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f(y) = 3 + 5 y + y^2, \quad g(w) = 3 + w \implies f(g(w)) = 27 + 11 w + w^2
40 - 22 t - t^2 + t^3 = 0 \implies t \in \{ -5, 2, 4 \}
\frac{d}{da}\left(a\right) = 1
\log_{3}\left(2 + 3 a\right) = 3 \implies a = \frac{25}{3}
-3 + u = 0 \implies u = 3
1 - 9 = -8
\frac{d}{dy}\left(\sin{\left(y\right)}\right) = \cos{\left(y\right)}
\frac{d}{da}\left(\sin{\left(a\right)}\right) = \cos{\left(a\right)}
8 - 10 t + t^2 + t^3 = 0 \implies t \in \{ -4, 1, 2 \}
f(c) = 2 + 2 c + c^2, \quad g(z) = 4 + 2 z \implies f(g(z)) = 26 + 20 z + 4 z^2
f(w) = 2 + w + w^2, \quad g(u) = 1 + 3 u \implies f(g(u)) = 4 + 9 u + 9 u^2
\log_{5}\left(1 + 4 y\right) = 3 \implies y = 31
\lim_{x \to 4} \left(\sin{\left(x\right)}\right) = \sin{\left(4\right)}
-45 \cdot 35 = -1575
4 + b = 0 \implies b = -4
\frac{24}{38} = \frac{12}{19}
\lim_{a \to -1} \left(a\right) = -1
-64 + a^2 = 0 \implies a \in \{ -8, 8 \}
\int \left(4 z^3\right) dz = z^4 + C
\log_{2}\left(3 + 4 t\right) = 3 \implies t = \frac{5}{4}
31 - 9 = 22
x^3 \left(-6 + t\right) = t x^3 - 6 x^3
f(x) = 1 + 2 x + x^2, \quad g(v) = 1 + v \implies f(g(v)) = 4 + 4 v + v^2
w = 0 \implies w = 0
\int \left(\cos{\left(x\right)}\right) dx = \sin{\left(x\right)} + C
33 + 48 = 81
-2 + u = 0 \implies u = 2
18 - 9 v + v^2 = 0 \implies v \in \{ 3, 6 \}
u^4 \left(9 + u\right) = 9 u^4 + u^5
\frac{3}{49} = \frac{3}{49}
\frac{d}{dw}\left(\cos{\left(w\right)}\right) = -\sin{\left(w\right)}
\int \left(3\right) dv = 3 v + C
f(b) = 5 + b + b^2, \quad g(w) = 2 + 2 w \implies f(g(w)) = 11 + 10 w + 4 w^2
-19 - 13 = -32
\int \left(-1 + \sin{\left(t\right)}\right) dt = 1 - t - \cos{\left(t\right)} + C
\int \left(-2 c \sin{\left(c\right)} + 2 \cos{\left(c\right)}\right) dc = 2 c \cos{\left(c\right)} + C
15 - 8 a + a^2 = 0 \implies a \in \{ 3, 5 \}
5 + a = 0 \implies a = -5
280 - 51 z - 6 z^2 + z^3 = 0 \implies z \in \{ -7, 5, 8 \}
20 + 29 x + 10 x^2 + x^3 = 0 \implies x \in \{ -5, -4, -1 \}
-25 - 5 = -30
\frac{-34}{17} = -2
15 + 8 v + v^2 = 0 \implies v \in \{ -5, -3 \}
-4 + y = 0 \implies y = 4
\int \left(1\right) dz = z + C
100 - 25 c - 4 c^2 + c^3 = 0 \implies c \in \{ -5, 4, 5 \}
\int \left(5 x^4\right) dx = x^5 + C
(-3, 0, 0) \times (-1, -2, -5) = (0, -15, 6)
(-3, -1, -1) \times (-3, 4, 4) = (0, 15, -15)
\left(a + b\right) \sin{\left(a\right)} = a \sin{\left(a\right)} + b \sin{\left(a\right)}
