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47 + 41 = 88 |
-9 + a^2 = 0 \implies a \in \{ -3, 3 \} |
4 + u = 0 \implies u = -4 |
-10 + 44 = 34 |
\frac{d}{dy}\left(y \left(-10 + y\right)\right) = -10 + 2 y |
-7 + y = 0 \implies y = 7 |
\lim_{z \to 5} \left(z\right) = 5 |
\int \left(2 b \left(10 + b\right) + b^2\right) db = b^2 \left(10 + b\right) + C |
-1 \cdot 32 = -32 |
\log_{2}\left(8 + 3 y\right) = 2 \implies y = \frac{-4}{3} |
\frac{-18}{37} = \frac{-18}{37} |
47 - 15 = 32 |
b = 0 \implies b = 0 |
\log_{3}\left(8 + 4 t\right) = 2 \implies t = \frac{1}{4} |
\frac{d}{dy}\left(5 y^2\right) = 10 y |
-49 + y^2 = 0 \implies y \in \{ -7, 7 \} |
\log_{4}\left(1 + 3 c\right) = 1 \implies c = 1 |
-47 + 39 = -8 |
\frac{d}{da}\left(2 a - a^4\right) = 2 - 4 a^3 |
f(w) = 2 + w + w^2, \quad g(b) = 4 + b \implies f(g(b)) = 22 + 9 b + b^2 |
\frac{d}{dw}\left(0\right) = 0 |
\frac{d}{dy}\left(\sin{\left(y\right)}\right) = \cos{\left(y\right)} |
\int \left(1\right) dt = t + C |
\log_{2}\left(7 + 2 w\right) = 3 \implies w = \frac{1}{2} |
-33 - 38 = -71 |
\frac{d}{du}\left(-3 + 2 u\right) = 2 |
42 - 13 b + b^2 = 0 \implies b \in \{ 6, 7 \} |
\int \left(5\right) da = 5 a + C |
\int \left(3 y^2\right) dy = y^3 + C |
\int \left(6 w^2\right) dw = 2 w^3 + C |
46 - 16 = 30 |
\int \left(-1 + 2 y\right) dy = -y + y^2 + C |
\frac{-1}{21} = \frac{-1}{21} |
-6 t + t^2 = 0 \implies t \in \{ 0, 6 \} |
\left(c + u\right) c^3 = c^3 u + c^4 |
\int \left(2 z\right) dz = z^2 + C |
\left(7 - u\right)^2 = 49 - 14 u + u^2 |
c^4 \left(a + c\right) = a c^4 + c^5 |
40 + 19 = 59 |
(-4, 4, 2) \times (5, -2, 1) = (8, 14, -12) |
-18 + 18 = 0 |
\frac{d}{dt}\left(t^3 \left(5 + t\right)\right) = 3 t^2 \left(5 + t\right) + t^3 |
\int \left(4 u^3 - \sin{\left(u\right)}\right) du = -1 + u^4 + \cos{\left(u\right)} + C |
-24 + 5 z + z^2 = 0 \implies z \in \{ -8, 3 \} |
20 v + 9 v^2 + v^3 = 0 \implies v \in \{ -5, -4, 0 \} |
\log_{4}\left(7 + v\right) = 1 \implies v = -3 |
-18 + 27 b - 10 b^2 + b^3 = 0 \implies b \in \{ 1, 3, 6 \} |
7 + y = 0 \implies y = -7 |
(3, -2, 2) \times (0, 5, -1) = (-8, 3, 15) |
2 + a = 0 \implies a = -2 |
f(c) = 4 + 3 c + c^2, \quad g(t) = 2 + 3 t \implies f(g(t)) = 14 + 21 t + 9 t^2 |
\int \left(1\right) da = a + C |
(-2, 1, 0) \times (-4, 3, 2) = (2, 4, -2) |
21 - 10 c + c^2 = 0 \implies c \in \{ 3, 7 \} |
