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-15 - 22 = -37
18 - 9 y - 2 y^2 + y^3 = 0 \implies y \in \{ -3, 2, 3 \}
\log_{4}\left(1 + 2 u\right) = 2 \implies u = \frac{15}{2}
-6 + v = 0 \implies v = 6
\frac{d}{du}\left(u^4\right) = 4 u^3
\log_{2}\left(1 + 4 w\right) = 1 \implies w = \frac{1}{4}
-8 + u = 0 \implies u = 8
1 + a = 0 \implies a = -1
7 + 18 = 25
(-5, -5, 0) \times (-2, -3, 1) = (-5, 5, 5)
\frac{-17}{9} = \frac{-17}{9}
7 t + t^2 = 0 \implies t \in \{ -7, 0 \}
\frac{d}{dv}\left(v\right) = 1
f(c) = 5 + 2 c + c^2, \quad g(t) = 1 + t \implies f(g(t)) = 8 + 4 t + t^2
-4 - 27 = -31
\log_{5}\left(2 + 4 t\right) = 3 \implies t = \frac{123}{4}
\log_{4}\left(4 + 2 v\right) = 3 \implies v = 30
48 - 14 a - 7 a^2 + a^3 = 0 \implies a \in \{ -3, 2, 8 \}
-5 - v + 5 v^2 + v^3 = 0 \implies v \in \{ -5, -1, 1 \}
\frac{11}{50} = \frac{11}{50}
\lim_{b \to 1} \left(b\right) = 1
f(a) = 5 + 4 a + a^2, \quad g(b) = 2 + b \implies f(g(b)) = 17 + 8 b + b^2
8 + 7 = 15
-4 + w = 0 \implies w = 4
f(c) = 4 + 4 c + c^2, \quad g(t) = 2 + t \implies f(g(t)) = 16 + 8 t + t^2
-10 c \left(-2 + v\right) = 20 c - 10 c v
u \left(u + v\right) = u v + u^2
-40 \cdot 15 = -600
(-2, -1, 5) \times (-4, 2, 3) = (-13, -14, -8)
\frac{d}{dv}\left(0\right) = 0
f(u) = 2 + 4 u + u^2, \quad g(y) = 2 + 3 y \implies f(g(y)) = 14 + 24 y + 9 y^2
-2 + x = 0 \implies x = 2
-14 - 5 z + z^2 = 0 \implies z \in \{ -2, 7 \}
\log_{3}\left(5 + 2 b\right) = 3 \implies b = 11
f(v) = 1 + 5 v + v^2, \quad g(x) = 1 + 2 x \implies f(g(x)) = 7 + 14 x + 4 x^2
\lim_{t \to -2} \left(3 + t\right) = 1
-7 - 35 = -42
f(a) = 2 + 5 a + a^2, \quad g(z) = 1 + z \implies f(g(z)) = 8 + 7 z + z^2
7 + t = 0 \implies t = -7
-28 - 41 = -69
\log_{4}\left(1 + 4 b\right) = 3 \implies b = \frac{63}{4}
\frac{d}{dc}\left(0\right) = 0
-6 + t = 0 \implies t = 6
21 + 10 b + b^2 = 0 \implies b \in \{ -7, -3 \}
-39 \cdot 22 = -858
\log_{2}\left(1 + 4 u\right) = 3 \implies u = \frac{7}{4}
\left(t + u\right) \left(-8 + t\right) = -8 t - 8 u + t u + t^2
-40 \cdot 6 = -240
\frac{-1}{27} = \frac{-1}{27}
(-2, 4, -5) \times (-1, -2, -2) = (-18, 1, 8)
-3 + 2 u + u^2 = 0 \implies u \in \{ -3, 1 \}
-6 \left(9 - u\right) = -54 + 6 u
5 + x = 0 \implies x = -5
\int \left(3 b^2\right) db = b^3 + C
-27 + 48 = 21
\frac{d}{dv}\left(v^3\right) = 3 v^2
f(c) = 2 + 3 c + c^2, \quad g(t) = 3 + 3 t \implies f(g(t)) = 20 + 27 t + 9 t^2
\int \left(2 + 2 z\right) dz = 2 z + z^2 + C
20 - 12 = 8
(-2, 2, -1) \times (-5, 0, -4) = (-8, -3, 10)
\int \left(1\right) db = 9 + 2 b - \left(9 + b\right) + C
7 u + u^2 = 0 \implies u \in \{ -7, 0 \}
(4, 1, 0) \times (-3, -2, 5) = (5, -20, -5)
\log_{3}\left(8 + 4 y\right) = 3 \implies y = \frac{19}{4}
-15 \cdot 46 = -690
f(b) = 5 + 5 b + b^2, \quad g(z) = 2 + 3 z \implies f(g(z)) = 19 + 27 z + 9 z^2
13 + 5 = 18
\frac{d}{dw}\left(2 w + w^2\right) = 2 + 2 w
\lim_{y \to -3} \left(\cos{\left(y\right)}\right) = \cos{\left(3\right)}
-35 + 2 w + w^2 = 0 \implies w \in \{ -7, 5 \}
\lim_{t \to 2} \left(\cos{\left(t\right)}\right) = \cos{\left(2\right)}
1 + w = 0 \implies w = -1
7 + w = 0 \implies w = -7
-5 + 21 = 16
-40 + 46 = 6
\int \left(10\right) du = 10 u + C
-48 - 16 a + 3 a^2 + a^3 = 0 \implies a \in \{ -4, -3, 4 \}
(3, 1, 3) \times (-5, 3, -3) = (-12, -6, 14)
\int \left(-\sin{\left(t\right)}\right) dt = -1 + \cos{\left(t\right)} + C
-210 - 23 u + 8 u^2 + u^3 = 0 \implies u \in \{ -7, -6, 5 \}
\lim_{c \to 2} \left(c^4\right) = 16
f(t) = 1 + 4 t + t^2, \quad g(w) = 1 + w \implies f(g(w)) = 6 + 6 w + w^2
\int \left(1\right) da = a + C
f(v) = 4 + v + v^2, \quad g(x) = 2 + 2 x \implies f(g(x)) = 10 + 10 x + 4 x^2
\frac{d}{dw}\left(-8 w^2\right) = -16 w
\frac{d}{db}\left(b\right) = 1
(0, -4, 0) \times (4, 3, 2) = (-8, 0, 16)
\log_{5}\left(7 + 3 z\right) = 2 \implies z = 6
\frac{d}{dc}\left(c\right) = 1
\frac{d}{dz}\left(-3 - \sin{\left(z\right)}\right) = -\cos{\left(z\right)}
f(t) = 4 + 2 t + t^2, \quad g(z) = 3 + 3 z \implies f(g(z)) = 19 + 24 z + 9 z^2
\lim_{a \to 4} \left(2 a\right) = 8
f(z) = 4 + 2 z + z^2, \quad g(c) = 3 + 2 c \implies f(g(c)) = 19 + 16 c + 4 c^2
-12 + 4 c + c^2 = 0 \implies c \in \{ -6, 2 \}
-4 + u = 0 \implies u = 4
f(x) = 1 + x + x^2, \quad g(w) = 4 + 3 w \implies f(g(w)) = 21 + 27 w + 9 w^2
\lim_{y \to -3} \left(2 + y\right) = -1
b + b^2 = 0 \implies b \in \{ -1, 0 \}
v^3 \left(-6 + v\right) = -6 v^3 + v^4
\left(-a + x\right) \cos{\left(x\right)} = -a \cos{\left(x\right)} + x \cos{\left(x\right)}