source stringclasses 1
value | problem stringlengths 156 1.39k | solution stringlengths 513 2.44k | messages listlengths 2 2 |
|---|---|---|---|
math | In the diagram below, $\|\overrightarrow{OA}\| = 1,$ $\|\overrightarrow{OB}\| = 1,$ and $\|\overrightarrow{OC}\| = \sqrt{2}.$ Also, $\tan \angle AOC = 7$ and $\angle BOC = 45^\circ.$
[asy]
unitsize(2 cm);
pair A, B, C, O;
A = (1,0);
B = (-0.6,0.8);
C = (0.2,1.4);
O = (0,0);
draw(O--A,Arrow(6));
draw(O--B,Arrow(6))... | To solve for the constants $m$ and $n$ in the vector equation $\overrightarrow{OC} = m \overrightarrow{OA} + n \overrightarrow{OB}$, we first need to find the trigonometric values associated with $\angle AOC$. Given that $\tan \angle AOC = 7$, we can construct a right triangle with an adjacent side of length $1$ (corre... | [
{
"content": "In the diagram below, $\\|\\overrightarrow{OA}\\| = 1,$ $\\|\\overrightarrow{OB}\\| = 1,$ and $\\|\\overrightarrow{OC}\\| = \\sqrt{2}.$ Also, $\\tan \\angle AOC = 7$ and $\\angle BOC = 45^\\circ.$\n\n[asy]\nunitsize(2 cm);\n\npair A, B, C, O;\n\nA = (1,0);\nB = (-0.6,0.8);\nC = (0.2,1.4);\nO = (0... |
math | In the diagram, two pairs of identical isosceles triangles are cut off of square $ABCD$, leaving rectangle $PQRS$. The total area cut off is $200 \text{ m}^2$. What is the length of $PR$, in meters? [asy]
size(5cm);
pair a = (0, 1); pair b = (1, 1); pair c = (1, 0); pair d = (0, 0);
pair s = (0, 0.333); pair p = (0.66... | To solve for the length of $PR$ in the given problem, we follow these steps:
1. **Identify the Variables**: Let $AS=x$ and $SD=y$. Given the isosceles triangles, we can deduce that $AP=x$ and $DR=y$.
2. **Identify Identical Triangles**: Since there are two pairs of identical isosceles triangles, we have $BP=BQ=y$ and... | [
{
"content": "In the diagram, two pairs of identical isosceles triangles are cut off of square $ABCD$, leaving rectangle $PQRS$. The total area cut off is $200 \\text{ m}^2$. What is the length of $PR$, in meters? [asy]\nsize(5cm);\n\npair a = (0, 1); pair b = (1, 1); pair c = (1, 0); pair d = (0, 0);\npair s =... |
math | In the diagram below, we have $AB = 24$ and $\angle ADB =90^\circ$. If $\sin A = \frac23$ and $\sin C = \frac13$, then what is $DC$?
[asy]
pair A,B,C,D;
A = (0,0);
B = (8*sqrt(5),16);
D = (8*sqrt(5),0);
C = (8*sqrt(5) + 32*sqrt(2),0);
draw(D--B--A--C--B);
label("$A$",A,SW);
label("$B$",B,N);
label("$C$",C,SE);
label... | To solve for $DC$, we follow the steps derived from the given solution closely:
1. **Finding $BD$ using $\sin A$:**
Given that $\sin A = \frac{BD}{AB}$ and $AB = 24$, we have:
\[
\sin A = \frac{2}{3} = \frac{BD}{24}
\]
Solving for $BD$, we get:
\[
BD = \frac{2}{3} \cdot 24 = 16
\]
2. **Finding $BC$ using $\sin C$:**... | [
{
"content": "In the diagram below, we have $AB = 24$ and $\\angle ADB =90^\\circ$. If $\\sin A = \\frac23$ and $\\sin C = \\frac13$, then what is $DC$?\n\n\n[asy]\npair A,B,C,D;\nA = (0,0);\nB = (8*sqrt(5),16);\nD = (8*sqrt(5),0);\nC = (8*sqrt(5) + 32*sqrt(2),0);\ndraw(D--B--A--C--B);\nlabel(\"$A$\",A,SW);\nl... |
math | In the diagram below, $\overline{AB}\parallel \overline{CD}$ and $\angle AXF= 118^\circ$. Find $\angle FYD$.
[asy]
unitsize(1inch);
pair A,B,C,D,X,Y,EE,F;
A = (0,0);
B=(1,0);
C = (0,0.8);
D=(1,0.8);
EE = (0.35,-0.3);
F = (0.8,1.1);
draw(EE--F);
draw(A--B);
draw(C--D);
dot(A);
dot(B);
dot(C);
dot(D);
dot(EE);
dot(F);
... | Given that $\overline{AB} \parallel \overline{CD}$ and $\angle AXF= 118^\circ$, we aim to find $\angle FYD$.
1. Since $\overline{AB}$ is parallel to $\overline{CD}$, the corresponding angles formed by a transversal with these parallel lines are supplementary. Therefore, we have the relationship $\angle AXF + \angle FY... | [
{
"content": "In the diagram below, $\\overline{AB}\\parallel \\overline{CD}$ and $\\angle AXF= 118^\\circ$. Find $\\angle FYD$.\n\n[asy]\nunitsize(1inch);\npair A,B,C,D,X,Y,EE,F;\nA = (0,0);\nB=(1,0);\nC = (0,0.8);\nD=(1,0.8);\nEE = (0.35,-0.3);\nF = (0.8,1.1);\ndraw(EE--F);\ndraw(A--B);\ndraw(C--D);\ndot(A);... |
math | From the diagram below, find the positive difference in the $x$-coordinates when lines $l$ and $m$ reach $y = 15.$ [asy]
import cse5; import olympiad;
size(120);
add(grid(8,8));
draw((0,0)--(8,0),linewidth(1.2));
draw((0,0)--(0,8),linewidth(1.2));
label("$x$",(8,0),E);
label("$y$",(0,8),N);
draw((0,5)--(3,0),Arrows);
d... | To find the equations of lines $l$ and $m$, we start by determining their slopes and y-intercepts.
For line $l$, it passes through points $(0,5)$ and $(3,0)$. The slope of $l$ is calculated as follows:
\[
\text{Slope of } l = \frac{0 - 5}{3 - 0} = -\frac{5}{3}.
\]
Given that it passes through $(0,5)$, the y-intercept ... | [
{
"content": "From the diagram below, find the positive difference in the $x$-coordinates when lines $l$ and $m$ reach $y = 15.$ [asy]\nimport cse5; import olympiad;\nsize(120);\nadd(grid(8,8));\ndraw((0,0)--(8,0),linewidth(1.2));\ndraw((0,0)--(0,8),linewidth(1.2));\nlabel(\"$x$\",(8,0),E);\nlabel(\"$y$\",(0,8)... |
math | In the diagram, $\triangle XYZ$ is right-angled at $X,$ with $YX=60$ and $XZ=80.$ The point $W$ is on $YZ$ so that $WX$ is perpendicular to $YZ.$ Determine the length of $WZ.$ [asy]
pair X, Y, Z, W;
Y=(0,0);
X=(36,48);
Z=(100,0);
W=(36,0);
draw(X--Y--Z--X--W);
label("Y", Y, SW);
label("X", X, N);
label("W", W, S);
labe... | To solve for the length of $WZ$, we can follow a step-by-step approach using the information given in the problem.
