Datasets:
problem stringlengths 15 3.63k | generated_solution stringlengths 190 5.26k | expected_answer stringlengths 1 281 | problem_source stringclasses 4
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values | source_row int64 16 333k | problem_id stringlengths 64 64 | problem_group_id stringlengths 64 64 | token_count int64 102 1.85k | nearest_benchmark_cosine float64 0.19 0.9 | messages listlengths 3 3 | source_dataset stringclasses 1
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Given the set of integers Z+, define a function g(x) = x^2 - |x-2| for all x in Z+. Is the function g(x) injective, surjective, or bijective? Explain your answer. | To determine whether the function $g(x) = x^2 - |x-2|$ is injective, surjective, or bijective, we need to analyze its properties.
Injective (One-to-One):
A function is injective if each output value corresponds to exactly one input value.
Let's consider two cases for $x \in Z^+$:
Case 1: $x \leq 2$
In this case, $|x... | \text{injective} | augmented_math | data/train_1M-00002-of-00003.parquet | 106,035 | 902007bad332b1492320947b8625f61aef83efdb15329e085cc6065fbe0f3f22 | 72d6c75b4a3b8f2833e6ffe59e63ff5bcd184c29481ea2fbbf9d009efdcbeea7 | 816 | 0.441834 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Given the set of integers Z+, define a function g(x) = x^2 - |x-2| for all x in Z+. Is the function g(x) injective, surjective, or bijective? Explain your answer.",
"role"... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Emily baked cookies for a party. She gave 3 cookies to her neighbor and ate 2 cookies herself. Her sister came over and ate 4 cookies. Then, her two friends arrived and each had 2 cookies. There were 5 cookies left. How many cookies did Emily bake? | To find out how many cookies Emily baked, we need to sum up all the cookies that were eaten and add them to the cookies that were left.
Emily gave 3 cookies to her neighbor, ate 2 cookies herself, her sister ate 4 cookies, and her two friends ate 2 * 2 = 4 cookies.
So the total number of cookies eaten is $3 + 2 + 4 + ... | 18 | augmented_gsm8k | data/train_1M-00000-of-00003.parquet | 111,121 | 7ae2e2640ff36c1f9aaa0782dee914a73e54664f9644ce786c376e74bcea38f3 | b8ea922f151a675d3d6d2115954040aa863300df3d79aba8b59c30f90cce0c59 | 240 | 0.769237 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Emily baked cookies for a party. She gave 3 cookies to her neighbor and ate 2 cookies herself. Her sister came over and ate 4 cookies. Then, her two friends arrived and each h... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $\alpha$ and $\beta$ be conjugate complex numbers such that $\frac{\alpha^2}{\beta}$ is a real number and $|\alpha + \beta| = 4.$ Find $|\alpha|.$ | Let $\alpha = a + bi$ and $\beta = a - bi$, where $a$ and $b$ are real numbers.
Then we have
\[ \frac{\alpha^2}{\beta} = \frac{(a + bi)^2}{a - bi} \]
To simplify this expression, multiply the numerator and denominator by the conjugate of the denominator, $a + bi$:
\[ \frac{(a + bi)^2(a + bi)}{(a - bi)(a + bi)} = \fra... | 4 | augmented_math | data/train_1M-00002-of-00003.parquet | 160,333 | da079945d60647203d7e69da585d7c39816cfe7bf667f4dd336de9486a6c8126 | ecc2a30364433d618155750ea46656512ade924b07c7e517a208c343259c3e13 | 672 | 0.44454 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $\\alpha$ and $\\beta$ be conjugate complex numbers such that $\\frac{\\alpha^2}{\\beta}$ is a real number and $|\\alpha + \\beta| = 4.$ Find $|\\alpha|.$",
"role": "... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
In triangle $ABC$, $A$ is a right angle, and the length of side $AB$ is $x$, where $x$ is a positive integer. The length of side $AC$ is $3$ units longer than the length of side $BC$. If the area of the triangle is $12$ square units, find the perimeter of the triangle. | Let the length of side $BC$ be $y$. Then the length of side $AC$ is $y + 3$.
The area of the triangle is given by:
\[ \frac{1}{2} \cdot x \cdot (y + 3) = 12 \Rightarrow x(y + 3) = 24 \]
Since $x$ is a positive integer, we can list the possible values of $x$ and $y + 3$ that multiply to $24$:
\begin{align*}
x &=... | 13 | augmented_math | data/train_1M-00002-of-00003.parquet | 41,694 | eff25013aa551f1b17e7ce88de943c345fe3c2676e9c0f270f3323d530b91f2b | 0ea3d593e0634bf78f4a6b1f59b087c2456c135e23a62f79fcfc4a9cfaefa25d | 910 | 0.644559 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "In triangle $ABC$, $A$ is a right angle, and the length of side $AB$ is $x$, where $x$ is a positive integer. The length of side $AC$ is $3$ units longer than the length of si... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Alex bikes 8 miles per hour. He bikes for 45 minutes on Monday, 2 hours on Tuesday, 30 minutes on Wednesday, and 1 hour on Thursday. If he wants to bike 30 miles for the week, how many minutes should he bike on Friday? | Let's analyze the problem step by step.
Alex bikes 8 miles per hour. To calculate the distance he bikes each day, we need to convert the time he bikes each day to hours and then multiply it by his speed.
On Monday, he bikes for 45 minutes, which is equal to 0.75 hours. So, he bikes 0.75 * 8 = 6 miles.
On Tuesday, he... | 0 | augmented_gsm8k | data/train_1M-00000-of-00003.parquet | 76,027 | 8ccf8534bcec5bf986c4cf0adf0d015232db0c68a2a519382a8c098ebd403c76 | 1d2195383bba6402876988a4ff75c6f37ae719d98b3b29670e064fa48b88e8b8 | 394 | 0.665546 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Alex bikes 8 miles per hour. He bikes for 45 minutes on Monday, 2 hours on Tuesday, 30 minutes on Wednesday, and 1 hour on Thursday. If he wants to bike 30 miles for the week,... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A water park has 120 people waiting to ride a water slide. The water slide has 8 tubes, and each tube can accommodate 3 people. How many times will the lifeguard need to send the tubes down the slide to give everyone in line a turn? | The water slide can accommodate 8 * 3 = 24 people at a time.
To give everyone a turn, we need to divide the total number of people (120) by the number of people that can be accommodated at a time (24).
120 / 24 = 5.
So the lifeguard needs to send the tubes down the slide \boxed{5} times. | 5 | augmented_gsm8k | data/train_1M-00000-of-00003.parquet | 246,193 | d7b6de84001174c4cf04e1a9339a035675b9859c5377334b3e68e3705019ef29 | 385c9fee1167bc4dffeda461d9ad99b9beb884ce8a4dd264f25e793ef50e7abd | 176 | 0.563347 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A water park has 120 people waiting to ride a water slide. The water slide has 8 tubes, and each tube can accommodate 3 people. How many times will the lifeguard need to send ... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $f(x) = 5x + 1$ and $g(x) = 2x^2 - 4$. If $f(g(x)) = 21$, find the value of $x$. | To find the value of $x$, we first need to find the expression for $f(g(x))$.
\[ f(g(x)) = f(2x^2 - 4) \]
Substitute $g(x) = 2x^2 - 4$ into the function $f$:
\[ f(g(x)) = 5(2x^2 - 4) + 1 \]
\[ f(g(x)) = 10x^2 - 20 + 1 \]
\[ f(g(x)) = 10x^2 - 19 \]
Now set $f(g(x))$ equal to $21$:
\[ 10x^2 - 19 = 21 \]
Solve for $... | 2 | augmented_math | data/train_1M-00001-of-00003.parquet | 267,414 | 841f0588fefb2c24ffba5a95537a2a41ec1eb0ef972027ce23b09977517f6c97 | eaa44cd01bae0cde6669fd44115db1bb0ae094561c6f83f47a2fc69cf1911b08 | 377 | 0.825324 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $f(x) = 5x + 1$ and $g(x) = 2x^2 - 4$. If $f(g(x)) = 21$, find the value of $x$.",
"role": "user"
},
{
"content": "To find the value of $x$, we first need to ... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Maya has 36 pencils in her pencil case. She has 18 red pencils, 10 black pencils, and the rest are yellow pencils. How many yellow pencils does Maya have? | To find the number of yellow pencils Maya has, we need to subtract the number of red and black pencils from the total number of pencils.
Total pencils = 36
Red pencils = 18
Black pencils = 10
Total pencils that are not yellow = Red pencils + Black pencils = 18 + 10 = 28
Number of yellow pencils = Total pencils - Tot... | 8 | augmented_gsm8k | data/train_1M-00000-of-00003.parquet | 23,028 | 5b3c75b8a63280ca61079a9192cb41ffee78092eba55b57c56e0db21a98d8d50 | abfef4886c4c1056ef8a01877d22db3e9950c41c07b2f68a538c33d27716517a | 187 | 0.680411 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Maya has 36 pencils in her pencil case. She has 18 red pencils, 10 black pencils, and the rest are yellow pencils. How many yellow pencils does Maya have?",
"role": "user"... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Given the quadratic equation $x^2 - 6x + 2 = 0,$ for what value of $k$ is the expression $\frac{k-3\sqrt{2}}{2}$ a root of this equation? | ## Step 1: Identify the given quadratic equation and the expression for the root.
The given quadratic equation is $x^2 - 6x + 2 = 0$, and the expression for the root is $\frac{k-3\sqrt{2}}{2}$.
## Step 2: Recall the formula for the roots of a quadratic equation.
The roots of a quadratic equation $ax^2 + bx + c = 0$ ar... | 8 | augmented_math | data/train_1M-00002-of-00003.parquet | 70,300 | 1016aa65df1be93609ead12aece430f5e73316830c7b2bfd847b3c05a59f2764 | e9cdc1a521fcd558a986ace134d21f542ce2fa471ba99b764c3eadfda39b490a | 920 | 0.517137 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Given the quadratic equation $x^2 - 6x + 2 = 0,$ for what value of $k$ is the expression $\\frac{k-3\\sqrt{2}}{2}$ a root of this equation?",
"role": "user"
},
{
"... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Ethan is preparing gift boxes of cookies for a holiday sale. He packs 6 boxes with 8 cookies in each box. How many boxes would he have if he put 10 cookies in each box instead? | To find the number of boxes, first, we need to find the total number of cookies.
