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[ { "from": "user", "value": "Return your final response within \\boxed{}. The operation" }, { "from": "assistant", "value": " $\\otimes$ is defined for all nonzero numbers by $a\\otimes b =\\frac{a^{2}}{b}$. Determine $[(1\\otimes 2)\\otimes 3]-[1\\otimes (2\\otimes 3)]$.\n$\\text{(A)}\\ -\\frac{...
[ { "from": "user", "value": "Return your final response within \\boxed{}. Doug constructs" }, { "from": "assistant", "value": " a square window using $8$ equal-size panes of glass, as shown. The ratio of the height to width for each pane is $5 : 2$, and the borders around and between the panes ar...
[ { "from": "user", "value": "4 simplifies to 5:2. Yes" }, { "from": "assistant", "value": ", so 10/4 = 5/2, so that's consistent. So if each pane is 10 units tall and 4 units wide, then with the ratio 5:2 (height to width), each unit is 2.5 inches in height and 2 inches in width? Wait, no, hold o...
[ { "from": "user", "value": "\n\n= 6 + 10k\n\n" }, { "from": "assistant", "value": "Since it's a square, 10 + 8k = 6 + 10k\n\nSolving:\n\n10 - 6 = 10k - 8k\n\n4 = 2k => k = 2\n\nTherefore, pane width = 2k = 4 inches, pane height = 5k = 10 inches.\n\nTotal width = 10 + 8k = 10 + 16 = 26 inches.\n\...
[ { "from": "user", "value": "Return your final response within \\boxed{}. $P" }, { "from": "assistant", "value": "(x)$ is a polynomial of degree $3n$ such that\n\\begin{eqnarray*} P(0) = P(3) = \\cdots &=& P(3n) = 2, \\\\ P(1) = P(4) = \\cdots &=& P(3n-2) = 1, \\\\ P(2) = P(5) = \\cdots &=& P(3n-...
[ { "from": "user", "value": "3, so P(3)=2, and" }, { "from": "assistant", "value": " then P(4)=730. Let's check if n=1 is possible.\n\nBut maybe trying small n can help. Let me try n=1. Then, P(x) is a cubic polynomial with P(0)=2, P(1)=1, P(2)=0, P(3)=2. Let's see if we can construct this polyno...
[ { "from": "user", "value": ",...,3n, f(x) can be" }, { "from": "assistant", "value": " expressed in terms of some polynomial. Maybe using the floor function or something else. But this might not help.\n\nAlternatively, think of the problem in terms of the Gregory-Newton formula for interpolation...
[ { "from": "user", "value": " roots at x=1,4,...,3" }, { "from": "assistant", "value": "n-2, so P(x)-1 = (x-1)(x-4)...(x-(3n-2)) * B(x). And P(x) has roots at x=2,5,...,3n-1, so P(x) = (x-2)(x-5)...(x-(3n-1)) * C(x). But since P(x) must satisfy all these conditions, perhaps we can relate A(x), B(...
[ { "from": "user", "value": ", the function f(k) =2,1" }, { "from": "assistant", "value": ",0,2,1,0,...,2 for k=0,1,2,...,3n. The finite difference table would be quite complex. Maybe there's a generating function approach.\n\nThe generating function for P(x) is G(t) = Σ_{k=0}^{3n} P(k) t^k = Σ_{...
[ { "from": "user", "value": ", for integer x, cos(2πx" }, { "from": "assistant", "value": "/3) is equal to:\n\n- 1, if x ≡0 mod3\n\n- -1/2, if x ≡1 or 2 mod3\n\nSimilarly, sin(2πx/3) is:\n\n- 0, if x ≡0 mod3\n\n- √3/2, if x≡1 mod3\n\n- -√3/2, if x≡2 mod3\n\nTherefore, for integer x, Indicator_0(x...
[ { "from": "user", "value": "1\n\n2-0=2\n\n1-" }, { "from": "assistant", "value": "2=-1\n\n0-1=-1\n\n2-0=2\n\nSecond differences (Δ²f):\n\n-1 - (-1)=0\n\n2 - (-1)=3\n\n-1 -2=-3\n\n-1 - (-1)=0\n\n2 - (-1)=3\n\nThird differences (Δ³f):\n\n0 -0=0\n\n3 -0=3\n\n-3 -3=-6\n\n0 - (-3)=3\n\n3 -0=3\n\nFour...
[ { "from": "user", "value": "3n) ] / [k(k-1" }, { "from": "assistant", "value": ")...1 * (-1)(-2)...(k -3n) ]\n\nBut this is too abstract. Alternatively, recognize that L_k(3n+1) is the same as C(3n+1, k) * (-1)^{3n -k} due to the properties of Lagrange basis polynomials. However, I need to verif...
[ { "from": "user", "value": " (-1)^k = (1/3)[" }, { "from": "assistant", "value": "(1 -1)^{3n+1} + (1 -ω)^{3n+1} + (1 -ω²)^{3n+1} ]\n\nSimilarly, Σ_{k ≡1 mod3} C(3n+1, k) (-1)^k = (1/3)[(1 -1)^{3n+1} ω^{-1} + (1 -ω)^{3n+1} ω^{0} + (1 -ω²)^{3n+1} ω^{-2} ]\n\nBut since (1 -1)^{3n+1} =0, these expre...
