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Add CodeWalk verus-proof-completion benchmark
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use vstd::prelude::*;
fn main() {}
verus!{
fn f1_reverse_to_k(list: &Vec<i32>, n: usize) -> (reversed_list: Vec<i32>)
requires
list@.len() > 0,
0 < n < list@.len(),
{
let mut reversed_list = Vec::new();
let mut index = 0;
while index < n
{
reversed_list.push(list[n - 1 - index]);
index += 1;
}
index = n;
while index < list.len()
{
reversed_list.push(list[index]);
index += 1;
}
reversed_list
}
fn f2_find_negative_numbers(arr: &Vec<i32>) -> (negative_list: Vec<i32>)
{
let mut negative_list: Vec<i32> = Vec::new();
let input_len = arr.len();
let mut index = 0;
while index < arr.len()
{
if (arr[index] < 0) {
negative_list.push(arr[index]);
}
index += 1;
}
negative_list
}
pub open spec fn count_frequency_rcr(seq: Seq<i32>, key: i32) -> int
decreases seq.len(),
{
if seq.len() == 0 {
0
} else {
count_frequency_rcr(seq.drop_last(), key) + if (seq.last() == key) {
1 as int
} else {
0 as int
}
}
}
fn f3_count_frequency(arr: &Vec<i32>, key: i32) -> (frequency: usize)
{
let mut index = 0;
let mut counter = 0;
while index < arr.len()
{
if (arr[index] == key) {
counter += 1;
}
index += 1;
}
counter
}
fn f3_remove_duplicates(arr: &Vec<i32>) -> (unique_arr: Vec<i32>)
{
let mut unique_arr: Vec<i32> = Vec::new();
let input_len = arr.len();
let mut index = 0;
while index < arr.len()
{
if f3_count_frequency(&arr, arr[index]) == 1 {
unique_arr.push(arr[index]);
}
index += 1;
}
unique_arr
}
spec fn step1(__hp0: Seq<i32>, __hp1: usize, outp: Seq<i32>) -> bool {
(outp == __hp0.subrange(0, __hp1 as int).reverse().add(
__hp0.subrange(__hp1 as int, __hp0.len() as int),
))
}
spec fn step2(inp: Seq<i32>, outp: Seq<i32>) -> bool {
(outp == inp.filter(|x: i32| x < 0))
}
spec fn step3(inp: Seq<i32>, p3_key: i32, outp: usize) -> bool {
(count_frequency_rcr(inp, p3_key) == outp)
}
fn chain_driver(list: &Vec<i32>, n: usize, p3_key: i32) -> (r_final: usize)
requires
list@.len() > 0,
0 < n < list@.len(),
ensures
exists|v1: Seq<i32>, v2: Seq<i32>| #[trigger] step1(list@, n, v1) && #[trigger] step2(v1, v2) && step3(v2, p3_key, r_final),
{
let x1 = f1_reverse_to_k(list, n);
let x2 = f2_find_negative_numbers(&x1);
let x3 = f3_count_frequency(&x2, p3_key);
proof {
assert(step1(list@, n, x1@));
assert(step2(x1@, x2@));
assert(step3(x2@, p3_key, x3));
}
x3
}
} // verus!