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\lim_{t \to -5} \left(3 + t\right) = -2 |
f(y) = 3 + y + y^2, \quad g(u) = 2 + 2 u \implies f(g(u)) = 9 + 10 u + 4 u^2 |
(0, 2, -1) \times (2, -5, -2) = (-9, -2, -4) |
32 \cdot 10 = 320 |
\int \left(6\right) da = 6 a + C |
\log_{2}\left(3 + x\right) = 1 \implies x = -1 |
-36 + 44 = 8 |
50 + 33 = 83 |
\frac{d}{dt}\left(5 + \sin{\left(t\right)}\right) = \cos{\left(t\right)} |
-6 - 44 = -50 |
\lim_{t \to 3} \left(2\right) = 2 |
7 - 8 y + y^2 = 0 \implies y \in \{ 1, 7 \} |
46 - 33 = 13 |
12 v - 7 v^2 + v^3 = 0 \implies v \in \{ 0, 3, 4 \} |
\log_{5}\left(4 + 2 a\right) = 3 \implies a = \frac{121}{2} |
-4 t + t^2 = 0 \implies t \in \{ 0, 4 \} |
\int \left(1\right) du = u + C |
(-4, -1, 3) \times (4, -3, -5) = (14, -8, 16) |
\lim_{b \to -5} \left(0\right) = 0 |
6 + 5 z + z^2 = 0 \implies z \in \{ -3, -2 \} |
(4, -5, -5) \times (-5, 4, 5) = (-5, 5, -9) |
9 y \left(1 + z\right) = 9 y + 9 y z |
(-3, -1, 3) \times (-4, 0, 4) = (-4, 0, -4) |
\int \left(-8\right) dv = -8 v + C |
-9 z \left(3 - z\right) = -27 z + 9 z^2 |
\lim_{v \to 5} \left(v^2\right) = 25 |
w^3 \left(v - w\right) = v w^3 - w^4 |
(2, -4, 5) \times (-5, 1, -2) = (3, -21, -18) |
-28 + 3 u + u^2 = 0 \implies u \in \{ -7, 4 \} |
f(w) = 1 + 2 w + w^2, \quad g(v) = 4 + 3 v \implies f(g(v)) = 25 + 30 v + 9 v^2 |
\log_{3}\left(7 + 2 w\right) = 1 \implies w = -2 |
24 - 19 b - 6 b^2 + b^3 = 0 \implies b \in \{ -3, 1, 8 \} |
-112 - 54 a + 3 a^2 + a^3 = 0 \implies a \in \{ -8, -2, 7 \} |
-8 + t = 0 \implies t = 8 |
(5, -2, -1) \times (-5, -5, 1) = (-7, 0, -35) |
5 - 17 = -12 |
47 + 1 = 48 |
\int \left(-20 t\right) dt = -10 t^2 + C |
-6 + x = 0 \implies x = 6 |
\frac{9}{42} = \frac{3}{14} |
8 - 9 w + w^2 = 0 \implies w \in \{ 1, 8 \} |
\log_{4}\left(4 + 2 w\right) = 1 \implies w = 0 |
\lim_{z \to 2} \left(\cos{\left(z\right)}\right) = \cos{\left(2\right)} |
f(b) = 4 + 4 b + b^2, \quad g(w) = 2 + 2 w \implies f(g(w)) = 16 + 16 w + 4 w^2 |
f(z) = 5 + z + z^2, \quad g(t) = 3 + 2 t \implies f(g(t)) = 17 + 14 t + 4 t^2 |
3 w - 4 w^2 + w^3 = 0 \implies w \in \{ 0, 1, 3 \} |
\int \left(-1 + 4 v^3\right) dv = -v + v^4 + C |
\log_{5}\left(8 + 2 z\right) = 2 \implies z = \frac{17}{2} |
2 + c = 0 \implies c = -2 |
(-2, -2, 4) \times (2, 5, 3) = (-26, 14, -6) |
\log_{5}\left(4 + 2 b\right) = 1 \implies b = \frac{1}{2} |