**Step 1: Find the length of $YZ$ using the Pythagorean Theorem.**
Given that $\triangle XYZ$ is right-angled at $X$, with $YX=60$ and $XZ=80$, we apply the Pythagorean Theorem:
\begin{align*}
YZ^2 &= YX... | [
{
"content": "In the diagram, $\\triangle XYZ$ is right-angled at $X,$ with $YX=60$ and $XZ=80.$ The point $W$ is on $YZ$ so that $WX$ is perpendicular to $YZ.$ Determine the length of $WZ.$ [asy]\npair X, Y, Z, W;\nY=(0,0);\nX=(36,48);\nZ=(100,0);\nW=(36,0);\ndraw(X--Y--Z--X--W);\nlabel(\"Y\", Y, SW);\nlabel(\... |
math | In the diagram, there are more than three triangles. If each triangle has the same probability of being selected, what is the probability that a selected triangle has all or part of its interior shaded? Express your answer as a common fraction.
[asy]
draw((0,0)--(1,0)--(0,1)--(0,0)--cycle,linewidth(1));
draw((0,0)--(.... | To solve this problem, we first need to identify all the triangles in the diagram and then determine which of these triangles have all or part of their interior shaded.
Step 1: Identify all the triangles in the diagram.
- The triangles that can be formed are: $AEC$, $AEB$, $BED$, $BEC$, and $BDC$.
Step 2: Determine ... | [
{
"content": "In the diagram, there are more than three triangles. If each triangle has the same probability of being selected, what is the probability that a selected triangle has all or part of its interior shaded? Express your answer as a common fraction.\n\n[asy]\ndraw((0,0)--(1,0)--(0,1)--(0,0)--cycle,line... |
math | In the diagram below, $AB = AC = 115,$ $AD = 38,$ and $CF = 77.$ Compute $\frac{[CEF]}{[DBE]}.$
[asy]
unitsize(0.025 cm);
pair A, B, C, D, E, F;
B = (0,0);
C = (80,0);
A = intersectionpoint(arc(B,115,0,180),arc(C,115,0,180));
D = interp(A,B,38/115);
F = interp(A,C,(115 + 77)/115);
E = extension(B,C,D,F);
draw(C--B... | Given that $AB = 115$ and $AD = 38$, we can find the length of $BD$ by subtracting the length of $AD$ from $AB$:
\[BD = AB - AD = 115 - 38 = 77.\]
Next, we represent the points as vectors, where $\mathbf{a}$ denotes $\overrightarrow{A}$, and similarly for other points. Given $AD = 38$ and $BD = 77$, we express $\mathb... | [
{
"content": "In the diagram below, $AB = AC = 115,$ $AD = 38,$ and $CF = 77.$ Compute $\\frac{[CEF]}{[DBE]}.$\n\n[asy]\nunitsize(0.025 cm);\n\npair A, B, C, D, E, F;\n\nB = (0,0);\nC = (80,0);\nA = intersectionpoint(arc(B,115,0,180),arc(C,115,0,180));\nD = interp(A,B,38/115);\nF = interp(A,C,(115 + 77)/115);\... |
math | In the diagram, what is the value of $y$?
[asy]
draw((0,0)--(18,0),black+linewidth(1));
draw((18,0)--(18,-6),black+linewidth(1));
draw((0,0)--(4,6)--(18,-6),black+linewidth(1));
draw((18,0)--(18,-0.5)--(17.5,-0.5)--(17.5,0)--cycle,black+linewidth(1));
label("$80^{\circ}$",(4.5,5),S);
label("$60^{\circ}$",(1,0),NE);
la... | To find the value of $y$ in the given diagram, we start by analyzing the triangle formed by points $A$, $B$, and $C$. We know that the sum of the angles in any triangle is $180^\circ$. Given that $\angle ABC = 80^\circ$ and $\angle BAC = 60^\circ$, we can find $\angle BCA$ using the formula for the sum of angles in a t... | [
{
"content": "In the diagram, what is the value of $y$?\n\n[asy]\ndraw((0,0)--(18,0),black+linewidth(1));\ndraw((18,0)--(18,-6),black+linewidth(1));\ndraw((0,0)--(4,6)--(18,-6),black+linewidth(1));\ndraw((18,0)--(18,-0.5)--(17.5,-0.5)--(17.5,0)--cycle,black+linewidth(1));\nlabel(\"$80^{\\circ}$\",(4.5,5),S);\nl... |
math | In the diagram below, $\overline{AB}\parallel \overline{CD}$ and $\angle AXF= 118^\circ$. Find $\angle FYD$.
[asy]
unitsize(1inch);
pair A,B,C,D,X,Y,EE,F;
A = (0,0);
B=(1,0);
C = (0,0.8);
D=(1,0.8);
EE = (0.35,-0.3);
F = (0.8,1.1);
draw(EE--F);
draw(A--B);
draw(C--D);
dot(A);
dot(B);
dot(C);
dot(D);
dot(EE);
dot(F);
... | Given that $\overline{AB} \parallel \overline{CD}$, we can apply the concept of alternate interior angles and linear pairs to find the measure of $\angle FYD$.
First, we recognize that $\angle AXF$ and $\angle FYD$ form a linear pair because the lines are parallel and the angles are on the same side of the transversa... | [
{
"content": "In the diagram below, $\\overline{AB}\\parallel \\overline{CD}$ and $\\angle AXF= 118^\\circ$. Find $\\angle FYD$.\n\n[asy]\nunitsize(1inch);\npair A,B,C,D,X,Y,EE,F;\nA = (0,0);\nB=(1,0);\nC = (0,0.8);\nD=(1,0.8);\nEE = (0.35,-0.3);\nF = (0.8,1.1);\ndraw(EE--F);\ndraw(A--B);\ndraw(C--D);\ndot(A);... |
math | What is the perimeter of pentagon $ABCDE$ in this diagram? [asy]
pair cis(real r,real t) { return (r*cos(t),r*sin(t)); }
pair a=(0,0);
pair b=cis(1,-pi/2);
pair c=cis(sqrt(2),-pi/4);
pair d=cis(sqrt(3),-pi/4+atan(1/sqrt(2)));
pair e=cis(2,-pi/4+atan(1/sqrt(2))+atan(1/sqrt(3)));
dot(a); dot(b); dot(c); dot(d); dot(e);
d... | To find the perimeter of pentagon $ABCDE$, we will use the Pythagorean theorem to calculate the lengths of the sides $AC$, $AD$, and $AE$.
First, we calculate the length of $AC$:
\begin{align*}
AC^2 &= AB^2 + BC^2 \\
&= 1^2 + 1^2 \\
&= 1 + 1 \\
&= 2.
\end{align*}
Therefore, $AC = \sqrt{2}$.
Next, we calculate the len... | [
{
"content": "What is the perimeter of pentagon $ABCDE$ in this diagram? [asy]\npair cis(real r,real t) { return (r*cos(t),r*sin(t)); }\npair a=(0,0);\npair b=cis(1,-pi/2);\npair c=cis(sqrt(2),-pi/4);\npair d=cis(sqrt(3),-pi/4+atan(1/sqrt(2)));\npair e=cis(2,-pi/4+atan(1/sqrt(2))+atan(1/sqrt(3)));\ndot(a); dot(... |
math | In the diagram, $\angle PQR=\angle PRQ$. If $QR=5$ and $PR=7$, what is the perimeter of $\triangle PQR$? [asy]
draw((0,0)--(2.5,7.43)--(5,0)--cycle);
label("5",(2.5,0),S);
label("$Q$",(0,0),SW);
label("$R$",(5,0),SE);
label("$P$",(2.5,7.43),N);
label("7",(4.2,3.7));
[/asy] | Given that $\angle PQR = \angle PRQ$, we can deduce that $\triangle PQR$ is an isosceles triangle. This means that two of its sides are equal in length. Specifically, since $\angle PQR$ and $\angle PRQ$ are the angles opposite the sides $PQ$ and $PR$ respectively, and these angles are equal, it follows that the sides o... | [
{
"content": "In the diagram, $\\angle PQR=\\angle PRQ$. If $QR=5$ and $PR=7$, what is the perimeter of $\\triangle PQR$? [asy]\ndraw((0,0)--(2.5,7.43)--(5,0)--cycle);\nlabel(\"5\",(2.5,0),S);\nlabel(\"$Q$\",(0,0),SW);\nlabel(\"$R$\",(5,0),SE);\nlabel(\"$P$\",(2.5,7.43),N);\nlabel(\"7\",(4.2,3.7));\n[/asy]",
... |
math | In the diagram, $AOB$ is a sector of a circle with $\angle AOB=60^\circ.$ $OY$ is drawn perpendicular to $AB$ and intersects $AB$ at $X.$ What is the length of $XY
?$ [asy]
draw((0,0)--(12,0),black+linewidth(1));
draw((0,0)--(10.3923,-6)..(12,0)..(10.3923,6)--(0,0),black+linewidth(1));
draw((10.3923,-6)--(10.3923,6),b... | To solve for the length of $XY$ in the given diagram, we follow these steps:
