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-3 + y = 0 \implies y = 3 |
2 u + u^2 = 0 \implies u \in \{ -2, 0 \} |
-14 - 8 = -22 |
\log_{2}\left(8 + 2 y\right) = 2 \implies y = -2 |
3 - 21 = -18 |
-3 + x = 0 \implies x = 3 |
f(w) = 5 + w + w^2, \quad g(y) = 4 + y \implies f(g(y)) = 25 + 9 y + y^2 |
-2 + 9 = 7 |
7 + u = 0 \implies u = -7 |
\frac{d}{dx}\left(x^3\right) = 3 x^2 |
44 + 28 = 72 |
\lim_{y \to -1} \left(y^2\right) = 1 |
\frac{d}{du}\left(u\right) = 1 |
f(w) = 4 + 3 w + w^2, \quad g(t) = 3 + 2 t \implies f(g(t)) = 22 + 18 t + 4 t^2 |
\cos{\left(y\right)} \left(-10 + y\right) = y \cos{\left(y\right)} - 10 \cos{\left(y\right)} |
f(w) = 3 + 5 w + w^2, \quad g(z) = 1 + z \implies f(g(z)) = 9 + 7 z + z^2 |
\frac{-48}{49} = \frac{-48}{49} |
(-3, -4, 3) \times (4, -5, 1) = (11, 15, 31) |
-112 - 16 c + 7 c^2 + c^3 = 0 \implies c \in \{ -7, -4, 4 \} |
f(t) = 2 + 3 t + t^2, \quad g(w) = 1 + w \implies f(g(w)) = 6 + 5 w + w^2 |
\int \left(-\sin{\left(w\right)} \left(-2 - w\right) - \cos{\left(w\right)}\right) dw = 2 + \cos{\left(w\right)} \left(-2 - w\right) + C |
(-3, -5, 5) \times (4, 4, -4) = (0, 8, 8) |
-7 + v = 0 \implies v = 7 |
\frac{d}{da}\left(a^2\right) = 2 a |
\cos{\left(u\right)} \left(-2 + x\right) = x \cos{\left(u\right)} - 2 \cos{\left(u\right)} |
36 - 12 z - 5 z^2 + z^3 = 0 \implies z \in \{ -3, 2, 6 \} |
\frac{-30}{23} = \frac{-30}{23} |
-16 - 16 x + x^2 + x^3 = 0 \implies x \in \{ -4, -1, 4 \} |
\log_{3}\left(7 + 4 v\right) = 1 \implies v = -1 |
2 + x = 0 \implies x = -2 |
\int \left(2 t + 2 \left(-2 + t\right)\right) dt = 2 t \left(-2 + t\right) + C |
\frac{d}{dw}\left(w^2 \sin{\left(w\right)}\right) = 2 w \sin{\left(w\right)} + w^2 \cos{\left(w\right)} |
\log_{2}\left(2 + u\right) = 2 \implies u = 2 |
-4 + b = 0 \implies b = 4 |
f(t) = 2 + t + t^2, \quad g(y) = 4 + y \implies f(g(y)) = 22 + 9 y + y^2 |
\log_{2}\left(5 + c\right) = 1 \implies c = -3 |
27 - 4 = 23 |
19 - 44 = -25 |
\log_{4}\left(7 + a\right) = 3 \implies a = 57 |
\log_{2}\left(4 + y\right) = 3 \implies y = 4 |
-24 + 5 w + w^2 = 0 \implies w \in \{ -8, 3 \} |
\int \left(\cos{\left(y\right)}\right) dy = \sin{\left(y\right)} + C |
-5 + u = 0 \implies u = 5 |
\log_{3}\left(4 + 2 a\right) = 1 \implies a = \frac{-1}{2} |
4 + x = 0 \implies x = -4 |
\int \left(2 u + \cos{\left(u\right)}\right) du = u^2 + \sin{\left(u\right)} + C |
\log_{2}\left(4 + 4 t\right) = 3 \implies t = 1 |
1 + y = 0 \implies y = -1 |
-210 - 47 u + 4 u^2 + u^3 = 0 \implies u \in \{ -6, -5, 7 \} |
