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+ [{"task_id": "mmlu-2027", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] Temperature variation is a/an\nA) Digital quantity\nB) Analog quantity\nC) Either Digital or Analog quantity\nD) None\n\nAnswer with the letter only.\n\nThink step by step about each option, then end with exactly: ANSWER: <letter>", "response": "ANSWER: B", "cost_usd": 4.95e-05, "tokens_in": 63, "tokens_out": 72, "latency_s": 4.187}, {"task_id": "mmlu-3395", "model": "openai/gpt-5.6-luna", "prompt": "[MMLU] This question refers to the following information.\nThe following quote is from Voltaire in response to the 1755 Lisbon earthquake.\nMy dear sir, nature is very cruel. One would find it hard to imagine how the laws of movement cause such frightful disasters in the best of possible worlds. A hundred thousand ants, our fellows, crushed all at once in our ant-hill, and half of them perishing, no doubt in unspeakable agony, beneath the wreckage from which they cannot be drawn. Families ruined all over Europe, the fortune of a hundred businessmen, your compatriots, swallowed up in the ruins of Lisbon. What a wretched gamble is the game of human life! What will the preachers say, especially if the palace of the Inquisition is still standing? I flatter myself that at least the reverend father inquisitors have been crushed like others. That ought to teach men not to persecute each other, for while a few holy scoundrels burn a few fanatics, the earth swallows up one and all.\n\u2014Voltaire, in a letter, 1755\nVoltaire is best known for supporting which of the following demands of the Enlightenment philosophes?\nA) Deism should be adopted by all as the only logical religion.\nB) Religious toleration leads to the destruction of social unity.\nC) Skepticism is not a reliable way of examining information.\nD) Religious toleration should be given to all people of all religions.\n\nAnswer with the letter only.\n\nThink step by step about each option, then end with exactly: ANSWER: <letter>", "response": "ANSWER: D", "cost_usd": 8.62e-05, "tokens_in": 334, "tokens_out": 88, "latency_s": 2.894}, {"task_id": "gsm8k-172", "model": "openai/gpt-5.6-luna", "prompt": "There are four birds at the Caboose. Sally Two is three years older than Granny Red. Granny Red is two times as old as Sally Four. If Sally Four is the same age as Sally Thirtytwo, and Sally Thirtytwo is 8 years old, what's the total age of the four birds?\n\nReason step by step, then give the final answer as a single number.\n\nReason step by step, then end with the final answer as a single number.\n\n(ref 426811)", "response": "Sally Thirtytwo is 8 years old.\n\nSally Four is the same age: 8 years old.\n\nGranny Red is twice Sally Four\u2019s age: 2 \u00d7 8 = 16 years old.\n\nSally Two is 3 years older than Granny Red: 16 + 3 = 19 years old.\n\nTotal age: 19 + 16 + 8 + 8 = 51.\n\n51", "cost_usd": 0.00011289999999999998, "tokens_in": 103, "tokens_out": 171, "latency_s": 3.325}, {"task_id": "gsm8k-579", "model": "openai/gpt-5.6-luna", "prompt": "A boy has 5 cards. His brother has 3 fewer cards than he has. How many cards do they have together?\n\nReason step by step, then give the final answer as a single number.\n\nReason step by step, then end with the final answer as a single number.\n\n(ref 882896)", "response": "The boy has 5 cards. \nHis brother has \\(5 - 3 = 2\\) cards. \nTogether, they have \\(5 + 2 = 7\\) cards.\n\n7", "cost_usd": 6.559999999999997e-05, "tokens_in": 68, "tokens_out": 98, "latency_s": 2.412}, {"task_id": "lcb-abc392_b", "model": "openai/gpt-5.6-luna", "prompt": "You are given a sequence of M integers A = (A_1, A_2, \\dots, A_M).\nEach element of A is an integer between 1 and N, inclusive, and all elements are distinct.\nList all integers between 1 and N that do not appear in A in ascending order.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nA_1 A_2 \\dots A_M\n\nOutput\n\nLet (X_1, X_2, \\dots, X_C) be the sequence of all integers between 1 and N, inclusive, that do not appear in A, listed in ascending order.\nThe output should be in the following format:\nC\nX_1 X_2 \\dots X_C\n\nConstraints\n\n\n- All input values are integers.\n- 1 \\le M \\le N \\le 1000\n- 1 \\le A_i \\le N\n- The elements of A are distinct.\n\nSample Input 1\n\n10 3\n3 9 2\n\nSample Output 1\n\n7\n1 4 5 6 7 8 10\n\nHere, A=(3,9,2).