1. Recognize that $OY$ is a radius of the circle with center $O$, which means $OY = 12$.
2. Understand that since $OA = OB$, $\triangle OAB$ is isosceles.
3. Given $\angle AOB = 60^\circ$, we calculate the angle $\angle OAB$ as follows:
... | [
{
"content": "In the diagram, $AOB$ is a sector of a circle with $\\angle AOB=60^\\circ.$ $OY$ is drawn perpendicular to $AB$ and intersects $AB$ at $X.$ What is the length of $XY\n?$ [asy]\ndraw((0,0)--(12,0),black+linewidth(1));\ndraw((0,0)--(10.3923,-6)..(12,0)..(10.3923,6)--(0,0),black+linewidth(1));\ndraw... |
math | In the diagram, $RSP$ is a straight line and $\angle QSP = 80^\circ$. What is the measure of $\angle PQR$, in degrees?
[asy]
draw((.48,-.05)--(.48,.05)); draw((.52,-.05)--(.52,.05)); draw((1.48,-.05)--(1.48,.05)); draw((1.52,-.05)--(1.52,.05));
draw((1.04,.51)--(1.14,.49)); draw((1.03,.47)--(1.13,.45));
draw((0,0)--... | Given that $RSP$ is a straight line, we can deduce that the angles along this line must sum up to $180^\circ$. Therefore, we have:
\[
\angle RSQ + \angle QSP = 180^\circ
\]
Given that $\angle QSP = 80^\circ$, we can substitute this value into the equation to find $\angle RSQ$:
\[
\angle RSQ = 180^\circ - 80^\circ = 100... | [
{
"content": "In the diagram, $RSP$ is a straight line and $\\angle QSP = 80^\\circ$. What is the measure of $\\angle PQR$, in degrees?\n\n[asy]\ndraw((.48,-.05)--(.48,.05)); draw((.52,-.05)--(.52,.05)); draw((1.48,-.05)--(1.48,.05)); draw((1.52,-.05)--(1.52,.05));\n\ndraw((1.04,.51)--(1.14,.49)); draw((1.03,.... |
math | Two right triangles, $ABC$ and $ACD$, are joined as shown. Squares are drawn on four of the sides. The areas of three of the squares are 9, 16 and 36 square units. What is the number of square units in the area of the fourth square?
Note that the diagram is not drawn to scale.
[asy]
defaultpen(linewidth(0.7));
draw((... | To solve this problem, we can follow the steps below using the information given and applying the Pythagorean theorem to the right triangles $ABC$ and $ACD$.
1. **Identify the areas of the squares**: We are given that the areas of three of the squares are 9, 16, and 36 square units. These correspond to the squares on ... | [
{
"content": "Two right triangles, $ABC$ and $ACD$, are joined as shown. Squares are drawn on four of the sides. The areas of three of the squares are 9, 16 and 36 square units. What is the number of square units in the area of the fourth square?\n\nNote that the diagram is not drawn to scale.\n\n[asy]\ndefault... |
math | What percent of square $ABCD$ is shaded? All angles in the diagram are right angles. [asy]
import graph;
defaultpen(linewidth(0.7));
xaxis(0,5,Ticks(1.0,NoZero));
yaxis(0,5,Ticks(1.0,NoZero));
fill((0,0)--(1,0)--(1,1)--(0,1)--cycle);
fill((2,0)--(3,0)--(3,3)--(0,3)--(0,2)--(2,2)--cycle);
fill((4,0)--(5,0)--(5,5)--(0... | To solve this problem, we start by calculating the area of the entire square $ABCD$. Since the side length of the square is $5$ units, the area of the square is calculated as follows:
\[ \text{Area of square} = \text{side}^2 = 5^2 = 25 \text{ square units} \]
Next, we calculate the shaded area. The shaded area consis... | [
{
"content": "What percent of square $ABCD$ is shaded? All angles in the diagram are right angles. [asy]\nimport graph;\ndefaultpen(linewidth(0.7));\n\nxaxis(0,5,Ticks(1.0,NoZero));\nyaxis(0,5,Ticks(1.0,NoZero));\n\nfill((0,0)--(1,0)--(1,1)--(0,1)--cycle);\nfill((2,0)--(3,0)--(3,3)--(0,3)--(0,2)--(2,2)--cycle)... |
math | In the diagram, $ABCD$ is a square with side length $6,$ and $WXYZ$ is a rectangle with $ZY=10$ and $XY=6.$ Also, $AD$ and $WX$ are perpendicular. If the shaded area is equal to half of the area of $WXYZ,$ what is the length of $AP?$
[asy]
draw((0,0)--(10,0)--(10,6)--(0,6)--cycle,black+linewidth(1));
draw((1.5,1)--(7.... | To solve this problem, let's break down the solution into detailed steps:
1. **Calculate the area of rectangle $WXYZ$:** Given that $ZY=10$ and $XY=6$, the area of rectangle $WXYZ$ can be calculated as the product of its length and width. Therefore, the area is $10 \times 6 = 60$.
2. **Determine the area of the shade... | [
{
"content": "In the diagram, $ABCD$ is a square with side length $6,$ and $WXYZ$ is a rectangle with $ZY=10$ and $XY=6.$ Also, $AD$ and $WX$ are perpendicular. If the shaded area is equal to half of the area of $WXYZ,$ what is the length of $AP?$\n\n[asy]\ndraw((0,0)--(10,0)--(10,6)--(0,6)--cycle,black+linewid... |
math | Regular hexagon $ABCDEF$ is divided into six smaller equilateral triangles, such as $\triangle ABG$, shown in boldface in the diagram. By connecting every other vertex, we obtain a larger equilateral triangle $\triangle ACE$, also shown in boldface. Compute the ratio $[\triangle ABG]/[\triangle ACE]$. [asy]
size(150)... | To solve for the ratio $[\triangle ABG]/[\triangle ACE]$, we first observe that the regular hexagon $ABCDEF$ is divided into six smaller equilateral triangles that are congruent. Let's denote the area of each small equilateral triangle as $K$.
1. The area of $\triangle ABG$ can be calculated by noting that it is compo... | [
{
"content": "Regular hexagon $ABCDEF$ is divided into six smaller equilateral triangles, such as $\\triangle ABG$, shown in boldface in the diagram. By connecting every other vertex, we obtain a larger equilateral triangle $\\triangle ACE$, also shown in boldface. Compute the ratio $[\\triangle ABG]/[\\trian... |
math | The pattern of Pascal's triangle is illustrated in the diagram shown. What is the fourth element in Row 15 of Pascal's triangle? $$
\begin{array}{ccccccccccccc}\vspace{0.1in}
\textrm{Row 0}: & \qquad & & & & & 1 & & & & & & \\ \vspace{0.1in}
\textrm{Row 1}: & \qquad & & & & 1 & & 1 & & & & &\\ \vspace{0.1in}
\textrm{R... | To find the fourth element in Row 15 of Pascal's triangle, we utilize the formula for the $k^\text{th}$ element in row $n$, which is given by $\binom{n}{k-1}$. For the fourth element, $k=4$, and the row is $15$, so we are looking for $\binom{15}{3}$.