Since Ethan packs 6 boxes with 8 cookies in each box, the total number of cookies is $8 * 6 = 48$.
If Ethan puts 10 cookies in each box, the total number of boxes will be $48 / 10 = 4.8$.
Since a fraction of a box does not make sense, we n... | 4 | augmented_gsm8k | data/train_1M-00001-of-00003.parquet | 167,076 | ed1fef9cdb03cc88b3ba0723336f544b8d01d2cddd7379c3917d876e0ce706b7 | 94b2e86e26ec0bec9620a27b80a08351336965c9150b47babb942b1a7beb74f6 | 194 | 0.720741 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Ethan is preparing gift boxes of cookies for a holiday sale. He packs 6 boxes with 8 cookies in each box. How many boxes would he have if he put 10 cookies in each box instead... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Maya discovered 3 beehives with 6 honeycombs each in a nearby forest and 2 hives with 4 honeycombs each in her backyard. There was also a hive with 5 honeycombs in her neighbor's garden. How many honeycombs did Maya find in total? | In the nearby forest, Maya found 3 beehives with 6 honeycombs each. So there were 3 * 6 = 18 honeycombs in the forest.
In her backyard, she found 2 hives with 4 honeycombs each. So there were 2 * 4 = 8 honeycombs in her backyard.
Additionally, she found a hive with 5 honeycombs in her neighbor's garden.
So the total nu... | 31 | augmented_gsm8k | data/train_1M-00000-of-00003.parquet | 176,091 | ded47f853723f94d892c5708c81f8dcea09e5a25aed064b164c05ddb7f7f446a | 5c6f4da33d219555fd207ad0cc0382f3ae0d99778c0b1068fd7c9677a03323e7 | 238 | 0.649241 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Maya discovered 3 beehives with 6 honeycombs each in a nearby forest and 2 hives with 4 honeycombs each in her backyard. There was also a hive with 5 honeycombs in her neighbo... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $r(x)$ be a rational function such that the graph of $y = r(x)$ has vertical asymptotes at $x = -2$ and $x = 3$, and a horizontal asymptote at $y = 2$. If $r(-3) = 0$, find $r(x)$. | A rational function $r(x)$ with vertical asymptotes at $x = -2$ and $x = 3$ must have the form:
\[ r(x) = \frac{a(x - p)}{(x + 2)(x - 3)} \]
where $p$ is the root of the numerator and $a$ is a constant.
Given that $r(-3) = 0$, we know that:
\[ r(-3) = \frac{a(-3 - p)}{(-3 + 2)(-3 - 3)} = 0 \Rightarrow a(-3 - p) = 0 \... | \frac{2(x + 3)}{(x + 2)(x - 3)} | augmented_math | data/train_1M-00002-of-00003.parquet | 329,330 | a97ed549c8e6c57e404ea94b44d2494519ca4fbe3f29b892ee489065053ae461 | 156713bfaa91d786de9b45bca2a774290ff9413d6f6c947b1f9958b4c3f1c1bc | 455 | 0.636771 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $r(x)$ be a rational function such that the graph of $y = r(x)$ has vertical asymptotes at $x = -2$ and $x = 3$, and a horizontal asymptote at $y = 2$. If $r(-3) = 0$, fi... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
In a four-dimensional space, there are four mutually orthogonal vectors: $\mathbf{u} = \begin{pmatrix} 2 \\ 0 \\ 0 \\ 1 \end{pmatrix},$ $\mathbf{v} = \begin{pmatrix} 0 \\ 3 \\ 1 \\ 0 \end{pmatrix},$ $\mathbf{w} = \begin{pmatrix} 0 \\ 0 \\ 1 \\ -1 \end{pmatrix},$ and $\mathbf{x} = \begin{pmatrix} 1 \\ 0 \\ 0 \\ 1 \end{p... | We have the following equation:
\[ \begin{pmatrix} -4 \\ 7 \\ 6 \\ 8 \end{pmatrix} = a \begin{pmatrix} 2 \\ 0 \\ 0 \\ 1 \end{pmatrix} + b \begin{pmatrix} 0 \\ 3 \\ 1 \\ 0 \end{pmatrix} + c \begin{pmatrix} 0 \\ 0 \\ 1 \\ -1 \end{pmatrix} + d \begin{pmatrix} 1 \\ 0 \\ 0 \\ 1 \end{pmatrix} \]
We need to find $a$, $b$, $c... | \left(-\frac{47}{3}, \frac{7}{3}, \frac{11}{3}, \frac{82}{3}\right) | augmented_math | data/train_1M-00000-of-00003.parquet | 201,030 | 36e55b76fe77fa88e2f7cfc887f29309f6ef8c2de64473ff3b67a19390758565 | 7b4b341eda47dd4743e38da7148df16ccf9de6111e5238a023d708f0d56ebae7 | 1,050 | 0.634456 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "In a four-dimensional space, there are four mutually orthogonal vectors: $\\mathbf{u} = \\begin{pmatrix} 2 \\\\ 0 \\\\ 0 \\\\ 1 \\end{pmatrix},$ $\\mathbf{v} = \\begin{pmatrix... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
What is the binary representation of the smallest positive integer that is divisible by 3 and has exactly 5 digits in base 8? | The smallest positive integer that has exactly 5 digits in base 8 is $10000_8$.
To find its decimal representation, we use the place values for base 8:
\[ 1 \cdot 8^4 + 0 \cdot 8^3 + 0 \cdot 8^2 + 0 \cdot 8^1 + 0 \cdot 8^0 = 4096 \]
Now, we need to find the smallest multiple of 3 that is greater than or equal to 4096... | 1000000000010_2 | augmented_math | data/train_1M-00001-of-00003.parquet | 47,708 | 65b7b40432e8a39db60737d669e83bebe40ef722a54d6ac669f47181ef40b0d2 | 2f7ece943a1e352753cfb62bbde3b8ec212514723c2825676e49b7ea25cc3bea | 380 | 0.627241 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "What is the binary representation of the smallest positive integer that is divisible by 3 and has exactly 5 digits in base 8?",
"role": "user"
},
{
"content": "The... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Lily and Finn are planning to decorate their house for a party. Lily has bought 3 packs of decorations while Finn has bought 2 packs. Lily's packs each contain 4 balloons and 6 streamers. Finn's packs each have 5 balloons and 8 streamers. In total, how many decorations do Lily and Finn have? | To find the total number of decorations, we first need to calculate the number of decorations each of them bought and then add them together.
Lily has 3 packs, each containing 4 balloons and 6 streamers.
So the total number of decorations Lily has is $3*(4+6) = 3*10 = 30$.
Finn has 2 packs, each containing 5 balloon... | 56 | augmented_gsm8k | data/train_1M-00002-of-00003.parquet | 287,581 | 1df279b81b2ba8bc20ce539c1396f86a775aa18fdef4f88a71b4fbbb0cc3f370 | 2a77c17b69726e9e0c2f6d98bfd4e132cf1bd058f716e22b49138f33575a1e4d | 251 | 0.596269 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Lily and Finn are planning to decorate their house for a party. Lily has bought 3 packs of decorations while Finn has bought 2 packs. Lily's packs each contain 4 balloons and ... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $\mathbf{u} = \begin{pmatrix} 2 \\ -3 \end{pmatrix}$ and $\mathbf{v} = \begin{pmatrix} 4 \\ 1 \end{pmatrix}.$ Find the area of the triangle with vertices $\mathbf{0},$ $\mathbf{u},$ and $\mathbf{v}.$ | The area of the triangle with vertices $\mathbf{0},$ $\mathbf{u},$ and $\mathbf{v}$ can be found using the formula:
\[ \text{Area} = \frac{1}{2} \begin{vmatrix} 2 & 4 \\ -3 & 1 \end{vmatrix} = \frac{1}{2}(2(1) - 4(-3)) = \frac{1}{2}(2 + 12) = \frac{1}{2}(14) = \boxed{7} \] | 7 | augmented_math | data/train_1M-00002-of-00003.parquet | 34,288 | b74914eaea2f732b7c364a2064601af342a279d7b570081dfbd06fa53781ba7f | 3e5a6d069fa8de9b5169b08faa2e2e3c576b191f7a5cd12b7a8c61f98e2e5d25 | 239 | 0.682197 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $\\mathbf{u} = \\begin{pmatrix} 2 \\\\ -3 \\end{pmatrix}$ and $\\mathbf{v} = \\begin{pmatrix} 4 \\\\ 1 \\end{pmatrix}.$ Find the area of the triangle with vertices $\\mat... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A brother and sister decided to open a joint savings account. The brother committed to saving $75 every week, while the sister committed to saving $150 every month. After 6 months of savings, they decided to invest one-third of their money in buying bonds. Each bond costs $25. How many bonds can they buy? | To solve this problem, we first need to calculate the total amount of money the brother and sister saved after 6 months.
The brother saves $75 every week. There are approximately 4 weeks in a month, so he saves $75 * 4 = 300$ every month. In 6 months, he will save $300 * 6 = 1800$.
The sister saves $150 every month. ... | 36 | augmented_gsm8k | data/train_1M-00001-of-00003.parquet | 202,940 | 1be0cf6ca1d70544b8fe550c09cbae353aeef78224bf8e17ae24846a0a1894b1 | 7ad2f6911cd31b7e1a37a473d7e5f5160bbe3793e555aa2bd3ebf9ab6093220c | 327 | 0.649792 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A brother and sister decided to open a joint savings account. The brother committed to saving $75 every week, while the sister committed to saving $150 every month. After 6 mo... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Every time Mark layers his foam sheets, their thickness triples. If the initial thickness is 2 inches, how thick will the layered foam sheets be after 3 layerings? | Let's compute the thickness after each layering.
