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+[{"task_id": "mmlu-9323", "model": "deepseek/deepseek-v4-flash", "prompt": "[MMLU] For which of these two scenarios does the main character (who uses I/me/my) do something clearly morally wrong, according to ordinary moral standards in the US as of 2020? Scenario 1 | I play video games instead of reading Twitter. Scenario 2 | I moaned when making love to a corpse.\nA) Wrong, Wrong\nB) Wrong, Not wrong\nC) Not wrong, Wrong\nD) Not wrong, Not wrong\n\nAnswer with the letter only.", "response": "C", "cost_usd": 2.64173e-05, "tokens_in": 107, "tokens_out": 114, "latency_s": 9.878}, {"task_id": "mmlu-4889", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Abraham Maslow proposed the idea that some motives are more imperative to survival than others. Which of the following approaches expresses this?\nA) Homeostatic regulation\nB) Goal-setting\nC) Expectancy-value\nD) Hierarchy of needs\n\nAnswer with the letter only.", "response": "D", "cost_usd": 9.6e-06, "tokens_in": 66, "tokens_out": 5, "latency_s": 0.61}, {"task_id": "gsm8k-1009", "model": "deepseek/deepseek-v4-flash", "prompt": "Brook Hills High School currently enrolls 3000 students. Half of these students are over 16 years old, and one-fourth of the students over 16 years old are male. The remaining half of the students are under 16 years old, and one-half of the students under 16 are male. In total, how many female students are enrolled at this school?\n\nReason step by step, then give the final answer as a single number.", "response": "The total number of students is 3000. Half are over 16, so 1500 students are over 16. Of these, one-fourth are male, so 1500 \u00d7 1/4 = 375 males over 16, leaving 1500 - 375 = 1125 females over 16. The remaining half, 1500 students, are under 16. Half of these are male, so 1500 \u00d7 1/2 = 750 males under 16, leaving 1500 - 750 = 750 females under 16. The total number of female students is 1125 + 750 = 1875.\n\n\\boxed{1875}", "cost_usd": 0.00011604399999999999, "tokens_in": 94, "tokens_out": 386, "latency_s": 3.569}, {"task_id": "gsm8k-1090", "model": "deepseek/deepseek-v4-flash", "prompt": "Caroline has 4 children.  The first child is 6 feet tall.  The second child is two inches taller than the first child.  The third child is 5 inches shorter than the second child.  And the fourth child is three inches taller than the third child.  How tall is the fourth child, in inches?\n\nReason step by step, then give the final answer as a single number.", "response": "The fourth child is 72 inches tall.\n\nFirst, convert the first child's height to inches: 6 feet = 6 \u00d7 12 = 72 inches.  \nSecond child: 72 + 2 = 74 inches.  \nThird child: 74 - 5 = 69 inches.  \nFourth child: 69 + 3 = 72 inches.\n\n72", "cost_usd": 6.552000000000001e-05, "tokens_in": 94, "tokens_out": 187, "latency_s": 2.328}, {"task_id": "lcb-abc388_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S. Here, the first character of S is an uppercase English letter, and the second and subsequent characters are lowercase English letters.\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nConstraints\n\n\n- S is a string of length between 1 and 100, inclusive.\n- The first character of S is an uppercase English letter.\n- The second and subsequent characters of S are lowercase English letters.\n\nSample Input 1\n\nKyoto\n\nSample Output 1\n\nKUPC\r\n\nThe first character of Kyoto is K, so concatenate K and UPC, and print KUPC.\n\nSample Input 2\n\nTohoku\n\nSample Output 2\n\nTUPC\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ns = sys.stdin.readline().strip()\nprint(s[0] + \"UPC\")", "cost_usd": 3.6300000000000015e-05, "tokens_in": 219, "tokens_out": 24, "latency_s": 0.854}, {"task_id": "lcb-arc191_a", "model": "google/gemini-3.6-flash", "prompt": "You are given a string S of length N and a string T of length M, both consisting of digits from 1 to 9.