Starting with the formula for combinations, we have:
$$\binom{15}{3}... | [
{
"content": "The pattern of Pascal's triangle is illustrated in the diagram shown. What is the fourth element in Row 15 of Pascal's triangle? $$\n\\begin{array}{ccccccccccccc}\\vspace{0.1in}\n\\textrm{Row 0}: & \\qquad & & & & & 1 & & & & & & \\\\ \\vspace{0.1in}\n\\textrm{Row 1}: & \\qquad & & & & 1 & & 1 & ... |
math | In the diagram, $\triangle PQR$ is right-angled at $P$ and has $PQ=2$ and $PR=2\sqrt{3}$. Altitude $PL$ intersects median $RM$ at $F$. What is the length of $PF$? [asy]
draw((0,0)--(10,0)--(0,10*sqrt(3))--cycle);
draw((0,0)--(7.5,4.33)); draw((0,10*sqrt(3))--(5,0));
draw((6.68,3.86)--(7.17,3.01)--(7.99,3.49));
label(... | To solve for the length of $PF$, we follow these steps:
1. **Find the length of $PM$ and $MQ$:** Since $PQ=2$ and $M$ is the midpoint of $PQ$, we have $PM = MQ = \frac{1}{2}(2) = 1$.
2. **Use the Pythagorean Theorem to find $RQ$:** Since $\triangle PQR$ is right-angled at $P$, we apply the Pythagorean Theorem to get ... | [
{
"content": "In the diagram, $\\triangle PQR$ is right-angled at $P$ and has $PQ=2$ and $PR=2\\sqrt{3}$. Altitude $PL$ intersects median $RM$ at $F$. What is the length of $PF$? [asy]\ndraw((0,0)--(10,0)--(0,10*sqrt(3))--cycle);\ndraw((0,0)--(7.5,4.33)); draw((0,10*sqrt(3))--(5,0));\ndraw((6.68,3.86)--(7.17,... |
math | In the diagram, each of the three identical circles touch the other two. The circumference of each circle is 36. What is the perimeter of the shaded region? [asy]
defaultpen(1);
path p = (1, 0){down}..{-dir(30)}dir(-60){dir(30)}..{dir(-30)}((2, 0) + dir(-120)){-dir(-30)}..{up}(1, 0)--cycle;
fill(p, gray(0.75));
dr... | To solve for the perimeter of the shaded region in the diagram with three identical circles touching each other, we follow these steps:
1. **Identify the Key Components**: Each circle touches the other two, and the circumference of each circle is given as $36$. We are asked to find the perimeter of the shaded region.
... | [
{
"content": "In the diagram, each of the three identical circles touch the other two. The circumference of each circle is 36. What is the perimeter of the shaded region? [asy]\n\ndefaultpen(1);\n\npath p = (1, 0){down}..{-dir(30)}dir(-60){dir(30)}..{dir(-30)}((2, 0) + dir(-120)){-dir(-30)}..{up}(1, 0)--cycle... |
math | In the diagram, $l\|k$. What is the number of degrees in $\angle SRQ$? [asy]
draw((-.4,-.4)--(2,2)--(2,-.4));
draw((-.5,0)--(3,0),Arrows);
draw((-.5,1)--(3,1),Arrows);
draw((1.9,0)--(1.9,.1)--(2,.1));
label("$S$",(1,1),NNW);
label("$R$",(2,2),N);
label("$Q$",(2,1),NE);
label("$l$",(3,1),E);
label("$k$",(3,0),E);
label(... | Given that line $l$ is parallel to line $k$, and the angle measure of $\angle RSQ$ is given as $130^\circ$, we aim to find the measure of $\angle SRQ$ in the triangle $RSQ$.
1. Since line $RQ$ is perpendicular to line $k$ (as indicated by the right angle), and given that $l\|k$, it follows that line $RQ$ is also perpe... | [
{
"content": "In the diagram, $l\\|k$. What is the number of degrees in $\\angle SRQ$? [asy]\ndraw((-.4,-.4)--(2,2)--(2,-.4));\ndraw((-.5,0)--(3,0),Arrows);\ndraw((-.5,1)--(3,1),Arrows);\ndraw((1.9,0)--(1.9,.1)--(2,.1));\nlabel(\"$S$\",(1,1),NNW);\nlabel(\"$R$\",(2,2),N);\nlabel(\"$Q$\",(2,1),NE);\nlabel(\"$l$\... |
math | In the diagram, $PQRS$ is a trapezoid with an area of $12.$ $RS$ is twice the length of $PQ.$ What is the area of $\triangle PQS?$
[asy]
draw((0,0)--(1,4)--(7,4)--(12,0)--cycle);
draw((7,4)--(0,0));
label("$S$",(0,0),W);
label("$P$",(1,4),NW);
label("$Q$",(7,4),NE);
label("$R$",(12,0),E);
[/asy] | To solve this problem, we start by understanding the relationship between the areas of the triangles $\triangle PQS$ and $\triangle SRQ$ within the trapezoid $PQRS$. Given that $PQ$ is parallel to $SR$, we know that the height from $PQ$ to $SR$ is the same for both triangles. This is a crucial observation because the a... | [
{
"content": "In the diagram, $PQRS$ is a trapezoid with an area of $12.$ $RS$ is twice the length of $PQ.$ What is the area of $\\triangle PQS?$\n\n[asy]\ndraw((0,0)--(1,4)--(7,4)--(12,0)--cycle);\ndraw((7,4)--(0,0));\nlabel(\"$S$\",(0,0),W);\nlabel(\"$P$\",(1,4),NW);\nlabel(\"$Q$\",(7,4),NE);\nlabel(\"$R$\",(... |
math | Sets $A$ and $B$, shown in the Venn diagram, are such that the total number of elements in set $A$ is twice the total number of elements in set $B$. Altogether, there are 3011 elements in the union of $A$ and $B$, and their intersection has 1000 elements. What is the total number of elements in set $A$?
[asy]
label("$... | To solve for the total number of elements in set $A$, we start by defining variables for the elements in sets $A$ and $B$. Let $a$ represent the total number of elements in set $A$, and let $b$ represent the total number of elements in set $B$. Given that the total number of elements in set $A$ is twice the total numbe... | [
{
"content": "Sets $A$ and $B$, shown in the Venn diagram, are such that the total number of elements in set $A$ is twice the total number of elements in set $B$. Altogether, there are 3011 elements in the union of $A$ and $B$, and their intersection has 1000 elements. What is the total number of elements in se... |
math | In the diagram, the smaller circles touch the larger circle and touch each other at the center of the larger circle. The radius of the larger circle is $6.$ What is the area of the shaded region?