The initial thickness is 2 inches.
After the first layering, the thickness triples to $2 * 3 = 6$ inches.
After the second layering, the thickness triples again to $6 * 3 = 18$ inches.
After the third layering, the thickness triples again to $18 * 3 = 54$ inches.
So, aft... | 54 | augmented_gsm8k | data/train_1M-00001-of-00003.parquet | 128,282 | 8df592db8823f56172d753bb6c9208924ed86f456178e89f89b461aa1891df5b | 448ce1960e708e340c3dab2bbcadb37c039033d7aae0cdc6d879f2016bc1867d | 175 | 0.442166 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Every time Mark layers his foam sheets, their thickness triples. If the initial thickness is 2 inches, how thick will the layered foam sheets be after 3 layerings?",
"role... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
What is the sum of the first 20 terms of the arithmetic sequence whose first term is -3 and common difference is 1/2? Express your answer as a decimal to the nearest tenth. | The sum of the first $n$ terms of an arithmetic sequence can be found using the formula:
\[ S_n = \frac{n}{2} [2a + (n - 1)d] \]
where $a$ is the first term, $d$ is the common difference, and $n$ is the number of terms.
Given:
- First term $a = -3$
- Common difference $d = 1/2$
- Number of terms $n = 20$
Substitute t... | 35.0 | augmented_math | data/train_1M-00002-of-00003.parquet | 48,710 | 248abd537cd71e72fb2097210cf6ce017787ad26f5dfd045e1252b118941adac | 1d398ca3cb9272d807438a91ff0d46de0e1764428ba163f980bc7e85377c3ce1 | 310 | 0.612715 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "What is the sum of the first 20 terms of the arithmetic sequence whose first term is -3 and common difference is 1/2? Express your answer as a decimal to the nearest tenth.",
... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
In $\triangle XYZ$, $X(1, 2)$, $Y(3, 5)$ and $Z(6, 1)$ are the vertices. If $\triangle XYZ$ is reflected about the line $y = 2x - 3$, what will be the coordinates of the image of point Z? | To reflect a point about a line, we can use the following steps:
1. Find the slope of the line. The line is $y = 2x - 3$, so the slope is $m = 2$.
2. Find the slope of the perpendicular line. The slope of the perpendicular line is the negative reciprocal of the slope of the original line, so $m_{\perp} = -1/2$.
3. F... | \left(-\frac{2}{5}, \frac{21}{5}\right) | augmented_math | data/train_1M-00000-of-00003.parquet | 321,094 | 450e86e28590a3c0344e5d76491367840c4502e14b99cdf94332198b7b02a5a3 | d43b8ddf68d2c43b1db913ee79ca9889b2e87de63bd478324efa764848cd722b | 589 | 0.696265 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "In $\\triangle XYZ$, $X(1, 2)$, $Y(3, 5)$ and $Z(6, 1)$ are the vertices. If $\\triangle XYZ$ is reflected about the line $y = 2x - 3$, what will be the coordinates of the ima... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A certain fruit salad contains a mixture of grapes and berries. If the grapes contain 80% water and the berries contain 60% water, what is the ratio of the weight of the grapes to the weight of the berries in the salad, if the overall water content of the salad is 72%? | Let the weight of the grapes be $g$ and the weight of the berries be $b$. The weight of water in the grapes is $0.8g$ and in the berries is $0.6b$. The total weight of water in the salad is $0.8g + 0.6b$. The total weight of the salad is $g + b$.
We know that the overall water content of the salad is 72%, so we can wr... | \frac{3}{2} | augmented_math | data/train_1M-00002-of-00003.parquet | 216,373 | e894b972ee4e1b59171916d7325365f6e50df130f13e922ca2b4c2515382c425 | 783fdf44ba973beb83e8949f4d3a7fb1e8760a53e9a15cfaf9cbe1def5ee66fe | 333 | 0.574784 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A certain fruit salad contains a mixture of grapes and berries. If the grapes contain 80% water and the berries contain 60% water, what is the ratio of the weight of the grape... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Find the value of $x$ that satisfies the equation $\sin x + \sin 2x + \sin 3x = 0$, where $0 < x < \frac{\pi}{2}$. | We have the equation $\sin x + \sin 2x + \sin 3x = 0$.
Use the sum-to-product identity to rewrite the equation:
\[ \sin x + \sin 3x = 2 \sin 2x \cos x \]
Now the equation becomes:
\[ 2 \sin 2x \cos x + \sin 2x = 0 \]
Factor out $\sin 2x$:
\[ \sin 2x (2 \cos x + 1) = 0 \]
We have two possible cases:
Case 1: $\sin 2... | \frac{\pi}{3} | augmented_math | data/train_1M-00000-of-00003.parquet | 261,301 | eb1b71d2de91a103beb2906f6f64b9feb21b182c48410c8fe91c08a125002cac | e19da4a3e30a9448f3e6b69b8619c3194baf265bcec24543d10c752f2b615eea | 381 | 0.513689 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Find the value of $x$ that satisfies the equation $\\sin x + \\sin 2x + \\sin 3x = 0$, where $0 < x < \\frac{\\pi}{2}$.",
"role": "user"
},
{
"content": "We have t... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Jacob spent eight hours to bake 16 cakes. How many hours will he have spent in total if he decides to bake 24 more cakes? | To find out how many hours Jacob spent to bake one cake, we divide 8 hours by 16 cakes.
So Jacob spent 8 / 16 = 0.5 hours to bake one cake.
To bake 24 more cakes he will spend 0.5 * 24 = 12 hours.
So in total Jacob will have spent 8 + 12 = 20 hours to bake all the cakes.
Thus Jacob will have spent \boxed{20} hours in t... | 20 | augmented_gsm8k | data/train_1M-00001-of-00003.parquet | 55,784 | f8824704087a71551b33b68b75a574fcf42b1a3a8d7a2a93587842b2f0fa5003 | 379af4ff5aebd8a618861bd588ec9105dd2e462ae0a3a608eff85bfdb3400ab5 | 172 | 0.688933 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Jacob spent eight hours to bake 16 cakes. How many hours will he have spent in total if he decides to bake 24 more cakes?",
"role": "user"
},
{
"content": "To find... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Maria has orange trees that produce 4 oranges each. If an orange can be sold for $2 and Maria needs $64, how many orange trees does she have to harvest? | Since each tree produces 4 oranges and each orange can be sold for $2, the total amount of money Maria can get from one tree is $2 * 4 = 8$.
To get $64, Maria needs to harvest $64 / 8 = 8$ trees.
Thus, Maria needs to harvest \boxed{8} trees. | 8 | augmented_gsm8k | data/train_1M-00001-of-00003.parquet | 289,813 | 113a36403b9b8b804ababd92ff85b29c76106ab57414e896a8868b7cf82007c5 | 121392aa5a68cce26e6e84fbe7bc8d4649bfbf90e7e6ff959bd22abe4a00ba49 | 145 | 0.691223 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Maria has orange trees that produce 4 oranges each. If an orange can be sold for $2 and Maria needs $64, how many orange trees does she have to harvest?",
"role": "user"
... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
What is the greatest common multiple of 8 and 12 that is less than 90? | To find the greatest common multiple of 8 and 12 less than 90, we first find the least common multiple (LCM) of 8 and 12.
1. List the multiples of 8 and 12:
- Multiples of 8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96,...
- Multiples of 12: 12, 24, 36, 48, 60, 72, 84, 96,...
2. Identify the smallest number t... | 72 | math | data/train_1M-00000-of-00003.parquet | 156,418 | 3d76d6fc9fbcdec3614184b836dbb7461c1da7e73a5e7db04a6c6a7cc1ca94cf | 25ce86debd8dd56d69543372edd0f016dae7648a7d990fc0a76664bf3c8420ad | 347 | 0.588443 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "What is the greatest common multiple of 8 and 12 that is less than 90?",
"role": "user"
},
{
"content": "To find the greatest common multiple of 8 and 12 less than... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
The Franzia wine is three times as old as the Carlo Rosi, while the Carlo Rosi is four times older than the Twin Valley. Calculate the total age of the three brands of wine if the Carlo Rosi is 40 years old. | Let's break down the problem:
Carlo Rosi is 40 years old.
Franzia wine is three times as old as Carlo Rosi, so Franzia wine is 3 x 40 = 120 years old.
Carlo Rosi is four times older than Twin Valley, so Twin Valley is 40 / 4 = 10 years old.
The total age of the three brands of wine is 120 + 40 + 10 = 160 + 10 = 170 y... | 170 | gsm8k | data/train_1M-00002-of-00003.parquet | 139,497 | e9c041a151d182227107bc6a313b1f8774d183a661d51af7d51bd571710660fa | 49044c9b876b54030a949b4d20eafc5a85293d977d2f112386e90c08231091f3 | 224 | 0.466379 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "The Franzia wine is three times as old as the Carlo Rosi, while the Carlo Rosi is four times older than the Twin Valley. Calculate the total age of the three brands of wine i... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
There were 1800 stickers that were evenly divided into 6 albums. Emily took an album and used one-third of the stickers for her art project. How many stickers did Emily use? | There are 1800 stickers evenly divided into 6 albums.
This means each album has 1800 / 6 = 300 stickers.
Emily took one album, so she had 300 stickers to begin with.
She used one-third of these stickers, which is 300 / 3 = 100 stickers.
So Emily used \boxed{100} stickers. | 100 | augmented_gsm8k | data/train_1M-00000-of-00003.parquet | 260,303 | 80dd3be22d94248e9128e47c0715d6d241612ce7d207349864159fbb8d4c41dd | 24479bde3c55b9698cf03dca71aa1ce2bb8cdd5aec558c4d56232e2ca4830873 | 162 | 0.706742 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "There were 1800 stickers that were evenly divided into 6 albums. Emily took an album and used one-third of the stickers for her art project. How many stickers did Emily use?",... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let g(n) be the product of all the divisors of a positive integer n. If g(g(n)) = n^2 + 1, then call n super-abundant. How many super-abundant positive integers are there? | We have that $g(n)$ is the product of all the divisors of $n$. If $g(g(n)) = n^2 + 1$, then $g(n)$ must be equal to $n + 1$, since $g(n)$ is the product of all the divisors of $n$ and $n + 1$ is the only number whose product of divisors is $n^2 + 1$.
