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| source: ncert | |
| topic: algebra | |
| class_level: class_11 | |
| chapter: ch6 | |
| difficulty: intermediate | |
| Class 11 | Ch6: Linear Inequalities | |
| RULES FOR INEQUALITIES: | |
| Adding/subtracting same quantity: inequality sign UNCHANGED. | |
| Multiplying/dividing by POSITIVE number: sign UNCHANGED. | |
| Multiplying/dividing by NEGATIVE number: sign REVERSED. | |
| SOLVING LINEAR INEQUALITIES IN ONE VARIABLE: | |
| Solve like equation but reverse sign when multiplying/dividing by negative. | |
| 3x-2>2x+1 β x>3. Solution: (3,infinity). On number line: open circle at 3, arrow right. | |
| GRAPHICAL METHOD FOR TWO VARIABLES: | |
| ax+by<c: boundary line ax+by=c (dashed for < or >, solid for <= or >=). | |
| Test point (usually origin) to determine which side. | |
| SYSTEM OF INEQUALITIES: | |
| Find region satisfying ALL inequalities simultaneously (feasible region). | |
| SOLVED EXAMPLES: | |
| Example 1: Solve 3x-2>2x+1. | |
| 3x-2x>1+2 β x>3. Solution set: (3,β). | |
| Example 2: Solve -3<(4x-1)/5<3. | |
| Multiply by 5: -15<4x-1<15 β -14<4x<16 β -7/2<x<4. | |
| Solution: (-3.5,4). | |
| Example 3: Solve system x+y<=10, x+3y<=15, x>=0, y>=0. | |
| Draw lines x+y=10 and x+3y=15. Find intersection: subtract to get 2y=5, y=2.5, x=7.5. | |
| Feasible region: bounded by vertices (0,0),(10,0),(7.5,2.5),(0,5). | |
| Example 4: IQ score: 62+4x/2<72 where x=age in months over 100. | |
| 124+4x<144 β 4x<20 β x<5. So age < 105 months. | |
| COMMON MISTAKES: | |
| MUST reverse inequality when multiplying/dividing by NEGATIVE number. | |
| For absolute value: |x|<a means -a<x<a (two conditions combined). | |
| Dashed line for strict inequality (<,>). Solid line for (<=,>=). |