[asy]
size(100);
import graph;
filldraw(Circle((0,0),2),mediumgray);
filldraw(Circle((-1,0),1),white);
filldraw(Circle((1,0... | To solve for the area of the shaded region, we follow these steps:
1. **Identify the Radius of the Smaller Circles**: The diagram shows two smaller circles touching each other and the larger circle at its center. The radius of the larger circle is given as $6$. By drawing the radius from the center of the larger circl... | [
{
"content": "In the diagram, the smaller circles touch the larger circle and touch each other at the center of the larger circle. The radius of the larger circle is $6.$ What is the area of the shaded region?\n\n[asy]\nsize(100);\nimport graph;\nfilldraw(Circle((0,0),2),mediumgray);\nfilldraw(Circle((-1,0),1),... |
math | In the diagram, $AB$ and $CD$ are straight lines. What is the value of $x?$ [asy]
draw((0,0)--(12,0));
draw((0,5)--(12,5));
draw((3,0)--(5,5)--(9,0));
label("$60^\circ$",(5,4.5),W);
label("$50^\circ$",(5.5,4.5),E);
label("$A$",(0,5),W);
label("$C$",(0,0),W);
label("$B$",(12,5),E);
label("$D$",(12,0),E);
label("$120^\ci... | To solve for the value of $x$ in the given diagram, we follow these steps:
1. We know that the sum of the angles in a triangle equals $180^\circ$. Given that $\angle AXB = 180^\circ$, we can find the angle $\angle YXZ$ by subtracting the angles $\angle AXZ$ and $\angle BXY$ from $180^\circ$:
\[
\angle YXZ = 180^... | [
{
"content": "In the diagram, $AB$ and $CD$ are straight lines. What is the value of $x?$ [asy]\ndraw((0,0)--(12,0));\ndraw((0,5)--(12,5));\ndraw((3,0)--(5,5)--(9,0));\nlabel(\"$60^\\circ$\",(5,4.5),W);\nlabel(\"$50^\\circ$\",(5.5,4.5),E);\nlabel(\"$A$\",(0,5),W);\nlabel(\"$C$\",(0,0),W);\nlabel(\"$B$\",(12,5),... |
math | In the diagram, triangles $ABC$ and $CBD$ are isosceles. The perimeter of $\triangle CBD$ is $19,$ the perimeter of $\triangle ABC$ is $20,$ and the length of $BD$ is $7.$ What is the length of $AB?$ [asy]
size(7cm);
defaultpen(fontsize(11));
pair b = (0, 0);
pair d = 7 * dir(-30);
pair a = 8 * dir(-140);
pair c = 6 ... | To solve the problem, we follow the given information and the properties of isosceles triangles step by step:
1. **Identify Isosceles Triangles**: We are given two isosceles triangles, $\triangle ABC$ and $\triangle CBD$. In isosceles triangles, two sides are equal in length.
2. **For $\triangle ABC$**: Since $\angl... | [
{
"content": "In the diagram, triangles $ABC$ and $CBD$ are isosceles. The perimeter of $\\triangle CBD$ is $19,$ the perimeter of $\\triangle ABC$ is $20,$ and the length of $BD$ is $7.$ What is the length of $AB?$ [asy]\n\nsize(7cm);\ndefaultpen(fontsize(11));\n\npair b = (0, 0);\npair d = 7 * dir(-30);\npair... |
math | In the diagram, the grid is made up of squares. What is the area of the shaded region? [asy]
size(8cm);
// Fill area
fill((0, 0)--(0, 2)--(3, 2)--(3, 3)--(7, 3)--(7, 4)--(12, 4)--cycle, gray(0.75));
defaultpen(1);
// Draw grid
draw((0, 0)--(12, 0));
draw((0, 1)--(12, 1));
draw((0, 2)--(12, 2));
draw((3, 3)--(12, 3)... | To find the area of the shaded region, we first calculate the area of the entire grid. The grid can be divided into three rectangles:
1. A rectangle with dimensions $2 \times 3$, giving an area of $2 \times 3 = 6$.
2. A rectangle with dimensions $3 \times 4$, giving an area of $3 \times 4 = 12$.
3. A rectangle with di... | [
{
"content": "In the diagram, the grid is made up of squares. What is the area of the shaded region? [asy]\n\nsize(8cm);\n\n// Fill area\nfill((0, 0)--(0, 2)--(3, 2)--(3, 3)--(7, 3)--(7, 4)--(12, 4)--cycle, gray(0.75));\n\ndefaultpen(1);\n\n// Draw grid\ndraw((0, 0)--(12, 0));\ndraw((0, 1)--(12, 1));\ndraw((0, ... |
math | In the diagram, $D$ and $E$ are the midpoints of $\overline{AB}$ and $\overline{BC}$ respectively. Find the sum of the slope and $y$-intercept of the line passing through the points $C$ and $D.$ [asy]
size(180); defaultpen(linewidth(.7pt)+fontsize(10pt));
pair A, B, C, D, E, F;
A=(0,6);
B=(0,0);
C=(8,0);
D=(0,3);
E=(4,... | To find the sum of the slope and $y$-intercept of the line passing through points $C$ and $D$, we first need to determine the coordinates of these points based on the given information.
1. **Finding Coordinates of $D$:**
Since $D$ is the midpoint of $\overline{AB}$, we use the midpoint formula to find its coordinat... | [
{
"content": "In the diagram, $D$ and $E$ are the midpoints of $\\overline{AB}$ and $\\overline{BC}$ respectively. Find the sum of the slope and $y$-intercept of the line passing through the points $C$ and $D.$ [asy]\nsize(180); defaultpen(linewidth(.7pt)+fontsize(10pt));\npair A, B, C, D, E, F;\nA=(0,6);\nB=(0... |
math | In the diagram, what is the measure of $\angle ACB$ in degrees? [asy]
size(250);
draw((-60,0)--(0,0));
draw((0,0)--(64.3,76.6)--(166,0)--cycle);
label("$A$",(64.3,76.6),N);
label("$93^\circ$",(64.3,73),S);
label("$130^\circ$",(0,0),NW);
label("$B$",(0,0),S);
label("$D$",(-60,0),S);
label("$C$",(166,0),S);
[/asy] | To find the measure of $\angle ACB$, we first look at the angles around point $B$. We know that the sum of angles on a straight line is $180^\circ$. Given that $\angle ABD = 130^\circ$, we can find $\angle ABC$ as follows:
\[
\angle ABC + \angle ABD = 180^\circ
\]
Substituting the given value of $\angle ABD$:
\[
\angle... | [
{
"content": "In the diagram, what is the measure of $\\angle ACB$ in degrees? [asy]\nsize(250);\ndraw((-60,0)--(0,0));\ndraw((0,0)--(64.3,76.6)--(166,0)--cycle);\nlabel(\"$A$\",(64.3,76.6),N);\nlabel(\"$93^\\circ$\",(64.3,73),S);\nlabel(\"$130^\\circ$\",(0,0),NW);\nlabel(\"$B$\",(0,0),S);\nlabel(\"$D$\",(-60,0... |
math | In the diagram, $D$ and $E$ are the midpoints of $\overline{AB}$ and $\overline{BC}$ respectively. Determine the sum of the $x$ and $y$ coordinates of $F$, the point of intersection of $\overline{AE}$ and $\overline{CD}$. [asy]
size(180); defaultpen(linewidth(.7pt)+fontsize(10pt));
pair A, B, C, D, E, F;
A=(0,6);
B=(0... | To solve this problem, we follow a step-by-step approach based on the given solution:
1. **Find the Coordinates of $E$**:
Since $E$ is the midpoint of $\overline{BC}$, we use the midpoint formula to find its coordinates. The midpoint formula is $\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)$, where $(x_1, y... | [
{
"content": "In the diagram, $D$ and $E$ are the midpoints of $\\overline{AB}$ and $\\overline{BC}$ respectively. Determine the sum of the $x$ and $y$ coordinates of $F$, the point of intersection of $\\overline{AE}$ and $\\overline{CD}$. [asy]\nsize(180); defaultpen(linewidth(.7pt)+fontsize(10pt));\npair A, ... |
math | In the diagram below, lines $k$ and $\ell$ are parallel. Find the measure of angle $x$ in degrees. [asy]
size(200);
import markers;
pair A = dir(-22)*(0,0);
pair B = dir(-22)*(4,0);
pair C = dir(-22)*(4,2);
pair D = dir(-22)*(0,2);
pair F = dir(-22)*(0,1.3);
pair G = dir(-22)*(4,1.3);
pair H = dir(-22)*(2,1);
pair I =... | To find the measure of angle $x$, we observe the diagram and focus on the three red lines, which are highlighted due to the parallel lines $k$ and $\ell$. By understanding the properties of parallel lines, we identify a pair of corresponding angles, one of which is given as $30^\circ$.