(1, 4, -2) \times (-2, -1, 0) = (-2, 4, 7) |
\lim_{c \to -2} \left(c^2\right) = 4 |
24 - 10 z + z^2 = 0 \implies z \in \{ 4, 6 \} |
-2 + z = 0 \implies z = 2 |
\int \left(-\sin{\left(v\right)}\right) dv = -1 + \cos{\left(v\right)} + C |
(-5, 5, 5) \times (0, -2, -5) = (-15, -25, 10) |
\frac{9}{10} = \frac{9}{10} |
-25 \cdot 29 = -725 |
-47 \cdot 4 = -188 |
28 - 11 x + x^2 = 0 \implies x \in \{ 4, 7 \} |
20 + 9 a + a^2 = 0 \implies a \in \{ -5, -4 \} |
-10 - 3 u + u^2 = 0 \implies u \in \{ -2, 5 \} |
\frac{d}{dy}\left(\cos{\left(y\right)}\right) = -\sin{\left(y\right)} |
f(y) = 2 + 5 y + y^2, \quad g(t) = 4 + t \implies f(g(t)) = 38 + 13 t + t^2 |
f(a) = 5 + a + a^2, \quad g(w) = 4 + w \implies f(g(w)) = 25 + 9 w + w^2 |
\log_{3}\left(7 + 3 t\right) = 3 \implies t = \frac{20}{3} |
14 \cdot 18 = 252 |
\frac{-27}{21} = \frac{-9}{7} |
f(w) = 3 + 5 w + w^2, \quad g(t) = 3 + t \implies f(g(t)) = 27 + 11 t + t^2 |
-24 - 5 u + u^2 = 0 \implies u \in \{ -3, 8 \} |
f(y) = 4 + 4 y + y^2, \quad g(v) = 3 + v \implies f(g(v)) = 25 + 10 v + v^2 |
\frac{d}{dt}\left(\sin{\left(t\right)} \cos{\left(t\right)}\right) = -\sin{\left(t\right)}^2 + \cos{\left(t\right)}^2 |
\int \left(\cos{\left(t\right)}\right) dt = \sin{\left(t\right)} + C |
\log_{5}\left(4 + 4 v\right) = 3 \implies v = \frac{121}{4} |
7 + c = 0 \implies c = -7 |
\int \left(-1 + 3 w^2\right) dw = -w + w^3 + C |
\frac{d}{dc}\left(2 c\right) = 2 |
\int \left(-1\right) dz = -z + C |
-4 + v = 0 \implies v = 4 |
\frac{d}{db}\left(4 b\right) = 4 |
-20 - 42 = -62 |
39 \cdot 27 = 1053 |
\lim_{b \to 2} \left(7 - b\right) = 5 |
-3 - 14 = -17 |
\log_{3}\left(2 + 3 x\right) = 1 \implies x = \frac{1}{3} |
t \left(7 + x\right) = 7 t + t x |
24 - 10 v + v^2 = 0 \implies v \in \{ 4, 6 \} |
f(w) = 3 + 5 w + w^2, \quad g(v) = 1 + v \implies f(g(v)) = 9 + 7 v + v^2 |
-26 + 30 = 4 |
(2, -3, 0) \times (-1, 2, -3) = (9, 6, 1) |
f(b) = 2 + 3 b + b^2, \quad g(y) = 3 + 2 y \implies f(g(y)) = 20 + 18 y + 4 y^2 |
\log_{4}\left(4 + 2 u\right) = 2 \implies u = 6 |
\int \left(10 + 2 v\right) dv = 10 v + v^2 + C |
(4, -5, -2) \times (5, 4, -5) = (33, 10, 41) |
\log_{4}\left(8 + 4 x\right) = 3 \implies x = 14 |
f(y) = 3 + 4 y + y^2, \quad g(v) = 3 + v \implies f(g(v)) = 24 + 10 v + v^2 |
\lim_{x \to -5} \left(0\right) = 0 |
-5 + 4 u + u^2 = 0 \implies u \in \{ -5, 1 \} |
8 - 6 t + t^2 = 0 \implies t \in \{ 2, 4 \} |
\frac{d}{dv}\left(-v^2\right) = -2 v |
\frac{d}{dc}\left(c\right) = 1 |
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