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\int \left(1\right) dt = t + C
\frac{46}{16} = \frac{23}{8}
\frac{-50}{35} = \frac{-10}{7}
6 - 7 z + z^2 = 0 \implies z \in \{ 1, 6 \}
-240 - 38 a + 7 a^2 + a^3 = 0 \implies a \in \{ -8, -5, 6 \}
\int \left(1\right) db = b + C
\log_{5}\left(4 + 3 w\right) = 2 \implies w = 7
\lim_{y \to -3} \left(2 y\right) = -6
\log_{4}\left(5 + 4 u\right) = 3 \implies u = \frac{59}{4}
-2 + a = 0 \implies a = 2
\log_{5}\left(3 + 3 z\right) = 3 \implies z = \frac{122}{3}
\frac{21}{42} = \frac{1}{2}
f(z) = 3 + 5 z + z^2, \quad g(v) = 4 + 2 v \implies f(g(v)) = 39 + 26 v + 4 v^2
-32 \cdot 30 = -960
19 \cdot 43 = 817
-4 + z = 0 \implies z = 4
(4, 1, -4) \times (2, 2, 5) = (13, -28, 6)
\lim_{b \to 4} \left(b^3\right) = 64
\frac{d}{dz}\left(z^2\right) = 2 z
\lim_{z \to -1} \left(z^2\right) = 1
-38 - 9 = -47
(2, -2, -5) \times (4, -3, 3) = (-21, -26, 2)
\left(b - v\right) \cos{\left(b\right)} = b \cos{\left(b\right)} - v \cos{\left(b\right)}
\log_{4}\left(7 + 4 w\right) = 2 \implies w = \frac{9}{4}
-15 + 2 x + x^2 = 0 \implies x \in \{ -5, 3 \}
\frac{-46}{13} = \frac{-46}{13}
-48 + 2 u + 9 u^2 + u^3 = 0 \implies u \in \{ -8, -3, 2 \}
\log_{3}\left(4 + w\right) = 2 \implies w = 5
(2, 5, -2) \times (0, -3, 3) = (9, -6, -6)
24 + 26 = 50
f(t) = 2 + 5 t + t^2, \quad g(u) = 3 + 2 u \implies f(g(u)) = 26 + 22 u + 4 u^2
\frac{d}{db}\left(b^2\right) = 2 b
-6 t + 5 t^2 + t^3 = 0 \implies t \in \{ -6, 0, 1 \}
f(b) = 5 + 4 b + b^2, \quad g(z) = 2 + z \implies f(g(z)) = 17 + 8 z + z^2
-25 + x^2 = 0 \implies x \in \{ -5, 5 \}
4 + x = 0 \implies x = -4
\left(c + z\right) \sin{\left(c\right)} = c \sin{\left(c\right)} + z \sin{\left(c\right)}
7 + y = 0 \implies y = -7
43 \cdot 7 = 301
f(t) = 5 + 5 t + t^2, \quad g(w) = 1 + 2 w \implies f(g(w)) = 11 + 14 w + 4 w^2
f(z) = 5 + z + z^2, \quad g(a) = 2 + 2 a \implies f(g(a)) = 11 + 10 a + 4 a^2
\lim_{w \to 4} \left(w\right) = 4
\frac{-3}{47} = \frac{-3}{47}
\log_{2}\left(8 + 3 a\right) = 3 \implies a = 0
\left(b - z\right) z = b z - z^2
42 + 13 u + u^2 = 0 \implies u \in \{ -7, -6 \}
20 \cdot 46 = 920
f(c) = 4 + c + c^2, \quad g(z) = 3 + 3 z \implies f(g(z)) = 16 + 21 z + 9 z^2
-3 + t = 0 \implies t = 3
\frac{-26}{15} = \frac{-26}{15}
6 + a = 0 \implies a = -6
-60 + 47 v - 12 v^2 + v^3 = 0 \implies v \in \{ 3, 4, 5 \}
f(a) = 4 + a + a^2, \quad g(w) = 3 + 3 w \implies f(g(w)) = 16 + 21 w + 9 w^2
\frac{d}{dy}\left(10 + y - y^3\right) = 1 - 3 y^2
\left(t + z\right) \sin{\left(t\right)} = t \sin{\left(t\right)} + z \sin{\left(t\right)}
\log_{4}\left(3 + 4 x\right) = 2 \implies x = \frac{13}{4}
-7 - b + 7 b^2 + b^3 = 0 \implies b \in \{ -7, -1, 1 \}
4 \cdot 44 = 176
2 + a = 0 \implies a = -2
f(w) = 5 + w + w^2, \quad g(b) = 1 + 3 b \implies f(g(b)) = 7 + 9 b + 9 b^2
\frac{d}{da}\left(a\right) = 1
\left(-v + y\right) \left(8 - v\right) = -8 v + 8 y - v y + v^2
-36 + 47 = 11
f(b) = 4 + 4 b + b^2, \quad g(w) = 4 + w \implies f(g(w)) = 36 + 12 w + w^2
\log_{5}\left(6 + u\right) = 3 \implies u = 119
-8 \left(2 + b\right) = -16 - 8 b
6 t + t^2 = 0 \implies t \in \{ -6, 0 \}
\frac{d}{dz}\left(\cos{\left(z\right)}\right) = -\sin{\left(z\right)}
-9 + u^2 = 0 \implies u \in \{ -3, 3 \}
18 + 9 v + v^2 = 0 \implies v \in \{ -6, -3 \}
\lim_{u \to 5} \left(u^2\right) = 25
(-3, 3, -4) \times (-4, 1, 5) = (19, 31, 9)
-2 + c = 0 \implies c = 2
\frac{32}{13} = \frac{32}{13}
\left(c - v\right) c v = -c v^2 + c^2 v
f(y) = 5 + y + y^2, \quad g(x) = 3 + x \implies f(g(x)) = 17 + 7 x + x^2
\log_{3}\left(2 + 4 c\right) = 3 \implies c = \frac{25}{4}
5 + u = 0 \implies u = -5
f(a) = 5 + 4 a + a^2, \quad g(t) = 4 + 2 t \implies f(g(t)) = 37 + 24 t + 4 t^2
\lim_{b \to -5} \left(\sin{\left(b\right)}\right) = -\sin{\left(5\right)}
\lim_{y \to -4} \left(2 y\right) = -8
3 + v = 0 \implies v = -3
7 + y = 0 \implies y = -7
-5 - 4 x + x^2 = 0 \implies x \in \{ -1, 5 \}
\log_{3}\left(1 + y\right) = 3 \implies y = 26
f(z) = 2 + z + z^2, \quad g(a) = 3 + a \implies f(g(a)) = 14 + 7 a + a^2
6 + t = 0 \implies t = -6
\int \left(2 v\right) dv = v^2 + C
\int \left(3\right) db = 3 b + C
\lim_{a \to 1} \left(a\right) = 1
16 + 10 t + t^2 = 0 \implies t \in \{ -8, -2 \}
1 + x = 0 \implies x = -1
\lim_{c \to 4} \left(c^3\right) = 64
1 - 27 = -26
\log_{4}\left(2 + 4 w\right) = 3 \implies w = \frac{31}{2}
-36 \cdot 19 = -684
-30 + 28 = -2
\lim_{z \to -5} \left(-7 z\right) = 35
\int \left(-2\right) dt = -2 t + C
-1 - 31 = -32