Now, if $g(n) = n + 1$, then $n$ must be a perfect square, since the... | 1 | augmented_math | data/train_1M-00002-of-00003.parquet | 278,218 | aaa1457f94eae6a70f0908bc086f9283efffa573bfdf9a98fb739bf3be2e4a30 | 3b746a95beea39088e18b7a0beec7df342e3854e3d06ccfa4f1e3e8b4e70ba71 | 369 | 0.486648 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let g(n) be the product of all the divisors of a positive integer n. If g(g(n)) = n^2 + 1, then call n super-abundant. How many super-abundant positive integers are there?",
... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $g(x)$ be a function defined as follows:
\[g(x) =
\begin{cases}
\lceil{x}\rceil^2 &\text{if }x\text{ is a rational number}, \\
2\lfloor{x}\rfloor-1 &\text{if }x\text{ is an irrational number}.
\end{cases}
\]
Find $g(\sqrt[3]{11})$. | Since $\sqrt[3]{11}$ is an irrational number, we use the formula:
\[ g(x) = 2\lfloor{x}\rfloor - 1 \]
Find $\lfloor{\sqrt[3]{11}}\rfloor$.
Given that $2^3 = 8$ and $3^3 = 27$, we know that:
\[ 2 < \sqrt[3]{11} < 3 \]
So, $\lfloor{\sqrt[3]{11}}\rfloor = 2$.
Now, substitute this value into the formula:
\[ g(\sqrt[3]{... | 3 | augmented_math | data/train_1M-00001-of-00003.parquet | 42,277 | 332ea0841b0f81253b4a48355d97e3c3cecc71a2c482e4866e96896fb8c8b282 | c152b31f24280c93bdf0c704982aa95107e7165f1f3d66b151f3694fd1a41a1c | 278 | 0.539959 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $g(x)$ be a function defined as follows:\n\n\\[g(x) =\n\\begin{cases}\n\\lceil{x}\\rceil^2 &\\text{if }x\\text{ is a rational number}, \\\\\n2\\lfloor{x}\\rfloor-1 &\\text... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Maya is biking 45 miles in 3 hours. How far will she go in 20 minutes? | To find out how far Maya will go in 20 minutes, we need to calculate her speed in miles per minute.
She bikes 45 miles in 3 hours. We convert 3 hours to minutes: 3 hours * 60 minutes/hour = 180 minutes.
Her speed is then 45 miles / 180 minutes = 0.25 miles per minute.
Now, to find out how far she goes in 20 minutes,... | 5 | augmented_gsm8k | data/train_1M-00002-of-00003.parquet | 316,635 | 4c64a6437ea4c1dba7c15508563236719341d5dff76873469f4a9576af06de80 | a136f00fc42e646e2a376e7f08bbe06458d87ca78551202ea0693ef9f70da60f | 201 | 0.603651 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Maya is biking 45 miles in 3 hours. How far will she go in 20 minutes?",
"role": "user"
},
{
"content": "To find out how far Maya will go in 20 minutes, we need to... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let g be a quadratic function for which $g(5)=g(3)=0$. Find $g(7)-g(1)$. | Given that $g(5) = g(3) = 0$, we can write the quadratic function $g(x)$ in factored form as:
\[ g(x) = a(x - 5)(x - 3) \]
where $a$ is a constant.
To find $g(7) - g(1)$, we substitute $x = 7$ and $x = 1$ into the function:
\[ g(7) = a(7 - 5)(7 - 3) = a(2)(4) = 8a \]
\[ g(1) = a(1 - 5)(1 - 3) = a(-4)(-2) = 8a \]
Now,... | 0 | augmented_math | data/train_1M-00001-of-00003.parquet | 204,910 | 87a4a9f956ab11f42c7c38f7bd7d4692c669f877ef7c27fbf3842c4fa14d0d21 | 47ce66d6be928f06cc9ea1d05482c9ac22cca1488696987f7be89b1ebd11d2e6 | 250 | 0.653026 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let g be a quadratic function for which $g(5)=g(3)=0$. Find $g(7)-g(1)$.",
"role": "user"
},
{
"content": "Given that $g(5) = g(3) = 0$, we can write the quadratic... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A bookshelf has 5 shelves, and each shelf can hold 8 rows of books, with each row containing 9 books. If the bookshelf is currently empty, what is the smallest number of books that need to be placed on it so that the total number of books is a multiple of 504? | Let's break down the information:
* Each shelf can hold 8 rows of books.
* Each row can hold 9 books.
* There are 5 shelves.
The total capacity of the bookshelf is:
\[ 5 \text{ shelves} \times 8 \text{ rows/shelf} \times 9 \text{ books/row} = 360 \text{ books} \]
We need to find the smallest number of books that, wh... | 144 | augmented_math | data/train_1M-00002-of-00003.parquet | 149,244 | d8a1831d26fe903a9e223f24e586169dea05a5642124158d11c1cf26b8f7b8ac | dc91901e8b4410118d326aa93e2ca1c843962bc76cf0ed395edfc2f7029c6bd8 | 381 | 0.725138 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A bookshelf has 5 shelves, and each shelf can hold 8 rows of books, with each row containing 9 books. If the bookshelf is currently empty, what is the smallest number of books... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Find the smallest positive integer that is equal to the sum of its distinct prime divisors. | We can start by testing small positive integers.
1. $n = 1$: It has no prime divisors.
2. $n = 2$: It is prime, so its only prime divisor is 2. $2 = 2$.
3. $n = 3$: It is prime, so its only prime divisor is 3. $3 = 3$.
4. $n = 4$: Its prime divisors are 2. $4 \neq 2$.
5. $n = 5$: It is prime, so its only prime divisor... | 6 | augmented_math | data/train_1M-00001-of-00003.parquet | 175,178 | aa6125c72100f19ea81a87fe466f45166003cc2169b4dba7e03197595214e7e2 | aa6125c72100f19ea81a87fe466f45166003cc2169b4dba7e03197595214e7e2 | 240 | 0.641964 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Find the smallest positive integer that is equal to the sum of its distinct prime divisors.",
"role": "user"
},
{
"content": "We can start by testing small positiv... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $a$, $b$, and $c$ be complex numbers such that $a + b + c = 1$ and $|a| = |b| = |c|$. Find $\frac{a}{b} + \frac{b}{c} + \frac{c}{a}$. | Let $r = |a| = |b| = |c|$. Then $a$, $b$, and $c$ lie on a circle of radius $r$ centered at the origin.
Since $a + b + c = 1$, the centroid of the triangle formed by $a$, $b$, and $c$ is $1/3$. This implies that the origin (the center of the circle) is also the centroid of the triangle.
Since the centroid and circumc... | 1 | augmented_math | data/train_1M-00001-of-00003.parquet | 218,160 | 9f4eb405d9a32ed653cc27ca9b524fdb1a0bc05acf43f5714894a5abb91b7d9d | 381fe03fb51c8cc178842b8f5eec4fe9ed8d55e75500d386a0fdd2e280c1acbc | 359 | 0.627317 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $a$, $b$, and $c$ be complex numbers such that $a + b + c = 1$ and $|a| = |b| = |c|$. Find $\\frac{a}{b} + \\frac{b}{c} + \\frac{c}{a}$.",
"role": "user"
},
{
... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A rectangular prism has a length of 10 cm, a width of 5 cm, and a height of 4 cm. If the length and width are both decreased by the same amount, while the height is increased by that same amount, what is the amount of the change if the resulting volume is equal to the original volume? Express your answer as a decimal. | The volume of a rectangular prism is given by the formula $V = lwh$, where $l$ is the length, $w$ is the width, and $h$ is the height.
The original volume is:
\[ V_{\text{original}} = lwh = 10 \times 5 \times 4 = 200 \, \text{cm}^3 \]
Let's denote the change in length and width by $x$. The new dimensions are:
\[ l_{\... | 1 | augmented_math | data/train_1M-00002-of-00003.parquet | 266,577 | 19caa1b673678b8f1d64386969257b85d885ab3d5ee5d738c830e672ba8e5be4 | df5543afd01a204c4ab2d974d462a904cd3cdf46800261603f04aa66b92ece30 | 610 | 0.53606 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A rectangular prism has a length of 10 cm, a width of 5 cm, and a height of 4 cm. If the length and width are both decreased by the same amount, while the height is increased ... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
The equation \[\frac{x^2}{25} + \frac{(z-3)^2}{64} = 0\]describes a degenerate ellipse. Determine the point on the graph of this equation that has the smallest $x$-coordinate. | The equation of a degenerate ellipse is
\[ \frac{x^2}{25} + \frac{(z-3)^2}{64} = 0 \]
Since the equation is the sum of two squares, both squares must be zero to satisfy the equation. Thus, we have
\[ \frac{x^2}{25} = 0 \quad \text{and} \quad \frac{(z-3)^2}{64} = 0 \]
Solving these two equations gives us
\[ x = 0 \qua... | (0, 3) | augmented_math | data/train_1M-00001-of-00003.parquet | 53,739 | 03eab1e6772bc85ade83cd71d5306c5d6fa39a39ac6619fe347d83a077ca053b | bd0bf271f328363fe922723a470b465295c03955397da5c33a96ce1be3d3a19e | 260 | 0.486186 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "The equation \\[\\frac{x^2}{25} + \\frac{(z-3)^2}{64} = 0\\]describes a degenerate ellipse. Determine the point on the graph of this equation that has the smallest $x$-coordin... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A bookshelf contains $n$ books, each labeled with a unique integer from $1$ to $n$. The books are arranged on the shelf in a seemingly random order. However, it is known that for any two adjacent books, the difference between their labels is either $1$ or $2$. What is the maximum possible value of $n$ such that there e... | Let's consider the possible arrangements of the books. Since the difference between the labels of any two adjacent books is either 1 or 2, we can start by placing the book with label 1 on the shelf.
