|
Download knowledge-base/class_10/ch10/0075_geometry.md from False45/math-api: direct link, hf CLI and curl.
- Browser
- Download file 1.91 kB
-
https://huggingface.co/spaces/False45/math-api/resolve/main/knowledge-base/class_10/ch10/0075_geometry.md
- Command line
-
hf download hf://spaces/False45/math-api/knowledge-base/class_10/ch10/0075_geometry.md
-
curl -L -o 0075_geometry.md https://huggingface.co/spaces/False45/math-api/resolve/main/knowledge-base/class_10/ch10/0075_geometry.md
1.91 kB
| source: ncert | |
| topic: geometry | |
| class_level: class_10 | |
| chapter: ch10 | |
| difficulty: intermediate | |
| Class 10 | Ch10: Circles | |
| KEY DEFINITIONS: | |
| Tangent: line touching circle at exactly ONE point (point of tangency/contact). | |
| Secant: line intersecting circle at TWO points. | |
| A tangent is perpendicular to radius at point of contact. | |
| THEOREMS: | |
| Theorem 1: Tangent at any point of circle is perpendicular to radius through that point. | |
| Proof: Any point on tangent other than contact point is outside circle (farther from centre). | |
| So perpendicular from centre to tangent = shortest distance = radius. Hence radius ⊥ tangent. | |
| Theorem 2: Lengths of tangents drawn from external point are EQUAL. | |
| If PA and PB are tangents from P to circle with centre O: | |
| In triangles OAP and OBP: OA=OB (radii), OP=OP (common), angle OAP=angle OBP=90°. | |
| By RHS: triangles congruent → PA=PB (CPCT). | |
| Also: OP bisects angle APB and angle AOB. | |
| LENGTH OF TANGENT FROM EXTERNAL POINT: | |
| If d=distance from external point to centre, r=radius: | |
| Length of tangent=sqrt(d^2-r^2). | |
| ANGLE IN ALTERNATE SEGMENT (Tangent-Chord angle): | |
| Angle between tangent and chord = inscribed angle in alternate segment. | |
| SOLVED EXAMPLES: | |
| Example 1: Point P is 17cm from centre. Radius=8cm. Find tangent length. | |
| Tangent=sqrt(17^2-8^2)=sqrt(289-64)=sqrt(225)=15cm. | |
| Example 2: Two tangents PA=PB from external point P. PA=12cm, OA=5cm. Find OP. | |
| OP^2=OA^2+PA^2=25+144=169. OP=13cm. | |
| Example 3: Tangents from P touch circle at A and B. Angle APB=60°. Find angle AOB. | |
| Since PA=PB, triangle PAB is isosceles. Angle OAP=90°. | |
| In quadrilateral OAPB: angle AOB+angle OBP+angle APB+angle OAP=360°. | |
| angle AOB+90°+60°+90°=360° → angle AOB=120°. | |
| COMMON MISTAKES: | |
| Tangent from EXTERNAL point has equal length — this fails for internal points. | |
| Tangent ⊥ radius at POINT OF CONTACT (not at every point of tangent). | |
| Length of tangent uses Pythagoras: sqrt(d^2-r^2), not d-r. |