-280 - 51 t + 6 t^2 + t^3 = 0 \implies t \in \{ -8, -5, 7 \}
-128 - 16 x + 8 x^2 + x^3 = 0 \implies x \in \{ -8, -4, 4 \}
-10 + 17 x - 8 x^2 + x^3 = 0 \implies x \in \{ 1, 2, 5 \}
f(a) = 5 + 3 a + a^2, \quad g(t) = 2 + 3 t \implies f(g(t)) = 15 + 21 t + 9 t^2
-35 + 3 = -32
(0, -4, -4) \times (2, -3, -3) = (0, -8, 8)
f(c) = 3 + 5 c + c^2, \quad g(z) = 3 + z \implies f(g(z)) = 27 + 11 z + z^2
\frac{20}{41} = \frac{20}{41}
6 + 5 c + c^2 = 0 \implies c \in \{ -3, -2 \}
-49 + a^2 = 0 \implies a \in \{ -7, 7 \}
\frac{41}{25} = \frac{41}{25}
(4, -2, 3) \times (4, 0, -1) = (2, 16, 8)
\frac{d}{dv}\left(\sin{\left(v\right)}\right) = \cos{\left(v\right)}
-40 - 5 = -45
f(b) = 5 + 5 b + b^2, \quad g(v) = 4 + 3 v \implies f(g(v)) = 41 + 39 v + 9 v^2
f(x) = 4 + 3 x + x^2, \quad g(c) = 4 + 2 c \implies f(g(c)) = 32 + 22 c + 4 c^2
(-1, -3, -3) \times (3, 3, 3) = (0, -6, 6)
\lim_{a \to 3} \left(a^2\right) = 9
\int \left(1 - \sin{\left(x\right)}\right) dx = -1 + x + \cos{\left(x\right)} + C
\log_{2}\left(2 + 2 x\right) = 2 \implies x = 1
-28 - 3 t + t^2 = 0 \implies t \in \{ -4, 7 \}
-32 - 4 v + v^2 = 0 \implies v \in \{ -4, 8 \}
-4 + a^2 = 0 \implies a \in \{ -2, 2 \}
80 + 66 x + 15 x^2 + x^3 = 0 \implies x \in \{ -8, -5, -2 \}
3 + x = 0 \implies x = -3
-31 \cdot 26 = -806
10 + 18 = 28
-14 \cdot 45 = -630
f(x) = 5 + 4 x + x^2, \quad g(v) = 2 + v \implies f(g(v)) = 17 + 8 v + v^2
6 u + u^2 = 0 \implies u \in \{ -6, 0 \}
-5 y + y^2 = 0 \implies y \in \{ 0, 5 \}
\frac{-24}{26} = \frac{-12}{13}
-8 - 7 = -15
f(b) = 3 + 5 b + b^2, \quad g(t) = 1 + 3 t \implies f(g(t)) = 9 + 21 t + 9 t^2
\lim_{b \to -5} \left(8 + b\right) = 3
\log_{5}\left(8 + z\right) = 1 \implies z = -3
\log_{3}\left(1 + 3 z\right) = 1 \implies z = \frac{2}{3}
2 v \left(5 + v\right) = 10 v + 2 v^2
\log_{3}\left(6 + b\right) = 2 \implies b = 3
-5 + 42 = 37
\frac{d}{dv}\left(-3\right) = 0
-40 - 43 x - 2 x^2 + x^3 = 0 \implies x \in \{ -5, -1, 8 \}
\log_{4}\left(5 + 4 c\right) = 3 \implies c = \frac{59}{4}
\log_{4}\left(4 + 2 y\right) = 1 \implies y = 0
2 + w = 0 \implies w = -2
-2 - 13 = -15
\sin{\left(u\right)} \left(-5 - u\right) = -u \sin{\left(u\right)} - 5 \sin{\left(u\right)}
f(t) = 1 + 5 t + t^2, \quad g(a) = 2 + 2 a \implies f(g(a)) = 15 + 18 a + 4 a^2
f(w) = 4 + 2 w + w^2, \quad g(z) = 2 + 2 z \implies f(g(z)) = 12 + 12 z + 4 z^2
f(z) = 4 + 5 z + z^2, \quad g(y) = 2 + y \implies f(g(y)) = 18 + 9 y + y^2