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The dataset generation failed
Error code: DatasetGenerationError
Exception: ValueError
Message: Expected object or value
Traceback: Traceback (most recent call last):
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 290, in _generate_tables
pa_table = paj.read_json(
io.BytesIO(batch), read_options=paj.ReadOptions(block_size=block_size)
)
File "pyarrow/_json.pyx", line 342, in pyarrow._json.read_json
File "pyarrow/error.pxi", line 155, in pyarrow.lib.pyarrow_internal_check_status
File "pyarrow/error.pxi", line 92, in pyarrow.lib.check_status
raise convert_status(status)
pyarrow.lib.ArrowInvalid: JSON parse error: Column() changed from object to string in row 0
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1827, in _prepare_split_single
for key, table in generator:
^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 613, in wrapped
for item in generator(*args, **kwargs):
~~~~~~~~~^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 304, in _generate_tables
batch = json_encode_fields_in_json_lines(original_batch, json_field_paths)
File "/usr/local/lib/python3.14/site-packages/datasets/utils/json.py", line 111, in json_encode_fields_in_json_lines
examples = [ujson_loads(line) for line in original_batch.splitlines()]
~~~~~~~~~~~^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/utils/json.py", line 20, in ujson_loads
return pd.io.json.ujson_loads(*args, **kwargs)
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^
ValueError: Expected object or value
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1369, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
~~~~~~~~~~~~~~~~~~~~~~~~~^
builder, max_dataset_size_bytes=max_dataset_size_bytes
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
)
^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 948, in stream_convert_to_parquet
builder._prepare_split(split_generator=splits_generators[split], file_format="parquet")
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1694, in _prepare_split
for job_id, done, content in self._prepare_split_single(
~~~~~~~~~~~~~~~~~~~~~~~~~~^
gen_kwargs=gen_kwargs, job_id=job_id, **_prepare_split_args
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
):
^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1880, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
problem_key string | rollout_index int64 | arm string | steer string | label string | committed bool | correct bool | hit_token_cap bool | finish_reason string | output_tokens int64 | max_tokens_used int64 | completion string |
|---|---|---|---|---|---|---|---|---|---|---|---|
precalculus__8ee539 | 0 | nn_okay_bare | base | run | true | true | false | stop | 571 | 31,744 |
Okay, so I need to convert the rectangular coordinates (0, 3) to polar coordinates. Let me recall the formulas for converting from rectangular (x, y) to polar (r, θ).
First, the radius r is calculated using the formula:
\[
r = \sqrt{x^2 + y^2}
\]
Plugging in the given values, x = 0 and y = 3:
\[
r = \sqrt{0^2 + 3^2... |
precalculus__8ee539 | 1 | nn_okay_bare | base | run | true | true | false | stop | 509 | 31,744 |
Okay, so I need to convert the rectangular coordinates (0, 3) to polar coordinates. Hmm, let me remember the formulas for that. I think polar coordinates are given in terms of radius r and angle θ. The formulas are:
r = √(x² + y²)
and
θ = arctan(y/x), but you have to be careful with the quadrant, right?
Alright, ... |
precalculus__8ee539 | 2 | nn_okay_bare | base | run | true | true | false | stop | 952 | 31,744 |
Okay, so I need to convert the rectangular coordinates (0, 3) to polar coordinates. Hmm, let me remember the formulas for this conversion. I think the process involves using the radius r and the angle θ.
First, the formula for the radius r in polar coordinates is given by the square root of the sum of the squares o... |
precalculus__8ee539 | 3 | nn_okay_bare | base | run | true | true | false | stop | 594 | 31,744 |
Okay, so I need to convert the rectangular coordinates (0, 3) to polar coordinates. Let me remember the formulas for this conversion. I think the process involves using the radius r and the angle θ.
First, the radius r is calculated using the Pythagorean theorem with the x and y coordinates. The formula should be r... |
precalculus__8ee539 | 4 | nn_okay_bare | base | run | true | true | false | stop | 1,032 | 31,744 |
Okay, so I need to convert the rectangular coordinates (0, 3) to polar coordinates. Hmm, let me remember the formulas for this conversion. I think polar coordinates are given in terms of radius r and angle θ. The formulas are:
r = √(x² + y²)
and
θ = arctan(y/x), but you have to be careful with the quadrant, right?... |
precalculus__8ee539 | 5 | nn_okay_bare | base | run | true | true | false | stop | 578 | 31,744 |
Okay, so I need to convert the point (0, 3) from rectangular coordinates to polar coordinates. Hmm, let me remember the formulas for that. I think polar coordinates are given in terms of radius (r) and angle (θ). The formulas are:
\[
r = \sqrt{x^2 + y^2}
\]
and
\[
\theta = \arctan\left(\frac{y}{x}\right)
\]
But wai... |
precalculus__8ee539 | 6 | nn_okay_bare | base | run | true | true | false | stop | 777 | 31,744 |
Okay, so I need to convert the point (0, 3) from rectangular coordinates to polar coordinates. Hmm, let me recall the formulas for converting between these coordinate systems.
