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| package Reptile_package; | |
| //捕获分组1 | |
| public class Reptile_demo6 { | |
| public static void main(String[] args) { | |
| //需求1:判断一个字符串的开始字符和结束字符是否一致?只考虑一个字符 | |
| //举例: a123a b456b 17891 &abc& a123b(false) | |
| // \\组号:表示把第x组的内容再拿出来用一次 | |
| String regex1 = "(.).+\\1"; | |
| System.out.println("a123a".matches(regex1)); | |
| System.out.println("b456b".matches(regex1)); | |
| System.out.println("17891".matches(regex1)); | |
| System.out.println("&abc&".matches(regex1)); | |
| System.out.println("a123b".matches(regex1)); | |
| System.out.println("---------------------"); | |
| //需求2:判断一个字符串的开始部分和结束部分是否一致?可以有多个字符 | |
| //举例: abc123abc 123789123 &!@abc&!@ abc123abd(false) | |
| String regex2 = "(.+).+\\1"; | |
| System.out.println("abc123abc".matches(regex2)); | |
| System.out.println("123789123".matches(regex2)); | |
| System.out.println("&!@abc&!@".matches(regex2)); | |
| System.out.println("abc123abd".matches(regex2)); | |
| System.out.println("---------------------"); | |
| //需求3:判断一个字符串的开始部分和结束部分是否一致?开始部分内部每个字符也需要一致 | |
| //举例:aaa123aaa bbb456bbb 111789111 &&abc&& | |
| //* 0次或多次 | |
| // (.):把首字母看做一组 | |
| // \\2:把首字母拿出来再次使用 | |
| // *:作用于\\2,表示后面重复的内容出现0次或多次 | |
| String regex3 = "((.)\\2*).+\\1"; | |
| System.out.println("aaa123aaa".matches(regex3)); | |
| System.out.println("bbb456bbb".matches(regex3)); | |
| System.out.println("111789111".matches(regex3)); | |
| System.out.println("&&abc&&".matches(regex3)); | |
| } | |
| } | |