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+[{"task_id": "mmlu-2244", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Use the Associative Property of Multiplication to simplify 8 \u2022 (\u22127) \u2022 (\u22121).\nA) \u221263\nB) 56\nC) 48\nD) \u221256\n\nAnswer with the letter only.\n\nThink step by step about each option, then end with exactly: ANSWER: <letter>", "response": "ANSWER: B", "cost_usd": 0.0001294, "tokens_in": 77, "tokens_out": 95, "latency_s": 3.816}, {"task_id": "mmlu-12101", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] A plaintiff filed an action in federal district court and served the defendant with the summons and complaint. The defendant moved to dismiss the complaint for failure to state a claim. Instead of opposing the motion to dismiss, the plaintiff voluntarily dismissed the action and filed a new action, alleging the same claims but also addressing the pleading defects outlined in the defendant's motion to dismiss. The defendant then moved to dismiss the second action, and the plaintiff again voluntarily dismissed the second action instead of filing opposition papers. The plaintiff then filed a third action, alleging the same claims but also including additional allegations that were responsive to the defendant's second motion. The defendant has moved to dismiss the third action; the plaintiff opposes the motion. Is the court likely to grant the defendant's motion?\nA) No, because the plaintiff has promptly and diligently attempted to address the pleading defects.\nB) No, because the plaintiff voluntarily dismissed each previous action before the defendant filed an answer or moved for summary judgment.\nC) Yes, because the plaintiff failed to seek a court order dismissing the second action.\nD) Yes, because the plaintiff's previously dismissed actions asserting the same claims dismissed actions asserting the same claims operate as an adjudication on the merits.\n\nAnswer with the letter only.\n\nThink step by step about each option, then end with exactly: ANSWER: <letter>", "response": "ANSWER: D", "cost_usd": 0.0002488, "tokens_in": 278, "tokens_out": 161, "latency_s": 2.7}, {"task_id": "gsm8k-370", "model": "openai/gpt-5.6-luna", "prompt": "A hand-painted wallpaper costs $400 at the market. A DIY will saves 20% after considering the materials cost. If Ethan made his own hand-painted wallpaper, how much was the total cost?\n\nReason step by step, then give the final answer as a single number.\n\nReason step by step, then end with the final answer as a single number.\n\n(ref 714262)", "response": "1. Savings = 20% of $400 = $80.  \n2. Total DIY cost = $400 \u2212 $80 = $320.  \n\n320", "cost_usd": 0.00011000000000000002, "tokens_in": 82, "tokens_out": 78, "latency_s": 1.975}, {"task_id": "gsm8k-252", "model": "openai/gpt-5.6-luna", "prompt": "Last night Rick killed ten wolves and 15 cougars while hunting. Today Rick killed three times as many wolves as cougars and three fewer cougars than the previous night. How many animals did Rick kill?\n\nReason step by step, then give the final answer as a single number.\n\nReason step by step, then end with the final answer as a single number.\n\n(ref 805683)", "response": "1. Today Rick killed 3 fewer cougars than the previous night: \\(15 - 3 = 12\\).\n2. He killed 3 times as many wolves as cougars: \\(3 \\times 12 = 36\\).\n3. Total animals killed today: \\(36 + 12 = 48\\).\n\n48", "cost_usd": 0.00028079999999999994, "tokens_in": 84, "tokens_out": 220, "latency_s": 3.394}, {"task_id": "lcb-abc388_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S. Here, the first character of S is an uppercase English letter, and the second and subsequent characters are lowercase English letters.\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nConstraints\n\n\n- S is a string of length between 1 and 100, inclusive.\n- The first character of S is an uppercase English letter.\n- The second and subsequent characters of S are lowercase English letters.\n\nSample Input 1\n\nKyoto\n\nSample Output 1\n\nKUPC\r\n\nThe first character of Kyoto is K, so concatenate K and UPC, and print KUPC.