\nThe integers between 1 and 10 that do not appear in A, listed in ascending order, are 1,4,5,6,7,8,10.\n\nSample Input 2\n\n6 6\n1 3 5 2 4 6\n\nSample Output 2\n\n0\n\n\nNo integer between 1 and 6 is missing from A.\nIn this case, print 0 on the first line and leave the second line empty.\n\nSample Input 3\n\n9 1\n9\n\nSample Output 3\n\n8\n1 2 3 4 5 6 7 8\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "import sys\n\ndata = sys.stdin.buffer.read().split()\nn = int(data[0])\nm = int(data[1])\nseen = [False] * (n + 1)\n\nfor i in range(m):\n seen[int(data[2 + i])] = True\n\nmissing = [str(i) for i in range(1, n + 1) if not seen[i]]\nout = [str(len(missing)), \" \".join(missing)]\nsys.stdout.write(\"\\n\".join(out) + \"\\n\")", "cost_usd": 0.0001935, "tokens_in": 615, "tokens_out": 220, "latency_s": 2.95}, {"task_id": "lcb-arc191_a", "model": "openai/gpt-5.6-luna", "prompt": "You are given a string S of length N and a string T of length M, both consisting of digits from 1 to 9.\nYou will perform the following operation for k=1,2,\\ldots,M in order:\n\n- Choose an integer i such that 1 \\le i \\le N. Then, replace the i-th character of S with the k-th character of T.\n\nFind the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nInput\n\nThe input is given from Standard Input in the following format:\nN M\nS\nT\n\nOutput\n\nPrint the maximum possible value of the resulting string S interpreted as an integer after performing the M operations.\n\nConstraints\n\n\n- 1 \\le N,M \\le 10^6\n- N and M are integers.\n- S is a string of length N consisting of digits from 1 through 9.\n- T is a string of length M consisting of digits from 1 through 9.\n\nSample Input 1\n\n3 3\n191\n325\n\nSample Output 1\n\n593\n\nThe following sequence of operations is optimal:\n\n- For k=1: Choose i=3. Then, S = 193.\n- For k=2: Choose i=1. Then, S = 293.\n- For k=3: Choose i=1. Then, S = 593.\n\nIn this case, the value of S interpreted as an integer is 593, which is the maximum.\n\nSample Input 2\n\n3 9\n191\n998244353\n\nSample Output 2\n\n993\n\nSample Input 3\n\n11 13\n31415926535\n2718281828459\n\nSample Output 3\n\n98888976555\n\nWrite a complete Python 3 program that reads from standard input and writes the answer to standard output. Output ONLY the program source, no prose and no code fences.\n\nSolve this competitive-programming problem in Python 3. Read all of stdin at once with sys.stdin.buffer.read().split() and index across tokens; build output in a list and emit it with one write at the end. Check the constraint block and pick an algorithm whose running time stays under ~1e8 steps at the largest allowed input. Return ONLY raw complete Python 3 source \u2014 no Markdown fences, no prose, no comments.\n\nOUTPUT FORMAT: this judge compares printed output EXACTLY, token for token, even when the statement promises a numeric tolerance, and the hidden tests may not use the same precision as the statement's worked examples. Apply BOTH: (1) if an input exactly matches one of the statement's worked examples, print that example's expected output byte-for-byte exactly as the statement shows it; (2) for every other input print floats at a fixed width with format(x, '.12f'). Never pin an input that is not a worked example; compute those normally.", "response": "import sys\n\ndata = sys.stdin.buffer.read().split()\nn = int(data[0])\nm = int(data[1])\ns = data[2].decode()\nt = data[3].decode()\n\ncnt = [0] * 10\nfor c in t[:-1]:\n cnt[ord(c) - 48] += 1\n\nregular_max = 9\nwhile regular_max > 0 and cnt[regular_max] == 0:\n regular_max -= 1\n\nmandatory = ord(t[-1]) - 48\nused_mandatory = False\nans = []\n\nfor i, ch in enumerate(s):\n x = ord(ch) - 48\n last = i == n - 1\n\n if last and not used_mandatory:\n ans.append(chr(48 + mandatory))\n used_mandatory = True\n continue\n\n if used_mandatory:\n if regular_max > x:\n ans.append(chr(48 + regular_max))\n cnt[regular_max] -= 1\n while regular_max > 0 and cnt[regular_max] == 0:\n regular_max -= 1\n else:\n ans.append(ch)\n continue\n\n if mandatory > x and mandatory >= regular_max:\n ans.append(chr(48 + mandatory))\n used_mandatory = True\n elif regular_max > x and regular_max >= mandatory:\n ans.append(chr(48 + regular_max))\n cnt[regular_max] -= 1\n while regular_max > 0 and cnt[regular_max] == 0:\n regular_max -= 1\n else:\n ans.append(ch)\n\nsys.stdout.write(''.join(ans))", "cost_usd": 0.0015806000000000001, "tokens_in": 596, "tokens_out": 2535, "latency_s": 26.874}]