In polar coordinates, a point is represented as (r, θ), where r is the radius (or distance from the origin) and θ is the angle measured coun... |
precalculus__8ee539 | 7 | nn_okay_bare | base | run | true | true | false | stop | 1,034 | 31,744 |
Okay, so I need to convert the rectangular coordinates (0, 3) to polar coordinates. Hmm, let me remember the formulas for this conversion. I think polar coordinates are given in terms of radius r and angle θ, right? The formulas are:
\[
r = \sqrt{x^2 + y^2}
\]
and
\[
\theta = \arctan\left(\frac{y}{x}\right)
\]
But ... |
precalculus__8ee539 | 8 | nn_okay_bare | base | run | true | true | false | stop | 531 | 31,744 |
Okay, so I need to convert the point (0, 3) from rectangular coordinates to polar coordinates. Hmm, let me remember the formulas for this conversion. I think the process involves using the radius r and the angle θ.
First, the radius r is calculated using the Pythagorean theorem with the x and y coordinates. The for... |
precalculus__8ee539 | 9 | nn_okay_bare | base | run | true | true | false | stop | 761 | 31,744 |
Okay, so I need to convert the point (0, 3) from rectangular coordinates to polar coordinates. Let me remember how that works.
First, the formulas for converting from rectangular (x, y) to polar (r, θ) coordinates are:
\[
r = \sqrt{x^2 + y^2}
\]
and
\[
\theta = \arctan\left(\frac{y}{x}\right)
\]
But I also have t... |
precalculus__8ee539 | 10 | nn_okay_bare | base | run | true | true | false | stop | 749 | 31,744 |
Okay, so I need to convert the point (0, 3) from rectangular coordinates to polar coordinates. Hmm, let me remember the formulas for that. I think polar coordinates are given in terms of radius r and angle θ, right? The formulas are:
r = √(x² + y²)
and
θ = arctan(y/x), but adjusted for the correct quadrant.
Alrig... |
precalculus__8ee539 | 11 | nn_okay_bare | base | run | true | true | false | stop | 567 | 31,744 |
Okay, so I need to convert the rectangular coordinates (0, 3) to polar coordinates. Let me remember the formulas for this conversion.
From what I recall, in polar coordinates, a point is represented as (r, θ), where r is the distance from the origin to the point (the radius), and θ is the angle measured countercloc... |
precalculus__8ee539 | 12 | nn_okay_bare | base | run | true | true | false | stop | 1,125 | 31,744 |
Okay, so I need to convert the point (0, 3) from rectangular coordinates to polar coordinates. Hmm, let me remember the formulas for converting between the two systems.
I recall that in polar coordinates, a point is represented as (r, θ), where r is the radius (distance from the origin) and θ is the angle measured ... |
precalculus__8ee539 | 13 | nn_okay_bare | base | run | true | true | false | stop | 1,056 | 31,744 |
Okay, so I need to convert the rectangular point (0, 3) to polar coordinates. Let me recall the formulas for converting between rectangular and polar coordinates.
In polar coordinates, a point is represented as (r, θ), where r is the radius (distance from the origin) and θ is the angle measured counterclockwise fro... |
precalculus__8ee539 | 14 | nn_okay_bare | base | run | true | true | false | stop | 500 | 31,744 |
Okay, so I need to convert the rectangular coordinates (0, 3) to polar coordinates. Hmm, let me remember the formulas for that. I think polar coordinates are given in terms of radius r and angle θ. The formulas are:
r = √(x² + y²)
and
θ = arctan(y/x), but you have to be careful with the quadrant.
Alright, let's s... |
precalculus__8ee539 | 15 | nn_okay_bare | base | run | true | true | false | stop | 880 | 31,744 |
Okay, so I need to convert the point (0, 3) from rectangular coordinates to polar coordinates. Hmm, let me remember the formulas for converting between these coordinate systems.