There are two possible cases:
Case 1: The book with label 2 is placed next to the book with label 1.
In this case, the... | 8 | augmented_math | data/train_1M-00000-of-00003.parquet | 91,181 | aa38bdcfcab289649868bb7752d0a977cb9b20231785cc7fb43233a9fe695cb5 | 90d237f361120799ee1ce210d00af8b66fd8e1165d68c0ddfd8106347465e99c | 713 | 0.528965 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A bookshelf contains $n$ books, each labeled with a unique integer from $1$ to $n$. The books are arranged on the shelf in a seemingly random order. However, it is known that ... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A box contains 5 red balls, 3 blue balls, and 2 green balls. A ball is chosen at random, its color is noted, and then it is put back in the box. This process is repeated until a ball of each color has been chosen. What is the probability that this happens in exactly 5 draws? | Let's define the probability of drawing a red ball as $R$, a blue ball as $B$, and a green ball as $G$.
The total number of balls is $5 + 3 + 2 = 8 + 2 = 10$.
The probabilities are:
\[ R = \frac{5}{10} = \frac{1}{2} \]
\[ B = \frac{3}{10} \]
\[ G = \frac{2}{10} = \frac{1}{5} \]
We want to find the probability that w... | \frac{27}{200} | augmented_math | data/train_1M-00000-of-00003.parquet | 147,515 | cc779977dfcc79aee5f2375152813d3548d4be06262b931959871a8a2c3a2eaf | b458f05b0482eff5094ebe777f308fa5666cf798d5519427c34a2ca8e4bdb772 | 600 | 0.553403 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A box contains 5 red balls, 3 blue balls, and 2 green balls. A ball is chosen at random, its color is noted, and then it is put back in the box. This process is repeated until... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $a$, $b$ and $c$ be positive numbers satisfying
\begin{align*}
\log_c a & = bc - b + 1, \\
\log_b c & = ac - a - 1, \\
\log_a b & = ab - c - 1.
\end{align*}
Find $a + b + c$. | Since the problem involves logarithmic equations, we can start by using the properties of logarithms to simplify the given equations.
Recall that $\log_a b = c$ is equivalent to $a^c = b$.
1. $\log_c a = bc - b + 1$
\[ \Rightarrow c^{bc - b + 1} = a \]
2. $\log_b c = ac - a - 1$
\[ \Rightarrow b^{ac - a - 1} =... | 3 | augmented_math | data/train_1M-00000-of-00003.parquet | 275,415 | a36be81a1ec8e8a76e183cb5bb0f38cbc2abcc199b824af2070cb9a429d9e620 | af6b541282f2ce34c22f221cfaf42b057ee9bb80a8b10447354ce4f007548a40 | 712 | 0.466639 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $a$, $b$ and $c$ be positive numbers satisfying\n\\begin{align*}\n\\log_c a & = bc - b + 1, \\\\\n\\log_b c & = ac - a - 1, \\\\\n\\log_a b & = ab - c - 1.\n\\end{align*}\... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Find the maximum value of $3\cos^2 \theta + 4\sin \theta - 2\cos \theta + 5$ for $0 \leq \theta \leq 2\pi$. | We can express $3\cos^2 \theta$ in terms of $\sin^2 \theta$ by using the identity $\cos^2 \theta + \sin^2 \theta = 1$.
Substituting $3\cos^2 \theta = 3(1 - \sin^2 \theta)$, we get:
\[ 3\cos^2 \theta + 4\sin \theta - 2\cos \theta + 5 = 3(1 - \sin^2 \theta) + 4\sin \theta - 2\cos \theta + 5 = 8 - 3\sin^2 \theta + 4\sin \... | \frac{34}{3} | augmented_math | data/train_1M-00001-of-00003.parquet | 23,880 | 7895926e894e8fd01036c1651845c4914d8cf5db4c8367a471c968059e14a508 | 7ea35bc58d5aae659d2fa9b4779e92d7035bdc9649801cec1ec93de4b8d05837 | 598 | 0.465528 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Find the maximum value of $3\\cos^2 \\theta + 4\\sin \\theta - 2\\cos \\theta + 5$ for $0 \\leq \\theta \\leq 2\\pi$.",
"role": "user"
},
{
"content": "We can expr... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Ethan has yard work to do. He has a lawn that will take 90 minutes to mow and 30 minutes to edge. He has a garden that will take 75 minutes to weed and 45 minutes to water. He has a patio that will take 60 minutes to sweep and 40 minutes to clean. If he does one task at a time, how long will it take him to complete all... | To find the total time taken by Ethan to complete all tasks, we need to add the time taken by each task.
Time to mow the lawn: 90 minutes
Time to edge the lawn: 30 minutes
Total time for lawn: 90 + 30 = 120 minutes
Time to weed the garden: 75 minutes
Time to water the garden: 45 minutes
Total time for garden: 75 + 45... | 340 | augmented_gsm8k | data/train_1M-00001-of-00003.parquet | 64,672 | df795f5f8b74f358daa8bbaa3d48ab376e706eab857eae793bfb1cc4219f488c | 7fc77c671ff0537a9f05e81fe700598ba560954a128c08906cd7511c1f8ce866 | 333 | 0.684599 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Ethan has yard work to do. He has a lawn that will take 90 minutes to mow and 30 minutes to edge. He has a garden that will take 75 minutes to weed and 45 minutes to water. He... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
The ratio of $x+2$ to $2x+2$ is equal to the ratio of $4x+3$ to $7x+3$. What is the product of all real x which satisfy this statement?
If the ratio of $x+2$ to $2x+2$ is equal to the ratio of $4x+3$ to $7x+3$, then we can write:
$$\frac{x+2}{2x+2} = \frac{4x+3}{7x+3}$$
To solve for x, we can cross-multiply and sim... | $$\frac{x+2}{2x+2} = \frac{4x+3}{7x+3}$$
$$(x+2)(7x+3) = (4x+3)(2x+2)$$
$$7x^2 + 17x + 6 = 8x^2 + 14x + 6$$
$$-x^2 + 3x = 0$$
$$x(-x + 3) = 0$$
$$x = 0 \text{ or } x = 3$$
$$0 \times 3 = 0$$
The answer is $\boxed{0}.$ | 0 | augmented_math | data/train_1M-00001-of-00003.parquet | 228,647 | 5276c6a0a13a80f99b4a299a9afc39a372013b30c763d56de93bf7a9efe9274f | c400d78d5818f41f1c64d21b8c28a0c212324875cc30cce2583bb81cc26e8c99 | 465 | 0.490146 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "The ratio of $x+2$ to $2x+2$ is equal to the ratio of $4x+3$ to $7x+3$. What is the product of all real x which satisfy this statement?\n\nIf the ratio of $x+2$ to $2x+2$ is ... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A popular coffee shop typically serves 120 customers per hour. However, on Fridays, this number increases by 50%. If the coffee shop is open for 10 hours on a Friday, how many customers will it serve that day? | The coffee shop typically serves 120 customers per hour.
On Fridays, this number increases by 50%.
50% of 120 is 120 * 50 / 100 = 6000 / 100 = 60
So on Fridays, the coffee shop serves 120 + 60 = 180 customers per hour.
Since the coffee shop is open for 10 hours on a Friday, it will serve 180 * 10 = 1800 customers t... | 1800 | augmented_gsm8k | data/train_1M-00000-of-00003.parquet | 329,795 | 8039e3cfc7483a24c6544a26fc58175cdefcd3fc0d20a58b963694dc99c896ce | 25cc6afe11e769fa9b42a95ba89ec33b3b3cef69c0ccef0951d9b9ed532c825c | 230 | 0.586039 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A popular coffee shop typically serves 120 customers per hour. However, on Fridays, this number increases by 50%. If the coffee shop is open for 10 hours on a Friday, how many... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $T$ be the set of all possible remainders when a number of the form $3^n + 4^n$, $n$ a positive integer, is divided by 100. Let $U$ be the product of the elements in $T$. Find the remainder when $U$ is divided by 100. | We need to find the set $T$ of all possible remainders when $3^n + 4^n$ is divided by 100 for positive integers $n$.
Notice that we can rewrite $3^n + 4^n$ as follows:
\[ 3^n + 4^n = (3^n + 4^n) \mod 100 \]
To find the remainders, we can start by computing the first few values of $3^n + 4^n$ modulo 100:
\begin{ali... | 25 | augmented_math | data/train_1M-00002-of-00003.parquet | 232,419 | 7a4b977b0d1136431647a58d382708dbbacea6740d444fafd6bfc12473461490 | 731ade07a9de2843e8491154273f5964e7f4cea60085ee778211bfd6c462751b | 1,004 | 0.54128 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $T$ be the set of all possible remainders when a number of the form $3^n + 4^n$, $n$ a positive integer, is divided by 100. Let $U$ be the product of the elements in $T$. ... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
The line $y = m$ intersects the graph of the parabola $y = 3x^2 + 2x - 4$ at exactly one point. What is $m$? | For the line $y = m$ to intersect the parabola at exactly one point, the equation $3x^2 + 2x - 4 = m$ must have exactly one solution.
This means that the quadratic equation $3x^2 + 2x - (m + 4) = 0$ must have a discriminant of 0, so its solutions will be equal.
The discriminant of a quadratic equation $ax^2 + bx + c ... | -\frac{13}{3} | augmented_math | data/train_1M-00001-of-00003.parquet | 167,998 | 18f5b48adf96cc35b370a32c1c6a8e1a2ed4fc2ee4b1d21d4923ece8c8c01720 | b1d499076e0b0d9e9ae4299fefcf566f3157a8bc5866e44cc952bf65f9f66da9 | 295 | 0.561326 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "The line $y = m$ intersects the graph of the parabola $y = 3x^2 + 2x - 4$ at exactly one point. What is $m$?",
"role": "user"
},
{
"content": "For the line $y = m... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $A$, $B$, and $C$ be the vertices of an equilateral triangle, and let $\mathbf{P}$ be a matrix such that for any point $X$, $\mathbf{P}X$ is the image of $X$ under a $120^\circ$ counterclockwise rotation about the center of the triangle. Compute $\mathbf{P}^3$. | For an equilateral triangle, the center is also the centroid. Let the centroid be $O$. We know that $O$ is the average of the vertices $A$, $B$, and $C$, so $O = \frac{A + B + C}{3}$. Also, $A + B + C = 3O$.