[ { "from": "user", "value": "^{i(2π/3 + (3" }, { "from": "assistant", "value": "n+1)π/6)} ]\n\nSimplify the exponent:\n\n2π/3 = 4π/6, so 4π/6 + (3n+1)π/6 = (4 + 3n +1)π/6 = (3n +5)π/6\n\nThus,\n\nS1 = (√3)^{3n+1} /3 * 2 cos( (3n +5)π/6 )\n\n= (2/3)(√3)^{3n+1} cos( (3n +5)π/6 )\n\nSimilarly, S0 = ...
[ { "from": "user", "value": "= (1/3)(729 *" }, { "from": "assistant", "value": " √3 * 3√3 )\n\n= (1/3)(729 * 3 * 3 )\n\n= (1/3)(729 *9 )\n\n= (729 *3 )=2187\n\nBut 2187≠730. So n=4 is not the answer.\n\nWait, maybe n=3:\n\nFor n=3, 3n+1=10. Compute A=10π/6=5π/3.\n\ncos(5π/3)=1/2, sin(5π/3)=-√3/2....
[ { "from": "user", "value": "Return your final response within \\boxed{}. Let $" }, { "from": "assistant", "value": "f$ be the function defined by $f(x)=ax^2-\\sqrt{2}$ for some positive $a$. If $f(f(\\sqrt{2}))=-\\sqrt{2}$ then $a=$\n$\\text{(A) } \\frac{2-\\sqrt{2}}{2}\\quad \\text{(B) } \\frac...
[ { "from": "user", "value": ".\n\nSubtracting -√2 from both sides" }, { "from": "assistant", "value": " gives 4a³ - 4a²√2 + 2a = 0. Then factor out 2a: 2a(2a² - 2a√2 + 1) = 0. Correct.\n\nSince a is positive, 2a ≠ 0, so solve 2a² - 2a√2 + 1 = 0. That's a quadratic equation. Applying quadratic for...
[ { "from": "user", "value": " and use the fact that a is positive. That" }, { "from": "assistant", "value": "'s a much cleaner approach. The initial expansion led to a cubic equation, which might have confused me into thinking there were more solutions, but actually, the structure of the equation...
[ { "from": "user", "value": "Return your final response within \\boxed{}. The total" }, { "from": "assistant", "value": " in-store price for an appliance is $\\textdollar 99.99$. A television commercial advertises the same product for three easy payments of $\\textdollar 29.98$ and a one-time shi...
[ { "from": "user", "value": " \\[\n 8994 +" }, { "from": "assistant", "value": " 998 = 9992 \\text{ cents}\n \\]\n\nThe savings in cents is:\n\\[\n9999 - 9992 = 7 \\text{ cents}\n\\]\n\nThus, the answer is \\(\\boxed{B}\\).\n\n<|end_of_solution|>" } ]
[ { "from": "user", "value": "Return your final response within \\boxed{}. Points $" }, { "from": "assistant", "value": "A,B,C,D,E$ and $F$ lie, in that order, on $\\overline{AF}$, dividing it into five segments, each of length 1. Point $G$ is not on line $AF$. Point $H$ lies on $\\overline{GD}$, ...
[ { "from": "user", "value": " - 4s) = 1\n\nMultiply" }, { "from": "assistant", "value": " both sides by (3 - 4s):\n\n-1 + s = 3 - 4s\n\nBring terms over:\n\ns + 4s = 3 + 1 => 5s = 4 => s = 4/5\n\nTherefore, J is (1 + 4*(4/5), 1 - 4/5) = (1 + 16/5, 1/5) = (21/5, 1/5). Then JE is from (21/5, 1/5) t...
[ { "from": "user", "value": " \\(\\overline{GD}\\) and \\" }, { "from": "assistant", "value": "(\\overline{GF}\\) respectively, such that \\(\\overline{HC}\\), \\(\\overline{JE}\\), and \\(\\overline{AG}\\) are parallel. We need to find the ratio \\(\\frac{HC}{JE}\\).\n\n1. **Parametric Equations...
[ { "from": "user", "value": "Return your final response within \\boxed{}. During the" }, { "from": "assistant", "value": " softball season, Judy had $35$ hits. Among her hits were $1$ home run, $1$ triple and $5$ doubles. The rest of her hits were single. What percent of her hits were single?\...
[ { "from": "user", "value": "Return your final response within \\boxed{}. The graph" }, { "from": "assistant", "value": ", $G$ of $y=\\log_{10}x$ is rotated $90^{\\circ}$ counter-clockwise about the origin to obtain a new graph $G'$. Which of the following is an equation for $G'$?\n(A) $y=\\log_{...
[ { "from": "user", "value": "-clockwise to the point \\((-y, x" }, { "from": "assistant", "value": ")\\) on the new graph \\( G' \\).\n2. **Relating Coordinates**: For a point \\((X, Y)\\) on \\( G' \\), the original coordinates \\((x, y)\\) on \\( G \\) are related by:\n \\[\n X = -y \\quad ...