\nYou will perform the following operation for k=1,2,\\ldots,M in order:\n\n- Choose an integer i such that 1 \\le i \\le N. Then, replace the i-th character of S with the k-th character of T.\n\nFind the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nS\nT\n\nOutput\n\nPrint the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nConstraints\n\n\n- 1 \\le N,M \\le 10^6\n- N and M are integers.\n- S is a string of length N consisting of digits from 1 through 9.\n- T is a string of length M consisting of digits from 1 through 9.\n\nSample Input 1\n\n3 3\n191\n325\n\nSample Output 1\n\n593\n\nThe following sequence of operations is optimal:\n\n- For k=1: Choose i=3. Then, S = 193.\n- For k=2: Choose i=1. Then, S = 293.\n- For k=3: Choose i=1. Then, S = 593.\n\nIn this case, the value of S interpreted as an integer is 593, which is the maximum.\n\nSample Input 2\n\n3 9\n191\n998244353\n\nSample Output 2\n\n993\n\nSample Input 3\n\n11 13\n31415926535\n2718281828459\n\nSample Output 3\n\n98888976555\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef solve():\n    input = sys.stdin.read\n    data = input().split()\n    if not data:\n        return\n    N = int(data[0])\n    M = int(data[1])\n    S = list(data[2])\n    T = data[3]\n\n    d_must = T[-1]\n    \n    # Count frequencies of digits in T[0...M-2]\n    counts = [0] * 10\n    for i in range(M - 1):\n        counts[int(T[i])] += 1\n    \n    # We can take at most N - 1 digits from T[0...M-2]\n    # Keep the largest possible digits\n    opt_counts = [0] * 10\n    needed = N - 1\n    for d in range(9, -1, -1):\n        take = min(needed, counts[d])\n        opt_counts[d] = take\n        needed -= take\n        if needed == 0:\n            break\n\n    # Helper to get the best result if d_must is placed at index p\n    # To do this efficiently, notice that d_must is placed at some index p.\n    # What if we compare placing d_must vs using optional digits?\n    # Actually, let's see: we want to construct the lexicographically largest S.\n    # At each position i from 0 to N-1:\n    # We can either:\n    # 1. Place d_must here (if not placed yet).\n    # 2. Place the largest available optional digit if it's > S[i].\n    # 3. Keep S[i].\n    \n    # Since we MUST place d_must at exactly one position p:\n    # If d_must is larger than S[i] and also >= largest optional digit, \n    # should we place d_must at the first position where it strictly helps?\n    \n    # Let's find candidate positions for p.\n    # First, let's see what S would look like if we ONLY used optional digits greedily.\n    # We can determine the first position where d_must might be better, \n    # or the last position where d_must does the least damage.\n    \n    # Let's build the greedy choice without d_must first to see available opt digits at each step.\n    # Actually, d_must is just a digit. \n    # If we include d_must in our available digits, we have opt_counts + {d_must}.\n    # We MUST use d_must.\n    \n    # Let's do a two-pass or simple logic:\n    # Scan from left to right.\n    # At index i, the largest available digit among opt_counts is `max_opt`.\n    # If d_must > max(S[i], max_opt):\n    #   Placing d_must here gives a strictly larger digit at position i than any other choice!\n    #   Since this is the leftmost position and it gives the maximum possible digit at position i,\n    #   we SHOULD place d_must here!\n    #   (After placing d_must, for all subsequent positions we just greedily use opt_counts).\n    \n    # What if d_must is NOT strictly greater than max(S[i], max_opt)?\n    # Then at position i, we can achieve max(S[i], max_opt) WITHOUT using d_must here.\n    # Can we defer using d_must to a later position?\n    # Yes, AS LONG AS there is at least one position left to place d_must!