Now, let's consider the effect of $\mathbf{P}$ on the vertices $A$, $B$, and $C$. Since $\mathbf{P}$ is a $120^... | \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix} | augmented_math | data/train_1M-00002-of-00003.parquet | 316,808 | 46e1312854029db12c287d2087f43c3085281724adb62c0ef6a2fbadaa836224 | 1d91e6fda01c30e301b4038b2de553d44986a6cef1593427c9e8675140ef1209 | 544 | 0.471784 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $A$, $B$, and $C$ be the vertices of an equilateral triangle, and let $\\mathbf{P}$ be a matrix such that for any point $X$, $\\mathbf{P}X$ is the image of $X$ under a $12... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A sequence of integers is defined recursively as follows:
The first term is 5 and each subsequent term is obtained by appending 3 to the end of the previous term.
For example, the second term is 53, the third term is 533, and the fourth term is 5333.
How many terms of this sequence are divisible by 7? | To determine how many terms of the sequence are divisible by 7, we can start by examining the pattern and checking divisibility for each term.
The terms are:
\[ 5, 53, 533, 5333, 53333, \ldots \]
We can check the divisibility of each term by 7:
- 5 is not divisible by 7.
- 53 is not divisible by 7.
- 533 is not divis... | 1 | augmented_math | data/train_1M-00000-of-00003.parquet | 283,553 | b22fce3c10c267480bad59445f2d7905d8318102ddfe9e8a5c6595f89c5e78e6 | 55b8d124a4b20cc925bab2fedb6a7b0ada717a33097a45d079274100c07d8ee9 | 934 | 0.555007 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A sequence of integers is defined recursively as follows: \nThe first term is 5 and each subsequent term is obtained by appending 3 to the end of the previous term. \nFor exam... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
500 students and 300 teachers attend a concert. The price of a teacher's ticket is three times that of a student's ticket. What is the price of a teacher's ticket if the total amount collected is $24,000? | Let's denote the price of a student's ticket as $x.
Then, the price of a teacher's ticket is $3x.
Given that 500 students and 300 teachers attended the concert and the total amount collected was $24,000, we can set up an equation:
\[500x + 300(3x) = 24,000\]
This simplifies to:
\[500x + 900x = 24,000\]
\[1400x = 24,000... | 51.42 | augmented_gsm8k | data/train_1M-00001-of-00003.parquet | 66,406 | fbd774f133522029c5cb54d10e97f7d18cdc50b8ad5ebcb1603e5ba4a6da7a8a | 19d3be537cc6cb73097fd45800c078ac866b8a6f918808d7784f0f8e0a8a8fe2 | 316 | 0.702846 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "500 students and 300 teachers attend a concert. The price of a teacher's ticket is three times that of a student's ticket. What is the price of a teacher's ticket if the total... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Calculate the sum of the areas of two rectangles, one with a length of 8 feet and a width of $\frac{2}{3}$ yards, and the other with a length of 6 yards and a width of $\frac{3}{4}$ feet. | Convert both rectangles' dimensions to feet to facilitate the calculation.
Rectangle 1:
- Length = 8 feet
- Width = $\frac{2}{3}$ yards = $\frac{2}{3} \times 3$ feet = 2 feet
Rectangle 2:
- Length = 6 yards = $6 \times 3$ feet = 18 feet
- Width = $\frac{3}{4}$ feet
Now calculate the area of each rectangle:
Rectangl... | 29.5 | augmented_math | data/train_1M-00001-of-00003.parquet | 114,733 | 87edcf5d187fba96684bba8aa49682423c4884665eb4fc2a28a53af217e136fc | 21ba1932bfbbf4b07c325a4c46979dbc588d556a5043d111f5810731052c8f9c | 264 | 0.521619 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Calculate the sum of the areas of two rectangles, one with a length of 8 feet and a width of $\\frac{2}{3}$ yards, and the other with a length of 6 yards and a width of $\\fra... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Real numbers $a$ and $b$ have a harmonic mean of 12 and a geometric mean of $\sqrt{50}$. Find $a^2+b^2$. | The harmonic mean of two numbers $a$ and $b$ is given by $\frac{2ab}{a+b}$ and their geometric mean is $\sqrt{ab}$. We are given that:
\begin{align*}
\frac{2ab}{a+b} &= 12 \\
\sqrt{ab} &= \sqrt{50}
\end{align*}
From the second equation, we have $ab = 50$.
Substituting $ab = 50$ into the first equation, we... | \frac{275}{9} | augmented_math | data/train_1M-00001-of-00003.parquet | 271,584 | 333b4eba01f31d71b980d1289b4bbc80bccb574da66f956944c1535572e54271 | ed8d70e7ce046247f82ef488742aa860263c85530a8709d08cf58de86d5c4b7a | 434 | 0.452031 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Real numbers $a$ and $b$ have a harmonic mean of 12 and a geometric mean of $\\sqrt{50}$. Find $a^2+b^2$.",
"role": "user"
},
{
"content": "The harmonic mean of tw... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
In late August, the water level in the reservoir is 8 feet deep. By early September, the water level has risen by 6 feet. By early October, the water level is twice as deep as it was in early September. How many feet deep is the water level in the reservoir by early October? | In late August, the water level is 8 feet deep.
By early September, the water level has risen by 6 feet, making it 8 + 6 = 14 feet deep.
By early October, the water level is twice as deep as it was in early September, making it 2 * 14 = 28 feet deep.
So, the water level in the reservoir by early October is \boxed{28} ... | 28 | augmented_gsm8k | data/train_1M-00002-of-00003.parquet | 327,374 | d0d39ced73db4bf0a4d5c11297a84eb37f3247eddf9aeefff992d54fdd3edb50 | b356e90fcad782d9aade6aeb6108cb8f25f380a5adc47fa61993b20041bb8c7d | 192 | 0.642936 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "In late August, the water level in the reservoir is 8 feet deep. By early September, the water level has risen by 6 feet. By early October, the water level is twice as deep as... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
The perimeter of a right triangle is 84 cm. If the length of the hypotenuse is increased by 5 cm, and the lengths of the legs remain the same, the perimeter of the new triangle is 87 cm. What is the length of the hypotenuse of the original triangle? | Let the lengths of the legs of the original triangle be $x$ and $y$, and let the length of the hypotenuse be $z$. The perimeter of the original triangle is $84$, so:
\[ x + y + z = 84 \quad \text{(1)} \]
The perimeter of the new triangle is $87$, and the hypotenuse is increased by $5$ cm, so:
\[ x + y + (z + 5) = 87 \... | 30 | augmented_math | data/train_1M-00001-of-00003.parquet | 23,500 | 6591f88da4ef0a69781cfff6aac1e1606e24c458a16c8128d32b9ce27e75e5e5 | c1321db3df489466931f4aa7c3f9e1ea3609bc7bb4767772b30e4a3327eee265 | 668 | 0.649648 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "The perimeter of a right triangle is 84 cm. If the length of the hypotenuse is increased by 5 cm, and the lengths of the legs remain the same, the perimeter of the new triangl... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Ana can assemble toy cars at a rate of one every 3 minutes for the first 2 hours of her shift. After that, she can assemble them at a rate of one every 5 minutes. How many toy cars can Ana assemble in a 6-hour shift? | To find the number of toy cars Ana can assemble in 6 hours, let's calculate the number of toy cars she can assemble in the first 2 hours and in the remaining 4 hours separately and then add them up.
In the first 2 hours, she can assemble 1 toy car every 3 minutes.
2 hours is 120 minutes.
So in 120 minutes she can ass... | 88 | augmented_gsm8k | data/train_1M-00002-of-00003.parquet | 121,138 | 9ef34ec7f16693c271652693606609c7caf88f643303e352f2b34649612b76db | 627def1a7d45ce523c76ef46776879020e6e564eb7329a2cf909d35a81bacfdf | 289 | 0.732268 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Ana can assemble toy cars at a rate of one every 3 minutes for the first 2 hours of her shift. After that, she can assemble them at a rate of one every 5 minutes. How many toy... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Alexandra purchases a set of dumbbells that weigh 40 pounds each. As she progresses in her workout routine, she decides to increase the weight by 75%. The weights can be upgraded with 5-pound metal plates. Each plate costs $8, and a 15% discount is applied if more than 5 plates are purchased. How much will it cost Alex... | To increase the weight by 75%, Alexandra needs to add 40 * 0.75 = 30 pounds to each dumbbell.
Since each dumbbell needs to be upgraded by 30 pounds and each plate weighs 5 pounds, she will need 30 / 5 = 6 plates per dumbbell.
Since she has 2 dumbbells (a set), she will need 6 * 2 = 12 plates in total.
The total cost of... | 81.6 | augmented_gsm8k | data/train_1M-00001-of-00003.parquet | 178,436 | 52e475f4083098f63eec9eee7ccebefa5d653bef09e98f702499ba67cb9b6eb9 | 4b972f3c0f5717f4b3bba620e455871d71a8b3027daaa98a40492e7770189cee | 321 | 0.588068 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Alexandra purchases a set of dumbbells that weigh 40 pounds each. As she progresses in her workout routine, she decides to increase the weight by 75%. The weights can be upgra... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
The measures of the interior angles of a convex hexagon form an increasing geometric sequence. How many such sequences are possible if the hexagon is not equiangular and all of the angle degree measures are positive integers less than 180 degrees? | ## Step 1: Recall the sum of interior angles of a hexagon
The sum of the interior angles of a hexagon is given by the formula (n-2)*180 degrees, where n is the number of sides. For a hexagon, this is (6-2)*180 = 4*180 = 720 degrees.