[ { "from": "user", "value": "Return your final response within \\boxed{}. Jose," }, { "from": "assistant", "value": " Thuy, and Kareem each start with the number 10. Jose subtracts 1 from the number 10, doubles his answer, and then adds 2. Thuy doubles the number 10, subtracts 1 from her answer...
[ { "from": "user", "value": "9\\)\n2. Double the result: \\(" }, { "from": "assistant", "value": "9 \\times 2 = 18\\)\n3. Add 2: \\(18 + 2 = 20\\)\n\n**Thuy:**\n1. Double the number 10: \\(10 \\times 2 = 20\\)\n2. Subtract 1: \\(20 - 1 = 19\\)\n3. Add 2: \\(19 + 2 = 21\\)\n\n**Kareem:**\n1. Subtr...
[ { "from": "user", "value": "Return your final response within \\boxed{}. A set" }, { "from": "assistant", "value": " of consecutive positive integers beginning with $1$ is written on a blackboard. One number is erased. The average (arithmetic mean) of the remaining numbers is $35\\frac{7}{17}$. ...
[ { "from": "user", "value": "1 to n is (n +1)/2" }, { "from": "assistant", "value": ". Since after removing a number, the average is 35.41, the original average must be close to that. So (n +1)/2 ≈35.41. Therefore, n +1 ≈70.82, so n≈69.82. So n is approximately 70. But since n must be of the form...
[ { "from": "user", "value": " clear the fraction**:\n \\[\n " }, { "from": "assistant", "value": "17 \\left( \\frac{n(n + 1)}{2} \\right) - 17x = 602(n - 1)\n \\]\n\n6. **Simplify and solve for \\(x\\)**:\n \\[\n 17x = \\frac{17n(n + 1)}{2} - 602(n - 1)\n \\]\n\n7. **Determine \\(n\\)...
[ { "from": "user", "value": "Return your final response within \\boxed{}. A rectangular" }, { "from": "assistant", "value": " yard contains two flower beds in the shape of congruent isosceles right triangles. The remainder of the yard has a trapezoidal shape, as shown. The parallel sides of the t...
[ { "from": "user", "value": " 100 square meters. Then, the" }, { "from": "assistant", "value": " area of the entire yard (the rectangle) is length * width. The length is 25 meters (from x=0 to x=25) and the width (height) is 5 meters (from y=0 to y=5). So area is 25*5=125 square meters. Then, the...
[ { "from": "user", "value": "Return your final response within \\boxed{}. What is" }, { "from": "assistant", "value": " the sum of all possible values of $t$ between $0$ and $360$ such that the triangle in the coordinate plane whose vertices are \\[(\\cos 40^\\circ,\\sin 40^\\circ), (\\cos 60^\\c...
[ { "from": "user", "value": "80° is 40°, chord" }, { "from": "assistant", "value": " length 2*sin20°, so same as previous case. So, triangle with two sides 2*sin10° and one 2*sin20°, so isosceles.\n\nSo, t=20°, 50°, 80°.\n\nBut wait, when t=50°, the two chords adjacent to t are equal, so the tria...
[ { "from": "user", "value": " through the center if the chord is not a diameter" }, { "from": "assistant", "value": ". Wait, but since the chord is not a diameter, the perpendicular bisector passes through the center. Wait, in a circle, the perpendicular bisector of any chord passes through the c...
[ { "from": "user", "value": " t=140° and 32" }, { "from": "assistant", "value": "0°, but t=140° when checked didn't give an isosceles triangle. Wait, perhaps I made a mistake in the geometric approach.\n\nWait, let's take t=140°. The coordinates would be (cos140°, sin140°). Let's compute the dist...
[ { "from": "user", "value": "0° or t=230°," }, { "from": "assistant", "value": " as solutions.\n\nWait, let's formalize this. For the minimal central angles to be equal, we have:\n\nmin(|t -40°|, 360° - |t -40°|) = min(|t -60°|, 360° - |t -60°|)\n\nThis can happen in two cases:\n\n1. |t -40°| = |...
[ { "from": "user", "value": ".\n\n**Final Answer**\n\\boxed{E}\n\n" }, { "from": "assistant", "value": "<|end_of_thought|>\n\n<|begin_of_solution|>\n\nTo determine the sum of all possible values of \\( t \\) between \\( 0 \\) and \\( 360 \\) such that the triangle formed by the points \\((\\cos 4...
[ { "from": "user", "value": "Return your final response within \\boxed{}. Given:" }, { "from": "assistant", "value": " $x > 0, y > 0, x > y$ and $z\\ne 0$. The inequality which is not always correct is:\n$\\textbf{(A)}\\ x + z > y + z \\qquad\\textbf{(B)}\\ x - z > y - z \\qquad\\textbf{(C)}\\ xz...
[ { "from": "user", "value": "Return your final response within \\boxed{}. The harmonic" }, { "from": "assistant", "value": " mean of two numbers can be calculated as twice their product divided by their sum. The harmonic mean of $1$ and $2016$ is closest to which integer?\n$\\textbf{(A)}\\ 2 \\qq...
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