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\log_{2}\left(7 + 4 a\right) = 2 \implies a = \frac{-3}{4}
\log_{2}\left(2 + 3 x\right) = 2 \implies x = \frac{2}{3}
\int \left(1\right) dz = z + C
\log_{5}\left(2 + t\right) = 1 \implies t = 3
(-2, 5, -5) \times (-2, 4, -5) = (-5, 0, 2)
\lim_{c \to 1} \left(c\right) = 1
-8 t + t^2 = 0 \implies t \in \{ 0, 8 \}
\log_{3}\left(4 + 4 c\right) = 1 \implies c = \frac{-1}{4}
(-5, -5, 0) \times (5, 0, -1) = (5, -5, 25)
18 \cdot 43 = 774
\log_{4}\left(1 + 2 v\right) = 3 \implies v = \frac{63}{2}
\frac{16}{39} = \frac{16}{39}
\frac{50}{17} = \frac{50}{17}
\log_{2}\left(5 + 2 y\right) = 3 \implies y = \frac{3}{2}
\log_{4}\left(3 + v\right) = 3 \implies v = 61
(-5, 2, 2) \times (-4, 4, -3) = (-14, -23, -12)
32 - 12 u + u^2 = 0 \implies u \in \{ 4, 8 \}
-8 - 7 b + b^2 = 0 \implies b \in \{ -1, 8 \}
\lim_{b \to -3} \left(\cos{\left(b\right)}\right) = \cos{\left(3\right)}
-23 - 40 = -63
6 + 7 b + b^2 = 0 \implies b \in \{ -6, -1 \}
(-3, -2, 2) \times (-3, 2, 5) = (-14, 9, -12)
\left(-t + w\right) \cos{\left(w\right)} = -t \cos{\left(w\right)} + w \cos{\left(w\right)}
\frac{d}{dt}\left(10 + t - \sin{\left(t\right)}\right) = 1 - \cos{\left(t\right)}
(2, 0, 5) \times (1, -4, -5) = (20, 15, -8)
\lim_{y \to 1} \left(y^3\right) = 1
-6 + c = 0 \implies c = 6
(3, 2, 4) \times (2, 0, 5) = (10, -7, -4)
(3, -3, 1) \times (4, -5, -3) = (14, 13, -3)
\log_{4}\left(2 + 2 z\right) = 2 \implies z = 7
\log_{4}\left(1 + 2 y\right) = 3 \implies y = \frac{63}{2}
f(u) = 5 + u + u^2, \quad g(w) = 2 + 2 w \implies f(g(w)) = 11 + 10 w + 4 w^2
7 + 16 = 23
f(v) = 4 + v + v^2, \quad g(z) = 2 + z \implies f(g(z)) = 10 + 5 z + z^2
(4, 5, 5) \times (-2, -5, 3) = (40, -22, -10)
\lim_{y \to 0} \left(-5 + y\right) = -5
\frac{d}{dy}\left(y\right) = 1
\frac{d}{dc}\left(c\right) = 1
\frac{21}{50} = \frac{21}{50}
-33 - 4 = -37
21 + 10 v + v^2 = 0 \implies v \in \{ -7, -3 \}
(-3, -1, 3) \times (1, -1, -3) = (6, -6, 4)
f(a) = 3 + 4 a + a^2, \quad g(t) = 2 + 3 t \implies f(g(t)) = 15 + 24 t + 9 t^2
\int \left(1\right) dv = v + C
\frac{-8}{28} = \frac{-2}{7}
(2, 1, 4) \times (0, 2, 1) = (-7, -2, 4)
-10 + 3 a + a^2 = 0 \implies a \in \{ -5, 2 \}
28 y - 11 y^2 + y^3 = 0 \implies y \in \{ 0, 4, 7 \}
\frac{d}{db}\left(\sin{\left(b\right)}\right) = \cos{\left(b\right)}
\lim_{v \to -1} \left(\sin{\left(v\right)}\right) = -\sin{\left(1\right)}
-30 - w + w^2 = 0 \implies w \in \{ -5, 6 \}
\log_{5}\left(4 + 2 b\right) = 3 \implies b = \frac{121}{2}
7 - 18 = -11
-3 + z = 0 \implies z = 3
-8 - 2 a + a^2 = 0 \implies a \in \{ -2, 4 \}
16 c - 10 c^2 + c^3 = 0 \implies c \in \{ 0, 2, 8 \}
\log_{5}\left(1 + 4 x\right) = 1 \implies x = 1
z^4 \left(-w + z\right) = -w z^4 + z^5
f(a) = 2 + 4 a + a^2, \quad g(v) = 2 + 2 v \implies f(g(v)) = 14 + 16 v + 4 v^2
\log_{5}\left(6 + z\right) = 3 \implies z = 119
27 - 47 = -20
\int \left(2 a\right) da = a^2 + C
-7 + 6 u + u^2 = 0 \implies u \in \{ -7, 1 \}
3 a + a^2 = 0 \implies a \in \{ -3, 0 \}
\int \left(1\right) da = a + C
\lim_{x \to 4} \left(2 x\right) = 8
\frac{-7}{1} = -7
\lim_{x \to 5} \left(x^2\right) = 25
\frac{d}{da}\left(\sin{\left(a\right)} + \cos{\left(a\right)}\right) = -\sin{\left(a\right)} + \cos{\left(a\right)}
\frac{d}{dx}\left(x^2\right) = 2 x
-2 + a = 0 \implies a = 2
(1, -2, -2) \times (0, 1, -5) = (12, 5, 1)
(-5, 1, 5) \times (-1, 0, 5) = (5, 20, 1)
\log_{3}\left(8 + 2 a\right) = 3 \implies a = \frac{19}{2}
44 - 32 = 12
\int \left(3 v^2\right) dv = v^3 + C
4 \cdot 37 = 148
-20 + z + z^2 = 0 \implies z \in \{ -5, 4 \}
-11 + 2 = -9
-8 - 2 y + y^2 = 0 \implies y \in \{ -2, 4 \}
(-1, 5, 3) \times (0, 4, 0) = (-12, 0, -4)
37 - 13 = 24
80 - 34 y - 5 y^2 + y^3 = 0 \implies y \in \{ -5, 2, 8 \}
-34 \cdot 41 = -1394
(-2, 0, -1) \times (-1, -3, 2) = (-3, 5, 6)
\log_{5}\left(4 + 2 b\right) = 3 \implies b = \frac{121}{2}
\log_{5}\left(6 + z\right) = 3 \implies z = 119
\int \left(1\right) dw = w + C
(1, -3, 5) \times (-4, -5, 2) = (19, -22, -17)
-6 + 5 z + z^2 = 0 \implies z \in \{ -6, 1 \}
-30 + y + y^2 = 0 \implies y \in \{ -6, 5 \}
-30 + 31 b - 10 b^2 + b^3 = 0 \implies b \in \{ 2, 3, 5 \}
(-2, -2, -5) \times (-5, -4, -2) = (-16, 21, -2)
f(y) = 2 + 4 y + y^2, \quad g(c) = 1 + 2 c \implies f(g(c)) = 7 + 12 c + 4 c^2
f(u) = 5 + 3 u + u^2, \quad g(x) = 3 + x \implies f(g(x)) = 23 + 9 x + x^2
(0, 4, -3) \times (-1, 2, -2) = (-2, 3, 4)
\log_{3}\left(7 + 2 b\right) = 2 \implies b = 1
\frac{d}{du}\left(-u^2\right) = -2 u
\frac{35}{45} = \frac{7}{9}
-7 + x = 0 \implies x = 7