## Step 2: Express the sum of the interior angles as a geometric series
Let's denote t... | 5 | augmented_math | data/train_1M-00002-of-00003.parquet | 53,520 | c3d2ebbb1f934399962ec45ad2e6e4c6e4713c7946d04a921ed628ebe6292826 | 5ba7bcbabc8a024e611a17e0ee7acda98f2e3d278867fbfa4e9df23593b11739 | 572 | 0.576656 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "The measures of the interior angles of a convex hexagon form an increasing geometric sequence. How many such sequences are possible if the hexagon is not equiangular and all o... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Given a sequence of real numbers $a_1, a_2,..., a_n$ satisfying $\sum_{i=1}^{n} a_i^2 = 1$, find the largest positive integer $n$ such that for all sequences $a_1, a_2,..., a_n$ and for any positive real number $x$,
\[(a_1x)^n + (a_2x)^n +... + (a_nx)^n \ge x\] | Using the power mean inequality, we have:
\[ \frac{(a_1x)^n + (a_2x)^n + \dots + (a_nx)^n}{n} \ge \left( \frac{a_1^2x^2 + a_2^2x^2 + \dots + a_n^2x^2}{n} \right)^{\frac{n}{2}} \]
Simplifying and using the given condition $\sum_{i=1}^{n} a_i^2 = 1$, we get:
\[ \frac{(a_1x)^n + (a_2x)^n + \dots + (a_nx)^n}{n} \ge \left(... | 2 | augmented_math | data/train_1M-00000-of-00003.parquet | 105,007 | 22007d731c3652221dcbc1f4eb1c4010847906e64726cae351f50f26cb0f0dcc | c4be68bf80ecd6b2bc7d43057b1d565a41549fc4221b936a6a14f80378c60c0f | 484 | 0.564983 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Given a sequence of real numbers $a_1, a_2,..., a_n$ satisfying $\\sum_{i=1}^{n} a_i^2 = 1$, find the largest positive integer $n$ such that for all sequences $a_1, a_2,..., a... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
There are 5 buses in a fleet and each bus has 30 seats. If each bus could accommodate 8 more passengers, how many passengers would fill up 2 fleets? | Each bus can accommodate 30 + 8 = 38 passengers.
Since there are 5 buses in each fleet, each fleet can accommodate 38 * 5 = 190 passengers.
Two fleets can accommodate 190 * 2 = 380 passengers.
Thus, it would take \boxed{380} passengers to fill up 2 fleets. | 380 | augmented_gsm8k | data/train_1M-00000-of-00003.parquet | 86,956 | 61a15aec57fc2c244b0a6242e23e5789684ba8b186e3d1b93cecc5a185bd5f1c | b067ee9c48a0c10020ca67e2209f05f5ca3d5425117016fadc59f636d207a3db | 152 | 0.710459 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "There are 5 buses in a fleet and each bus has 30 seats. If each bus could accommodate 8 more passengers, how many passengers would fill up 2 fleets?",
"role": "user"
},
... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
A basketball team has five centers and eight power forwards. The team also has three times as many small forwards as power forwards, and the rest of the players are shooting guards. If the team has 50 players, how many shooting guards are on the team? | Let's break down the number of players by position:
* Centers: 5
* Power forwards: 8
* Small forwards: 3 times the number of power forwards, so 3 * 8 = 24
* Total number of centers, power forwards, and small forwards: 5 + 8 + 24 = 13 + 24 = 37
Since the team has 50 players, the number of shooting guards is:
50 - 37 ... | 13 | augmented_gsm8k | data/train_1M-00000-of-00003.parquet | 230,280 | 7c8f7eb745c6af79210eae1ab92016882f208b4c0ac0d28fa55cf6f3e2edc964 | dd37f03f662dd09c2fc1b2e1b036a3d25a6db40b0564db013c1be7db3aaa9dcd | 213 | 0.695733 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "A basketball team has five centers and eight power forwards. The team also has three times as many small forwards as power forwards, and the rest of the players are shooting g... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Emily is three times younger than her grandmother, who is 6 years older than Emily's mother. If Emily's grandmother is 54 years old, what's the age difference between Emily and her mother? | Let's break it down step by step:
1. Emily's grandmother is 54 years old.
2. Emily's grandmother is 6 years older than Emily's mother, so Emily's mother is 54 - 6 = 48 years old.
3. Emily is three times younger than her grandmother, so Emily is 54 / 3 = 18 years old.
4. The age difference between Emily and her mother ... | 30 | augmented_gsm8k | data/train_1M-00002-of-00003.parquet | 96,775 | 262ed5d7ace6903c1da738eec02735df9480fe892e161d0f9832a877eb2503cf | 1ce27ff64076f3c421eb78cd7b8758943dd33215184d2e4ae119bed466ae49f9 | 200 | 0.743941 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Emily is three times younger than her grandmother, who is 6 years older than Emily's mother. If Emily's grandmother is 54 years old, what's the age difference between Emily an... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
In triangle $ABC$, $\angle A = \angle C = 60^\circ$, $AB = 1$, and $BC = 2$. Compute the sine of the angle formed by the intersection of the angle bisector of $\angle A$ and the perpendicular bisector of side $BC$. | Since $\angle A = \angle C = 60^\circ$, triangle $ABC$ is isosceles, so $AC = AB = 1$. Let $M$ be the midpoint of $BC$, and let $D$ be the point where the angle bisector of $\angle A$ intersects $BC$. Then, $\triangle AMD$ is a right triangle with $\angle MAD = 30^\circ$, since the angle bisector of $\angle A$ cuts it ... | \frac{1}{2} | augmented_math | data/train_1M-00001-of-00003.parquet | 221,739 | 7607e94450b0bd17ab05984abf8d6dcede3aae9d6560f914439ce566a2c8ea25 | fc350ea54950e08cf3a178c6bb48efab317a34d8955c4d0bac4afac2420556d1 | 233 | 0.563414 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "In triangle $ABC$, $\\angle A = \\angle C = 60^\\circ$, $AB = 1$, and $BC = 2$. Compute the sine of the angle formed by the intersection of the angle bisector of $\\angle A$ a... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
In the equation $x^3 + 3x^2 - 2x - 8 = 0$, one root is an integer, and the product of the other two roots is $-3$. Determine the value of the integer root. | Let the integer root be $r$. The other two roots can be denoted as $x_1$ and $x_2$, and their product is $x_1 \cdot x_2 = -3$.
The sum of the roots of a cubic equation $ax^3 + bx^2 + cx + d = 0$ is given by $-\frac{b}{a}$. For our equation, this means the sum of the roots is:
\[ r + x_1 + x_2 = -3 \]
The product of t... | -2 | augmented_math | data/train_1M-00002-of-00003.parquet | 327,423 | ee28d05122dd6eebf89eeffdff916d288753e245e272d90cf657d55a3cba2683 | f1f97e14d827c952b4a45989472d417d668fb001596a49fa8f1a67e485b7416a | 873 | 0.629672 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "In the equation $x^3 + 3x^2 - 2x - 8 = 0$, one root is an integer, and the product of the other two roots is $-3$. Determine the value of the integer root.",
"role": "user... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
If $x, y,$ and $z$ are three non-zero positive real numbers such that $\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 1$ and $x^2 + y^2 + z^2 = 144$, compute $\frac{xy + yz + zx}{xyz}$ | ## Step 1: We are given the equation $\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = 1$ and $x^2 + y^2 + z^2 = 144$.
We need to use these equations to find $\frac{xy + yz + zx}{xyz}$.
## Step 2: First, notice that $\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = \frac{xy + yz + zx}{xyz}$.
This is because we can rewrite each frac... | 1 | augmented_math | data/train_1M-00000-of-00003.parquet | 93,594 | 01ff8edd1274678f0ab78762bbdc639c68781c5e94103a3b1eaf81c413945cb3 | a51e171ba31878d22fd511cb1468f79f4386f285d8ff29ee2c9f87984d2ccdac | 773 | 0.699445 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "If $x, y,$ and $z$ are three non-zero positive real numbers such that $\\frac{1}{x} + \\frac{1}{y} + \\frac{1}{z} = 1$ and $x^2 + y^2 + z^2 = 144$, compute $\\frac{xy + yz + z... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Let $a$ and $b$ be two randomly chosen real numbers such that $a^2 + b^2 = 1.$ Find the probability that the equation $ax^2 + bx + 1 = 0$ has no real roots. | We need to find when the equation $ax^2 + bx + 1 = 0$ has no real roots. This happens when the discriminant of the quadratic equation is less than 0:
\[ b^2 - 4a(1) < 0 \Rightarrow b^2 - 4a < 0 \]
We also know that $a^2 + b^2 = 1$. We can use this condition to eliminate $b^2$ from the inequality:
\[ b^2 = 1 - a^2 \]
... | \frac{3 - \sqrt{5}}{2} | augmented_math | data/train_1M-00001-of-00003.parquet | 92,460 | 3baae177becd28b03af3886f8e689c43d3311923c0dbc695fc6cbb54187482f5 | 1bc7034683ebfb804bc3e46052f6b5ddbc118b3dcbac0624f693e0a2bc201519 | 634 | 0.505915 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Let $a$ and $b$ be two randomly chosen real numbers such that $a^2 + b^2 = 1.$ Find the probability that the equation $ax^2 + bx + 1 = 0$ has no real roots.",
"role": "use... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Two teams of five players each are participating in a friendly competition to see which team can roll the highest sum with a set of five six-sided dice. The team with the highest sum wins. If the competition is held multiple times, what is the probability that the same team wins three times in a row? Express your answe... | The probability of a team winning once is $\frac{1}{2}$, since there are only two teams.