\n\nSample Input 2\n\nTohoku\n\nSample Output 2\n\nTUPC\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nWhen enumerating partitions into UNLABELED groups, generate each partition once: process items in order and place the next item into each existing group or one new group. Do not recursively choose arbitrary subsets as blocks \u2014 permuting block order repeats the same partition and can turn a feasible search into a timeout. Start from the first item, update aggregate values incrementally, put final values straight into a set, and skip existing groups with equal state: those branches are symmetric.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "import sys\n\ntokens = sys.stdin.buffer.read().split()\ns = tokens[0].decode()\noutput = [s[0], \"UPC\"]\nsys.stdout.write(\"\".join(output))", "cost_usd": 0.00029220000000000006, "tokens_in": 513, "tokens_out": 158, "latency_s": 3.127}, {"task_id": "lcb-abc388_a", "model": "openai/gpt-5.6-luna", "prompt": "Now help me test that solution. Write TWO short programs and nothing else.\n\nFirst, a REFERENCE solution: correct by construction and as slow as you like -- enumerate every possibility, simulate the process directly, try all subsets or permutations. Do NOT reuse the idea from your solution above; the point is that it can disagree with it. It will only ever be run on TINY inputs, so exponential is fine and preferred over anything clever. It reads the same stdin format and prints the same output format.\n\nSecond, a GENERATOR taking TWO command line arguments, an integer seed and an integer size. It must call random.seed(seed) and print ONE random input to stdout in exactly the statement's input format. Treat size as the approximate number of elements, clamped to what the constraints allow: at size 2 emit the smallest legal input, larger sizes proportionally bigger. Vary the VALUES aggressively -- repeats, extremes of the allowed range, adversarial patterns. Every input it prints must satisfy every stated constraint.\n\nOutput exactly two fenced blocks and no other text:\n```reference\n<the reference program>\n```\n```generator\n<the generator program>\n```", "response": "```reference\nimport sys\n\ns = sys.stdin.buffer.read().split()[0].decode()\nsys.stdout.write(s[0] + \"UPC\\n\")\n```\n```generator\nimport random\nimport sys\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nn = max(1, min(100, size - 1))\nif n == 1:\n    s = \"A\"\nelse:\n    first = random.choice(\"ABCDEFGHIJKLMNOPQRSTUVWXYZ\")\n    patterns = [\n        \"a\" * (n - 1),\n        \"z\" * (n - 1),\n        (\"az\" * n)[:n - 1],\n        (\"zyxwvutsrqponmlkjihgfedcba\" * n)[:n - 1],\n        \"\".join(random.choice(\"abcdefghijklmnopqrstuvwxyz\") for _ in range(n - 1)),\n    ]\n    s = first + random.choice(patterns)\n\nsys.stdout.write(s + \"\\n\")\n```", "cost_usd": 0.0007401999999999999, "tokens_in": 749, "tokens_out": 492, "latency_s": 5.713}, {"task_id": "lcb-abc388_a", "model": "google/gemini-3.6-flash", "prompt": "You are given a string S. Here, the first character of S is an uppercase English letter, and the second and subsequent characters are lowercase English letters.\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nConstraints\n\n\n- S is a string of length between 1 and 100, inclusive.\n- The first character of S is an uppercase English letter.\n- The second and subsequent characters of S are lowercase English letters.\n\nSample Input 1\n\nKyoto\n\nSample Output 1\n\nKUPC\r\n\nThe first character of Kyoto is K, so concatenate K and UPC, and print KUPC.\n\nSample Input 2\n\nTohoku\n\nSample Output 2\n\nTUPC\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nWhen enumerating partitions into UNLABELED groups, generate each partition once: process items in order and place the next item into each existing group or one new group. Do not recursively choose arbitrary subsets as blocks \u2014 permuting block order repeats the same partition and can turn a feasible search into a timeout. Start from the first item, update aggregate values incrementally, put final values straight into a set, and skip existing groups with equal state: those branches are symmetric.