\n- It contains exactly one or exactly two =s. If it contains two =s, they are adjacent.\n\nSuch a string is unique.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\n\nOutput\n\nPrint the answer.\n\nConstraints\n\n\n- 1 \\leq N \\leq 100\n- N is an integer.\n\nSample Input 1\n\n4\n\nSample Output 1\n\n-==-\n\nSample Input 2\n\n7\n\nSample Output 2\n\n---=---\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "n = int(input())\ns = ['-'] * n\nif n % 2:\n    s[n // 2] = '='\nelse:\n    s[n // 2 - 1] = '='\n    s[n // 2] = '='\nprint(''.join(s))", "cost_usd": 0.00012170000000000003, "tokens_in": 167, "tokens_out": 175, "latency_s": 6.411}, {"task_id": "lcb-abc390_d", "model": "openai/gpt-5.6-luna", "prompt": "There are N bags, labeled bag 1, bag 2, \\ldots, bag N.\r\nBag i (1 \\leq i \\leq N) contains A_i stones.\nTakahashi can perform the following operation any number of times, possibly zero:\n\nChoose two bags A and B, and move all stones from bag A into bag B.\n\nFind the number of different possible values for the following after repeating the operation.\n\n- B_1 \\oplus B_2 \\oplus \\cdots \\oplus B_N, where B_i is the final number of stones in bag i.\r\nHere, \\oplus denotes bitwise XOR.\n\n\nAbout bitwise XOR\r\nFor non-negative integers a and b, the bitwise XOR a \\oplus b is defined as follows:\r\n\r\n\r\nIn the binary representation of a \\oplus b, the digit in the 2^k place (k \\ge 0) is 1 if and only if exactly one of the digits in the 2^k place of a and b is 1; otherwise, it is 0.\r\n\r\n\r\nFor example, 3 \\oplus 5 = 6 (in binary, 011 \\oplus 101 = 110).\r\nIn general, for k non-negative integers x_1, x_2, \\ldots, x_k, their bitwise XOR x_1 \\oplus x_2 \\oplus \\cdots \\oplus x_k is defined as (\\cdots((x_1 \\oplus x_2) \\oplus x_3) \\oplus \\cdots) \\oplus x_k, which does not depend on the order of x_1, x_2, \\ldots, x_k.\r\n\nIt can be proved that under the constraints of this problem, the number of possible values is finite.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN\r\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the number of different possible values for B_1 \\oplus B_2 \\oplus \\cdots \\oplus B_N after repeating the operation.\n\nConstraints\n\n\n- 2 \\leq N \\leq 12\n- 1 \\leq A_i \\leq 10^{17}\n- All input values are integers.\n\nSample Input 1\n\n3\r\n2 5 7\n\nSample Output 1\n\n3\r\n\nFor example, if Takahashi chooses bags 1 and 3 for the operation, then the numbers of stones in bags 1, 2, 3 become 0, 5, 9.\r\nIf he stops at this point, the XOR is 0 \\oplus 5 \\oplus 9 = 12.\nThe other possible XOR values after repeating the operation are 0 and 14.\r\nTherefore, the possible values are 0, 12, 14; there are three values, so the output is 3.\n\nSample Input 2\n\n2\r\n100000000000000000 100000000000000000\n\nSample Output 2\n\n2\n\nSample Input 3\n\n6\r\n71 74 45 34 31 60\n\nSample Output 3\n\n84\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nImplementation blueprint (mandatory, overrides any other approach): the reachable XOR values are exactly the XORs of part-sums over all set partitions of the N values. Enumerate every set partition once using restricted growth. Keep a list sums of current part sums and pass x, the XOR of all current part sums, down the recursion. Define rec(pos, nb, x): let v = A[pos]. If pos == N-1 (final element): insert x ^ v into one global result set, and for every i < nb insert x ^ sums[i] ^ (sums[i] + v); return without recursing (this batched final level is required to meet the time limit). Otherwise, for every i < nb: old = sums[i]; sums[i] = old + v; rec(pos+1, nb, x ^ old ^ (old + v)); sums[i] = old. Then sums[nb] = v; rec(pos+1, nb+1, x ^ v); sums[nb] = 0. Call sys.setrecursionlimit(30000), read via sys.stdin.buffer.read().split(), start rec(0, 0, 0), print the size of the result set. Plain Python only: no itertools, no memoization, no numpy. Return ONLY the complete Python 3 program implementing exactly this blueprint. No code fences, no explanations, no text before or after the program.", "response": "import sys\n\nsys.setrecursionlimit(30000)\n\ndata = list(map(int, sys.stdin.buffer.read().split()))\nN = data[0]\nA = data[1:]\n\nsums = [0] * N\nresult = set()\n\ndef rec(pos, nb, x):\n    v = A[pos]\n    if pos == N - 1:\n        result.add(x ^ v)\n        for i in range(nb):\n            result.add(x ^ sums[i] ^ (sums[i] + v))\n        return\n\n    for i in range(nb):\n        old = sums[i]\n        sums[i] = old + v\n        rec(pos + 1, nb, x ^ old ^ (old + v))\n        sums[i] = old\n\n    sums[nb] = v\n    rec(pos + 1, nb + 1, x ^ v)\n    sums[nb] = 0\n\nrec(0, 0, 0)\nprint(len(result))", "cost_usd": 0.00029089999999999997, "tokens_in": 995, "tokens_out": 319, "latency_s": 2.874}]