The probability of a team winning three times in a row is:
\[ \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8} \]
So, the answer is:
\[ \boxed{0.13} \] | 0.13 | augmented_math | data/train_1M-00001-of-00003.parquet | 117,159 | abb6233cf43ae7a45bd481865c8a06881b75cd1d85c2ce924d8a761e15611002 | abb6233cf43ae7a45bd481865c8a06881b75cd1d85c2ce924d8a761e15611002 | 195 | 0.559674 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "Two teams of five players each are participating in a friendly competition to see which team can roll the highest sum with a set of five six-sided dice. The team with the high... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
John has a habit of going to the gym every third day. If he starts going to the gym on a Monday, what day of the week will he be going to the gym on his 20th visit? | John goes to the gym every third day. So, we can make a list of days he goes to the gym:
- 1st visit: Monday
- 2nd visit: Thursday
- 3rd visit: Sunday
- 4th visit: Wednesday
- 5th visit: Saturday
- 6th visit: Tuesday
- 7th visit: Friday
- 8th visit: Monday
- 9th visit: Thursday
- 10th visi... | \text{Tuesday} | augmented_math | data/train_1M-00000-of-00003.parquet | 159,270 | fe980f5e0286885faf936e711119b3141e78ae96df5940536287bce5b83ab3cf | 86bd1f3c7102315e6063d08ccdf9839c2ee502f1a429712c50585070570cb81c | 309 | 0.604985 | [
{
"content": "Solve the math problem step by step. Put the final answer in \\boxed{...}.",
"role": "system"
},
{
"content": "John has a habit of going to the gym every third day. If he starts going to the gym on a Monday, what day of the week will he be going to the gym on his 20th visit?",
"rol... | nvidia/OpenMathInstruct-2 | 469216e3f46f4dacf476b382e192485ea51a143e | train_1M |
Qwen2.5 OpenMathInstruct-2 SFT 50K
A 50,000-example, short-context mathematics SFT dataset extracted from NVIDIA OpenMathInstruct-2. It was prepared for instruction tuning mssfj/qwen25-0.5b-finemath-4plus and subsequent GSM8K and MATH-500 benchmarking, including controlled comparisons with TDT. This is an extracted and filtered dataset, not a newly generated set of solutions.
Composition
MATH-related examples make up 70% of each split; GSM8K-related examples make up 30%.
These categories describe the upstream problem_source, not a newly assigned difficulty label.
Each selected numeric problem template occurs only once across the entire dataset.
| Split | Examples | MATH-related | GSM8K-related | Total formatted tokens | Maximum tokens |
|---|---|---|---|---|---|
| train | 49,000 | 34,300 | 14,700 | 21,212,482 | 1854 |
| validation | 1,000 | 700 | 300 | 427,265 | 1868 |
The token limit is 2,048 per complete conversation, including the system prompt, user problem, full assistant solution, and Qwen chat-template delimiters. Problems and solutions are not truncated. The published solution text is retained apart from trimming outer whitespace; no answer line or solution was regenerated or appended.
Source and provenance
- Source:
nvidia/OpenMathInstruct-2, splittrain_1M. - Source revision:
469216e3f46f4dacf476b382e192485ea51a143e. - Upstream fields:
problem,generated_solution,expected_answer,problem_source. - Upstream teacher model: Llama3.1-405B-Instruct, as documented by NVIDIA.
- Tokenizer:
mssfj/qwen25-0.5b-finemath-4plus, revision0600e6f3b418e77d7323b8934451ac66d49a1185, using its Qwen2.5 tokenizer and chat template. - Selection and split seed: 42.
The source paper is OpenMathInstruct-2: Accelerating AI for Math with Massive Open-Source Instruction Data, by Shubham Toshniwal, Wei Du, Ivan Moshkov, Branislav Kisacanin, Alexan Ayrapetyan, and Igor Gitman (2024).
Selection procedure
- Scan all 1,000,000 rows in the pinned
train_1Mfiles in sorted filename order. - Reject empty required fields, unknown source categories, problems containing
[asy]diagram markup, and problem/solution text containing chat control-token strings. - Require a balanced final
\boxed{...}or\fbox{...}and compare it withexpected_answerafter limited whitespace and LaTeX-format normalization. This is a string-consistency check, not verification of the mathematical reasoning. - Deduplicate normalized problems. Choose the shortest answer-consistent solution by character length, with a seeded SHA-256 tie-breaker.
- Render complete conversations with the pinned chat template and reject lengths greater than 2,048 tokenizer tokens.
- Deduplicate numeric templates. Normalization uses NFKC, lowercase text, removes
selected LaTeX presentation commands, and keeps letter, number, and math-operator
tokens. Numeric templates replace numeric literals with
NUM. Keep the problem with the lowest seeded SHA-256 rank per template. - Form a deterministic candidate pool of up to 70,000 MATH-related and 30,000 GSM8K-related examples. Apply the benchmark checks below to this candidate pool.
- Select 35,000 MATH-related and 15,000 GSM8K-related surviving examples by seeded hash. Assign 700 MATH-related and 300 GSM8K-related examples to validation using a separate seeded hash ordering, leaving 49,000 training examples. Shuffle file order by another deterministic hash.
- Retokenize every exported example to verify its saved length and check that normalized problem IDs and numeric-template group IDs are disjoint between splits.
This favors short complete solutions and template diversity. It is not a representative random sample of the original corpus or its difficulty distribution. Derived problems whose templates change substantially may still occur in both train and validation.
Benchmark overlap filtering
Reference sets:
openai/gsm8k,main,test: 1,319 problems, revision740312add88f781978c0658806c59bc2815b9866.HuggingFaceH4/MATH-500,test: 500 problems, revision6e4ed1a2a79af7d8630a6b768ec859cb5af4d3be.
An example is removed when its problem meets any of these conditions:
- Exact match after problem normalization.
- Exact numeric-template match, targeting number-substitution variants.
- RapidFuzz normalized-problem ratio of at least 90 against any benchmark problem.
- Maximum sentence-embedding cosine similarity of at least 0.94.
- Maximum cosine similarity of at least 0.90, together with a normalized-problem ratio of at least 70 or a numeric-template ratio of at least 85 for that nearest benchmark.
Embedding model: sentence-transformers/all-MiniLM-L6-v2, revision
1110a243fdf4706b3f48f1d95db1a4f5529b4d41, with normalized embeddings and a maximum
input length of 512 embedding-model tokens. Longer questions are truncated for this
similarity check only, not in the SFT data. These thresholds are heuristics: they can
remove related but distinct problems and miss paraphrases or mathematical equivalents.
This dataset does not guarantee complete semantic decontamination.
The filtering checks problem text, not all mentions within generated solutions. It also does not undo possible benchmark exposure during the base model's prior FineWeb-Edu or FineMath pretraining, or during the teacher model's training. GSM8K training problems remain eligible; only the named evaluation sets are exclusion references. MATH test problems outside MATH-500 were not an additional exclusion set.
decontamination_audit.jsonl records removed candidate IDs, matched benchmark row IDs,
and matching scores. It does not reproduce benchmark questions or answers.
selection_stats.json records filter counts, split composition, source revisions,
template/script fingerprints, token statistics, and Parquet SHA-256 checksums.
Fields
| Field | Description |
|---|---|
messages |
System/user/assistant messages for SFT |
problem |
Selected upstream problem |
generated_solution |
Selected upstream solution |
expected_answer |
Upstream reference or majority-vote answer |
problem_source |
math, augmented_math, gsm8k, or augmented_gsm8k |
problem_id |
SHA-256 of the normalized problem |
problem_group_id |
SHA-256 of its numeric template |
token_count |
Complete conversation length under the pinned tokenizer/template |
source_dataset, source_revision, source_split |
Upstream provenance |
source_file, source_row |
Source Parquet path and zero-based row number |
nearest_benchmark_cosine |
Maximum embedding similarity to the exclusion references; audit metadata only |
Usage
from datasets import load_dataset
dataset = load_dataset("mssfj/qwen25-openmathinstruct2-sft-50k")
train = dataset["train"]
validation = dataset["validation"]
print(train[0]["messages"])
Use messages for training and keep the reference/audit fields out of the prompt.
The system prompt is:
Solve the math problem step by step. Put the final answer in \boxed{...}.
Render with the pinned Qwen chat template (chat_template.jinja is also supplied),
train with loss on the assistant response and its turn-ending token, and keep the
input embeddings and output weights untied to match the base checkpoint. At inference,
stop on the Qwen assistant turn terminator <|im_end|> as well as the base EOS token.
Use this dataset's validation split for model selection; keep GSM8K test and MATH-500
for final evaluation. For TDT comparisons, fix the dataset revision and examples,
initial weights, training token budget, template, and evaluation settings.
Reproduction
The included prepare_openmath_sft.py downloads pinned input revisions and rebuilds
the Parquet files and selection statistics. A CUDA GPU accelerates embedding checks.
Install a suitable PyTorch build for your system, then:
pip install -r requirements.txt
python prepare_openmath_sft.py \
--output ./rebuilt-openmath-sft-50k \
--total 50000 --validation 1000 --math-ratio 0.70 \
--max-tokens 2048 --seed 42 --candidate-multiplier 2
environment.json records the generation environment, including the CUDA PyTorch
build. Different numerical environments can change borderline embedding decisions.
Compare output checksums and statistics when reproducing the dataset. The build script
creates data and statistics; this README and dependency/environment files accompany the
published release separately.
Build statistics
Counters refer to the stage where each filter is applied; they are not all counts over the same population. Similarity checks apply to the hash-selected candidate pool.
| Counter | Count |
|---|---|
source_rows |
1,000,000 |
diagram_or_control_token |
21,843 |
missing_or_mismatched_final_box |
993 |
duplicate_normalized_problem |
386,845 |
empty_field |
733 |
unique_answer_checked_candidates |
589,586 |
over_token_limit |
355 |
duplicate_numeric_template |
28,173 |
eligible_math |
481,746 |
eligible_gsm8k |
79,312 |
similarity_candidate_pool |
100,000 |
benchmark_fuzzy_ratio_90 |
81 |
benchmark_numeric_template_exact |
11 |
embedding_input_over_512_tokens |
169 |
benchmark_semantic_similarity |
11 |
License and attribution
This derived dataset follows the upstream OpenMathInstruct-2 dataset's CC BY 4.0 license. Attribute NVIDIA and the OpenMathInstruct-2 authors, and identify this release as an extracted subset with formatting, consistency, length, deduplication, benchmark overlap filtering, and split changes. Refer to the upstream dataset card for the original release and citation.
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