From what I recall, in polar coordinates, a point is represented as (r, θ), where r is the radius (or the distance from the origin) and θ ... |
intermediate_algebra__f4e837 | 0 | nn_okay_bare | base | run | true | true | false | stop | 1,594 | 31,744 |
Okay, so I need to find a way to express the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
in terms of the given definitions of \( p \) and \( q \), where
\[
p = \sum_{k=1}^\infty \frac{1}{k^2} \quad \text{and} \quad q = \sum_{k=1}^\infty \frac{1}{k^3}.
\]
Let me start by understanding t... |
intermediate_algebra__f4e837 | 1 | nn_okay_bare | base | run | true | true | false | stop | 2,170 | 31,744 |
Okay, so I need to find the value of the double sum \(\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}\) in terms of the given series \(p = \sum_{k=1}^\infty \frac{1}{k^2}\) and \(q = \sum_{k=1}^\infty \frac{1}{k^3}\).
First, let me recall that the inner sum is over all positive integers \(j\) and \(k\), and ... |
intermediate_algebra__f4e837 | 2 | nn_okay_bare | base | run | true | true | false | stop | 1,796 | 31,744 |
Okay, so I need to find a way to express the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
in terms of the given values \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Let me start by trying to understand the structure of the double sum. The term i... |
intermediate_algebra__f4e837 | 3 | nn_okay_bare | base | run | true | true | false | stop | 1,890 | 31,744 |
Okay, so I need to find a way to express the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
in terms of the given values \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Hmm, let's start by understanding the structure of the double sum. The term insi... |
intermediate_algebra__f4e837 | 4 | nn_okay_bare | base | run | true | true | false | stop | 1,543 | 31,744 |
Okay, so I need to find a way to express the double sum
\[
\sum_{j = 1}^\infty \sum_{k = 1}^\infty \frac{1}{(j + k)^3}
\]
in terms of the given \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Let me start by understanding the structure of the double sum. The term inside is \... |
intermediate_algebra__f4e837 | 5 | nn_okay_bare | base | run | true | true | false | stop | 1,310 | 31,744 |
Okay, so I need to find the value of the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
and express it in terms of the given \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Let me start by understanding the structure of the double sum. The term insi... |
intermediate_algebra__f4e837 | 6 | nn_okay_bare | base | run | true | true | false | stop | 1,953 | 31,744 |
Okay, so I need to find a way to express the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
in terms of the given values \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Let me start by understanding the structure of the double sum. Each term is \( \... |
intermediate_algebra__f4e837 | 7 | nn_okay_bare | base | run | true | true | false | stop | 2,215 | 31,744 |
Okay, so I need to find a way to express the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
in terms of the given series \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Let me start by understanding the structure of the double sum. The term inside t... |
intermediate_algebra__f4e837 | 8 | nn_okay_bare | base | run | true | true | false | stop | 1,868 | 31,744 |
Okay, so I have this problem here where I need to express the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
in terms of the given values \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \). Hmm, let's see how to approach this.
First, I remember that som... |
intermediate_algebra__f4e837 | 9 | nn_okay_bare | base | run | true | true | false | stop | 1,995 | 31,744 |
Okay, so I need to find the value of the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
and express it in terms of the given \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Let me start by understanding the structure of the double sum. The term insi... |
intermediate_algebra__f4e837 | 10 | nn_okay_bare | base | run | true | true | false | stop | 2,940 | 31,744 |
Okay, so I need to find a way to express the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
in terms of the given \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Hmm, let's start by understanding the structure of the double sum. The term inside is \... |
intermediate_algebra__f4e837 | 11 | nn_okay_bare | base | run | true | true | false | stop | 1,806 | 31,744 |
Okay, let's see. I need to find the double sum \(\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}\) in terms of \(p\) and \(q\), where \(p = \sum_{k=1}^\infty \frac{1}{k^2}\) and \(q = \sum_{k=1}^\infty \frac{1}{k^3}\).
First, I recall that the given single sums \(p\) and \(q\) are the Riemann zeta functions ... |
intermediate_algebra__f4e837 | 12 | nn_okay_bare | base | run | true | true | false | stop | 2,205 | 31,744 |
Okay, so I need to find a way to express the double sum \(\displaystyle \sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}\) in terms of the given \(p\) and \(q\), where
\[
p = \sum_{k=1}^\infty \frac{1}{k^2} \quad \text{and} \quad q = \sum_{k=1}^\infty \frac{1}{k^3}.