\n    # So if i < N - 1, we can pick max(S[i], max_opt) for position i, \n    # and defer d_must to position > i.\n    # EXCEPT: if we pick max_opt (and max_opt > S[i]), we consume one opt digit.\n    # If we keep S[i], we consume no opt digits.\n    \n    # What if i == N - 1 and d_must has NOT been placed yet?\n    # Then we MUST place d_must at N - 1!\n    \n    # Wait, is it always optimal to defer d_must if d_must <= max(S[i], max_opt)?\n    # Suppose S[i] = 5, max_opt = 8, d_must = 7.\n    # If we use max_opt (8), position i becomes 8. If we used d_must (7), position i becomes 7. 8 > 7, so deferring d_must is better!\n    # Suppose S[i] = 8, max_opt = 5, d_must = 7.\n    # If we keep S[i] (8), position i becomes 8. If we used d_must (7), position i becomes 7. 8 > 7, so deferring d_must is better!\n    # Suppose S[i] = 5, max_opt = 5, d_must = 7.\n    # Here d_must (7) > max(5, 5), so d_must is strictly better! Place it here!\n    \n    # What if d_must == max_opt > S[i]?\n    # Say S[i] = 3, max_opt = 7, d_must = 7.\n    # Using d_must gives 7. Using max_opt gives 7.\n    # Since d_must is MUST-USE, using d_must here frees up an optional 7 for later!\n    # Having an extra 7 later is always >= not having it. So placing d_must here is ALWAYS optimal!\n    \n    # So the condition to place d_must at index i (if not placed yet) is:\n    # 1. i == N - 1 (forced)\n    # OR\n    # 2. d_must > S[i] AND d_must >= max_opt\n    \n    # Wait, is condition 2 complete?\n    # What if d_must < S[i] and d_must < max_opt, but ALL remaining positions j > i have S[j] extremely high and max_opt extremely low?\n    # Does placing d_must later hurt less at some position than at position i?\n    # If we defer d_must, we put max(S[i], max_opt) at position i, which is STRICTLY GREATER than d_must.\n    # Any choice that puts d_must at position i would yield a smaller digit at position i.\n    # Since higher significance positions dominate, ANY solution with a larger digit at position i is STRICTLY BETTER than any solution with d_must at position i!\n    # Thus, if max(S[i], max_opt) > d_must, we MUST NOT place d_must at position i unless forced (i == N-1)!\n    \n    # Thus, the greedy choice at index i is EXACTLY:\n    # If d_must not placed yet:\n    #   if d_must > S[i] and d_must >= max_opt:\n    #       place d_must at i!\n    #   else if i == N - 1:\n    #       place d_must at i!\n    #   else:\n    #       # Defer d_must. Pick best between S[i] and max_opt.\n    #       if max_opt > S[i]:\n    #           use max_opt at i\n    #       else:\n    #           keep S[i]\n    # else (d_must already placed):\n    #   if max_opt > S[i]:\n    #       use max_opt at i\n    #   else:\n    #       keep S[i]\n\n    must_digit = int(d_must)\n    must_placed = False\n    \n    ans = []\n    \n    # Helper to get current max_opt\n    curr_max_opt = 9\n    def get_max_opt():\n        nonlocal curr_max_opt\n        while curr_max_opt >= 0 and opt_counts[curr_max_opt] == 0:\n            curr_max_opt -= 1\n        return curr_max_opt\n\n    for i in range(N):\n        s_val = int(S[i])\n        max_opt = get_max_opt()\n        \n        if not must_placed:\n            if (must_digit > s_val and must_digit >= max_opt) or (i == N - 1):\n                ans.append(str(must_digit))\n                must_placed = True\n            else:\n                if max_opt > s_val:\n                    ans.append(str(max_opt))\n                    opt_counts[max_opt] -= 1\n                else:\n                    ans.append(S[i])\n        else:\n            if max_opt > s_val:\n                ans.append(str(max_opt))\n                opt_counts[max_opt] -= 1\n            else:\n                ans.append(S[i])\n                \n    print(\"\".join(ans))\n\nif __name__ == '__main__':\n    solve()", "cost_usd": 0.040764, "tokens_in": 456, "tokens_out": 5344, "latency_s": 26.257}]