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| # Copyright 2026 DeepMind Technologies Limited. | |
| # | |
| # Licensed under the Apache License, Version 2.0 (the "License"); | |
| # you may not use this file except in compliance with the License. | |
| # You may obtain a copy of the License at | |
| # | |
| # http://www.apache.org/licenses/LICENSE-2.0 | |
| # | |
| # Unless required by applicable law or agreed to in writing, software | |
| # distributed under the License is distributed on an "AS IS" BASIS, | |
| # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. | |
| # See the License for the specific language governing permissions and | |
| # limitations under the License. | |
| """Utils.""" | |
| import itertools | |
| from kauldron.ktyping import Array | |
| import numpy as np | |
| def count_consecutive(values: Array['L']) -> tuple[tuple[int | bool, int], ...]: # pyrefly: ignore[unknown-name] | |
| """Counts consecutive identical elements in a list. | |
| Useful to debug masks with padding. | |
| Args: | |
| values: A list of elements. | |
| Returns: | |
| A tuple of tuples, where each inner tuple contains the element | |
| and its consecutive count. | |
| """ | |
| return tuple( | |
| (np.asarray(key).item(), len(list(group))) | |
| for key, group in itertools.groupby(values) | |
| ) | |