\log_{5}\left(6 + x\right) = 3 \implies x = 119 |
\int \left(1\right) du = u + C |
\lim_{y \to -1} \left(y^4\right) = 1 |
\left(a + y\right) y^3 = a y^3 + y^4 |
\frac{-29}{40} = \frac{-29}{40} |
72 - 18 w - 5 w^2 + w^3 = 0 \implies w \in \{ -4, 3, 6 \} |
f(u) = 5 + 2 u + u^2, \quad g(a) = 3 + 3 a \implies f(g(a)) = 20 + 24 a + 9 a^2 |
-2 + b = 0 \implies b = 2 |
\frac{-42}{13} = \frac{-42}{13} |
-14 - 9 = -23 |
\int \left(1\right) dw = w + C |
-10 + 3 x + x^2 = 0 \implies x \in \{ -5, 2 \} |
44 \cdot 1 = 44 |
\log_{2}\left(1 + 3 y\right) = 3 \implies y = \frac{7}{3} |
f(w) = 2 + 5 w + w^2, \quad g(a) = 2 + 3 a \implies f(g(a)) = 16 + 27 a + 9 a^2 |
\log_{3}\left(8 + 2 v\right) = 1 \implies v = \frac{-5}{2} |
f(c) = 3 + 4 c + c^2, \quad g(u) = 3 + 3 u \implies f(g(u)) = 24 + 30 u + 9 u^2 |
\frac{27}{33} = \frac{9}{11} |
45 + 17 = 62 |
f(t) = 5 + 5 t + t^2, \quad g(w) = 2 + 2 w \implies f(g(w)) = 19 + 18 w + 4 w^2 |
\log_{4}\left(7 + 2 b\right) = 1 \implies b = \frac{-3}{2} |
f(t) = 2 + t + t^2, \quad g(v) = 2 + v \implies f(g(v)) = 8 + 5 v + v^2 |
f(w) = 4 + 4 w + w^2, \quad g(c) = 4 + 2 c \implies f(g(c)) = 36 + 24 c + 4 c^2 |
\frac{d}{db}\left(\cos{\left(b\right)}\right) = -\sin{\left(b\right)} |
\log_{3}\left(8 + v\right) = 2 \implies v = 1 |
\frac{-28}{10} = \frac{-14}{5} |
\lim_{w \to 5} \left(w^3\right) = 125 |
\frac{d}{dv}\left(v\right) = 1 |
2 + w = 0 \implies w = -2 |
-5 + u = 0 \implies u = 5 |
\log_{2}\left(4 + 2 w\right) = 3 \implies w = 2 |
6 + u = 0 \implies u = -6 |
f(t) = 3 + 2 t + t^2, \quad g(b) = 4 + b \implies f(g(b)) = 27 + 10 b + b^2 |
(-2, 2, 5) \times (-3, -2, 3) = (16, -9, 10) |
\log_{5}\left(1 + t\right) = 1 \implies t = 4 |
44 \cdot 30 = 1320 |
\int \left(1\right) da = a + C |
\int \left(\cos{\left(c\right)}\right) dc = \sin{\left(c\right)} + C |
4 a + a^2 = 0 \implies a \in \{ -4, 0 \} |
\lim_{u \to 3} \left(u^2\right) = 9 |
\lim_{z \to -3} \left(z^2\right) = 9 |
\lim_{a \to 0} \left(2\right) = 2 |
\lim_{b \to 5} \left(7 + b\right) = 12 |
\log_{2}\left(3 + 2 z\right) = 3 \implies z = \frac{5}{2} |
\log_{5}\left(3 + a\right) = 3 \implies a = 122 |
\int \left(2 t\right) dt = t^2 + C |
34 - 32 = 2 |
\frac{d}{db}\left(4 b^3\right) = 12 b^2 |
\log_{4}\left(4 + 4 b\right) = 3 \implies b = 15 |
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