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\frac{d}{dt}\left(0\right) = 0
-7 + z = 0 \implies z = 7
f(v) = 3 + v + v^2, \quad g(t) = 3 + 2 t \implies f(g(t)) = 15 + 14 t + 4 t^2
f(w) = 4 + 4 w + w^2, \quad g(a) = 4 + a \implies f(g(a)) = 36 + 12 a + a^2
f(z) = 2 + 3 z + z^2, \quad g(a) = 3 + a \implies f(g(a)) = 20 + 9 a + a^2
35 - 40 = -5
\log_{2}\left(5 + 2 b\right) = 1 \implies b = \frac{-3}{2}
20 + 37 = 57
\frac{40}{30} = \frac{4}{3}
\log_{5}\left(7 + 2 b\right) = 3 \implies b = 59
\frac{1}{35} = \frac{1}{35}
-210 - 37 w + 6 w^2 + w^3 = 0 \implies w \in \{ -7, -5, 6 \}
-18 + 32 = 14
f(c) = 4 + 3 c + c^2, \quad g(b) = 1 + b \implies f(g(b)) = 8 + 5 b + b^2
-39 - 29 = -68
(-3, 3, -2) \times (3, -1, -1) = (-5, -9, -6)
8 \cdot 38 = 304
-28 \cdot 27 = -756
35 - 12 x + x^2 = 0 \implies x \in \{ 5, 7 \}
\frac{d}{du}\left(u^2\right) = 2 u
\int \left(-1 + \cos{\left(x\right)}\right) dx = -x + \sin{\left(x\right)} + C
\int \left(4 t^3\right) dt = t^4 + C
2 + a = 0 \implies a = -2
\int \left(-\sin{\left(w\right)}\right) dw = -1 + \cos{\left(w\right)} + C
\lim_{x \to -3} \left(x^2\right) = 9
-34 \cdot 37 = -1258
\log_{4}\left(2 + 3 b\right) = 2 \implies b = \frac{14}{3}
f(b) = 5 + 5 b + b^2, \quad g(x) = 4 + 2 x \implies f(g(x)) = 41 + 26 x + 4 x^2
8 - 9 v + v^2 = 0 \implies v \in \{ 1, 8 \}
-6 + v = 0 \implies v = 6
\frac{d}{dw}\left(\cos{\left(w\right)}\right) = -\sin{\left(w\right)}
-7 - 6 x + x^2 = 0 \implies x \in \{ -1, 7 \}
\int \left(2 v\right) dv = v^2 + C
\sin{\left(x\right)} \left(7 + z\right) = z \sin{\left(x\right)} + 7 \sin{\left(x\right)}
\log_{5}\left(6 + 3 b\right) = 3 \implies b = \frac{119}{3}
\lim_{c \to 1} \left(2 c\right) = 2
(2, -3, -1) \times (1, 1, -2) = (7, 3, 5)
31 \cdot 2 = 62
(3, 0, 1) \times (-2, 2, 0) = (-2, -2, 6)
-19 \cdot 35 = -665
f(t) = 2 + t + t^2, \quad g(w) = 2 + 2 w \implies f(g(w)) = 8 + 10 w + 4 w^2
\frac{d}{db}\left(2 b\right) = 2
\frac{d}{db}\left(\sin{\left(b\right)}\right) = \cos{\left(b\right)}
15 + 8 w + w^2 = 0 \implies w \in \{ -5, -3 \}
-8 - 7 t + t^2 = 0 \implies t \in \{ -1, 8 \}
(-1, 0, 4) \times (-1, 0, 4) = (0, 0, 0)
\lim_{w \to -4} \left(\sin{\left(w\right)}\right) = -\sin{\left(4\right)}
48 + 46 a + 13 a^2 + a^3 = 0 \implies a \in \{ -8, -3, -2 \}
\frac{-50}{40} = \frac{-5}{4}
50 - 25 x - 2 x^2 + x^3 = 0 \implies x \in \{ -5, 2, 5 \}
-42 - b + b^2 = 0 \implies b \in \{ -6, 7 \}
(-2, -1, 0) \times (-2, -2, 5) = (-5, 10, 2)
280 - 51 w - 6 w^2 + w^3 = 0 \implies w \in \{ -7, 5, 8 \}
f(a) = 3 + 2 a + a^2, \quad g(t) = 3 + 3 t \implies f(g(t)) = 18 + 24 t + 9 t^2
-12 - 8 = -20
f(a) = 3 + 5 a + a^2, \quad g(u) = 1 + u \implies f(g(u)) = 9 + 7 u + u^2
8 + 6 t + t^2 = 0 \implies t \in \{ -4, -2 \}
(1, 0, -1) \times (1, -3, -3) = (-3, 2, -3)
\frac{d}{dx}\left(x \left(9 + x\right)\right) = 9 + 2 x
-3 b + b^2 = 0 \implies b \in \{ 0, 3 \}
f(v) = 3 + v + v^2, \quad g(b) = 3 + b \implies f(g(b)) = 15 + 7 b + b^2
-60 - 28 c + 3 c^2 + c^3 = 0 \implies c \in \{ -6, -2, 5 \}
48 - 41 = 7
\int \left(1\right) dv = v + C
-30 - t + t^2 = 0 \implies t \in \{ -5, 6 \}
\frac{-36}{6} = -6
22 + 45 = 67
x \left(2 + t\right) = 2 x + t x
4 + c = 0 \implies c = -4
f(v) = 1 + 3 v + v^2, \quad g(a) = 3 + a \implies f(g(a)) = 19 + 9 a + a^2
72 - 30 u - u^2 + u^3 = 0 \implies u \in \{ -6, 3, 4 \}
\frac{d}{dc}\left(\cos{\left(c\right)}\right) = -\sin{\left(c\right)}
9 \cdot 9 = 81
\left(2 + a\right) \left(-1 + a\right) = -2 + a + a^2
26 + 10 = 36
\int \left(-1\right) da = -a + C
-6 + z = 0 \implies z = 6
-42 - 20 = -62
\lim_{z \to -1} \left(z\right) = -1
-4 + w = 0 \implies w = 4
\log_{4}\left(4 + 3 u\right) = 3 \implies u = 20
-24 \cdot 11 = -264
12 - 7 t + t^2 = 0 \implies t \in \{ 3, 4 \}
17 + 6 = 23
\log_{5}\left(3 + w\right) = 2 \implies w = 22
-6 + c = 0 \implies c = 6
(-4, 3, 3) \times (3, 2, -2) = (-12, 1, -17)
(3, 1, -5) \times (-1, 3, 5) = (20, -10, 10)
\int \left(1\right) da = a + C
-64 + z^2 = 0 \implies z \in \{ -8, 8 \}
(-2, 5, -4) \times (2, -5, 3) = (-5, -2, 0)
f(u) = 1 + 5 u + u^2, \quad g(v) = 1 + 2 v \implies f(g(v)) = 7 + 14 v + 4 v^2
-14 \cdot 1 = -14
f(y) = 4 + 5 y + y^2, \quad g(c) = 2 + c \implies f(g(c)) = 18 + 9 c + c^2
45 + 13 = 58
\lim_{y \to -4} \left(0\right) = 0
112 - 16 t - 7 t^2 + t^3 = 0 \implies t \in \{ -4, 4, 7 \}
c^4 \left(-10 + c\right) = -10 c^4 + c^5
\log_{2}\left(2 + 3 x\right) = 2 \implies x = \frac{2}{3}
-20 - t + t^2 = 0 \implies t \in \{ -4, 5 \}