Given that lines $k$ and $\ell$ ... | [
{
"content": "In the diagram below, lines $k$ and $\\ell$ are parallel. Find the measure of angle $x$ in degrees. [asy]\nsize(200);\nimport markers;\npair A = dir(-22)*(0,0);\npair B = dir(-22)*(4,0);\npair C = dir(-22)*(4,2);\npair D = dir(-22)*(0,2);\npair F = dir(-22)*(0,1.3);\npair G = dir(-22)*(4,1.3);\np... |
math | Find $AX$ in the diagram.
[asy]
import markers;
real t=.56;
pair A=(0,0);
pair B=(3,2);
pair C=(.5,1.5);
pair X=t*A+(1-t)*B;
draw(C--A--B--C--X);
label("$A$",A,SW);
label("$B$",B,E);
label("$C$",C,N);
label("$X$",X,SE);
markangle(n=1,radius=15,A,C,X,marker(markinterval(stickframe(n=1),true)));
markangle(n... | To solve for $AX$ in the given diagram, we apply the Angle Bisector Theorem, which states that the ratio of the lengths of the sides opposite to the angles is equal to the ratio of the lengths of the segments the bisector divides the opposite side into. Therefore, we have:
\[
\frac{AC}{AX} = \frac{BC}{BX}
\]
Given th... | [
{
"content": "Find $AX$ in the diagram.\n\n[asy]\n\nimport markers;\n\nreal t=.56;\n\npair A=(0,0);\n\npair B=(3,2);\n\npair C=(.5,1.5);\n\npair X=t*A+(1-t)*B;\n\ndraw(C--A--B--C--X);\n\nlabel(\"$A$\",A,SW);\n\nlabel(\"$B$\",B,E);\n\nlabel(\"$C$\",C,N);\n\nlabel(\"$X$\",X,SE);\n\nmarkangle(n=1,radius=15,A,C,X,m... |
math | In the diagram, $\triangle ABE$, $\triangle BCE$ and $\triangle CDE$ are right-angled, with $\angle AEB=\angle BEC = \angle CED = 60^\circ$, and $AE=24$. [asy]
pair A, B, C, D, E;
A=(0,20.785);
B=(0,0);
C=(9,-5.196);
D=(13.5,-2.598);
E=(12,0);
draw(A--B--C--D--E--A);
draw(B--E);
draw(C--E);
label("A", A, N);
label("B",... | To find the perimeter of quadrilateral $ABCD$, we first need to calculate the lengths of its sides. Given that $\triangle ABE$, $\triangle BCE$, and $\triangle CDE$ are right-angled at $E$ and have angles of $60^\circ$, we recognize these as 30-60-90 triangles. In such triangles, the ratio of the longer leg to the hypo... | [
{
"content": "In the diagram, $\\triangle ABE$, $\\triangle BCE$ and $\\triangle CDE$ are right-angled, with $\\angle AEB=\\angle BEC = \\angle CED = 60^\\circ$, and $AE=24$. [asy]\npair A, B, C, D, E;\nA=(0,20.785);\nB=(0,0);\nC=(9,-5.196);\nD=(13.5,-2.598);\nE=(12,0);\ndraw(A--B--C--D--E--A);\ndraw(B--E);\ndr... |
math | In the diagram, $PQR$ is a straight line. What is the value of $x$?
[asy]
draw((-2,0)--(8,0),linewidth(0.7)); draw((8,0)--(5,-5.5)--(0,0),linewidth(0.7));
label("$P$",(-2,0),W); label("$Q$",(0,0),N); label("$R$",(8,0),E); label("$S$",(5,-5.5),S);
label("$136^\circ$",(0,0),SW); label("$64^\circ$",(7,0),S);
label("$x... | To find the value of $x$, we observe that $\angle PQS$ is an exterior angle of $\triangle QRS$. According to the exterior angle theorem, the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.
Given that $\angle PQS = 136^\circ$ and $\angle QRS = 64^\... | [
{
"content": "In the diagram, $PQR$ is a straight line. What is the value of $x$?\n\n[asy]\ndraw((-2,0)--(8,0),linewidth(0.7)); draw((8,0)--(5,-5.5)--(0,0),linewidth(0.7));\nlabel(\"$P$\",(-2,0),W); label(\"$Q$\",(0,0),N); label(\"$R$\",(8,0),E); label(\"$S$\",(5,-5.5),S);\n\nlabel(\"$136^\\circ$\",(0,0),SW); ... |
math | In the diagram, point $E$ lies on line segment $AB$, and triangles $AED$ and $BEC$ are isosceles. Also, $\angle DEC$ is twice $\angle ADE$. What is the measure of $\angle EBC$ in degrees? [asy]
import olympiad;
import math;
size(7cm);
// Draw triangles
pair a = (-2 * Cos(70), 0);
pair b = (1, 0);
pair c = dir(30);
pa... | Given that $\triangle ADE$ and $\triangle BEC$ are isosceles, and $\angle DEC$ is twice $\angle ADE$, we aim to find the measure of $\angle EBC$.
1. In $\triangle ADE$, since it is isosceles with $\angle AED=\angle EAD=70^\circ$, we can calculate $\angle ADE$ as follows:
\[
\angle ADE = 180^\circ - 2(70^\circ) =... | [
{
"content": "In the diagram, point $E$ lies on line segment $AB$, and triangles $AED$ and $BEC$ are isosceles. Also, $\\angle DEC$ is twice $\\angle ADE$. What is the measure of $\\angle EBC$ in degrees? [asy]\nimport olympiad;\nimport math;\n\nsize(7cm);\n\n// Draw triangles\npair a = (-2 * Cos(70), 0);\npair... |
math | In the diagram, four circles of radius 4 units intersect at the origin. What is the number of square units in the area of the shaded region? Express your answer in terms of $\pi$. [asy]
import olympiad; import geometry; size(100); defaultpen(linewidth(0.8));
fill(Arc((1,0),1,90,180)--Arc((0,1),1,270,360)--cycle,gray(0.... | To find the area of the shaded region, we first focus on one of the eight identical checkered regions. The area of this region can be calculated by subtracting the area of an isosceles right triangle from the area of a quarter-circle, both of which have sides or radii of length 4 units.
1. **Calculate the area of the ... | [
{
"content": "In the diagram, four circles of radius 4 units intersect at the origin. What is the number of square units in the area of the shaded region? Express your answer in terms of $\\pi$. [asy]\nimport olympiad; import geometry; size(100); defaultpen(linewidth(0.8));\nfill(Arc((1,0),1,90,180)--Arc((0,1),... |
math | In the diagram below, lines $k$ and $\ell$ are parallel. Find the measure of angle $x$ in degrees.