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "import sys\n\ndef main():\n    S = sys.stdin.read().split()[0]\n    sys.stdout.write(S[0] + \"UPC\\n\")\n\nif __name__ == '__main__':\n    main()", "cost_usd": 0.0005955000000000001, "tokens_in": 534, "tokens_out": 52, "latency_s": 0.904}, {"task_id": "lcb-abc388_a", "model": "deepseek/deepseek-v4-pro", "prompt": "You are given a string S. Here, the first character of S is an uppercase English letter, and the second and subsequent characters are lowercase English letters.\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nConstraints\n\n\n- S is a string of length between 1 and 100, inclusive.\n- The first character of S is an uppercase English letter.\n- The second and subsequent characters of S are lowercase English letters.\n\nSample Input 1\n\nKyoto\n\nSample Output 1\n\nKUPC\r\n\nThe first character of Kyoto is K, so concatenate K and UPC, and print KUPC.\n\nSample Input 2\n\nTohoku\n\nSample Output 2\n\nTUPC\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nWhen enumerating partitions into UNLABELED groups, generate each partition once: process items in order and place the next item into each existing group or one new group. Do not recursively choose arbitrary subsets as blocks \u2014 permuting block order repeats the same partition and can turn a feasible search into a timeout. Start from the first item, update aggregate values incrementally, put final values straight into a set, and skip existing groups with equal state: those branches are symmetric.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "import sys\n\ndef main():\n    data = sys.stdin.buffer.read().split()\n    if not data:\n        return\n    s = data[0].decode()\n    out = s[0] + \"UPC\"\n    sys.stdout.write(out + \"\\n\")\n\nif __name__ == \"__main__\":\n    main()", "cost_usd": 0.0008310067999999999, "tokens_in": 520, "tokens_out": 387, "latency_s": 5.726}, {"task_id": "lcb-abc388_a", "model": "z-ai/glm-5.2", "prompt": "You are given a string S. Here, the first character of S is an uppercase English letter, and the second and subsequent characters are lowercase English letters.\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nS\n\nOutput\n\nPrint the string formed by concatenating the first character of S and UPC in this order.\n\nConstraints\n\n\n- S is a string of length between 1 and 100, inclusive.\n- The first character of S is an uppercase English letter.\n- The second and subsequent characters of S are lowercase English letters.\n\nSample Input 1\n\nKyoto\n\nSample Output 1\n\nKUPC\r\n\nThe first character of Kyoto is K, so concatenate K and UPC, and print KUPC.\n\nSample Input 2\n\nTohoku\n\nSample Output 2\n\nTUPC\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nWhen enumerating partitions into UNLABELED groups, generate each partition once: process items in order and place the next item into each existing group or one new group. Do not recursively choose arbitrary subsets as blocks \u2014 permuting block order repeats the same partition and can turn a feasible search into a timeout. Start from the first item, update aggregate values incrementally, put final values straight into a set, and skip existing groups with equal state: those branches are symmetric.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "import sys\n\ndef main():\n    data = sys.stdin.buffer.read().split()\n    if not data:\n        return\n    S = data[0].decode()\n    result = S[0] + \"UPC\"\n    sys.stdout.write(result + \"\\n\")\n\nif __name__ == \"__main__\":\n    main()", "cost_usd": 0.0022285619999999995, "tokens_in": 525, "tokens_out": 567, "latency_s": 8.382}, {"task_id": "lcb-arc195_a", "model": "openai/gpt-5.6-luna", "prompt": "There is a sequence A = (A_1,\\dots,A_N). Determine whether there are at least two subsequences of A that match the sequence B = (B_1,\\dots,B_M). Two subsequences are distinguished if they are taken from different positions, even if they coincide as sequences.\n\nSubsequence\nA subsequence of A is a sequence obtained by removing zero or more elements from A and leaving the remaining elements in their original order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nA_1 A_2 \\ldots A_N\nB_1 B_2 \\ldots B_M\n\nOutput\n\nIf there are at least two subsequences of A that match B, print Yes. Otherwise, print No.