\]
Let me start by understanding the struc... |
intermediate_algebra__f4e837 | 13 | nn_okay_bare | base | run | true | true | false | stop | 1,323 | 31,744 |
Okay, so I need to find the value of the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
and express it in terms of the given \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Let me start by understanding the structure of the double sum. The term in... |
intermediate_algebra__f4e837 | 14 | nn_okay_bare | base | run | true | true | false | stop | 1,866 | 31,744 |
Okay, so I need to find a way to express the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
in terms of the given values \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Let me start by understanding the structure of the double sum. Each term is \( \... |
intermediate_algebra__f4e837 | 15 | nn_okay_bare | base | run | true | true | false | stop | 1,083 | 31,744 |
Okay, let's see. I need to find the value of the double sum
\[
\sum_{j=1}^\infty \sum_{k=1}^\infty \frac{1}{(j + k)^3}
\]
and express it in terms of \( p = \sum_{k=1}^\infty \frac{1}{k^2} \) and \( q = \sum_{k=1}^\infty \frac{1}{k^3} \).
Hmm, so first, I should think about how to relate this double sum to the given... |
algebra__96e5cb | 0 | nn_okay_bare | base | run | true | true | false | stop | 1,095 | 31,744 |
Okay, so I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is given by \( f(x) = \frac{3x - 2}{x - 2} \). Let me take this step by step to make sure I don't make any mistakes.
First, I'll recall the function:
\[
f(x) = \frac{3x - 2}{x - 2}
\]
This is a rational function, and it's undefined wh... |
algebra__96e5cb | 1 | nn_okay_bare | base | run | true | true | false | stop | 749 | 31,744 |
Okay, let me try to solve this problem step by step. The function given is \( f(x) = \frac{3x - 2}{x - 2} \), and we need to find the value of \( f(-2) + f(-1) + f(0) \).
First, I'll compute each term individually.
**1. Calculating \( f(-2) \):**
Substitute \( x = -2 \) into the function:
\[
f(-2) = \frac{3(-2) ... |
algebra__96e5cb | 2 | nn_okay_bare | base | run | true | true | false | stop | 1,059 | 31,744 |
Okay, so I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is given by \( f(x) = \frac{3x - 2}{x - 2} \). Let me take this step by step to make sure I don't make any mistakes.
First, let me recall the function:
\[ f(x) = \frac{3x - 2}{x - 2} \]
This function is a rational function, meaning ... |
algebra__96e5cb | 3 | nn_okay_bare | base | run | true | true | false | stop | 1,352 | 31,744 |
Okay, let's see. I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is defined as \( f(x) = \frac{3x - 2}{x - 2} \). Hmm, I should probably calculate each term separately and then add them up. Let me start with each function evaluation one by one.
First, let's compute \( f(-2) \). To do that, ... |
algebra__96e5cb | 4 | nn_okay_bare | base | run | true | true | false | stop | 733 | 31,744 |
Okay, let's tackle this problem step by step. We have the function \( f(x) = \frac{3x - 2}{x - 2} \), and we need to find the value of \( f(-2) + f(-1) + f(0) \).
First, let's compute each term individually.
**1. Calculating \( f(-2) \):**
Substitute \( x = -2 \) into the function:
\[
f(-2) = \frac{3(-2) - 2}{-2 -... |
algebra__96e5cb | 5 | nn_okay_bare | base | run | true | true | false | stop | 1,307 | 31,744 |
Okay, let's see. I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is given by \( f(x) = \frac{3x - 2}{x - 2} \). Hmm, I should probably compute each term separately and then add them up. Let me take it step by step.
First, let's find \( f(-2) \). To do this, I substitute \( x = -2 \) into th... |
algebra__96e5cb | 6 | nn_okay_bare | base | run | true | true | false | stop | 791 | 31,744 |
Okay, let's tackle this problem step by step. We have the function \( f(x) = \frac{3x - 2}{x - 2} \), and we need to find the value of \( f(-2) + f(-1) + f(0) \).
First, I'll compute each term individually.
**1. Calculating \( f(-2) \):**
Substitute \( x = -2 \) into the function:
\[
f(-2) = \frac{3(-2) - 2}{-2 -... |
algebra__96e5cb | 7 | nn_okay_bare | base | run | true | true | false | stop | 2,209 | 31,744 |
Okay, so I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is given by \( f(x) = \frac{3x - 2}{x - 2} \). Let me take this step by step to make sure I don't make any mistakes.
First, let me recall the function:
\[
f(x) = \frac{3x - 2}{x - 2}
\]
This function is a rational function, meaning i... |
algebra__96e5cb | 8 | nn_okay_bare | base | run | true | true | false | stop | 2,098 | 31,744 |
Okay, so I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is given by \( f(x) = \frac{3x - 2}{x - 2} \). Let me take this step by step to make sure I don't make any mistakes.
