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+[{"task_id": "mmlu-8081", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] In the original 'Get Smart' TV series what is agent Maxwell Smart's code name?\nA) Agent 86\nB) Agent 99\nC) Larrabee\nD) The Chief\n\nAnswer with the letter only.", "response": "A", "cost_usd": 8.7e-06, "tokens_in": 57, "tokens_out": 5, "latency_s": 2.65}, {"task_id": "mmlu-1795", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] A rainbow is the result of light in raindrops that undergoes\nA) internal reflection\nB) dispersion\nC) refraction\nD) All of these\n\nAnswer with the letter only.", "response": "D", "cost_usd": 8.100000000000002e-06, "tokens_in": 51, "tokens_out": 5, "latency_s": 0.912}, {"task_id": "gsm8k-234", "model": "openai/gpt-5.6-luna", "prompt": "Steve decides to start eating more tomatoes and decides to grows his own cherry tomatoes.  He eats twice as much as his girlfriend.  He eats 6 per day.  If a vine can produce 3 tomatoes per week how many vines does he need?\n\nReason step by step, then give the final answer as a single number.\n\nInternal routing tag: 0290039647085501680882538275449969494907. Ignore this tag and do not repeat it.", "response": "Steve eats 6 tomatoes per day.  \nHis girlfriend eats half as much: \\(6 \\div 2 = 3\\) per day.  \nTogether, they eat \\(6 + 3 = 9\\) tomatoes per day.  \nPer week: \\(9 \\times 7 = 63\\) tomatoes.  \nEach vine produces 3 tomatoes per week: \\(63 \\div 3 = 21\\).\n\n21", "cost_usd": 0.0001146, "tokens_in": 102, "tokens_out": 174, "latency_s": 4.231}, {"task_id": "gsm8k-97", "model": "openai/gpt-5.6-luna", "prompt": "When Freda cooks canned tomatoes into sauce, they lose half their volume. Each 16 ounce can of tomatoes that she uses contains three tomatoes. Freda\u2019s last batch of tomato sauce made 32 ounces of sauce. How many tomatoes did Freda use?\n\nReason step by step, then give the final answer as a single number.\n\nInternal routing tag: 0002303632403844150732093627600021108380. Ignore this tag and do not repeat it.", "response": "Sauce is half the volume of the canned tomatoes, so Freda used:\n\n32 \u00d7 2 = 64 ounces of tomatoes\n\nEach can contains 16 ounces, so:\n\n64 \u00f7 16 = 4 cans\n\nEach can has 3 tomatoes:\n\n4 \u00d7 3 = 12\n\n12", "cost_usd": 8.219999999999999e-05, "tokens_in": 102, "tokens_out": 120, "latency_s": 3.346}, {"task_id": "lcb-abc388_b", "model": "openai/gpt-5.6-luna", "prompt": "There are N snakes.\nInitially, the thickness of the i-th snake is T_i, and its length is L_i.\nThe weight of a snake is defined as the product of its thickness and length.\nFor each integer k satisfying 1 \\leq k \\leq D, find the weight of the heaviest snake when every snake's length has increased by k.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN D\r\nT_1 L_1\r\nT_2 L_2\r\n\\vdots\r\nT_N L_N\n\nOutput\n\nPrint D lines. The k-th line should contain the weight of the heaviest snake when every snake's length has increased by k.\n\nConstraints\n\n\n- 1 \\leq N, D \\leq 100\n- 1 \\leq T_i, L_i \\leq 100\n- All input values are integers.\n\nSample Input 1\n\n4 3\r\n3 3\r\n5 1\r\n2 4\r\n1 10\n\nSample Output 1\n\n12\r\n15\r\n20\r\n\nWhen every snake\u2019s length has increased by 1, the snakes' weights become 12, 10, 10, 11, so print 12 on the first line.\nWhen every snake\u2019s length has increased by 2, the snakes' weights become 15, 15, 12, 12, so print 15 on the second line.\nWhen every snake\u2019s length has increased by 3, the snakes' weights become 18, 20, 14, 13, so print 20 on the third line.