-16 - 6 u + u^2 = 0 \implies u \in \{ -2, 8 \} |
f(u) = 1 + 3 u + u^2, \quad g(a) = 1 + 3 a \implies f(g(a)) = 5 + 15 a + 9 a^2 |
\log_{2}\left(1 + t\right) = 2 \implies t = 3 |
(2, -3, -3) \times (4, -1, 5) = (-18, -22, 10) |
70 - 31 z - 4 z^2 + z^3 = 0 \implies z \in \{ -5, 2, 7 \} |
32 - 12 w + w^2 = 0 \implies w \in \{ 4, 8 \} |
\log_{3}\left(8 + 2 z\right) = 1 \implies z = \frac{-5}{2} |
\cos{\left(x\right)} \left(10 - t\right) = -t \cos{\left(x\right)} + 10 \cos{\left(x\right)} |
f(t) = 2 + 2 t + t^2, \quad g(b) = 3 + b \implies f(g(b)) = 17 + 8 b + b^2 |
\lim_{b \to -3} \left(b^2\right) = 9 |
\left(-b + v\right) b v = b v^2 - b^2 v |
\log_{2}\left(5 + 2 z\right) = 2 \implies z = \frac{-1}{2} |
-240 - 38 b + 7 b^2 + b^3 = 0 \implies b \in \{ -8, -5, 6 \} |
8 + c = 0 \implies c = -8 |
(5, 5, 3) \times (0, 0, 2) = (10, -10, 0) |
f(u) = 1 + u + u^2, \quad g(w) = 2 + 2 w \implies f(g(w)) = 7 + 10 w + 4 w^2 |
\log_{5}\left(5 + 3 x\right) = 3 \implies x = 40 |
\log_{2}\left(2 + 2 c\right) = 1 \implies c = 0 |
-28 + 18 = -10 |
\frac{d}{dz}\left(z^2\right) = 2 z |
-5 + x = 0 \implies x = 5 |
\log_{2}\left(2 + 2 a\right) = 2 \implies a = 1 |
-48 \cdot 11 = -528 |
3 + t = 0 \implies t = -3 |
f(c) = 1 + c + c^2, \quad g(w) = 3 + 2 w \implies f(g(w)) = 13 + 14 w + 4 w^2 |
f(y) = 5 + y + y^2, \quad g(v) = 2 + 3 v \implies f(g(v)) = 11 + 15 v + 9 v^2 |
-8 + y = 0 \implies y = 8 |
-45 - 9 t + 5 t^2 + t^3 = 0 \implies t \in \{ -5, -3, 3 \} |
\log_{5}\left(4 + 4 w\right) = 2 \implies w = \frac{21}{4} |
-24 - 5 a + a^2 = 0 \implies a \in \{ -3, 8 \} |
\frac{d}{db}\left(-6 + b + \cos{\left(b\right)}\right) = 1 - \sin{\left(b\right)} |
\log_{5}\left(4 + 4 a\right) = 3 \implies a = \frac{121}{4} |
\frac{d}{dc}\left(c^2\right) = 2 c |
28 - 11 u + u^2 = 0 \implies u \in \{ 4, 7 \} |
-2 + t = 0 \implies t = 2 |
\int \left(-20\right) dx = -20 x + C |
96 + 76 a + 16 a^2 + a^3 = 0 \implies a \in \{ -8, -6, -2 \} |
\frac{-48}{29} = \frac{-48}{29} |
\int \left(4 w^3\right) dw = w^4 + C |
35 + 5 = 40 |
-12 - 4 x + x^2 = 0 \implies x \in \{ -2, 6 \} |
\lim_{y \to 5} \left(y^2\right) = 25 |
-35 - 2 b + b^2 = 0 \implies b \in \{ -5, 7 \} |
15 + 8 y + y^2 = 0 \implies y \in \{ -5, -3 \} |
\frac{d}{dc}\left(c^3\right) = 3 c^2 |
\log_{3}\left(1 + 2 u\right) = 2 \implies u = 4 |
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