\n\nConstraints\n\n\n- 1 \\leq M \\leq N \\leq 2\\times 10^5\n- 1 \\leq A_i \\leq 10^9\n- 1 \\leq B_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n4 2\n1 2 1 2\n1 2\n\nSample Output 1\n\nYes\n\nThere are three subsequences of A that match B: (A_1,A_2), (A_1,A_4), (A_3,A_4).\n\nSample Input 2\n\n3 2\n1 2 1\n1 2\n\nSample Output 2\n\nNo\n\nThere is only one subsequence of A that matches B: (A_1,A_2).\n\nSample Input 3\n\n3 2\n1 1 2\n2 1\n\nSample Output 3\n\nNo\n\nThere are no subsequences of A that match B.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nWhen enumerating partitions into UNLABELED groups, generate each partition once: process items in order and place the next item into each existing group or one new group. Do not recursively choose arbitrary subsets as blocks \u2014 permuting block order repeats the same partition and can turn a feasible search into a timeout. Start from the first item, update aggregate values incrementally, put final values straight into a set, and skip existing groups with equal state: those branches are symmetric.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "import sys\n\ndata = sys.stdin.buffer.read().split()\nn = int(data[0])\nm = int(data[1])\na = list(map(int, data[2:2 + n]))\nb = list(map(int, data[2 + n:2 + n + m]))\n\ndp = [0] * (m + 1)\ndp[0] = 1\n\nfor x in a:\n    for j in range(m, 0, -1):\n        if x == b[j - 1]:\n            dp[j] = min(2, dp[j] + dp[j - 1])\n\nsys.stdout.write(\"Yes\\n\" if dp[m] >= 2 else \"No\\n\")", "cost_usd": 0.0004829999999999999, "tokens_in": 699, "tokens_out": 286, "latency_s": 2.886}, {"task_id": "lcb-arc195_a", "model": "openai/gpt-5.6-luna", "prompt": "Now help me test that solution. Write TWO short programs and nothing else.\n\nFirst, a REFERENCE solution: correct by construction and as slow as you like -- enumerate every possibility, simulate the process directly, try all subsets or permutations. Do NOT reuse the idea from your solution above; the point is that it can disagree with it. It will only ever be run on TINY inputs, so exponential is fine and preferred over anything clever. It reads the same stdin format and prints the same output format.\n\nSecond, a GENERATOR taking TWO command line arguments, an integer seed and an integer size. It must call random.seed(seed) and print ONE random input to stdout in exactly the statement's input format. Treat size as the approximate number of elements, clamped to what the constraints allow: at size 2 emit the smallest legal input, larger sizes proportionally bigger. Vary the VALUES aggressively -- repeats, extremes of the allowed range, adversarial patterns. Every input it prints must satisfy every stated constraint.\n\nOutput exactly two fenced blocks and no other text:\n```reference\n<the reference program>\n```\n```generator\n<the generator program>\n```", "response": "```reference\nimport sys\nfrom itertools import combinations\n\ndata = sys.stdin.buffer.read().split()\nif not data:\n    sys.exit()\n\nn = int(data[0])\nm = int(data[1])\na = list(map(int, data[2:2 + n]))\nb = list(map(int, data[2 + n:2 + n + m]))\n\ncount = 0\nfor positions in combinations(range(n), m):\n    if all(a[positions[i]] == b[i] for i in range(m)):\n        count += 1\n        if count >= 2:\n            break\n\nsys.stdout.write(\"Yes\\n\" if count >= 2 else \"No\\n\")\n```\n\n```generator\nimport sys\nimport random\n\nseed = int(sys.argv[1])\nsize = int(sys.argv[2])\nrandom.seed(seed)\n\nif size <= 2:\n    print(\"1 1\")\n    print(\"1\")\n    print(\"1\")\n    sys.exit()\n\nn = max(1, min(200000, size - 1))\nm = random.randint(1, n)\n\nspecial = [1, 2, 3, 10**9, 10**9 - 1, 500000000]\nmode = random.randrange(8)\n\ndef value(i):\n    if mode == 0:\n        return random.choice(special)\n    if mode == 1:\n        return 1 if i % 2 == 0 else 10**9\n    if mode == 2:\n        return (i % 7) + 1\n    if mode == 3:\n        return 10**9 - (i % 11)\n    if mode == 4:\n        return random.randint(1, 4)\n    if mode == 5:\n        return random.randint(1, 10**9)\n    if mode == 6:\n        return special[i % len(special)]\n    return random.choice([random.randint(1, 20), random.randint(10**9 - 20, 10**9)])\n\na = [value(i) for i in range(n)]\n\nif random.random() < 0.7:\n    b = [a[random.randrange(n)] for _ in range(m)]\nelse:\n    b = [value(i + n) for i in range(m)]\n\nif random.random() < 0.35:\n    for i in range(1, m):\n        if random.random() < 0.8:\n            b[i] = b[i - 1]\n\nout = [f\"{n} {m}\", \" \".join(map(str, a)), \" \".join(map(str, b))]\nsys.stdout.write(\"\\n\".join(out) + \"\\n\")\n```", "cost_usd": 0.0014013999999999997, "tokens_in": 935, "tokens_out": 1012, "latency_s": 8.469}, {"task_id": "lcb-arc195_a", "model": "google/gemini-3.6-flash", "prompt": "There is a sequence A = (A_1,\\dots,A_N). Determine whether there are at least two subsequences of A that match the sequence B = (B_1,\\dots,B_M). Two subsequences are distinguished if they are taken from different positions, even if they coincide as sequences.\n\nSubsequence\nA subsequence of A is a sequence obtained by removing zero or more elements from A and leaving the remaining elements in their original order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nA_1 A_2 \\ldots A_N\nB_1 B_2 \\ldots B_M\n\nOutput\n\nIf there are at least two subsequences of A that match B, print Yes. Otherwise, print No.\n\nConstraints\n\n\n- 1 \\leq M \\leq N \\leq 2\\times 10^5\n- 1 \\leq A_i \\leq 10^9\n- 1 \\leq B_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n4 2\n1 2 1 2\n1 2\n\nSample Output 1\n\nYes\n\nThere are three subsequences of A that match B: (A_1,A_2), (A_1,A_4), (A_3,A_4).\n\nSample Input 2\n\n3 2\n1 2 1\n1 2\n\nSample Output 2\n\nNo\n\nThere is only one subsequence of A that matches B: (A_1,A_2).\n\nSample Input 3\n\n3 2\n1 1 2\n2 1\n\nSample Output 3\n\nNo\n\nThere are no subsequences of A that match B.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nWhen enumerating partitions into UNLABELED groups, generate each partition once: process items in order and place the next item into each existing group or one new group. Do not recursively choose arbitrary subsets as blocks \u2014 permuting block order repeats the same partition and can turn a feasible search into a timeout. Start from the first item, update aggregate values incrementally, put final values straight into a set, and skip existing groups with equal state: those branches are symmetric.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "import sys\nfrom bisect import bisect_left, bisect_right\nfrom collections import defaultdict\n\ndef main():\n    input_data = sys.stdin.buffer.read().split()\n    if not input_data:\n        return\n    N = int(input_data[0])\n    M = int(input_data[1])\n    \n    A = [int(x) for x in input_data[2:2+N]]\n    B = [int(x) for x in input_data[2+N:2+N+M]]\n    \n    pos = defaultdict(list)\n    for i, a in enumerate(A):\n        pos[a].append(i)\n        \n    L = []\n    cur = -1\n    for b in B:\n        lst = pos[b]\n        idx = bisect_right(lst, cur)\n        if idx == len(lst):\n            print(\"No\")\n            return\n        cur = lst[idx]\n        L.append(cur)\n        \n    R = []\n    cur = N\n    for b in reversed(B):\n        lst = pos[b]\n        idx = bisect_left(lst, cur) - 1\n        if idx < 0:\n            print(\"No\")\n            return\n        cur = lst[idx]\n        R.append(cur)\n    R.reverse()\n    \n    if L != R:\n        print(\"Yes\")\n    else:\n        print(\"No\")\n\nif __name__ == '__main__':\n    main()", "cost_usd": 0.007371000000000001, "tokens_in": 718, "tokens_out": 1822, "latency_s": 9.015}, {"task_id": "lcb-arc195_a", "model": "deepseek/deepseek-v4-pro", "prompt": "There is a sequence A = (A_1,\\dots,A_N). Determine whether there are at least two subsequences of A that match the sequence B = (B_1,\\dots,B_M). Two subsequences are distinguished if they are taken from different positions, even if they coincide as sequences.\n\nSubsequence\nA subsequence of A is a sequence obtained by removing zero or more elements from A and leaving the remaining elements in their original order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nA_1 A_2 \\ldots A_N\nB_1 B_2 \\ldots B_M\n\nOutput\n\nIf there are at least two subsequences of A that match B, print Yes. Otherwise, print No.