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openai/math challenge AlgorithmicThinTrees (family 174)
Prove the following result from OpenAI's openai/math release in Lean 4, with a proof the Lean kernel accepts.
Context: this statement belongs to family 174 of the release, Deterministic construction of strong thin spanning trees (Combinatorics). The family as a whole: Resolves the strong thin-tree conjecture constructively. Every finite loopless $k$-edge-connected multigraph on at least two vertices has a spanning tree containing at most a universal $C/k$ fraction of the edges of every cut. Such a tree can be found deterministically in polynomial time, even with binary-encoded parallel-edge multiplicities.
The challenge is AlgorithmicThinTrees, also at /opt/openai-math/challenges/AlgorithmicThinTrees.lean:
import Mathlib
namespace OAI
/-! Deterministic polynomial-time construction of strong thin trees. -/
namespace StrongThinTree
structure MultiGraph (n m : ℕ) where
left : Fin m → Fin n
right : Fin m → Fin n
loopless : ∀ e, left e ≠ right e
namespace MultiGraph
def cut {n m : ℕ} (G : MultiGraph n m) (T : Finset (Fin m))
(S : Finset (Fin n)) : Finset (Fin m) :=
T.filter fun e => (G.left e ∈ S ∧ G.right e ∉ S) ∨
(G.right e ∈ S ∧ G.left e ∉ S)
def Connected {n m : ℕ} (G : MultiGraph n m) (T : Finset (Fin m)) : Prop :=
∀ S : Finset (Fin n), S.Nonempty → S ≠ Finset.univ → (G.cut T S).Nonempty
def SpanningTree {n m : ℕ} (G : MultiGraph n m) (T : Finset (Fin m)) : Prop :=
G.Connected T ∧ ∀ e ∈ T, ¬ G.Connected (T.erase e)
def EdgeConnected {n m : ℕ} (G : MultiGraph n m) (k : ℕ) : Prop :=
∀ S : Finset (Fin n), S.Nonempty → S ≠ Finset.univ →
k ≤ (G.cut Finset.univ S).card
end MultiGraph
end StrongThinTree
namespace CurrentKS
def frame : List Bool → List Bool
| [] => [true]
| b :: bs => false :: b :: frame bs
def encodeNat (n : ℕ) : List Bool := frame (Computability.encodeNat n)
inductive StackAction where
| stay
| pop
| push (bit : Bool)
deriving DecidableEq
def StackAction.apply : StackAction → List Bool → List Bool
| .stay, xs => xs
| .pop, xs => xs.tail
| .push b, xs => b :: xs
structure Instruction (k q : ℕ) where
next : Option (Fin q)
actions : Fin k → StackAction
def Instruction.halt (k q : ℕ) : Instruction k q := ⟨none, fun _ => .stay⟩
structure Machine where
stackCount : ℕ
states : ℕ
initial : Fin states
inputStack : Fin stackCount
outputStack : Fin stackCount
table : List (Instruction stackCount states)
structure Config (k q : ℕ) where
state : Option (Fin q)
«stacks» : Fin k → List Bool
def topCode : List Bool → ℕ
| [] => 0
| false :: _ => 1
| true :: _ => 2
def headsCode : (k : ℕ) → (Fin k → List Bool) → ℕ
| 0, _ => 0
| k + 1, s => topCode (s 0) + 3 * headsCode k (fun j => s j.succ)
def Machine.step (M : Machine) (c : Config M.stackCount M.states) :
Config M.stackCount M.states :=
match c.state with
| none => c
| some q =>
let instruction := M.table.getD
(3 ^ M.stackCount * q.val + headsCode M.stackCount c.stacks)
(Instruction.halt M.stackCount M.states)
⟨instruction.next, fun j => (instruction.actions j).apply (c.stacks j)⟩
def Machine.init (M : Machine) (input : List Bool) : Config M.stackCount M.states :=
⟨some M.initial, fun j => if j = M.inputStack then input else []⟩
def Machine.run (M : Machine) (input : List Bool) (fuel : ℕ) :
Config M.stackCount M.states := (M.step^[fuel]) (M.init input)
end CurrentKS
namespace AlgorithmicThinTrees
open StrongThinTree
structure ExplicitInput where
n : ℕ
m : ℕ
k : ℕ
graph : MultiGraph n m
structure BinaryInput where
n : ℕ
p : ℕ
k : ℕ
left : Fin p → Fin n
right : Fin p → Fin n
ordered : ∀ i, left i < right i
distinct : Function.Injective (fun i => (left i, right i))
multiplicity : Fin p → ℕ
abbrev BinaryInput.Edge (x : BinaryInput) := Σ i : Fin x.p, Fin (x.multiplicity i)
noncomputable def BinaryInput.edgeEquiv (x : BinaryInput) :
x.Edge ≃ Fin (Fintype.card x.Edge) := Fintype.equivFin x.Edge
noncomputable def BinaryInput.graph (x : BinaryInput) :
MultiGraph x.n (Fintype.card x.Edge) where
left e := x.left (x.edgeEquiv.symm e).1
right e := x.right (x.edgeEquiv.symm e).1
loopless e := ne_of_lt (x.ordered (x.edgeEquiv.symm e).1)
inductive Input where
| explicit (x : ExplicitInput)
| binary (x : BinaryInput)
def ExplicitInput.encode (x : ExplicitInput) : List Bool :=