[asy]
size(200);
import markers;
pair A = dir(-22)*(0,0);
pair B = dir(-22)*(4,0);
pair C = dir(-22)*(4,2);
pair D = dir(-22)*(0,2);
pair F = dir(-22)*(0,1.3);
pair G = dir(-22)*(4,1.3);
pair H = dir(-22)*(2,1);
//mark... | To find the measure of angle $x$, we first observe the red triangle drawn in the diagram. This triangle has two angles measuring $30^\circ$ each. The sum of angles in a triangle is $180^\circ$, so we can calculate the third angle in the triangle as follows:
\[180^\circ - 30^\circ - 30^\circ = 120^\circ.\]
This means t... | [
{
"content": "In the diagram below, lines $k$ and $\\ell$ are parallel. Find the measure of angle $x$ in degrees.\n\n[asy]\nsize(200);\nimport markers;\npair A = dir(-22)*(0,0);\npair B = dir(-22)*(4,0);\npair C = dir(-22)*(4,2);\npair D = dir(-22)*(0,2);\npair F = dir(-22)*(0,1.3);\npair G = dir(-22)*(4,1.3);... |
math | In the diagram, what is the perimeter of polygon $PQRST$? [asy]
import olympiad;
size(6cm); // ADJUST
pair p = (0, 6);
pair q = (3, 6);
pair r = (3, 3);
pair t = (0, 0);
pair s = (7, 0);
draw(p--q--r--s--t--cycle);
label("$P$", p, NW);
label("$Q$", q, NE);
label("$R$", r, E + NE);
label("$S$", s, SE);
label("$T$",... | To find the perimeter of polygon $PQRST$, we follow these steps:
1. **Extend $QR$ to meet $TS$ at $X$.** This creates a new point $X$ on $TS$ such that $RX$ is an extension of $QR$.
2. **Determine the length of $QR$:** Since it is given that $PQ=QR$, and we know $PQ=3$ (from the diagram), we can conclude that $QR=3$.... | [
{
"content": "In the diagram, what is the perimeter of polygon $PQRST$? [asy]\n\nimport olympiad;\n\nsize(6cm); // ADJUST\n\npair p = (0, 6);\npair q = (3, 6);\n\npair r = (3, 3);\npair t = (0, 0);\npair s = (7, 0);\n\ndraw(p--q--r--s--t--cycle);\nlabel(\"$P$\", p, NW);\nlabel(\"$Q$\", q, NE);\nlabel(\"$R$\", r... |
math | In the diagram, $\triangle ABE$, $\triangle BCE$ and $\triangle CDE$ are right-angled, with $\angle AEB=\angle BEC = \angle CED = 60^\circ$, and $AE=24$. [asy]
pair A, B, C, D, E;
A=(0,20.785);
B=(0,0);
C=(9,-5.196);
D=(13.5,-2.598);
E=(12,0);
draw(A--B--C--D--E--A);
draw(B--E);
draw(C--E);
label("A", A, N);
label("B",... | To find the length of $CE$, we start by determining the length of $BE$ using the properties of right-angled triangles and the fact that $\angle AEB = 60^\circ$.
Given that $\triangle ABE$ is a right-angled triangle with $\angle AEB = 60^\circ$ and $AE = 24$, we can identify $AE$ as the hypotenuse and $BE$ as the short... | [
{
"content": "In the diagram, $\\triangle ABE$, $\\triangle BCE$ and $\\triangle CDE$ are right-angled, with $\\angle AEB=\\angle BEC = \\angle CED = 60^\\circ$, and $AE=24$. [asy]\npair A, B, C, D, E;\nA=(0,20.785);\nB=(0,0);\nC=(9,-5.196);\nD=(13.5,-2.598);\nE=(12,0);\ndraw(A--B--C--D--E--A);\ndraw(B--E);\ndr... |
math | In the diagram below, $BC$ is 8 cm. In square centimeters, what is the area of triangle $ABC$?
[asy]
defaultpen(linewidth(0.7));
draw((0,0)--(16,0)--(23,20)--cycle);
draw((16,0)--(23,0)--(23,20),dashed);
label("8 cm",(8,0),S);
label("10 cm",(23,10),E);
label("$A$",(23,20),N);
label("$B$",(0,0),SW);
label("$C$",(16,0)... | To find the area of triangle $ABC$, we use the formula for the area of a triangle, which is $\frac{1}{2}(\text{base})(\text{height})$. In this case, the base of the triangle is $BC$, which measures $8\, \text{cm}$, and the height of the triangle, which is perpendicular to $BC$, measures $10\, \text{cm}$.
Applying the... | [
{
"content": "In the diagram below, $BC$ is 8 cm. In square centimeters, what is the area of triangle $ABC$?\n\n[asy]\ndefaultpen(linewidth(0.7));\ndraw((0,0)--(16,0)--(23,20)--cycle);\ndraw((16,0)--(23,0)--(23,20),dashed);\nlabel(\"8 cm\",(8,0),S);\nlabel(\"10 cm\",(23,10),E);\nlabel(\"$A$\",(23,20),N);\nlabe... |
math | Find $AX$ in the diagram if $CX$ bisects $\angle ACB$.
[asy]
import markers;
real t=.56;
pair A=(0,0);
pair B=(3,2);
pair C=(.5,1.5);
pair X=t*A+(1-t)*B;
draw(C--A--B--C--X);
label("$A$",A,SW);
label("$B$",B,E);
label("$C$",C,N);
label("$X$",X,SE);
//markangle(n=1,radius=15,A,C,X,marker(markinterval(stickframe(n=1... | To solve for $AX$ in the given diagram where $CX$ bisects $\angle ACB$, we apply the Angle Bisector Theorem. This theorem states that the ratio of the lengths of the two segments created on one side of the bisected angle is equal to the ratio of the lengths of the other two sides of the triangle. In mathematical terms,... | [
{
"content": "Find $AX$ in the diagram if $CX$ bisects $\\angle ACB$.\n\n[asy]\nimport markers;\n\nreal t=.56;\npair A=(0,0);\npair B=(3,2);\npair C=(.5,1.5);\npair X=t*A+(1-t)*B;\n\ndraw(C--A--B--C--X);\n\nlabel(\"$A$\",A,SW);\nlabel(\"$B$\",B,E);\nlabel(\"$C$\",C,N);\nlabel(\"$X$\",X,SE);\n\n//markangle(n=1,r... |
math | In the following diagram, $AB=50$. Find $AX$.
[asy]
import markers;
real t=.67;
pair A=(0,0);
pair B=(3,-2);
pair C=(1.5,1.5);
pair X=t*A+(1-t)*B;
draw(C--A--B--C--X);
label("$A$",A,SW);
label("$B$",B,E);
label("$C$",C,N);
label("$X$",X,SW);
markangle(n=1,radius=15,A,C,X,marker(markinterval(stickframe(n=1),true))... | To solve for $AX$ in the given diagram, we apply the Angle Bisector Theorem, which states that the ratio of the lengths of the two segments created on one side of the triangle by the angle bisector is equal to the ratio of the lengths of the other two sides of the triangle. In mathematical terms, for triangle $ABC$ wit... | [
{
"content": "In the following diagram, $AB=50$. Find $AX$.\n\n[asy]\nimport markers;\n\nreal t=.67;\npair A=(0,0);\npair B=(3,-2);\npair C=(1.5,1.5);\npair X=t*A+(1-t)*B;\n\ndraw(C--A--B--C--X);\n\nlabel(\"$A$\",A,SW);\nlabel(\"$B$\",B,E);\nlabel(\"$C$\",C,N);\nlabel(\"$X$\",X,SW);\n\nmarkangle(n=1,radius=15,... |
math | In the diagram, $\triangle ABE$, $\triangle BCE$ and $\triangle CDE$ are right-angled, with $\angle AEB=\angle BEC = \angle CED = 60^\circ$, and $AE=24$. [asy]
pair A, B, C, D, E;
A=(0,20.785);
B=(0,0);
C=(9,-5.196);
D=(13.5,-2.598);
E=(12,0);
draw(A--B--C--D--E--A);
draw(B--E);
draw(C--E);
label("A", A, N);
label("B",... | To solve for the area of quadrilateral $ABCD$, we first need to determine the lengths of the sides of the triangles within the quadrilateral. Given that $\triangle ABE$, $\triangle BCE$, and $\triangle CDE$ are all right-angled at $E$ and have angles of $60^\circ$, they are 30-60-90 triangles. The side lengths in a 30-... | [
{
"content": "In the diagram, $\\triangle ABE$, $\\triangle BCE$ and $\\triangle CDE$ are right-angled, with $\\angle AEB=\\angle BEC = \\angle CED = 60^\\circ$, and $AE=24$. [asy]\npair A, B, C, D, E;\nA=(0,20.785);\nB=(0,0);\nC=(9,-5.196);\nD=(13.5,-2.598);\nE=(12,0);\ndraw(A--B--C--D--E--A);\ndraw(B--E);\ndr... |
math | A square and isosceles triangle of equal height are side-by-side, as shown, with both bases on the $x$-axis. The lower right vertex of the square and the lower left vertex of the triangle are at $(10, 0)$. The side of the square and the base of the triangle on the $x$-axis each equal $10$ units. A segment is drawn from... | To solve for the area of the shaded region, we first label the square, triangle, and intersections as shown in the diagram. We denote the square's vertices as $A$, $B$, $C$, and $D$, the triangle's vertices as $E$ and $F$, and the intersection points as $G$ and $H$.