\n\nConstraints\n\n\n- 1 \\leq M \\leq N \\leq 2\\times 10^5\n- 1 \\leq A_i \\leq 10^9\n- 1 \\leq B_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n4 2\n1 2 1 2\n1 2\n\nSample Output 1\n\nYes\n\nThere are three subsequences of A that match B: (A_1,A_2), (A_1,A_4), (A_3,A_4).\n\nSample Input 2\n\n3 2\n1 2 1\n1 2\n\nSample Output 2\n\nNo\n\nThere is only one subsequence of A that matches B: (A_1,A_2).\n\nSample Input 3\n\n3 2\n1 1 2\n2 1\n\nSample Output 3\n\nNo\n\nThere are no subsequences of A that match B.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nWhen enumerating partitions into UNLABELED groups, generate each partition once: process items in order and place the next item into each existing group or one new group. Do not recursively choose arbitrary subsets as blocks \u2014 permuting block order repeats the same partition and can turn a feasible search into a timeout. Start from the first item, update aggregate values incrementally, put final values straight into a set, and skip existing groups with equal state: those branches are symmetric.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "", "cost_usd": 0.010850691794, "tokens_in": 773, "tokens_out": 8192, "latency_s": 94.232}, {"task_id": "lcb-arc195_a", "model": "z-ai/glm-5.2", "prompt": "There is a sequence A = (A_1,\\dots,A_N). Determine whether there are at least two subsequences of A that match the sequence B = (B_1,\\dots,B_M). Two subsequences are distinguished if they are taken from different positions, even if they coincide as sequences.\n\nSubsequence\nA subsequence of A is a sequence obtained by removing zero or more elements from A and leaving the remaining elements in their original order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nA_1 A_2 \\ldots A_N\nB_1 B_2 \\ldots B_M\n\nOutput\n\nIf there are at least two subsequences of A that match B, print Yes. Otherwise, print No.\n\nConstraints\n\n\n- 1 \\leq M \\leq N \\leq 2\\times 10^5\n- 1 \\leq A_i \\leq 10^9\n- 1 \\leq B_i \\leq 10^9\n- All input values are integers.\n\nSample Input 1\n\n4 2\n1 2 1 2\n1 2\n\nSample Output 1\n\nYes\n\nThere are three subsequences of A that match B: (A_1,A_2), (A_1,A_4), (A_3,A_4).\n\nSample Input 2\n\n3 2\n1 2 1\n1 2\n\nSample Output 2\n\nNo\n\nThere is only one subsequence of A that matches B: (A_1,A_2).\n\nSample Input 3\n\n3 2\n1 1 2\n2 1\n\nSample Output 3\n\nNo\n\nThere are no subsequences of A that match B.\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nWhen enumerating partitions into UNLABELED groups, generate each partition once: process items in order and place the next item into each existing group or one new group. Do not recursively choose arbitrary subsets as blocks \u2014 permuting block order repeats the same partition and can turn a feasible search into a timeout. Start from the first item, update aggregate values incrementally, put final values straight into a set, and skip existing groups with equal state: those branches are symmetric.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "```python\nimport sys\n\ndef main():\n    data = sys.stdin.buffer.read().split()\n    if not data:\n        return\n    N = int(data[0])\n    M = int(data[1])\n    A = list(map(int, data[2:2+N]))\n    B = list(map(int, data[2+N:2+N+M]))\n\n    left = []\n    idx = 0\n    for b in B:\n        while idx < N and A[idx] != b:\n            idx += 1\n        if idx == N:\n            left = None\n            break\n        left.append(idx)\n        idx += 1\n\n    if left is None:\n        sys.stdout.write(\"No\")\n        return\n\n    right = []\n    idx = N - 1\n    for b in reversed(B):\n        while idx >= 0 and A[idx] != b:\n            idx -= 1\n        if idx < 0:\n            right = None\n            break\n        right.append(idx)\n        idx -= 1\n\n    if right is None:\n        sys.stdout.write(\"No\")\n        return\n\n    right.reverse()\n\n    out = \"Yes\" if left != right else \"No\"\n    sys.stdout.write(out)\n\nif __name__ == \"__main__\":\n    main()\n```", "cost_usd": 0.0259524, "tokens_in": 708, "tokens_out": 5673, "latency_s": 23.294}]