CurrentKS.encodeNat x.n ++ CurrentKS.encodeNat x.m ++ CurrentKS.encodeNat x.k ++
(List.ofFn fun i : Fin x.m =>
CurrentKS.encodeNat (x.graph.left i).val ++
CurrentKS.encodeNat (x.graph.right i).val).flatten
def BinaryInput.encode (x : BinaryInput) : List Bool :=
CurrentKS.encodeNat x.n ++ CurrentKS.encodeNat x.p ++ CurrentKS.encodeNat x.k ++
(List.ofFn fun i : Fin x.p =>
CurrentKS.encodeNat (x.left i).val ++ CurrentKS.encodeNat (x.right i).val ++
CurrentKS.encodeNat (x.multiplicity i)).flatten
def Input.encode : Input → List Bool
| .explicit x => false :: x.encode
| .binary x => true :: x.encode
def Input.length (x : Input) : ℕ := x.encode.length
def Input.n : Input → ℕ
| .explicit x => x.n
| .binary x => x.n
def Valid : Input → Prop
| .explicit x => 1 ≤ x.n ∧ 1 ≤ x.k ∧ x.graph.EdgeConnected x.k
| .binary x => 1 ≤ x.n ∧ 1 ≤ x.k ∧ x.graph.EdgeConnected x.k
def ThinTree {n m : ℕ} (C : ℝ) (k : ℕ) (G : MultiGraph n m)
(T : Finset (Fin m)) : Prop :=
G.SpanningTree T ∧ ∀ S : Finset (Fin n), S.Nonempty → S ≠ Finset.univ →
((G.cut T S).card : ℝ) ≤ C / (k : ℝ) * (G.cut Finset.univ S).card
def ExplicitInput.encodeEdges (x : ExplicitInput) (edges : List (Fin x.m)) : List Bool :=
edges.flatMap (fun e => CurrentKS.encodeNat e.val)
def BinaryInput.encodeEdges (x : BinaryInput) (edges : List x.Edge) : List Bool :=
edges.flatMap (fun e => CurrentKS.encodeNat e.1.val ++ CurrentKS.encodeNat e.2.val)
noncomputable def BinaryInput.selected (x : BinaryInput) (edges : List x.Edge) :
Finset (Fin (Fintype.card x.Edge)) := edges.toFinset.map x.edgeEquiv.toEmbedding
def TreeOutput (C : ℝ) : Input → List Bool → Prop
| .explicit x, bits => ∃ edges : List (Fin x.m), edges.Nodup ∧
bits = x.encodeEdges edges ∧ ThinTree C x.k x.graph edges.toFinset
| .binary x, bits => ∃ edges : List x.Edge, edges.Nodup ∧
bits = x.encodeEdges edges ∧ ThinTree C x.k x.graph (x.selected edges)
def GoodOutput (C : ℝ) (x : Input) (bits : List Bool) : Prop :=
TreeOutput C x bits ∧ (x.n = 1 → bits = [])
def AlgorithmicStrongThinTrees : Prop :=
∃ C : ℝ, 0 < C ∧ ∃ M : CurrentKS.Machine, ∃ a degree : ℕ, 0 < a ∧
∀ x : Input, Valid x →
let result := M.run x.encode (a * (x.length + 1) ^ degree)
result.state = none ∧ GoodOutput C x (result.stacks M.outputStack)
end AlgorithmicThinTrees
namespace AlgorithmicThinTrees
theorem algorithmic_strong_thin_trees : AlgorithmicStrongThinTrees := by
sorry
end AlgorithmicThinTrees
end OAI
What to submit
Write /workspace/Submission.lean. Start from a copy of the challenge:
cp /opt/openai-math/challenges/AlgorithmicThinTrees.lean /workspace/Submission.lean
then replace every sorry with a proof. The file is graded on three things:
- Same statements. The theorem
OAI.AlgorithmicThinTrees.algorithmic_strong_thin_treesmust keep exactly the statement shown above: same names, namespaces, binders and types. Every definition the statements use must stay exactly as written. Change nothing except the proofs. - Standard axioms only. Proofs may use only
propext,Quot.soundandClassical.choice.sorry,admit, newaxioms andnative_decide(it introduces an axiom of its own) are rejected. - Keep the challenge's declarations as they are. Put new lemmas and instances after the
definitions the statements use, or in a separate
Submission/*.leanmodule. A declaration added before them can change how they elaborate, and then they no longer match the challenge. - Kernel-checked. The proofs are re-checked by the Lean kernel, not just the elaborator.
Long proofs can be split into modules under /workspace/Submission/ (module names
Submission.Foo, Submission.Foo.Bar) imported from Submission.lean. Only .lean files at
those two paths are graded.
Environment
- Lean
v4.34.1and Mathlib at commitd13f23bare installed and prebuilt;/workspaceis a Lake project. - The sandbox has 4 CPUs and 8 GB of memory;
LEAN_NUM_THREADS=3keepslake buildto three parallel jobs. Check your work withcd /workspace && lake build Submission. Add#print axioms <name>to see which axioms a proof uses. - There is no internet access. OpenAI's own proofs are not installed.
Grading
When you finish, Submission.lean and Submission/**.lean are copied to a fresh machine and
checked with Comparator, the Lean FRO's proof checker.
The reward is 1 if Comparator accepts the proof and 0 otherwise. A partial proof scores 0.