First, let me recall the function:
\[
f(x) = \frac{3x - 2}{x - 2}
\]
This is a rational function, so I need to be ca... |
algebra__96e5cb | 9 | nn_okay_bare | base | run | true | true | false | stop | 819 | 31,744 |
Okay, let's tackle this problem step by step. We have the function \( f(x) = \frac{3x - 2}{x - 2} \), and we need to find the sum \( f(-2) + f(-1) + f(0) \).
First, I'll compute each term individually. Let's start with \( f(-2) \).
**Calculating \( f(-2) \):**
Substitute \( x = -2 \) into the function:
\[
f(-2) = \... |
algebra__96e5cb | 10 | nn_okay_bare | base | run | true | true | false | stop | 1,384 | 31,744 |
Okay, let's see. I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is given by \( f(x) = \frac{3x - 2}{x - 2} \). Hmm, alright, so I'll start by calculating each term separately.
First, let's compute \( f(-2) \). To do this, I substitute \( x = -2 \) into the function:
\[
f(-2) = \frac{3(-2)... |
algebra__96e5cb | 11 | nn_okay_bare | base | run | true | true | false | stop | 1,216 | 31,744 |
Okay, so I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is given by \( f(x) = \frac{3x - 2}{x - 2} \). Let me take this step by step to make sure I don't make any mistakes.
First, I'll recall the function definition clearly:
\[
f(x) = \frac{3x - 2}{x - 2}
\]
This function is a rational fu... |
algebra__96e5cb | 12 | nn_okay_bare | base | run | true | true | false | stop | 935 | 31,744 |
Okay, so I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is defined as \( f(x) = \frac{3x - 2}{x - 2} \). Let me take this step by step to make sure I don't make any mistakes.
First, let me recall the function:
\[
f(x) = \frac{3x - 2}{x - 2}
\]
This is a rational function, and the only poi... |
algebra__96e5cb | 13 | nn_okay_bare | base | run | true | true | false | stop | 915 | 31,744 |
Okay, so I have this function \( f(x) = \frac{3x - 2}{x - 2} \), and I need to find the value of \( f(-2) + f(-1) + f(0) \). Let me take it step by step to make sure I don't make any mistakes.
First, I'll calculate each term separately.
**1. Calculating \( f(-2) \):**
Substitute \( x = -2 \) into the function:
\[... |
algebra__96e5cb | 14 | nn_okay_bare | base | run | true | true | false | stop | 1,010 | 31,744 |
Okay, so I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is given by \( f(x) = \frac{3x - 2}{x - 2} \). Let me take this step by step to make sure I don't make any mistakes.
First, I'll start by evaluating each term individually.
**1. Calculating \( f(-2) \):**
- Substitute \( x = -2 \)... |
algebra__96e5cb | 15 | nn_okay_bare | base | run | true | true | false | stop | 836 | 31,744 |
Okay, so I need to find the value of \( f(-2) + f(-1) + f(0) \) where the function is given by \( f(x) = \frac{3x - 2}{x - 2} \). Let me take this step by step to avoid any mistakes.
First, I'll compute each term individually.
**1. Calculating \( f(-2) \):**
Substitute \( x = -2 \) into the function:
\[
f(-2) = \... |
number_theory__7ffac5 | 0 | nn_okay_bare | base | run | true | true | false | stop | 1,151 | 31,744 |
Okay, let me figure out how many positive whole-number divisors 196 has. Hmm, I remember that to find the number of divisors of a number, it's easiest to first find its prime factorization. Let me start there.
So, 196. Let me see if it's divisible by 2 first. 196 is an even number, so yes. Dividing by 2:
196 ÷ 2 = ... |
number_theory__7ffac5 | 1 | nn_okay_bare | base | run | true | true | false | stop | 1,334 | 31,744 |
Okay, so I need to find how many positive whole-number divisors 196 has. Hmm, let me think about the best way to approach this. I remember from math class that to find the number of divisors of a number, it's easiest to first break it down into its prime factors. Then, there's a formula you can use with those factors... |
End of preview.
rollouts-olmo7b-instruct — evaluation rollouts
Model: allenai/Olmo-3-7B-Instruct. Tokenizer used for answer positions: allenai/Olmo-3-7B-Instruct.
Protocol: 32 rollouts per problem (two seeded batches of 16), temperature 0.6, top-p 0.95,
budget 31,744 generated tokens, seed 20260819. Prompts and grader: the paper's repository
(sophicle/reason). Rollout jsonl files are kept as written (one graded rollout per line, with the
completion), under the run directories as on disk (run/, run_regraded/, *_execgraded/);
cell summaries are at <prompt>/<benchmark>/summary/<arm>.json.
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