Given that triangles $BCG$ and $FDG$ are congruent,... | [
{
"content": "A square and isosceles triangle of equal height are side-by-side, as shown, with both bases on the $x$-axis. The lower right vertex of the square and the lower left vertex of the triangle are at $(10, 0)$. The side of the square and the base of the triangle on the $x$-axis each equal $10$ units. A... |
math | In the diagram, square $ABCD$ has sides of length $4,$ and $\triangle ABE$ is equilateral. Line segments $BE$ and $AC$ intersect at $P.$ Point $Q$ is on $BC$ so that $PQ$ is perpendicular to $BC$ and $PQ=x.$ [asy]
pair A, B, C, D, E, P, Q;
A=(0,0);
B=(4,0);
C=(4,-4);
D=(0,-4);
E=(2,-3.464);
P=(2.535,-2.535);
Q=(4,-2.5... | To determine the measure of angle $BPC$, we start by analyzing the given information and applying geometric principles step by step.
1. **Identify $\angle ABE$ in $\triangle ABE$:**
Since $\triangle ABE$ is equilateral, all its angles are equal. Therefore, we have:
\[ \angle ABE = 60^\circ. \]
2. **Calculate $\... | [
{
"content": "In the diagram, square $ABCD$ has sides of length $4,$ and $\\triangle ABE$ is equilateral. Line segments $BE$ and $AC$ intersect at $P.$ Point $Q$ is on $BC$ so that $PQ$ is perpendicular to $BC$ and $PQ=x.$ [asy]\npair A, B, C, D, E, P, Q;\nA=(0,0);\nB=(4,0);\nC=(4,-4);\nD=(0,-4);\nE=(2,-3.464)... |
math | The diagram shows 28 lattice points, each one unit from its nearest neighbors. Segment $AB$ meets segment $CD$ at $E$. Find the length of segment $AE$.
[asy]
unitsize(0.8cm);
for (int i=0; i<7; ++i) {
for (int j=0; j<4; ++j) {
dot((i,j));
};}
label("$A$",(0,3),W);
label("$B$",(6,0),E);
label("$D$",(2,0),S);
label("$E$... | To solve the problem step by step, we first extend $\overline{DC}$ to $F$ to form a triangle $FAE$ and observe that triangle $FAE$ is similar to triangle $DBE$. The similarity ratio is determined by the lengths of the sides parallel to $AB$ and $CD$, which are $5$ units and $4$ units long, respectively. Therefore, the ... | [
{
"content": "The diagram shows 28 lattice points, each one unit from its nearest neighbors. Segment $AB$ meets segment $CD$ at $E$. Find the length of segment $AE$.\n\n[asy]\nunitsize(0.8cm);\nfor (int i=0; i<7; ++i) {\nfor (int j=0; j<4; ++j) {\ndot((i,j));\n};}\nlabel(\"$A$\",(0,3),W);\nlabel(\"$B$\",(6,0),E... |
math | In the diagram below, points $A$, $B$, $C$, and $P$ are situated so that $PA=2$, $PB=3$, $PC=4$, and $BC=5$. What is the maximum possible area of $\triangle ABC$? [asy]
defaultpen(linewidth(0.8)); size(150);
pair B = (0,0), C = (5,0), A = (2,3), P = (2.2,2);
draw(A--B--C--cycle^^B--P^^C--P^^A--P);
label("$A$",A,N); lab... | To solve for the maximum possible area of $\triangle ABC$, we follow these steps:
1. **Observation of $\triangle PBC$**:
- Given that $PB=3$, $PC=4$, and $BC=5$, we recognize that these lengths satisfy the Pythagorean theorem ($3^2 + 4^2 = 5^2$). Therefore, $\triangle PBC$ is a right triangle with the right angle a... | [
{
"content": "In the diagram below, points $A$, $B$, $C$, and $P$ are situated so that $PA=2$, $PB=3$, $PC=4$, and $BC=5$. What is the maximum possible area of $\\triangle ABC$? [asy]\ndefaultpen(linewidth(0.8)); size(150);\npair B = (0,0), C = (5,0), A = (2,3), P = (2.2,2);\ndraw(A--B--C--cycle^^B--P^^C--P^^A-... |
math | In the diagram, $PQ$ and $RS$ are diameters of a circle with radius 4. If $PQ$ and $RS$ are perpendicular, what is the area of the shaded region?
[asy]
size(120);
import graph;
fill((-1,-1)--(-1,1)--(1,1)--(1,-1)--cycle,mediumgray);
fill(Arc((0,0),sqrt(2),45,135)--cycle,mediumgray);fill(Arc((0,0),sqrt(2),225,315)--cy... | To find the area of the shaded region in the diagram, we start by recognizing that diameters $PQ$ and $RS$ intersect at the circle's center, denoted as $O$. The shaded region consists of two parts: the areas of $\triangle POS$ and $\triangle ROQ$, and the areas of sectors $POR$ and $SOQ$.
1. **Area of $\triangle POS$ ... | [
{
"content": "In the diagram, $PQ$ and $RS$ are diameters of a circle with radius 4. If $PQ$ and $RS$ are perpendicular, what is the area of the shaded region?\n\n[asy]\nsize(120);\nimport graph;\nfill((-1,-1)--(-1,1)--(1,1)--(1,-1)--cycle,mediumgray);\nfill(Arc((0,0),sqrt(2),45,135)--cycle,mediumgray);fill(Ar... |
math | The diagram below shows a $4\times4$ rectangular array of points, each of which is $1$ unit away from its nearest neighbors.
[asy] unitsize(0.25inch); defaultpen(linewidth(0.7)); int i, j; for(i = 0; i < 4; ++i) for(j = 0; j < 4; ++j) dot(((real)i, (real)j)); [/asy]
Define a growing path to be a sequence of distinc... | To solve this problem, we first need to understand the concept of a growing path and how it applies to a $4\times4$ grid of points. We'll follow the solution's approach closely, breaking it down into detailed steps.
1. **Labeling and Distance Calculation**:
- We label the points using coordinates $(x,y)$ where $0 \... | [
{
"content": "The diagram below shows a $4\\times4$ rectangular array of points, each of which is $1$ unit away from its nearest neighbors.\n[asy] unitsize(0.25inch); defaultpen(linewidth(0.7)); int i, j; for(i = 0; i < 4; ++i) \tfor(j = 0; j < 4; ++j) \t\tdot(((real)i, (real)j)); [/asy]\nDefine a growing path... |
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