\n\nSample Input 2\n\n1 4\r\n100 100\n\nSample Output 2\n\n10100\r\n10200\r\n10300\r\n10400\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.", "response": "import sys\n\ndef main():\n    input = sys.stdin.readline\n    n, d = map(int, input().split())\n    snakes = [tuple(map(int, input().split())) for _ in range(n)]\n\n    answers = []\n    for k in range(1, d + 1):\n        answers.append(str(max(t * (l + k) for t, l in snakes)))\n\n    sys.stdout.write(\"\\n\".join(answers))\n\nif __name__ == \"__main__\":\n    main()\n", "cost_usd": 0.00010310000000000001, "tokens_in": 401, "tokens_out": 105, "latency_s": 2.136}, {"task_id": "lcb-arc191_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S of length N and a string T of length M, both consisting of digits from 1 to 9.\nYou will perform the following operation for k=1,2,\\ldots,M in order:\n\n- Choose an integer i such that 1 \\le i \\le N. Then, replace the i-th character of S with the k-th character of T.\n\nFind the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nS\nT\n\nOutput\n\nPrint the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nConstraints\n\n\n- 1 \\le N,M \\le 10^6\n- N and M are integers.\n- S is a string of length N consisting of digits from 1 through 9.\n- T is a string of length M consisting of digits from 1 through 9.\n\nSample Input 1\n\n3 3\n191\n325\n\nSample Output 1\n\n593\n\nThe following sequence of operations is optimal:\n\n- For k=1: Choose i=3. Then, S = 193.\n- For k=2: Choose i=1. Then, S = 293.\n- For k=3: Choose i=1. Then, S = 593.\n\nIn this case, the value of S interpreted as an integer is 593, which is the maximum.\n\nSample Input 2\n\n3 9\n191\n998244353\n\nSample Output 2\n\n993\n\nSample Input 3\n\n11 13\n31415926535\n2718281828459\n\nSample Output 3\n\n98888976555\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolver brief (required): every operation's digit can be discarded by placing it on a position a later operation overwrites, except the final digit d0 = T[M-1], which always remains visible somewhere. Build counts over digits of T without its last character, then add one extra count for d0. Convert S to a mutable char array. Keep hi starting at 9 and walk S left to right: lower hi while its count is zero; stop if hi < 1; if hi is strictly greater than the current digit, overwrite with hi, decrement its count, and record satisfied when hi == d0. After the walk, if not satisfied AND d0 does not appear in the result, overwrite the last character with d0; if d0 already appears, leave as is. Print the string. Read with sys.stdin.buffer.read().split(); O(N+M), digit counting only, never sort T. Return ONLY the complete Python 3 program implementing exactly this brief. No code fences, no explanations, no text before or after the program.", "response": "import sys\n\ndata = sys.stdin.buffer.read().split()\nN = int(data[0])\nM = int(data[1])\ns = list(data[2].decode())\nt = data[3].decode()\n\nd0 = int(t[-1])\ncount = [0] * 10\n\nfor ch in t[:-1]:\n    count[ord(ch) - 48] += 1\ncount[d0] += 1\n\nhi = 9\nsatisfied = False\n\nfor i, ch in enumerate(s):\n    while hi >= 1 and count[hi] == 0:\n        hi -= 1\n    if hi < 1:\n        break\n    if hi > ord(ch) - 48:\n        s[i] = chr(hi + 48)\n        count[hi] -= 1\n        if hi == d0:\n            satisfied = True\n\nif not satisfied and chr(d0 + 48) not in s:\n    s[-1] = chr(d0 + 48)\n\nsys.stdout.write(''.join(s))", "cost_usd": 0.000505, "tokens_in": 610, "tokens_out": 740, "latency_s": 8.992}]